i'am trying to make a function that deletes vowels in a string
2
def disemvowel(word):
new_word =
list_of_letter = list(word)
for letter in list_of_letter:
if letter == 'a' or 'A' or 'E' or 'e' or 'O' or 'o' or 'U' or 'u':
continue
else:
new_word.append(letter)
return ''.join(new_word)
python-3.x list definition
edited Nov 14 '18 at 19:42
Johnny Mopp
6,92622444
asked Nov 14 '18 at 19:41
A.RizgarA.Rizgar
307
add a comment |
2
def disemvowel(word):
new_word =
list_of_letter = list(word)
for letter in list_of_letter:
if letter == 'a' or 'A' or 'E' or 'e' or 'O' or 'o' or 'U' or 'u':
continue
else:
new_word.append(letter)
return ''.join(new_word)
python-3.x list definition
edited Nov 14 '18 at 19:42
Johnny Mopp
6,92622444
asked Nov 14 '18 at 19:41
A.RizgarA.Rizgar
307
don't forget to include 'i' or 'I'. Also what's the problem?
– Rohlex32
Nov 14 '18 at 19:42
2
''.join([letter for letter in word if letter not in "AEIOUaeiou"])
– Johnny Mopp
Nov 14 '18 at 19:46
thank you very much, just solved the problem :)
– A.Rizgar
Nov 14 '18 at 20:57
add a comment |
2
2
2
def disemvowel(word):
new_word =
list_of_letter = list(word)
for letter in list_of_letter:
if letter == 'a' or 'A' or 'E' or 'e' or 'O' or 'o' or 'U' or 'u':
continue
else:
new_word.append(letter)
return ''.join(new_word)
python-3.x list definition
edited Nov 14 '18 at 19:42
Johnny Mopp
6,92622444
asked Nov 14 '18 at 19:41
A.RizgarA.Rizgar
307
def disemvowel(word):
new_word =
list_of_letter = list(word)
for letter in list_of_letter:
if letter == 'a' or 'A' or 'E' or 'e' or 'O' or 'o' or 'U' or 'u':
continue
else:
new_word.append(letter)
return ''.join(new_word)
python-3.x list definition
python-3.x list definition
edited Nov 14 '18 at 19:42
Johnny Mopp
6,92622444
asked Nov 14 '18 at 19:41
A.RizgarA.Rizgar
307
edited Nov 14 '18 at 19:42
Johnny Mopp
6,92622444
asked Nov 14 '18 at 19:41
A.RizgarA.Rizgar
307
edited Nov 14 '18 at 19:42
Johnny Mopp
6,92622444
edited Nov 14 '18 at 19:42
Johnny Mopp
6,92622444
edited Nov 14 '18 at 19:42
Johnny Mopp
6,92622444
6,92622444
asked Nov 14 '18 at 19:41
A.RizgarA.Rizgar
307
asked Nov 14 '18 at 19:41
A.RizgarA.Rizgar
307
asked Nov 14 '18 at 19:41
A.RizgarA.Rizgar
307
307
don't forget to include 'i' or 'I'. Also what's the problem?
– Rohlex32
Nov 14 '18 at 19:42
2
''.join([letter for letter in word if letter not in "AEIOUaeiou"])
– Johnny Mopp
Nov 14 '18 at 19:46
thank you very much, just solved the problem :)
– A.Rizgar
Nov 14 '18 at 20:57
add a comment |
don't forget to include 'i' or 'I'. Also what's the problem?
– Rohlex32
Nov 14 '18 at 19:42
2
''.join([letter for letter in word if letter not in "AEIOUaeiou"])
– Johnny Mopp
Nov 14 '18 at 19:46
thank you very much, just solved the problem :)
– A.Rizgar
Nov 14 '18 at 20:57
don't forget to include 'i' or 'I'. Also what's the problem?
– Rohlex32
Nov 14 '18 at 19:42
don't forget to include 'i' or 'I'. Also what's the problem?
– Rohlex32
Nov 14 '18 at 19:42
2
2
''.join([letter for letter in word if letter not in "AEIOUaeiou"])– Johnny Mopp
Nov 14 '18 at 19:46
''.join([letter for letter in word if letter not in "AEIOUaeiou"])– Johnny Mopp
Nov 14 '18 at 19:46
thank you very much, just solved the problem :)
– A.Rizgar
Nov 14 '18 at 20:57
thank you very much, just solved the problem :)
– A.Rizgar
Nov 14 '18 at 20:57
add a comment |
1 Answer
1
active
oldest
votes
2
Your condition is always True
You should change it to:
if letter in "aAeEiIoOuU":
When you write
if letter == 'a' or 'A'
You said "if letter is 'a' or if 'A' is not a empty string", and a is not a empty string.
answered Nov 14 '18 at 19:44
iEldeniElden
684517
thank you very much
– A.Rizgar
Nov 14 '18 at 20:54
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
2
Your condition is always True
You should change it to:
if letter in "aAeEiIoOuU":
When you write
if letter == 'a' or 'A'
You said "if letter is 'a' or if 'A' is not a empty string", and a is not a empty string.
answered Nov 14 '18 at 19:44
iEldeniElden
684517
thank you very much
– A.Rizgar
Nov 14 '18 at 20:54
add a comment |
2
Your condition is always True
You should change it to:
if letter in "aAeEiIoOuU":
When you write
if letter == 'a' or 'A'
You said "if letter is 'a' or if 'A' is not a empty string", and a is not a empty string.
answered Nov 14 '18 at 19:44
iEldeniElden
684517
thank you very much
– A.Rizgar
Nov 14 '18 at 20:54
add a comment |
2
2
2
Your condition is always True
You should change it to:
if letter in "aAeEiIoOuU":
When you write
if letter == 'a' or 'A'
You said "if letter is 'a' or if 'A' is not a empty string", and a is not a empty string.
answered Nov 14 '18 at 19:44
iEldeniElden
684517
Your condition is always True
You should change it to:
if letter in "aAeEiIoOuU":
When you write
if letter == 'a' or 'A'
You said "if letter is 'a' or if 'A' is not a empty string", and a is not a empty string.
answered Nov 14 '18 at 19:44
iEldeniElden
684517
answered Nov 14 '18 at 19:44
iEldeniElden
684517
answered Nov 14 '18 at 19:44
iEldeniElden
684517
answered Nov 14 '18 at 19:44
iEldeniElden
684517
684517
thank you very much
– A.Rizgar
Nov 14 '18 at 20:54
add a comment |
thank you very much
– A.Rizgar
Nov 14 '18 at 20:54
thank you very much
– A.Rizgar
Nov 14 '18 at 20:54
thank you very much
– A.Rizgar
Nov 14 '18 at 20:54
add a comment |
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don't forget to include 'i' or 'I'. Also what's the problem?
– Rohlex32
Nov 14 '18 at 19:42
2
''.join([letter for letter in word if letter not in "AEIOUaeiou"])– Johnny Mopp
Nov 14 '18 at 19:46
thank you very much, just solved the problem :)
– A.Rizgar
Nov 14 '18 at 20:57