Using string instead of kind of shape in createShape()
I want to pass an array of strings to a function in draw() and have the function draw each shape with the first parameter specifying which type of shape to draw. Here's my code (inside of draw()):
params = new String{"LINE","0","0","2","3"};
if (params.length == 2) {
createShape(params[0],float(params[1]));
} else if (params.length == 3) {
createShape(params[0],float(params[1]),float(params[2]));
} ...
} else if (params.length == 5) {
createShape(params[0],float(params[1]),float(params[2]),float(params[3]),float(params[4]));
} ...
The ellipsis marks denote more else if statements with different numbers of parameters. I know that passing values to createShape() in this way seems redundant, but it's the best way I could find to serve my purpose, and I would like to know how to make it work. Currently, this code gives me an error and says The function createShape() expects parameters like: "createShape(int,)".
Is there any way to get around this, or will I have to specify a case for every single kind of shape?
java processing
asked Nov 13 '18 at 1:36
user6003925
2314
add a comment |
I want to pass an array of strings to a function in draw() and have the function draw each shape with the first parameter specifying which type of shape to draw. Here's my code (inside of draw()):
params = new String{"LINE","0","0","2","3"};
if (params.length == 2) {
createShape(params[0],float(params[1]));
} else if (params.length == 3) {
createShape(params[0],float(params[1]),float(params[2]));
} ...
} else if (params.length == 5) {
createShape(params[0],float(params[1]),float(params[2]),float(params[3]),float(params[4]));
} ...
The ellipsis marks denote more else if statements with different numbers of parameters. I know that passing values to createShape() in this way seems redundant, but it's the best way I could find to serve my purpose, and I would like to know how to make it work. Currently, this code gives me an error and says The function createShape() expects parameters like: "createShape(int,)".
Is there any way to get around this, or will I have to specify a case for every single kind of shape?
java processing
asked Nov 13 '18 at 1:36
user6003925
2314
why not show us thecreateShapemethod?
– Scary Wombat
Nov 13 '18 at 1:39
ThecreateShape(kind,p)function draws akind(can be things like LINE, ELLIPSE, RECT) with parameterspwherepis some array of floats. I'm pretty sure it's specific to the processing library . Here's the documentation: processing.org/reference/createShape_.html
– user6003925
Nov 13 '18 at 1:44
Yes, as per the link you sent me Parameters kind int: either POINT, LINE, TRIANGLE, QUAD, RECT, ELLIPSE, ARC, BOX, SPHERE The first parameter e.g.LINEis actually an integer. It will be defined somewhere
– Scary Wombat
Nov 13 '18 at 1:54
add a comment |
I want to pass an array of strings to a function in draw() and have the function draw each shape with the first parameter specifying which type of shape to draw. Here's my code (inside of draw()):
params = new String{"LINE","0","0","2","3"};
if (params.length == 2) {
createShape(params[0],float(params[1]));
} else if (params.length == 3) {
createShape(params[0],float(params[1]),float(params[2]));
} ...
} else if (params.length == 5) {
createShape(params[0],float(params[1]),float(params[2]),float(params[3]),float(params[4]));
} ...
The ellipsis marks denote more else if statements with different numbers of parameters. I know that passing values to createShape() in this way seems redundant, but it's the best way I could find to serve my purpose, and I would like to know how to make it work. Currently, this code gives me an error and says The function createShape() expects parameters like: "createShape(int,)".
Is there any way to get around this, or will I have to specify a case for every single kind of shape?
java processing
asked Nov 13 '18 at 1:36
user6003925
2314
I want to pass an array of strings to a function in draw() and have the function draw each shape with the first parameter specifying which type of shape to draw. Here's my code (inside of draw()):
params = new String{"LINE","0","0","2","3"};
if (params.length == 2) {
createShape(params[0],float(params[1]));
} else if (params.length == 3) {
createShape(params[0],float(params[1]),float(params[2]));
} ...
