Show and group all records with the same id with two fields that are not null
I have a table that shows all the products, the price_fact field, calculates the average when invoiced and updates the price_fact field when it makes an insert, and the price_alb field is the same but with a delivery note.
So when invoice (price_fact) has no delivery note (price_alb) and when it is delivery note has no invoice.
+---------------+------------+-------+-------------+-----------+
| name | id_product | price | price_fact| price_alb|
+---------------+------------+-------+-------------+-----------+
| phone | 1 | 300 | NULL | 275|
| mouse | 2 | 100 | 100 | NULL|
| phone | 1 | 250 | NULL | 275|
| mouse | 2 | 100 | NULL | 100|
| phone | 1 | 300 | 300 | NULL|
+---------------+------------+------+--------------+-----------+
And what I want is to calculate all the products in a single row, the number of products in total and the final result shows the column price_fact and price_alb of that product, of those who have had records that are not null.
+---------------+------------+-------+-------------+-----------+------+
| name | id_product | price | price_fact| price_alb| units|
+---------------+------------+-------+-------------+-----------+------+
| phone | 1 | 300 | 300 | 275| 3|
| mouse | 2 | 100 | 100 | 100| 2|
+---------------+------------+------+--------------+-----------+------+
Solved (I have put MAX(price_fact), MAX(price_alb) in select).
mysql select
edited Nov 13 '18 at 19:24
Brian Tompsett - 汤莱恩
4,1931337101
asked Nov 13 '18 at 14:12
SylarSylar
277
add a comment |
I have a table that shows all the products, the price_fact field, calculates the average when invoiced and updates the price_fact field when it makes an insert, and the price_alb field is the same but with a delivery note.
So when invoice (price_fact) has no delivery note (price_alb) and when it is delivery note has no invoice.
+---------------+------------+-------+-------------+-----------+
| name | id_product | price | price_fact| price_alb|
+---------------+------------+-------+-------------+-----------+
| phone | 1 | 300 | NULL | 275|
| mouse | 2 | 100 | 100 | NULL|
| phone | 1 | 250 | NULL | 275|
| mouse | 2 | 100 | NULL | 100|
| phone | 1 | 300 | 300 | NULL|
+---------------+------------+------+--------------+-----------+
And what I want is to calculate all the products in a single row, the number of products in total and the final result shows the column price_fact and price_alb of that product, of those who have had records that are not null.
+---------------+------------+-------+-------------+-----------+------+
| name | id_product | price | price_fact| price_alb| units|
+---------------+------------+-------+-------------+-----------+------+
| phone | 1 | 300 | 300 | 275| 3|
| mouse | 2 | 100 | 100 | 100| 2|
+---------------+------------+------+--------------+-----------+------+
Solved (I have put MAX(price_fact), MAX(price_alb) in select).
mysql select
edited Nov 13 '18 at 19:24
Brian Tompsett - 汤莱恩
4,1931337101
asked Nov 13 '18 at 14:12
SylarSylar
277
Why did mouseprice = 50in your expect result?
– D-Shih
Nov 13 '18 at 14:22
I have the solution now, only put MAX(price_alb), MAX(price_fact).
– Sylar
Nov 13 '18 at 14:27
But I am curious how can do you getprice = 50instead of 100
– D-Shih
Nov 13 '18 at 14:29
I sorry I have calculated wrong when I have written. It's 100.
– Sylar
Nov 13 '18 at 14:30
add a comment |
I have a table that shows all the products, the price_fact field, calculates the average when invoiced and updates the price_fact field when it makes an insert, and the price_alb field is the same but with a delivery note.
So when invoice (price_fact) has no delivery note (price_alb) and when it is delivery note has no invoice.
+---------------+------------+-------+-------------+-----------+
| name | id_product | price | price_fact| price_alb|
+---------------+------------+-------+-------------+-----------+
| phone | 1 | 300 | NULL | 275|
| mouse | 2 | 100 | 100 | NULL|
| phone | 1 | 250 | NULL | 275|
| mouse | 2 | 100 | NULL | 100|
| phone | 1 | 300 | 300 | NULL|
+---------------+------------+------+--------------+-----------+
And what I want is to calculate all the products in a single row, the number of products in total and the final result shows the column price_fact and price_alb of that product, of those who have had records that are not null.
+---------------+------------+-------+-------------+-----------+------+
| name | id_product | price | price_fact| price_alb| units|
+---------------+------------+-------+-------------+-----------+------+
| phone | 1 | 300 | 300 | 275| 3|
| mouse | 2 | 100 | 100 | 100| 2|
+---------------+------------+------+--------------+-----------+------+
Solved (I have put MAX(price_fact), MAX(price_alb) in select).
mysql select
edited Nov 13 '18 at 19:24
Brian Tompsett - 汤莱恩
4,1931337101
asked Nov 13 '18 at 14:12
SylarSylar
277
I have a table that shows all the products, the price_fact field, calculates the average when invoiced and updates the price_fact field when it makes an insert, and the price_alb field is the same but with a delivery note.
So when invoice (price_fact) has no delivery note (price_alb) and when it is delivery note has no invoice.
+---------------+------------+-------+-------------+-----------+
| name | id_product | price | price_fact| price_alb|
+---------------+------------+-------+-------------+-----------+
| phone | 1 | 300 | NULL | 275|
| mouse | 2 | 100 | 100 | NULL|
| phone | 1 | 250 | NULL | 275|
| mouse | 2 | 100 | NULL | 100|
| phone | 1 | 300 | 300 | NULL|
+---------------+------------+------+--------------+-----------+
And what I want is to calculate all the products in a single row, the number of products in total and the final result shows the column price_fact and price_alb of that product, of those who have had records that are not null.
