jQuery infinite loop through each div












4















I have some divs with divs in them, which I want to loop through while removing a class from the current one, then adding a class to the next one.



Then when I reach the last one, I want to go back to the start and do it all over again.



I already have a way of doing this, but it only works for one set of divs, I'm going to be having many sets of divs that need to loop independently.



Here's an example few sets (there would be a random amount of divs in each):



<div class="set">
<div class="current">Item1</div>
<div>Item2</div>
<div>Item3</div>
</div>


<div class="set">
<div class="current">Item1</div>
<div>Item2</div>
<div>Item3</div>
<div>Item4</div>
<div>Item5</div>
</div>


I need to remove that current class, and add it to the next div in each set, and so on.



Here is the code I have that works with one set:



$(function() {
var items = $('.set div').length;
current = 0;

setInterval(function() {
$('.set div').eq(current).removeClass('current');

if (current == items - 1){
current = 0;
} else {
current++;
}

$('.set div').eq(current).addClass('current');
}, 500);
});









share|improve this question

























  • posting your current jquery code could help, if you already have a method for doing it to one set of divs using each() for all divs of class "set" should solve the problem, or am I mistaken?

    – optimusprime619
    Jun 8 '12 at 12:47











  • would all parent divs have class="set"? and when you say that you'll have "many sets of divs that need to loop independently" are you saying that while all sets have a parent div with class="set", the number of sets n to work on would be anywhere from 1 to n?

    – jimmym715
    Jun 8 '12 at 12:49
















4















I have some divs with divs in them, which I want to loop through while removing a class from the current one, then adding a class to the next one.



Then when I reach the last one, I want to go back to the start and do it all over again.



I already have a way of doing this, but it only works for one set of divs, I'm going to be having many sets of divs that need to loop independently.



Here's an example few sets (there would be a random amount of divs in each):



<div class="set">
<div class="current">Item1</div>
<div>Item2</div>
<div>Item3</div>
</div>


<div class="set">
<div class="current">Item1</div>
<div>Item2</div>
<div>Item3</div>
<div>Item4</div>
<div>Item5</div>
</div>


I need to remove that current class, and add it to the next div in each set, and so on.



Here is the code I have that works with one set:



$(function() {
var items = $('.set div').length;
current = 0;

setInterval(function() {
$('.set div').eq(current).removeClass('current');

if (current == items - 1){
current = 0;
} else {
current++;
}

$('.set div').eq(current).addClass('current');
}, 500);
});









share|improve this question

























  • posting your current jquery code could help, if you already have a method for doing it to one set of divs using each() for all divs of class "set" should solve the problem, or am I mistaken?

    – optimusprime619
    Jun 8 '12 at 12:47











  • would all parent divs have class="set"? and when you say that you'll have "many sets of divs that need to loop independently" are you saying that while all sets have a parent div with class="set", the number of sets n to work on would be anywhere from 1 to n?

    – jimmym715
    Jun 8 '12 at 12:49














4












4








4








I have some divs with divs in them, which I want to loop through while removing a class from the current one, then adding a class to the next one.



Then when I reach the last one, I want to go back to the start and do it all over again.



I already have a way of doing this, but it only works for one set of divs, I'm going to be having many sets of divs that need to loop independently.



Here's an example few sets (there would be a random amount of divs in each):



<div class="set">
<div class="current">Item1</div>
<div>Item2</div>
<div>Item3</div>
</div>


<div class="set">
<div class="current">Item1</div>
<div>Item2</div>
<div>Item3</div>
<div>Item4</div>
<div>Item5</div>
</div>


I need to remove that current class, and add it to the next div in each set, and so on.



Here is the code I have that works with one set:



$(function() {
var items = $('.set div').length;
current = 0;

setInterval(function() {
$('.set div').eq(current).removeClass('current');

if (current == items - 1){
current = 0;
} else {
current++;
}

$('.set div').eq(current).addClass('current');
}, 500);
});









share|improve this question
















I have some divs with divs in them, which I want to loop through while removing a class from the current one, then adding a class to the next one.



Then when I reach the last one, I want to go back to the start and do it all over again.



I already have a way of doing this, but it only works for one set of divs, I'm going to be having many sets of divs that need to loop independently.



Here's an example few sets (there would be a random amount of divs in each):



<div class="set">
<div class="current">Item1</div>
<div>Item2</div>
<div>Item3</div>
</div>


<div class="set">
<div class="current">Item1</div>
<div>Item2</div>
<div>Item3</div>
<div>Item4</div>
<div>Item5</div>
</div>


I need to remove that current class, and add it to the next div in each set, and so on.



