Excel VBA - Multiple regex pattern deletion












1















In Excel VBA I need to perform multiple regular expression matches which then deletes the match from the string while preserving the remainder of the string. I have it working by daisy-chaining two variables, and by not testing the pattern match first since the second match is the remainder of the first.



Consider the follow data:



(2.5.3) A. 100% of product will be delivered in 3 days



(2.5.3) B. Capability to deliver product by air.



(2.5.3) C. Support for xyz feature



(2.5.3) D. Vendor is to provide an overview of the network as proposed.



(2.5.3) E. The network should allow CustomerABC to discover their devices.



(2.5.3) F. The use of CustomerABC existing infrastructure should be optimized. CustomerABC's capability will vary.



(2.5.3) G. Describe the number of network devices requiring to run CustomerABC's center.



With this data, I am deleting the outline numbers in the beginning of the string, as well as any references to CustomerABC and any hyphenation that could possibly appear multiple times in the string at any location, with potentially upper and lower case. I have the regex's working. Here is the code I'm trying:



Function test(Txt As String) As String
Dim regEx As Object
Dim v1 As String
Dim v2 As String
Dim n As String
n = "CustomerABC"

If regEx Is Nothing Then
Set regEx = CreateObject("VBScript.RegExp")
regEx.Global = True
regEx.IgnoreCase = True
End If
If Len(Txt) > 0 Then
With regEx
' The 1st pattern
.Pattern = "^(?[0-9.]+)?"
'If Not .Test(Txt) Then Exit Function
v1 = .Replace(Txt, "")
' The 2nd pattern
.Pattern = n + "(S*)?(s+)?"
'If Not .Test(Txt) Then Exit Function
v2 = .Replace(v1, "")
' The result
test = Application.Trim(v2)
End With
End If
End Function


Is there a way to make this better, speed things up, and have a variable number of match/deletions?



Thanks in advance.










share|improve this question























  • You can pass in an array of patterns along with the string to be modified, or define an array within your function and then loop over it and perform the replacements.

    – Tim Williams
    Nov 14 '18 at 16:10











  • Hi Tim, I saw your post: stackoverflow.com/questions/9672436/…, but was unsure how to adapt it to my particular needs based on the fact that I am deleting and keeping remainders. May I have an example?

    – Bob
    Nov 14 '18 at 16:17
















1















In Excel VBA I need to perform multiple regular expression matches which then deletes the match from the string while preserving the remainder of the string. I have it working by daisy-chaining two variables, and by not testing the pattern match first since the second match is the remainder of the first.



Consider the follow data:



(2.5.3) A. 100% of product will be delivered in 3 days



(2.5.3) B. Capability to deliver product by air.



(2.5.3) C. Support for xyz feature



(2.5.3) D. Vendor is to provide an overview of the network as proposed.



(2.5.3) E. The network should allow CustomerABC to discover their devices.



(2.5.3) F. The use of CustomerABC existing infrastructure should be optimized. CustomerABC's capability will vary.



(2.5.3) G. Describe the number of network devices requiring to run CustomerABC's center.



With this data, I am deleting the outline numbers in the beginning of the string, as well as any references to CustomerABC and any hyphenation that could possibly appear multiple times in the string at any location, with potentially upper and lower case. I have the regex's working. Here is the code I'm trying:



Function test(Txt As String) As String
Dim regEx As Object
Dim v1 As String
Dim v2 As String
Dim n As String
n = "CustomerABC"

If regEx Is Nothing Then
Set regEx = CreateObject("VBScript.RegExp")
regEx.Global = True
regEx.IgnoreCase = True
End If
If Len(Txt) > 0 Then
With regEx
' The 1st pattern
.Pattern = "^(?[0-9.]+)?"
'If Not .Test(Txt) Then Exit Function
v1 = .Replace(Txt, "")
' The 2nd pattern
.Pattern = n + "(S*)?(s+)?"
'If Not .Test(Txt) Then Exit Function
v2 = .Replace(v1, "")
' The result
test = Application.Trim(v2)
End With
End If
End Function


Is there a way to make this better, speed things up, and have a variable number of match/deletions?



Thanks in advance.










share|improve this question























  • You can pass in an array of patterns along with the string to be modified, or define an array within your function and then loop over it and perform the replacements.

    – Tim Williams
    Nov 14 '18 at 16:10











  • Hi Tim, I saw your post: stackoverflow.com/questions/9672436/…, but was unsure how to adapt it to my particular needs based on the fact that I am deleting and keeping remainders. May I have an example?

    – Bob
    Nov 14 '18 at 16:17














1












1








1


1






In Excel VBA I need to perform multiple regular expression matches which then deletes the match from the string while preserving the remainder of the string. I have it working by daisy-chaining two variables, and by not testing the pattern match first since the second match is the remainder of the first.