+---------------+------------+-------+-------------+-----------+------+
| name | id_product | price | price_fact| price_alb| units|
+---------------+------------+-------+-------------+-----------+------+
| phone | 1 | 300 | 300 | 275| 3|
| mouse | 2 | 100 | 100 | 100| 2|
+---------------+------------+------+--------------+-----------+------+
Solved (I have put MAX(price_fact), MAX(price_alb) in select).
mysql select
mysql select
edited Nov 13 '18 at 19:24
Brian Tompsett - 汤莱恩
4,1931337101
asked Nov 13 '18 at 14:12
SylarSylar
277
edited Nov 13 '18 at 19:24
Brian Tompsett - 汤莱恩
4,1931337101
asked Nov 13 '18 at 14:12
SylarSylar
277
edited Nov 13 '18 at 19:24
Brian Tompsett - 汤莱恩
4,1931337101
edited Nov 13 '18 at 19:24
Brian Tompsett - 汤莱恩
4,1931337101
edited Nov 13 '18 at 19:24
Brian Tompsett - 汤莱恩
4,1931337101
4,1931337101
asked Nov 13 '18 at 14:12
SylarSylar
277
asked Nov 13 '18 at 14:12
SylarSylar
277
asked Nov 13 '18 at 14:12
SylarSylar
277
277
Why did mouseprice = 50in your expect result?
– D-Shih
Nov 13 '18 at 14:22
I have the solution now, only put MAX(price_alb), MAX(price_fact).
– Sylar
Nov 13 '18 at 14:27
But I am curious how can do you getprice = 50instead of 100
– D-Shih
Nov 13 '18 at 14:29
I sorry I have calculated wrong when I have written. It's 100.
– Sylar
Nov 13 '18 at 14:30
add a comment |
Why did mouseprice = 50in your expect result?
– D-Shih
Nov 13 '18 at 14:22
I have the solution now, only put MAX(price_alb), MAX(price_fact).
– Sylar
Nov 13 '18 at 14:27
But I am curious how can do you getprice = 50instead of 100
– D-Shih
Nov 13 '18 at 14:29
I sorry I have calculated wrong when I have written. It's 100.
– Sylar
Nov 13 '18 at 14:30
Why did mouse
price = 50 in your expect result?– D-Shih
Nov 13 '18 at 14:22
Why did mouse
price = 50 in your expect result?– D-Shih
Nov 13 '18 at 14:22
I have the solution now, only put MAX(price_alb), MAX(price_fact).
– Sylar
Nov 13 '18 at 14:27
I have the solution now, only put MAX(price_alb), MAX(price_fact).
– Sylar
Nov 13 '18 at 14:27
But I am curious how can do you get
price = 50 instead of 100– D-Shih
Nov 13 '18 at 14:29
But I am curious how can do you get
price = 50 instead of 100– D-Shih
Nov 13 '18 at 14:29
I sorry I have calculated wrong when I have written. It's 100.
– Sylar
Nov 13 '18 at 14:30
I sorry I have calculated wrong when I have written. It's 100.
– Sylar
Nov 13 '18 at 14:30
add a comment |
1 Answer
1
active
oldest
votes
You can try to use aggregate function.
SELECT name,
id_product,
MAX(price) price,
MAX(price_fact) price_fact,
MAX(price_alb) price_alb,
COUNT(*) units
FROM T
GROUP BY name,id_product
answered Nov 13 '18 at 14:24
D-ShihD-Shih
25.6k61531
add a comment |
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1 Answer
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oldest
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1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
You can try to use aggregate function.
SELECT name,
id_product,
MAX(price) price,
MAX(price_fact) price_fact,
MAX(price_alb) price_alb,
COUNT(*) units
FROM T
GROUP BY name,id_product
answered Nov 13 '18 at 14:24
D-ShihD-Shih
25.6k61531
add a comment |
You can try to use aggregate function.
SELECT name,
id_product,
MAX(price) price,
MAX(price_fact) price_fact,
MAX(price_alb) price_alb,
COUNT(*) units
FROM T
GROUP BY name,id_product
answered Nov 13 '18 at 14:24
D-ShihD-Shih
25.6k61531
add a comment |
You can try to use aggregate function.
SELECT name,
id_product,
MAX(price) price,
MAX(price_fact) price_fact,
MAX(price_alb) price_alb,
COUNT(*) units
FROM T
GROUP BY name,id_product
answered Nov 13 '18 at 14:24
D-ShihD-Shih
25.6k61531
You can try to use aggregate function.
SELECT name,
id_product,
MAX(price) price,
MAX(price_fact) price_fact,
MAX(price_alb) price_alb,
COUNT(*) units
FROM T
GROUP BY name,id_product
answered Nov 13 '18 at 14:24
D-ShihD-Shih
25.6k61531
answered Nov 13 '18 at 14:24
D-ShihD-Shih
25.6k61531
answered Nov 13 '18 at 14:24
D-ShihD-Shih
25.6k61531
answered Nov 13 '18 at 14:24
D-ShihD-Shih
25.6k61531
25.6k61531
add a comment |
add a comment |
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Why did mouse
price = 50in your expect result?– D-Shih
Nov 13 '18 at 14:22
I have the solution now, only put MAX(price_alb), MAX(price_fact).
– Sylar
Nov 13 '18 at 14:27
But I am curious how can do you get
price = 50instead of 100– D-Shih
Nov 13 '18 at 14:29
I sorry I have calculated wrong when I have written. It's 100.
– Sylar
Nov 13 '18 at 14:30