In PHP is there a built-in function to replace this foreach loop?
In order to integrate icons into the navbar I use key=>value arrays to store a file name with an icon tag. In the navbar I use a foreach loop to build dropdown menus or index into an array for an individual navlink. This also allows to dynamically build and alter the dropdown menus very easily.
$homepage = array(
'index.php'=>'<i class="fa fa-home"></i>'
);
$guestpages = array(
'createaccount.php'=>'<i class="fa fa-university"></i>',
'login.php'=>'<i class="fa fa-sign-in"></i>'
);
$logout = array(
'logout.php'=>'<i class="fa fa-sign-out"></i>'
);
$pages = array($homepage,$guestpages,$logout);
I also parse the URL to determine what page the client is viewing.
$pagename = basename($_SERVER['PHP_SELF']);
And in order to associate the parsed URL with the appropriate icon tag from the $pages array, I currently use a nested foreach loop:
foreach ($pages as $pagearray) {
foreach ($pagearray as $page => $icon) {
if($pagename == $page) {
$pageicon = $icon;
}
}
}
And what I'd like to do instead is something like this:
$pageicon = $pages[?][$pagename];
Does a similar alternative solution exist?
php arrays loops
asked Nov 13 '18 at 1:38
Derek Roberts
187
add a comment |
In order to integrate icons into the navbar I use key=>value arrays to store a file name with an icon tag. In the navbar I use a foreach loop to build dropdown menus or index into an array for an individual navlink. This also allows to dynamically build and alter the dropdown menus very easily.
$homepage = array(
'index.php'=>'<i class="fa fa-home"></i>'
);
$guestpages = array(
'createaccount.php'=>'<i class="fa fa-university"></i>',
'login.php'=>'<i class="fa fa-sign-in"></i>'
);
$logout = array(
'logout.php'=>'<i class="fa fa-sign-out"></i>'
);
$pages = array($homepage,$guestpages,$logout);
I also parse the URL to determine what page the client is viewing.
$pagename = basename($_SERVER['PHP_SELF']);
And in order to associate the parsed URL with the appropriate icon tag from the $pages array, I currently use a nested foreach loop:
foreach ($pages as $pagearray) {
foreach ($pagearray as $page => $icon) {
if($pagename == $page) {
$pageicon = $icon;
}
}
}
And what I'd like to do instead is something like this:
$pageicon = $pages[?][$pagename];
Does a similar alternative solution exist?
php arrays loops
asked Nov 13 '18 at 1:38
Derek Roberts
187
Why the three separate arrays? If you'd just have$pages = ['index.php' => ...], you could simply do$pages[basename($_SERVER['PHP_SELF'])]…
– deceze♦
Nov 13 '18 at 1:44
add a comment |
In order to integrate icons into the navbar I use key=>value arrays to store a file name with an icon tag. In the navbar I use a foreach loop to build dropdown menus or index into an array for an individual navlink. This also allows to dynamically build and alter the dropdown menus very easily.
$homepage = array(
'index.php'=>'<i class="fa fa-home"></i>'
);
$guestpages = array(
'createaccount.php'=>'<i class="fa fa-university"></i>',
'login.php'=>'<i class="fa fa-sign-in"></i>'
);
$logout = array(
'logout.php'=>'<i class="fa fa-sign-out"></i>'
);
$pages = array($homepage,$guestpages,$logout);
I also parse the URL to determine what page the client is viewing.
$pagename = basename($_SERVER['PHP_SELF']);
And in order to associate the parsed URL with the appropriate icon tag from the $pages array, I currently use a nested foreach loop:
foreach ($pages as $pagearray) {
foreach ($pagearray as $page => $icon) {
if($pagename == $page) {
$pageicon = $icon;
}
}
}
And what I'd like to do instead is something like this:
$pageicon = $pages[?][$pagename];
Does a similar alternative solution exist?
php arrays loops
asked Nov 13 '18 at 1:38
Derek Roberts
187
In order to integrate icons into the navbar I use key=>value arrays to store a file name with an icon tag. In the navbar I use a foreach loop to build dropdown menus or index into an array for an individual navlink. This also allows to dynamically build and alter the dropdown menus very easily.
$homepage = array(
'index.php'=>'<i class="fa fa-home"></i>'
);
$guestpages = array(
'createaccount.php'=>'<i class="fa fa-university"></i>',
'login.php'=>'<i class="fa fa-sign-in"></i>'
);
$logout = array(
'logout.php'=>'<i class="fa fa-sign-out"></i>'
);
$pages = array($homepage,$guestpages,$logout);
I also parse the URL to determine what page the client is viewing.