Here is the code I have that works with one set:



$(function() {
var items = $('.set div').length;
current = 0;

setInterval(function() {
$('.set div').eq(current).removeClass('current');

if (current == items - 1){
current = 0;
} else {
current++;
}

$('.set div').eq(current).addClass('current');
}, 500);
});






jquery infinite-loop






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Jun 8 '12 at 12:53







Dentor Uman

















asked Jun 8 '12 at 12:43









Dentor UmanDentor Uman

2314




2314













  • posting your current jquery code could help, if you already have a method for doing it to one set of divs using each() for all divs of class "set" should solve the problem, or am I mistaken?

    – optimusprime619
    Jun 8 '12 at 12:47











  • would all parent divs have class="set"? and when you say that you'll have "many sets of divs that need to loop independently" are you saying that while all sets have a parent div with class="set", the number of sets n to work on would be anywhere from 1 to n?

    – jimmym715
    Jun 8 '12 at 12:49



















  • posting your current jquery code could help, if you already have a method for doing it to one set of divs using each() for all divs of class "set" should solve the problem, or am I mistaken?

    – optimusprime619
    Jun 8 '12 at 12:47











  • would all parent divs have class="set"? and when you say that you'll have "many sets of divs that need to loop independently" are you saying that while all sets have a parent div with class="set", the number of sets n to work on would be anywhere from 1 to n?

    – jimmym715
    Jun 8 '12 at 12:49

















posting your current jquery code could help, if you already have a method for doing it to one set of divs using each() for all divs of class "set" should solve the problem, or am I mistaken?

– optimusprime619
Jun 8 '12 at 12:47





posting your current jquery code could help, if you already have a method for doing it to one set of divs using each() for all divs of class "set" should solve the problem, or am I mistaken?

– optimusprime619
Jun 8 '12 at 12:47













would all parent divs have class="set"? and when you say that you'll have "many sets of divs that need to loop independently" are you saying that while all sets have a parent div with class="set", the number of sets n to work on would be anywhere from 1 to n?

– jimmym715
Jun 8 '12 at 12:49





would all parent divs have class="set"? and when you say that you'll have "many sets of divs that need to loop independently" are you saying that while all sets have a parent div with class="set", the number of sets n to work on would be anywhere from 1 to n?

– jimmym715
Jun 8 '12 at 12:49












3 Answers
3






active

oldest

votes


















9














my take:



http://jsfiddle.net/yyY28/



$('.set').each(function(){
(function($set){
setInterval(function(){
var $cur = $set.find('.current').removeClass('current');
var $next = $cur.next().length?$cur.next():$set.children().eq(0);
$next.addClass('current');
},1000);
})($(this));

});​




version 2:



​setInterval(function(){
$('.set').each(function(){
var $cur = $(this).find('.current').removeClass('current');
var $next = $cur.next().length?$cur.next():$(this).children().eq(0);
$next.addClass('current');
});
},1000);​





share|improve this answer


























  • That works perfectly, and it's actually less code than my original. Amazing! Thanks!

    – Dentor Uman
    Jun 8 '12 at 13:10











  • You assign each .set a new setInterval, so in couple of minutes the sets will run out of synchronous work.

    – VisioN
    Jun 8 '12 at 13:19











  • @VisioN good point. I added a second version which can't run out of sync and is more elegant as well. edit: oh it's almost exactly your version now :P

    – Andy
    Jun 8 '12 at 13:27













  • @Andy As good as mine :D

    – VisioN
    Jun 8 '12 at 13:27



















2














Maybe I didn't get you right, but is that you are looking for?



function loop() {
$(".set").each(function() {
var current = $(this).children(".current").removeClass("current");
var i = current.next().length ? current.index() : 0;
current.siblings(":eq(" + i + ")").addClass("current");
});
}

setInterval(loop, 500);​


DEMO: http://jsfiddle.net/jGcsh/






share|improve this answer































    0














    try this one:



    function changeCurrent(){
    $('.set').each(function(){
    var currentSubDiv = $(this).children('.current');
    currentSubDiv.removeClass('current');
    currentSubDiv.next().addClass('current');
    })
    }

    setInterval(changeCurrent,timeInMillis);





    share|improve this answer

























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      3 Answers
      3






      active

      oldest

      votes








      3 Answers
      3






      active

      oldest

      votes









      active

      oldest

      votes






      active

      oldest

      votes









      9














      my take:



      http://jsfiddle.net/yyY28/



      $('.set').each(function(){
      (function($set){
      setInterval(function(){
      var $cur = $set.find('.current').removeClass('current');
      var $next = $cur.next().length?$cur.next():$set.children().eq(0);
      $next.addClass('current');
      },1000);
      })($(this));

      });​




      version 2:



      ​setInterval(function(){
      $('.set').each(function(){
      var $cur = $(this).find('.current').removeClass('current');
      var $next = $cur.next().length?$cur.next():$(this).children().eq(0);
      $next.addClass('current');
      });
      },1000);​





      share|improve this answer


























      • That works perfectly, and it's actually less code than my original. Amazing! Thanks!

