Delete specific content in Excel
I have a list of data format shown below.
???m,"N0000001","????(M)","201405","201405","0.57674","0.60831"
???{???Y,"N0000003","????(M)","201402","201402","0.78170","0.68470"
?}???n?j?`??,"N0000004","????(M)","201407","201407","1.54956","1.54956"
???????Y,"N0000015","????(M)","201412","201412","0.95776","0.98891"
and I want to delete the 'N000000' these part. only leave the valid number. the output should like this
???m,"1","????(M)","201405","201405","0.57674","0.60831"
???{???Y,"3","????(M)","201402","201402","0.78170","0.68470"
?}???n?j?`??,"4","????(M)","201407","201407","1.54956","1.54956"
???????Y,"15","????(M)","201412","201412","0.95776","0.98891"
Does anyone know what kind of operation should I do?
excel vba excel-vba
edited Nov 16 '18 at 11:03
Pᴇʜ
24.9k63052
asked Nov 16 '18 at 9:16
J.FengJ.Feng
15
add a comment |
I have a list of data format shown below.
???m,"N0000001","????(M)","201405","201405","0.57674","0.60831"
???{???Y,"N0000003","????(M)","201402","201402","0.78170","0.68470"
?}???n?j?`??,"N0000004","????(M)","201407","201407","1.54956","1.54956"
???????Y,"N0000015","????(M)","201412","201412","0.95776","0.98891"
and I want to delete the 'N000000' these part. only leave the valid number. the output should like this
???m,"1","????(M)","201405","201405","0.57674","0.60831"
???{???Y,"3","????(M)","201402","201402","0.78170","0.68470"
?}???n?j?`??,"4","????(M)","201407","201407","1.54956","1.54956"
???????Y,"15","????(M)","201412","201412","0.95776","0.98891"
Does anyone know what kind of operation should I do?
excel vba excel-vba
edited Nov 16 '18 at 11:03
Pᴇʜ
24.9k63052
asked Nov 16 '18 at 9:16
J.FengJ.Feng
15
isregexan option ?
– Hamza Abdaoui
Nov 16 '18 at 9:18
1
If it's a fixed lengthN000000then Ctrl + H find and replace it... You can highlight the range to reduce potential impact elsewhere if it could occur.
– Glitch_Doctor
Nov 16 '18 at 9:30
add a comment |
I have a list of data format shown below.
???m,"N0000001","????(M)","201405","201405","0.57674","0.60831"
???{???Y,"N0000003","????(M)","201402","201402","0.78170","0.68470"
?}???n?j?`??,"N0000004","????(M)","201407","201407","1.54956","1.54956"
???????Y,"N0000015","????(M)","201412","201412","0.95776","0.98891"
and I want to delete the 'N000000' these part. only leave the valid number. the output should like this
???m,"1","????(M)","201405","201405","0.57674","0.60831"
???{???Y,"3","????(M)","201402","201402","0.78170","0.68470"
?}???n?j?`??,"4","????(M)","201407","201407","1.54956","1.54956"
???????Y,"15","????(M)","201412","201412","0.95776","0.98891"
Does anyone know what kind of operation should I do?
excel vba excel-vba
edited Nov 16 '18 at 11:03
Pᴇʜ
24.9k63052
asked Nov 16 '18 at 9:16
J.FengJ.Feng
15
I have a list of data format shown below.
???m,"N0000001","????(M)","201405","201405","0.57674","0.60831"
???{???Y,"N0000003","????(M)","201402","201402","0.78170","0.68470"
?}???n?j?`??,"N0000004","????(M)","201407","201407","1.54956","1.54956"
???????Y,"N0000015","????(M)","201412","201412","0.95776","0.98891"
and I want to delete the 'N000000' these part. only leave the valid number. the output should like this
???m,"1","????(M)","201405","201405","0.57674","0.60831"
???{???Y,"3","????(M)","201402","201402","0.78170","0.68470"
?}???n?j?`??,"4","????(M)","201407","201407","1.54956","1.54956"
???????Y,"15","????(M)","201412","201412","0.95776","0.98891"
Does anyone know what kind of operation should I do?
excel vba excel-vba
excel vba excel-vba
edited Nov 16 '18 at 11:03
Pᴇʜ
24.9k63052
asked Nov 16 '18 at 9:16
J.FengJ.Feng
15
edited Nov 16 '18 at 11:03
Pᴇʜ
24.9k63052
asked Nov 16 '18 at 9:16
J.FengJ.Feng
15
edited Nov 16 '18 at 11:03
Pᴇʜ
24.9k63052
edited Nov 16 '18 at 11:03
Pᴇʜ
24.9k63052
edited Nov 16 '18 at 11:03
Pᴇʜ
24.9k63052
24.9k63052
asked Nov 16 '18 at 9:16
J.FengJ.Feng
15
asked Nov 16 '18 at 9:16
J.FengJ.Feng
15
asked Nov 16 '18 at 9:16
J.FengJ.Feng
15
15
isregexan option ?
– Hamza Abdaoui
Nov 16 '18 at 9:18
1
If it's a fixed lengthN000000then Ctrl + H find and replace it... You can highlight the range to reduce potential impact elsewhere if it could occur.
– Glitch_Doctor
Nov 16 '18 at 9:30
add a comment |
isregexan option ?
