Laravel echo listen for whisper function not working
I'm building a live chat app, but i found that listenforwhisper function is not working, but .whisper() function work fine, pusher also received client typing event.
Here is my code:
For listen whisper:
Echo.private(`messages.${this.user.id}`)
.listen("NewMessage", (e) => {
this.handleIncoming(e.message);
})
.listenForWhisper("typing", (e) => {
if(e.name !='') {
this.typeStatus = 'typing .........'
}
else {
this.typeStatus = ''
}
console.log(this.typeStatus);
});
For whisper:
watch: {
message() {
Echo.private(`messages.${this.user.id}`)
.whisper("typing", {
name: this.message
});
}
}
For channel:
Broadcast::channel('messages.{id}', function ($user, $id) {
return (int) $user->id === (int) $id;
});
Theoretically my console will return the typeStatus, but i got nothing in my console.
vue.js pusher laravel-echo
asked Nov 15 '18 at 2:15
chengweichengwei
428
add a comment |
I'm building a live chat app, but i found that listenforwhisper function is not working, but .whisper() function work fine, pusher also received client typing event.
Here is my code:
For listen whisper:
Echo.private(`messages.${this.user.id}`)
.listen("NewMessage", (e) => {
this.handleIncoming(e.message);
})
.listenForWhisper("typing", (e) => {
if(e.name !='') {
this.typeStatus = 'typing .........'
}
else {
this.typeStatus = ''
}
console.log(this.typeStatus);
});
For whisper:
watch: {
message() {
Echo.private(`messages.${this.user.id}`)
.whisper("typing", {
name: this.message
});
}
}
For channel:
Broadcast::channel('messages.{id}', function ($user, $id) {
return (int) $user->id === (int) $id;
});
Theoretically my console will return the typeStatus, but i got nothing in my console.
vue.js pusher laravel-echo
asked Nov 15 '18 at 2:15
chengweichengwei
428
add a comment |
I'm building a live chat app, but i found that listenforwhisper function is not working, but .whisper() function work fine, pusher also received client typing event.
Here is my code:
For listen whisper:
Echo.private(`messages.${this.user.id}`)
.listen("NewMessage", (e) => {
this.handleIncoming(e.message);
})
.listenForWhisper("typing", (e) => {
if(e.name !='') {
this.typeStatus = 'typing .........'
}
else {
this.typeStatus = ''
}
console.log(this.typeStatus);
});
For whisper:
watch: {
message() {
Echo.private(`messages.${this.user.id}`)
.whisper("typing", {
name: this.message
});
}
}
For channel:
Broadcast::channel('messages.{id}', function ($user, $id) {
return (int) $user->id === (int) $id;
});
Theoretically my console will return the typeStatus, but i got nothing in my console.
vue.js pusher laravel-echo
asked Nov 15 '18 at 2:15
chengweichengwei
428
I'm building a live chat app, but i found that listenforwhisper function is not working, but .whisper() function work fine, pusher also received client typing event.
Here is my code:
For listen whisper:
Echo.private(`messages.${this.user.id}`)
.listen("NewMessage", (e) => {
this.handleIncoming(e.message);
})
.listenForWhisper("typing", (e) => {
if(e.name !='') {
this.typeStatus = 'typing .........'
}
else {
this.typeStatus = ''
}
console.log(this.typeStatus);
});
For whisper:
watch: {
message() {
Echo.private(`messages.${this.user.id}`)
.whisper("typing", {
name: this.message
});
}
}
For channel:
Broadcast::channel('messages.{id}', function ($user, $id) {
return (int) $user->id === (int) $id;
});
Theoretically my console will return the typeStatus, but i got nothing in my console.
vue.js pusher laravel-echo
vue.js pusher laravel-echo
asked Nov 15 '18 at 2:15
chengweichengwei
428
asked Nov 15 '18 at 2:15
chengweichengwei
428
asked Nov 15 '18 at 2:15
chengweichengwei
428
asked Nov 15 '18 at 2:15
chengweichengwei
428
asked Nov 15 '18 at 2:15
chengweichengwei
428
428
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
Whisper works like broadcastToOthers. You're now trying to listen for the current users whispers. You should have a room where the whisper goes to and there should be multiple clients there to recieve. Now your channel is tied to the user and no-one else can see the messages that go through that channel.
answered Nov 15 '18 at 14:01
Niko PeltoniemiNiko Peltoniemi
21115
so you mean i have to have a channel that id is using a room id, and this room id will accept both the sender and receiver and return true??