        – Dentor Uman
        Jun 8 '12 at 13:10











      • You assign each .set a new setInterval, so in couple of minutes the sets will run out of synchronous work.

        – VisioN
        Jun 8 '12 at 13:19











      • @VisioN good point. I added a second version which can't run out of sync and is more elegant as well. edit: oh it's almost exactly your version now :P

        – Andy
        Jun 8 '12 at 13:27













      • @Andy As good as mine :D

        – VisioN
        Jun 8 '12 at 13:27
















      9














      my take:



      http://jsfiddle.net/yyY28/



      $('.set').each(function(){
      (function($set){
      setInterval(function(){
      var $cur = $set.find('.current').removeClass('current');
      var $next = $cur.next().length?$cur.next():$set.children().eq(0);
      $next.addClass('current');
      },1000);
      })($(this));

      });​




      version 2:



      ​setInterval(function(){
      $('.set').each(function(){
      var $cur = $(this).find('.current').removeClass('current');
      var $next = $cur.next().length?$cur.next():$(this).children().eq(0);
      $next.addClass('current');
      });
      },1000);​





      share|improve this answer


























      • That works perfectly, and it's actually less code than my original. Amazing! Thanks!

        – Dentor Uman
        Jun 8 '12 at 13:10











      • You assign each .set a new setInterval, so in couple of minutes the sets will run out of synchronous work.

        – VisioN
        Jun 8 '12 at 13:19











      • @VisioN good point. I added a second version which can't run out of sync and is more elegant as well. edit: oh it's almost exactly your version now :P

        – Andy
        Jun 8 '12 at 13:27













      • @Andy As good as mine :D

        – VisioN
        Jun 8 '12 at 13:27














      9












      9








      9







      my take:



      http://jsfiddle.net/yyY28/



      $('.set').each(function(){
      (function($set){
      setInterval(function(){
      var $cur = $set.find('.current').removeClass('current');
      var $next = $cur.next().length?$cur.next():$set.children().eq(0);
      $next.addClass('current');
      },1000);
      })($(this));

      });​




      version 2:



      ​setInterval(function(){
      $('.set').each(function(){
      var $cur = $(this).find('.current').removeClass('current');
      var $next = $cur.next().length?$cur.next():$(this).children().eq(0);
      $next.addClass('current');
      });
      },1000);​





      share|improve this answer















      my take:



      http://jsfiddle.net/yyY28/



      $('.set').each(function(){
      (function($set){
      setInterval(function(){
      var $cur = $set.find('.current').removeClass('current');
      var $next = $cur.next().length?$cur.next():$set.children().eq(0);
      $next.addClass('current');
      },1000);
      })($(this));

      });​




      version 2:



      ​setInterval(function(){
      $('.set').each(function(){
      var $cur = $(this).find('.current').removeClass('current');
      var $next = $cur.next().length?$cur.next():$(this).children().eq(0);
      $next.addClass('current');
      });
      },1000);​






      share|improve this answer














      share|improve this answer



      share|improve this answer








      edited Jun 8 '12 at 13:25

























      answered Jun 8 '12 at 12:54









      AndyAndy

      25.7k83357




      25.7k83357













      • That works perfectly, and it's actually less code than my original. Amazing! Thanks!

        – Dentor Uman
        Jun 8 '12 at 13:10











      • You assign each .set a new setInterval, so in couple of minutes the sets will run out of synchronous work.

        – VisioN
        Jun 8 '12 at 13:19











      • @VisioN good point. I added a second version which can't run out of sync and is more elegant as well. edit: oh it's almost exactly your version now :P

        – Andy
        Jun 8 '12 at 13:27













      • @Andy As good as mine :D

        – VisioN
        Jun 8 '12 at 13:27



















      • That works perfectly, and it's actually less code than my original. Amazing! Thanks!

        – Dentor Uman
        Jun 8 '12 at 13:10











      • You assign each .set a new setInterval, so in couple of minutes the sets will run out of synchronous work.