} else if (params.length == 5) {
createShape(params[0],float(params[1]),float(params[2]),float(params[3]),float(params[4]));
} ...
The ellipsis marks denote more else if statements with different numbers of parameters. I know that passing values to createShape() in this way seems redundant, but it's the best way I could find to serve my purpose, and I would like to know how to make it work. Currently, this code gives me an error and says The function createShape() expects parameters like: "createShape(int,)".
Is there any way to get around this, or will I have to specify a case for every single kind of shape?
java processing
java processing
asked Nov 13 '18 at 1:36
user6003925
2314
asked Nov 13 '18 at 1:36
user6003925
2314
asked Nov 13 '18 at 1:36
user6003925
2314
asked Nov 13 '18 at 1:36
user6003925
2314
asked Nov 13 '18 at 1:36
user6003925
2314
2314
why not show us thecreateShapemethod?
– Scary Wombat
Nov 13 '18 at 1:39
ThecreateShape(kind,p)function draws akind(can be things like LINE, ELLIPSE, RECT) with parameterspwherepis some array of floats. I'm pretty sure it's specific to the processing library . Here's the documentation: processing.org/reference/createShape_.html
– user6003925
Nov 13 '18 at 1:44
Yes, as per the link you sent me Parameters kind int: either POINT, LINE, TRIANGLE, QUAD, RECT, ELLIPSE, ARC, BOX, SPHERE The first parameter e.g.LINEis actually an integer. It will be defined somewhere
– Scary Wombat
Nov 13 '18 at 1:54
add a comment |
why not show us thecreateShapemethod?
– Scary Wombat
Nov 13 '18 at 1:39
ThecreateShape(kind,p)function draws akind(can be things like LINE, ELLIPSE, RECT) with parameterspwherepis some array of floats. I'm pretty sure it's specific to the processing library . Here's the documentation: processing.org/reference/createShape_.html
– user6003925
Nov 13 '18 at 1:44
Yes, as per the link you sent me Parameters kind int: either POINT, LINE, TRIANGLE, QUAD, RECT, ELLIPSE, ARC, BOX, SPHERE The first parameter e.g.LINEis actually an integer. It will be defined somewhere
– Scary Wombat
Nov 13 '18 at 1:54
why not show us the
createShape method?– Scary Wombat
Nov 13 '18 at 1:39
why not show us the
createShape method?– Scary Wombat
Nov 13 '18 at 1:39
The
createShape(kind,p) function draws a kind (can be things like LINE, ELLIPSE, RECT) with parameters p where p is some array of floats. I'm pretty sure it's specific to the processing library . Here's the documentation: processing.org/reference/createShape_.html– user6003925
Nov 13 '18 at 1:44
The
createShape(kind,p) function draws a kind (can be things like LINE, ELLIPSE, RECT) with parameters p where p is some array of floats. I'm pretty sure it's specific to the processing library . Here's the documentation: processing.org/reference/createShape_.html– user6003925
Nov 13 '18 at 1:44
Yes, as per the link you sent me Parameters kind int: either POINT, LINE, TRIANGLE, QUAD, RECT, ELLIPSE, ARC, BOX, SPHERE The first parameter e.g.
LINE is actually an integer. It will be defined somewhere– Scary Wombat
Nov 13 '18 at 1:54
Yes, as per the link you sent me Parameters kind int: either POINT, LINE, TRIANGLE, QUAD, RECT, ELLIPSE, ARC, BOX, SPHERE The first parameter e.g.
LINE is actually an integer. It will be defined somewhere– Scary Wombat
Nov 13 '18 at 1:54
add a comment |
1 Answer
1
active
oldest
votes
You can't do this out of the box, but you could do something like this:
void createMyShape(String myArray){
if(myArray[0].equals("LINE")){
Shape s = createShape(LINE);
s.vertex(int(myArray[1]), int(myArray[2]));
s.vertex(int(myArray[3]), int(myArray[4]));
s.endShape();
}
else if ...