Consider the follow data:



(2.5.3) A. 100% of product will be delivered in 3 days



(2.5.3) B. Capability to deliver product by air.



(2.5.3) C. Support for xyz feature



(2.5.3) D. Vendor is to provide an overview of the network as proposed.



(2.5.3) E. The network should allow CustomerABC to discover their devices.



(2.5.3) F. The use of CustomerABC existing infrastructure should be optimized. CustomerABC's capability will vary.



(2.5.3) G. Describe the number of network devices requiring to run CustomerABC's center.



With this data, I am deleting the outline numbers in the beginning of the string, as well as any references to CustomerABC and any hyphenation that could possibly appear multiple times in the string at any location, with potentially upper and lower case. I have the regex's working. Here is the code I'm trying:



Function test(Txt As String) As String
Dim regEx As Object
Dim v1 As String
Dim v2 As String
Dim n As String
n = "CustomerABC"

If regEx Is Nothing Then
Set regEx = CreateObject("VBScript.RegExp")
regEx.Global = True
regEx.IgnoreCase = True
End If
If Len(Txt) > 0 Then
With regEx
' The 1st pattern
.Pattern = "^(?[0-9.]+)?"
'If Not .Test(Txt) Then Exit Function
v1 = .Replace(Txt, "")
' The 2nd pattern
.Pattern = n + "(S*)?(s+)?"
'If Not .Test(Txt) Then Exit Function
v2 = .Replace(v1, "")
' The result
test = Application.Trim(v2)
End With
End If
End Function


Is there a way to make this better, speed things up, and have a variable number of match/deletions?



Thanks in advance.










share|improve this question














In Excel VBA I need to perform multiple regular expression matches which then deletes the match from the string while preserving the remainder of the string. I have it working by daisy-chaining two variables, and by not testing the pattern match first since the second match is the remainder of the first.



Consider the follow data:



(2.5.3) A. 100% of product will be delivered in 3 days



(2.5.3) B. Capability to deliver product by air.



(2.5.3) C. Support for xyz feature



(2.5.3) D. Vendor is to provide an overview of the network as proposed.



(2.5.3) E. The network should allow CustomerABC to discover their devices.



(2.5.3) F. The use of CustomerABC existing infrastructure should be optimized. CustomerABC's capability will vary.



(2.5.3) G. Describe the number of network devices requiring to run CustomerABC's center.



With this data, I am deleting the outline numbers in the beginning of the string, as well as any references to CustomerABC and any hyphenation that could possibly appear multiple times in the string at any location, with potentially upper and lower case. I have the regex's working. Here is the code I'm trying:



Function test(Txt As String) As String
Dim regEx As Object
Dim v1 As String
Dim v2 As String
Dim n As String
n = "CustomerABC"

If regEx Is Nothing Then
Set regEx = CreateObject("VBScript.RegExp")
regEx.Global = True
regEx.IgnoreCase = True
End If
If Len(Txt) > 0 Then
With regEx
' The 1st pattern
.Pattern = "^(?[0-9.]+)?"
'If Not .Test(Txt) Then Exit Function
v1 = .Replace(Txt, "")
' The 2nd pattern
.Pattern = n + "(S*)?(s+)?"
'If Not .Test(Txt) Then Exit Function
v2 = .Replace(v1, "")
' The result
test = Application.Trim(v2)
End With
End If
End Function


Is there a way to make this better, speed things up, and have a variable number of match/deletions?



Thanks in advance.







excel vba excel-vba






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked Nov 14 '18 at 16:06









BobBob

193




193













  • You can pass in an array of patterns along with the string to be modified, or define an array within your function and then loop over it and perform the replacements.

    – Tim Williams
    Nov 14 '18 at 16:10











  • Hi Tim, I saw your post: stackoverflow.com/questions/9672436/…, but was unsure how to adapt it to my particular needs based on the fact that I am deleting and keeping remainders. May I have an example?

    – Bob
    Nov 14 '18 at 16:17



















  • You can pass in an array of patterns along with the string to be modified, or define an array within your function and then loop over it and perform the replacements.

    – Tim Williams
    Nov 14 '18 at 16:10











  • Hi Tim, I saw your post: stackoverflow.com/questions/9672436/…, but was unsure how to adapt it to my particular needs based on the fact that I am deleting and keeping remainders. May I have an example?

    – Bob
    Nov 14 '18 at 16:17

















You can pass in an array of patterns along with the string to be modified, or define an array within your function and then loop over it and perform the replacements.

– Tim Williams
Nov 14 '18 at 16:10





You can pass in an array of patterns along with the string to be modified, or define an array within your function and then loop over it and perform the replacements.