        – VisioN
        Jun 8 '12 at 13:19











      • @VisioN good point. I added a second version which can't run out of sync and is more elegant as well. edit: oh it's almost exactly your version now :P

        – Andy
        Jun 8 '12 at 13:27













      • @Andy As good as mine :D

        – VisioN
        Jun 8 '12 at 13:27

















      That works perfectly, and it's actually less code than my original. Amazing! Thanks!

      – Dentor Uman
      Jun 8 '12 at 13:10





      That works perfectly, and it's actually less code than my original. Amazing! Thanks!

      – Dentor Uman
      Jun 8 '12 at 13:10













      You assign each .set a new setInterval, so in couple of minutes the sets will run out of synchronous work.

      – VisioN
      Jun 8 '12 at 13:19





      You assign each .set a new setInterval, so in couple of minutes the sets will run out of synchronous work.

      – VisioN
      Jun 8 '12 at 13:19













      @VisioN good point. I added a second version which can't run out of sync and is more elegant as well. edit: oh it's almost exactly your version now :P

      – Andy
      Jun 8 '12 at 13:27







      @VisioN good point. I added a second version which can't run out of sync and is more elegant as well. edit: oh it's almost exactly your version now :P

      – Andy
      Jun 8 '12 at 13:27















      @Andy As good as mine :D

      – VisioN
      Jun 8 '12 at 13:27





      @Andy As good as mine :D

      – VisioN
      Jun 8 '12 at 13:27













      2














      Maybe I didn't get you right, but is that you are looking for?



      function loop() {
      $(".set").each(function() {
      var current = $(this).children(".current").removeClass("current");
      var i = current.next().length ? current.index() : 0;
      current.siblings(":eq(" + i + ")").addClass("current");
      });
      }

      setInterval(loop, 500);​


      DEMO: http://jsfiddle.net/jGcsh/






      share|improve this answer




























        2














        Maybe I didn't get you right, but is that you are looking for?



        function loop() {
        $(".set").each(function() {
        var current = $(this).children(".current").removeClass("current");
        var i = current.next().length ? current.index() : 0;
        current.siblings(":eq(" + i + ")").addClass("current");
        });
        }

        setInterval(loop, 500);​


        DEMO: http://jsfiddle.net/jGcsh/






        share|improve this answer


























          2












          2








          2







          Maybe I didn't get you right, but is that you are looking for?



          function loop() {
          $(".set").each(function() {
          var current = $(this).children(".current").removeClass("current");
          var i = current.next().length ? current.index() : 0;
          current.siblings(":eq(" + i + ")").addClass("current");
          });
          }

          setInterval(loop, 500);​


          DEMO: http://jsfiddle.net/jGcsh/






          share|improve this answer













          Maybe I didn't get you right, but is that you are looking for?



          function loop() {
          $(".set").each(function() {
          var current = $(this).children(".current").removeClass("current");
          var i = current.next().length ? current.index() : 0;
          current.siblings(":eq(" + i + ")").addClass("current");
          });
          }

          setInterval(loop, 500);​


          DEMO: http://jsfiddle.net/jGcsh/







          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered Jun 8 '12 at 12:55









          VisioNVisioN

          112k24212229




          112k24212229























              0














              try this one:



              function changeCurrent(){
              $('.set').each(function(){
              var currentSubDiv = $(this).children('.current');
              currentSubDiv.removeClass('current');
              currentSubDiv.next().addClass('current');
              })
              }

              setInterval(changeCurrent,timeInMillis);





              share|improve this answer






























                0














                try this one:



                function changeCurrent(){
                $('.set').each(function(){
                var currentSubDiv = $(this).children('.current');
                currentSubDiv.removeClass('current');
                currentSubDiv.next().addClass('current');
                })
                }

                setInterval(changeCurrent,timeInMillis);





                share|improve this answer




























                  0












                  0








                  0







                  try this one:



                  function changeCurrent(){
                  $('.set').each(function(){
                  var currentSubDiv = $(this).children('.current');
                  currentSubDiv.removeClass('current');
                  currentSubDiv.next().addClass('current');
                  })
                  }

                  setInterval(changeCurrent,timeInMillis);





                  share|improve this answer















                  try this one:



                  function changeCurrent(){
                  $('.set').each(function(){
                  var currentSubDiv = $(this).children('.current');
                  currentSubDiv.removeClass('current');
                  currentSubDiv.next().addClass('current');
                  })
                  }

                  setInterval(changeCurrent,timeInMillis);






                  share|improve this answer














                  share|improve this answer



                  share|improve this answer








                  edited Jun 8 '12 at 13:35

























                  answered Jun 8 '12 at 12:53









                  Th0rndikeTh0rndike

                  2,92431331




                  2,92431331






























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