}
This function parses the myArray parameter and uses if statements to take the right actions to create a shape. It also uses the int() function to parse the string array.
Note that this is not a great design. You should probably not use a String array for this. It's probably better to use a class to encapsulate your data.
answered Nov 13 '18 at 1:50
Kevin Workman
33.4k53969
add a comment |
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1 Answer
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1 Answer
1
active
oldest
votes
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oldest
votes
active
oldest
votes
You can't do this out of the box, but you could do something like this:
void createMyShape(String myArray){
if(myArray[0].equals("LINE")){
Shape s = createShape(LINE);
s.vertex(int(myArray[1]), int(myArray[2]));
s.vertex(int(myArray[3]), int(myArray[4]));
s.endShape();
}
else if ...
}
This function parses the myArray parameter and uses if statements to take the right actions to create a shape. It also uses the int() function to parse the string array.
Note that this is not a great design. You should probably not use a String array for this. It's probably better to use a class to encapsulate your data.
answered Nov 13 '18 at 1:50
Kevin Workman
33.4k53969
add a comment |
You can't do this out of the box, but you could do something like this:
void createMyShape(String myArray){
if(myArray[0].equals("LINE")){
Shape s = createShape(LINE);
s.vertex(int(myArray[1]), int(myArray[2]));
s.vertex(int(myArray[3]), int(myArray[4]));
s.endShape();
}
else if ...
}
This function parses the myArray parameter and uses if statements to take the right actions to create a shape. It also uses the int() function to parse the string array.
Note that this is not a great design. You should probably not use a String array for this. It's probably better to use a class to encapsulate your data.
answered Nov 13 '18 at 1:50
Kevin Workman
33.4k53969
add a comment |
You can't do this out of the box, but you could do something like this:
void createMyShape(String myArray){
if(myArray[0].equals("LINE")){
Shape s = createShape(LINE);
s.vertex(int(myArray[1]), int(myArray[2]));
s.vertex(int(myArray[3]), int(myArray[4]));
s.endShape();
}
else if ...
}
This function parses the myArray parameter and uses if statements to take the right actions to create a shape. It also uses the int() function to parse the string array.
Note that this is not a great design. You should probably not use a String array for this. It's probably better to use a class to encapsulate your data.
answered Nov 13 '18 at 1:50
Kevin Workman
33.4k53969
You can't do this out of the box, but you could do something like this:
void createMyShape(String myArray){
if(myArray[0].equals("LINE")){
Shape s = createShape(LINE);
s.vertex(int(myArray[1]), int(myArray[2]));
s.vertex(int(myArray[3]), int(myArray[4]));
s.endShape();
}
else if ...
}
This function parses the myArray parameter and uses if statements to take the right actions to create a shape. It also uses the int() function to parse the string array.
Note that this is not a great design. You should probably not use a String array for this. It's probably better to use a class to encapsulate your data.
answered Nov 13 '18 at 1:50
Kevin Workman
33.4k53969
answered Nov 13 '18 at 1:50
Kevin Workman
33.4k53969
answered Nov 13 '18 at 1:50
Kevin Workman
33.4k53969
answered Nov 13 '18 at 1:50
Kevin Workman
33.4k53969
33.4k53969
add a comment |
add a comment |
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why not show us the
createShapemethod?– Scary Wombat
Nov 13 '18 at 1:39
The
createShape(kind,p)function draws akind(can be things like LINE, ELLIPSE, RECT) with parameterspwherepis some array of floats. I'm pretty sure it's specific to the processing library . Here's the documentation: processing.org/reference/createShape_.html– user6003925
Nov 13 '18 at 1:44
Yes, as per the link you sent me Parameters kind int: either POINT, LINE, TRIANGLE, QUAD, RECT, ELLIPSE, ARC, BOX, SPHERE The first parameter e.g.
LINEis actually an integer. It will be defined somewhere– Scary Wombat
Nov 13 '18 at 1:54