$pagename = basename($_SERVER['PHP_SELF']);
And in order to associate the parsed URL with the appropriate icon tag from the $pages array, I currently use a nested foreach loop:
foreach ($pages as $pagearray) {
foreach ($pagearray as $page => $icon) {
if($pagename == $page) {
$pageicon = $icon;
}
}
}
And what I'd like to do instead is something like this:
$pageicon = $pages[?][$pagename];
Does a similar alternative solution exist?
php arrays loops
php arrays loops
asked Nov 13 '18 at 1:38
Derek Roberts
187
asked Nov 13 '18 at 1:38
Derek Roberts
187
asked Nov 13 '18 at 1:38
Derek Roberts
187
asked Nov 13 '18 at 1:38
Derek Roberts
187
asked Nov 13 '18 at 1:38
Derek Roberts
187
187
Why the three separate arrays? If you'd just have$pages = ['index.php' => ...], you could simply do$pages[basename($_SERVER['PHP_SELF'])]…
– deceze♦
Nov 13 '18 at 1:44
add a comment |
Why the three separate arrays? If you'd just have$pages = ['index.php' => ...], you could simply do$pages[basename($_SERVER['PHP_SELF'])]…
– deceze♦
Nov 13 '18 at 1:44
Why the three separate arrays? If you'd just have
$pages = ['index.php' => ...], you could simply do $pages[basename($_SERVER['PHP_SELF'])]…– deceze♦
Nov 13 '18 at 1:44
Why the three separate arrays? If you'd just have
$pages = ['index.php' => ...], you could simply do $pages[basename($_SERVER['PHP_SELF'])]…– deceze♦
Nov 13 '18 at 1:44
add a comment |
1 Answer
1
active
oldest
votes
Since your pagename must be unique, you can build your array in a single dimension, like this:
$pages = [
'index.php'=>'<i class="fa fa-home"></i>',
'createaccount.php'=>'<i class="fa fa-university"></i>',
'login.php'=>'<i class="fa fa-sign-in"></i>',
'logout.php'=>'<i class="fa fa-sign-out"></i>',
];
Then just use:
$icon = $pages[basename($_SERVER['PHP_SELF'])] ?? '<some default>';
[Edit] Alternatively, you can use array_merge() to combine your arrays:
$pages = array_merge($homepage, $guestpages, $logout);
answered Nov 13 '18 at 1:44
Alex Howansky
35k55581
This would complicate the navbar construction though, because index.php and logout.php are individual links while createaccount.php and login.php are both in the same dropdown menu. So on the navbar I use a loop: foreach($guestpages as...) to build the dropdown menu containing the links to createaccount.php and login.php. I wouldn't be able to create individual dropdown menus from the $pages array, and don't want to maintain a seperate $pages array that is not nested.
– Derek Roberts
Nov 13 '18 at 1:49
Then just usearray_merge()to combine them.
– Alex Howansky
Nov 13 '18 at 1:50
add a comment |
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1 Answer
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active
oldest
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1 Answer
1
active
oldest
votes
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oldest
votes
active
oldest
votes
Since your pagename must be unique, you can build your array in a single dimension, like this:
$pages = [
'index.php'=>'<i class="fa fa-home"></i>',
'createaccount.php'=>'<i class="fa fa-university"></i>',
'login.php'=>'<i class="fa fa-sign-in"></i>',
'logout.php'=>'<i class="fa fa-sign-out"></i>',
];
Then just use:
$icon = $pages[basename($_SERVER['PHP_SELF'])] ?? '<some default>';
[Edit] Alternatively, you can use array_merge() to combine your arrays:
$pages = array_merge($homepage, $guestpages, $logout);
answered Nov 13 '18 at 1:44
Alex Howansky
35k55581
This would complicate the navbar construction though, because index.php and logout.php are individual links while createaccount.php and login.php are both in the same dropdown menu. So on the navbar I use a loop: foreach($guestpages as...) to build the dropdown menu containing the links to createaccount.php and login.php. I wouldn't be able to create individual dropdown menus from the $pages array, and don't want to maintain a seperate $pages array that is not nested.
– Derek Roberts
Nov 13 '18 at 1:49
Then just usearray_merge()to combine them.
– Alex Howansky
Nov 13 '18 at 1:50
add a comment |
Since your pagename must be unique, you can build your array in a single dimension, like this:
$pages = [
'index.php'=>'<i class="fa fa-home"></i>',
'createaccount.php'=>'<i class="fa fa-university"></i>',
'login.php'=>'<i class="fa fa-sign-in"></i>',
'logout.php'=>'<i class="fa fa-sign-out"></i>',
];
Then just use:
$icon = $pages[basename($_SERVER['PHP_SELF'])] ?? '<some default>';
[Edit] Alternatively, you can use array_merge() to combine your arrays:
$pages = array_merge($homepage, $guestpages, $logout);
answered Nov 13 '18 at 1:44
Alex Howansky
35k55581
This would complicate the navbar construction though, because index.php and logout.php are individual links while createaccount.php and login.php are both in the same dropdown menu. So on the navbar I use a loop: foreach($guestpages as...) to build the dropdown menu containing the links to createaccount.php and login.php. I wouldn't be able to create individual dropdown menus from the $pages array, and don't want to maintain a seperate $pages array that is not nested.