– Tim Williams
Nov 14 '18 at 16:10













Hi Tim, I saw your post: stackoverflow.com/questions/9672436/…, but was unsure how to adapt it to my particular needs based on the fact that I am deleting and keeping remainders. May I have an example?

– Bob
Nov 14 '18 at 16:17





Hi Tim, I saw your post: stackoverflow.com/questions/9672436/…, but was unsure how to adapt it to my particular needs based on the fact that I am deleting and keeping remainders. May I have an example?

– Bob
Nov 14 '18 at 16:17












1 Answer
1






active

oldest

votes


















1














Like this:



Function test(Txt As String) As String
Static regEx As Object '<< need Static here
Dim rv As String, p, n

n = "CustomerABC"

If regEx Is Nothing Then
Set regEx = CreateObject("VBScript.RegExp")
regEx.Global = True
regEx.IgnoreCase = True
End If
If Len(Txt) > 0 Then
rv = Txt
'looping over an array of patterns
For Each p In Array("^(?[0-9.]+)?", n & "(S*)?(s+)?")
With regEx
.Pattern = p
rv = .Replace(rv, "")
End With
Next p
End If
test = Application.Trim(rv)
End Function





share|improve this answer
























  • Boom! Thank you very kindly Tim.

    – Bob
    Nov 14 '18 at 17:44











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1 Answer
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1 Answer
1






active

oldest

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active

oldest

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active

oldest

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1














Like this:



Function test(Txt As String) As String
Static regEx As Object '<< need Static here
Dim rv As String, p, n

n = "CustomerABC"

If regEx Is Nothing Then
Set regEx = CreateObject("VBScript.RegExp")
regEx.Global = True
regEx.IgnoreCase = True
End If
If Len(Txt) > 0 Then
rv = Txt
'looping over an array of patterns
For Each p In Array("^(?[0-9.]+)?", n & "(S*)?(s+)?")
With regEx
.Pattern = p
rv = .Replace(rv, "")
End With
Next p
End If
test = Application.Trim(rv)
End Function





share|improve this answer
























  • Boom! Thank you very kindly Tim.

    – Bob
    Nov 14 '18 at 17:44
















1














Like this:



Function test(Txt As String) As String
Static regEx As Object '<< need Static here
Dim rv As String, p, n

n = "CustomerABC"

If regEx Is Nothing Then
Set regEx = CreateObject("VBScript.RegExp")
regEx.Global = True
regEx.IgnoreCase = True
End If
If Len(Txt) > 0 Then
rv = Txt
'looping over an array of patterns
For Each p In Array("^(?[0-9.]+)?", n & "(S*)?(s+)?")
With regEx
.Pattern = p
rv = .Replace(rv, "")
End With
Next p
End If
test = Application.Trim(rv)
End Function





share|improve this answer
























  • Boom! Thank you very kindly Tim.

    – Bob
    Nov 14 '18 at 17:44














1












1








1







Like this:



Function test(Txt As String) As String
Static regEx As Object '<< need Static here
Dim rv As String, p, n

n = "CustomerABC"

If regEx Is Nothing Then
Set regEx = CreateObject("VBScript.RegExp")
regEx.Global = True
regEx.IgnoreCase = True
End If
If Len(Txt) > 0 Then
rv = Txt
'looping over an array of patterns
For Each p In Array("^(?[0-9.]+)?", n & "(S*)?(s+)?")
With regEx
.Pattern = p
rv = .Replace(rv, "")
End With
Next p
End If
test = Application.Trim(rv)
End Function





share|improve this answer













Like this:



Function test(Txt As String) As String
Static regEx As Object '<< need Static here
Dim rv As String, p, n

n = "CustomerABC"

If regEx Is Nothing Then
Set regEx = CreateObject("VBScript.RegExp")
regEx.Global = True
regEx.IgnoreCase = True
End If
If Len(Txt) > 0 Then
rv = Txt
'looping over an array of patterns
For Each p In Array("^(?[0-9.]+)?", n & "(S*)?(s+)?")
With regEx
.Pattern = p
rv = .Replace(rv, "")
End With
Next p
End If
test = Application.Trim(rv)
End Function






share|improve this answer












share|improve this answer



share|improve this answer










answered Nov 14 '18 at 17:22









Tim WilliamsTim Williams

87k97086




87k97086













  • Boom! Thank you very kindly Tim.

    – Bob
    Nov 14 '18 at 17:44



















  • Boom! Thank you very kindly Tim.

    – Bob
    Nov 14 '18 at 17:44

















Boom! Thank you very kindly Tim.

– Bob
Nov 14 '18 at 17:44





Boom! Thank you very kindly Tim.

– Bob
Nov 14 '18 at 17:44




















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