– Hamza Abdaoui
Nov 16 '18 at 9:18
1
If it's a fixed lengthN000000then Ctrl + H find and replace it... You can highlight the range to reduce potential impact elsewhere if it could occur.
– Glitch_Doctor
Nov 16 '18 at 9:30
is
regex an option ?– Hamza Abdaoui
Nov 16 '18 at 9:18
is
regex an option ?– Hamza Abdaoui
Nov 16 '18 at 9:18
1
1
If it's a fixed length
N000000 then Ctrl + H find and replace it... You can highlight the range to reduce potential impact elsewhere if it could occur.– Glitch_Doctor
Nov 16 '18 at 9:30
If it's a fixed length
N000000 then Ctrl + H find and replace it... You can highlight the range to reduce potential impact elsewhere if it could occur.– Glitch_Doctor
Nov 16 '18 at 9:30
add a comment |
2 Answers
2
active
oldest
votes
Try this.
Sub test()
Dim rngDB As Range
Dim Ws As Worksheet
Set Ws = ActiveSheet
Set rngDB = Ws.UsedRange
rngDB.Replace "N000000", ""
End Sub
answered Nov 16 '18 at 11:26
Dy.LeeDy.Lee
3,6721511
add a comment |
your data list is very unclear. Assuming the data commening with N000000 is in an individual cell, the formula you could use would be:
for data in cell A1, place formula in cell B1:
with ';' as a delimiter:
=right(A1;LEN(A1)-LEN("N000000"))
with , as delimiter
=right(A1,LEN(A1)-LEN("N000000"))
answered Nov 16 '18 at 9:46
LambikLambik
500513
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
Try this.
Sub test()
Dim rngDB As Range
Dim Ws As Worksheet
Set Ws = ActiveSheet
Set rngDB = Ws.UsedRange
rngDB.Replace "N000000", ""
End Sub
answered Nov 16 '18 at 11:26
Dy.LeeDy.Lee
3,6721511
add a comment |
Try this.
Sub test()
Dim rngDB As Range
Dim Ws As Worksheet
Set Ws = ActiveSheet
Set rngDB = Ws.UsedRange
rngDB.Replace "N000000", ""
End Sub
answered Nov 16 '18 at 11:26
Dy.LeeDy.Lee
3,6721511
add a comment |
Try this.
Sub test()
Dim rngDB As Range
Dim Ws As Worksheet
Set Ws = ActiveSheet
Set rngDB = Ws.UsedRange
rngDB.Replace "N000000", ""
End Sub
answered Nov 16 '18 at 11:26
Dy.LeeDy.Lee
3,6721511
Try this.
Sub test()
Dim rngDB As Range
Dim Ws As Worksheet
Set Ws = ActiveSheet
Set rngDB = Ws.UsedRange
rngDB.Replace "N000000", ""
End Sub
answered Nov 16 '18 at 11:26
Dy.LeeDy.Lee
3,6721511
answered Nov 16 '18 at 11:26
Dy.LeeDy.Lee
3,6721511
answered Nov 16 '18 at 11:26
Dy.LeeDy.Lee
3,6721511
answered Nov 16 '18 at 11:26
Dy.LeeDy.Lee
3,6721511
3,6721511
add a comment |
add a comment |
your data list is very unclear. Assuming the data commening with N000000 is in an individual cell, the formula you could use would be:
for data in cell A1, place formula in cell B1:
with ';' as a delimiter:
=right(A1;LEN(A1)-LEN("N000000"))
with , as delimiter
=right(A1,LEN(A1)-LEN("N000000"))
answered Nov 16 '18 at 9:46
LambikLambik
500513
add a comment |
your data list is very unclear. Assuming the data commening with N000000 is in an individual cell, the formula you could use would be:
for data in cell A1, place formula in cell B1:
with ';' as a delimiter:
=right(A1;LEN(A1)-LEN("N000000"))
with , as delimiter
=right(A1,LEN(A1)-LEN("N000000"))
answered Nov 16 '18 at 9:46
LambikLambik
500513
add a comment |
your data list is very unclear. Assuming the data commening with N000000 is in an individual cell, the formula you could use would be:
for data in cell A1, place formula in cell B1:
with ';' as a delimiter:
=right(A1;LEN(A1)-LEN("N000000"))
with , as delimiter
=right(A1,LEN(A1)-LEN("N000000"))
answered Nov 16 '18 at 9:46
LambikLambik
500513
your data list is very unclear. Assuming the data commening with N000000 is in an individual cell, the formula you could use would be:
for data in cell A1, place formula in cell B1:
with ';' as a delimiter:
=right(A1;LEN(A1)-LEN("N000000"))
with , as delimiter
=right(A1,LEN(A1)-LEN("N000000"))
answered Nov 16 '18 at 9:46
LambikLambik
500513
answered Nov 16 '18 at 9:46
LambikLambik
500513
answered Nov 16 '18 at 9:46
LambikLambik
500513
answered Nov 16 '18 at 9:46
LambikLambik
500513
500513
add a comment |
add a comment |
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is
regexan option ?– Hamza Abdaoui
Nov 16 '18 at 9:18
1
If it's a fixed length
N000000then Ctrl + H find and replace it... You can highlight the range to reduce potential impact elsewhere if it could occur.– Glitch_Doctor
Nov 16 '18 at 9:30