– Derek Roberts
Nov 13 '18 at 1:49
Then just usearray_merge()to combine them.
– Alex Howansky
Nov 13 '18 at 1:50
add a comment |
Since your pagename must be unique, you can build your array in a single dimension, like this:
$pages = [
'index.php'=>'<i class="fa fa-home"></i>',
'createaccount.php'=>'<i class="fa fa-university"></i>',
'login.php'=>'<i class="fa fa-sign-in"></i>',
'logout.php'=>'<i class="fa fa-sign-out"></i>',
];
Then just use:
$icon = $pages[basename($_SERVER['PHP_SELF'])] ?? '<some default>';
[Edit] Alternatively, you can use array_merge() to combine your arrays:
$pages = array_merge($homepage, $guestpages, $logout);
answered Nov 13 '18 at 1:44
Alex Howansky
35k55581
Since your pagename must be unique, you can build your array in a single dimension, like this:
$pages = [
'index.php'=>'<i class="fa fa-home"></i>',
'createaccount.php'=>'<i class="fa fa-university"></i>',
'login.php'=>'<i class="fa fa-sign-in"></i>',
'logout.php'=>'<i class="fa fa-sign-out"></i>',
];
Then just use:
$icon = $pages[basename($_SERVER['PHP_SELF'])] ?? '<some default>';
[Edit] Alternatively, you can use array_merge() to combine your arrays:
$pages = array_merge($homepage, $guestpages, $logout);
answered Nov 13 '18 at 1:44
Alex Howansky
35k55581
edited Nov 13 '18 at 1:52
answered Nov 13 '18 at 1:44
Alex Howansky
35k55581
answered Nov 13 '18 at 1:44
Alex Howansky
35k55581
answered Nov 13 '18 at 1:44
Alex Howansky
35k55581
35k55581
This would complicate the navbar construction though, because index.php and logout.php are individual links while createaccount.php and login.php are both in the same dropdown menu. So on the navbar I use a loop: foreach($guestpages as...) to build the dropdown menu containing the links to createaccount.php and login.php. I wouldn't be able to create individual dropdown menus from the $pages array, and don't want to maintain a seperate $pages array that is not nested.
– Derek Roberts
Nov 13 '18 at 1:49
Then just usearray_merge()to combine them.
– Alex Howansky
Nov 13 '18 at 1:50
add a comment |
This would complicate the navbar construction though, because index.php and logout.php are individual links while createaccount.php and login.php are both in the same dropdown menu. So on the navbar I use a loop: foreach($guestpages as...) to build the dropdown menu containing the links to createaccount.php and login.php. I wouldn't be able to create individual dropdown menus from the $pages array, and don't want to maintain a seperate $pages array that is not nested.
– Derek Roberts
Nov 13 '18 at 1:49
Then just usearray_merge()to combine them.
– Alex Howansky
Nov 13 '18 at 1:50
This would complicate the navbar construction though, because index.php and logout.php are individual links while createaccount.php and login.php are both in the same dropdown menu. So on the navbar I use a loop: foreach($guestpages as...) to build the dropdown menu containing the links to createaccount.php and login.php. I wouldn't be able to create individual dropdown menus from the $pages array, and don't want to maintain a seperate $pages array that is not nested.
– Derek Roberts
Nov 13 '18 at 1:49
This would complicate the navbar construction though, because index.php and logout.php are individual links while createaccount.php and login.php are both in the same dropdown menu. So on the navbar I use a loop: foreach($guestpages as...) to build the dropdown menu containing the links to createaccount.php and login.php. I wouldn't be able to create individual dropdown menus from the $pages array, and don't want to maintain a seperate $pages array that is not nested.
– Derek Roberts
Nov 13 '18 at 1:49
Then just use
array_merge() to combine them.– Alex Howansky
Nov 13 '18 at 1:50
Then just use
array_merge() to combine them.– Alex Howansky
Nov 13 '18 at 1:50
add a comment |
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Why the three separate arrays? If you'd just have
$pages = ['index.php' => ...], you could simply do$pages[basename($_SERVER['PHP_SELF'])]…– deceze♦
Nov 13 '18 at 1:44