– chengwei
Nov 15 '18 at 14:44
1
Exactly, you can keep the room ids in database and add them as a manyToMany relationship for both users.
– Niko Peltoniemi
Nov 16 '18 at 15:15
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
Whisper works like broadcastToOthers. You're now trying to listen for the current users whispers. You should have a room where the whisper goes to and there should be multiple clients there to recieve. Now your channel is tied to the user and no-one else can see the messages that go through that channel.
answered Nov 15 '18 at 14:01
Niko PeltoniemiNiko Peltoniemi
21115
so you mean i have to have a channel that id is using a room id, and this room id will accept both the sender and receiver and return true??
– chengwei
Nov 15 '18 at 14:44
1
Exactly, you can keep the room ids in database and add them as a manyToMany relationship for both users.
– Niko Peltoniemi
Nov 16 '18 at 15:15
add a comment |
Whisper works like broadcastToOthers. You're now trying to listen for the current users whispers. You should have a room where the whisper goes to and there should be multiple clients there to recieve. Now your channel is tied to the user and no-one else can see the messages that go through that channel.
answered Nov 15 '18 at 14:01
Niko PeltoniemiNiko Peltoniemi
21115
so you mean i have to have a channel that id is using a room id, and this room id will accept both the sender and receiver and return true??
– chengwei
Nov 15 '18 at 14:44
1
Exactly, you can keep the room ids in database and add them as a manyToMany relationship for both users.
– Niko Peltoniemi
Nov 16 '18 at 15:15
add a comment |
Whisper works like broadcastToOthers. You're now trying to listen for the current users whispers. You should have a room where the whisper goes to and there should be multiple clients there to recieve. Now your channel is tied to the user and no-one else can see the messages that go through that channel.
answered Nov 15 '18 at 14:01
Niko PeltoniemiNiko Peltoniemi
21115
Whisper works like broadcastToOthers. You're now trying to listen for the current users whispers. You should have a room where the whisper goes to and there should be multiple clients there to recieve. Now your channel is tied to the user and no-one else can see the messages that go through that channel.
answered Nov 15 '18 at 14:01
Niko PeltoniemiNiko Peltoniemi
21115
answered Nov 15 '18 at 14:01
Niko PeltoniemiNiko Peltoniemi
21115
answered Nov 15 '18 at 14:01
Niko PeltoniemiNiko Peltoniemi
21115
answered Nov 15 '18 at 14:01
Niko PeltoniemiNiko Peltoniemi
21115
21115
so you mean i have to have a channel that id is using a room id, and this room id will accept both the sender and receiver and return true??
– chengwei
Nov 15 '18 at 14:44
1
Exactly, you can keep the room ids in database and add them as a manyToMany relationship for both users.
– Niko Peltoniemi
Nov 16 '18 at 15:15
add a comment |
so you mean i have to have a channel that id is using a room id, and this room id will accept both the sender and receiver and return true??
– chengwei
Nov 15 '18 at 14:44
1
Exactly, you can keep the room ids in database and add them as a manyToMany relationship for both users.
– Niko Peltoniemi
Nov 16 '18 at 15:15
so you mean i have to have a channel that id is using a room id, and this room id will accept both the sender and receiver and return true??
– chengwei
Nov 15 '18 at 14:44
so you mean i have to have a channel that id is using a room id, and this room id will accept both the sender and receiver and return true??
– chengwei
Nov 15 '18 at 14:44
1
1
Exactly, you can keep the room ids in database and add them as a manyToMany relationship for both users.
– Niko Peltoniemi
Nov 16 '18 at 15:15
Exactly, you can keep the room ids in database and add them as a manyToMany relationship for both users.
– Niko Peltoniemi
Nov 16 '18 at 15:15
add a comment |
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