Where is JVM PC stored during a call?
I am currently reading the last specification of the JVM. It is clear that each thread has its own call stack and its own program counter that keeps track of the (next) instruction to execute.
My question is maybe dump, but from the description, I cannot find an answer.
Where is the current program counter stored when a new or a method is invoked?
In other terms, how does the thread now where to continue after the invokation of a method?
jvm jvm-bytecode
asked Nov 16 '18 at 9:31
BriomkezBriomkez
148112
add a comment |
I am currently reading the last specification of the JVM. It is clear that each thread has its own call stack and its own program counter that keeps track of the (next) instruction to execute.
My question is maybe dump, but from the description, I cannot find an answer.
Where is the current program counter stored when a new or a method is invoked?
In other terms, how does the thread now where to continue after the invokation of a method?
jvm jvm-bytecode
asked Nov 16 '18 at 9:31
BriomkezBriomkez
148112
2
The PC is stored on the stack, either as a value for the interpreter to use or a regular CPU PC register for native code.
– Peter Lawrey
Nov 16 '18 at 9:56
add a comment |
I am currently reading the last specification of the JVM. It is clear that each thread has its own call stack and its own program counter that keeps track of the (next) instruction to execute.
My question is maybe dump, but from the description, I cannot find an answer.
Where is the current program counter stored when a new or a method is invoked?
In other terms, how does the thread now where to continue after the invokation of a method?
jvm jvm-bytecode
asked Nov 16 '18 at 9:31
BriomkezBriomkez
148112
I am currently reading the last specification of the JVM. It is clear that each thread has its own call stack and its own program counter that keeps track of the (next) instruction to execute.
My question is maybe dump, but from the description, I cannot find an answer.
Where is the current program counter stored when a new or a method is invoked?
In other terms, how does the thread now where to continue after the invokation of a method?
jvm jvm-bytecode
jvm jvm-bytecode
asked Nov 16 '18 at 9:31
BriomkezBriomkez
148112
asked Nov 16 '18 at 9:31
BriomkezBriomkez
148112
edited Nov 16 '18 at 13:47
Briomkez
asked Nov 16 '18 at 9:31
BriomkezBriomkez
148112
asked Nov 16 '18 at 9:31
BriomkezBriomkez
148112
asked Nov 16 '18 at 9:31
BriomkezBriomkez
148112
148112
2
The PC is stored on the stack, either as a value for the interpreter to use or a regular CPU PC register for native code.
– Peter Lawrey
Nov 16 '18 at 9:56
add a comment |
2
The PC is stored on the stack, either as a value for the interpreter to use or a regular CPU PC register for native code.
– Peter Lawrey
Nov 16 '18 at 9:56
2
2
The PC is stored on the stack, either as a value for the interpreter to use or a regular CPU PC register for native code.
– Peter Lawrey
Nov 16 '18 at 9:56
The PC is stored on the stack, either as a value for the interpreter to use or a regular CPU PC register for native code.
– Peter Lawrey
Nov 16 '18 at 9:56
add a comment |
1 Answer
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The answer is implementation-dependent as different hardware architectures and even different JVMs may implement this behavior in different ways. In the standard Oracle JVM, most of your bytecode will be compiled to native code by JIT (Just in Time compiler) and method calls will be executed as for native code (give or take some extra code which may be added to handle checkpointing etc.). On a PC this means that current register values, including the instruction pointer / program counter will be saved on the stack before a method call. When returning from the call, the processor pops these values from the stack, among them the return address.
answered Nov 16 '18 at 9:47
Michał KosmulskiMichał Kosmulski
8,2692445
add a comment |
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1 Answer
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1 Answer
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active
oldest
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oldest
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active
oldest
votes
The answer is implementation-dependent as different hardware architectures and even different JVMs may implement this behavior in different ways. In the standard Oracle JVM, most of your bytecode will be compiled to native code by JIT (Just in Time compiler) and method calls will be executed as for native code (give or take some extra code which may be added to handle checkpointing etc.). On a PC this means that current register values, including the instruction pointer / program counter will be saved on the stack before a method call. When returning from the call, the processor pops these values from the stack, among them the return address.
answered Nov 16 '18 at 9:47
Michał KosmulskiMichał Kosmulski
8,2692445
add a comment |
The answer is implementation-dependent as different hardware architectures and even different JVMs may implement this behavior in different ways. In the standard Oracle JVM, most of your bytecode will be compiled to native code by JIT (Just in Time compiler) and method calls will be executed as for native code (give or take some extra code which may be added to handle checkpointing etc.). On a PC this means that current register values, including the instruction pointer / program counter will be saved on the stack before a method call. When returning from the call, the processor pops these values from the stack, among them the return address.
answered Nov 16 '18 at 9:47
Michał KosmulskiMichał Kosmulski
8,2692445
add a comment |
The answer is implementation-dependent as different hardware architectures and even different JVMs may implement this behavior in different ways. In the standard Oracle JVM, most of your bytecode will be compiled to native code by JIT (Just in Time compiler) and method calls will be executed as for native code (give or take some extra code which may be added to handle checkpointing etc.). On a PC this means that current register values, including the instruction pointer / program counter will be saved on the stack before a method call. When returning from the call, the processor pops these values from the stack, among them the return address.
answered Nov 16 '18 at 9:47
Michał KosmulskiMichał Kosmulski
8,2692445
The answer is implementation-dependent as different hardware architectures and even different JVMs may implement this behavior in different ways. In the standard Oracle JVM, most of your bytecode will be compiled to native code by JIT (Just in Time compiler) and method calls will be executed as for native code (give or take some extra code which may be added to handle checkpointing etc.). On a PC this means that current register values, including the instruction pointer / program counter will be saved on the stack before a method call. When returning from the call, the processor pops these values from the stack, among them the return address.
answered Nov 16 '18 at 9:47
Michał KosmulskiMichał Kosmulski
8,2692445
answered Nov 16 '18 at 9:47
Michał KosmulskiMichał Kosmulski
8,2692445
answered Nov 16 '18 at 9:47
Michał KosmulskiMichał Kosmulski
8,2692445
answered Nov 16 '18 at 9:47
Michał KosmulskiMichał Kosmulski
8,2692445
8,2692445
add a comment |
add a comment |
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2
The PC is stored on the stack, either as a value for the interpreter to use or a regular CPU PC register for native code.
– Peter Lawrey
Nov 16 '18 at 9:56