Checking a regex against a string
I have a below regex expression,
/A(d{5}[A-Z]{2}[a-zA-Z0-9]{3,7}-TMP|d{5}[A-Z]{2}d{3,7}(-?d{2})*)z/
I am checking against below strings. The first and third should return a match I guess and second a no match. But I am not getting a match on all 3. Is my regex wrong?
99844RI1800001
99806CAAUSJ-TMP1
99844RI1800002
python regex
asked Nov 13 '18 at 14:23
themasterthemaster
13714
add a comment |
I have a below regex expression,
/A(d{5}[A-Z]{2}[a-zA-Z0-9]{3,7}-TMP|d{5}[A-Z]{2}d{3,7}(-?d{2})*)z/
I am checking against below strings. The first and third should return a match I guess and second a no match. But I am not getting a match on all 3. Is my regex wrong?
99844RI1800001
99806CAAUSJ-TMP1
99844RI1800002
python regex
asked Nov 13 '18 at 14:23
themasterthemaster
13714
Pythonredoes not supportz, it supportsZas equivalent pattern
– Wiktor Stribiżew
Nov 13 '18 at 14:24
1
if not <string>.endswith('-TMP1'):?
– Austin
Nov 13 '18 at 14:25
add a comment |
I have a below regex expression,
/A(d{5}[A-Z]{2}[a-zA-Z0-9]{3,7}-TMP|d{5}[A-Z]{2}d{3,7}(-?d{2})*)z/
I am checking against below strings. The first and third should return a match I guess and second a no match. But I am not getting a match on all 3. Is my regex wrong?
99844RI1800001
99806CAAUSJ-TMP1
99844RI1800002
python regex
asked Nov 13 '18 at 14:23
themasterthemaster
13714
I have a below regex expression,
/A(d{5}[A-Z]{2}[a-zA-Z0-9]{3,7}-TMP|d{5}[A-Z]{2}d{3,7}(-?d{2})*)z/
I am checking against below strings. The first and third should return a match I guess and second a no match. But I am not getting a match on all 3. Is my regex wrong?
99844RI1800001
99806CAAUSJ-TMP1
99844RI1800002
python regex
python regex
asked Nov 13 '18 at 14:23
themasterthemaster
13714
asked Nov 13 '18 at 14:23
themasterthemaster
13714
asked Nov 13 '18 at 14:23
themasterthemaster
13714
asked Nov 13 '18 at 14:23
themasterthemaster
13714
asked Nov 13 '18 at 14:23
themasterthemaster
13714
13714
Pythonredoes not supportz, it supportsZas equivalent pattern
– Wiktor Stribiżew
Nov 13 '18 at 14:24
1
if not <string>.endswith('-TMP1'):?
– Austin
Nov 13 '18 at 14:25
add a comment |
Pythonredoes not supportz, it supportsZas equivalent pattern
– Wiktor Stribiżew
Nov 13 '18 at 14:24
1
if not <string>.endswith('-TMP1'):?
– Austin
Nov 13 '18 at 14:25
Python
re does not support z, it supports Z as equivalent pattern– Wiktor Stribiżew
Nov 13 '18 at 14:24
Python
re does not support z, it supports Z as equivalent pattern– Wiktor Stribiżew
Nov 13 '18 at 14:24
1
1
if not <string>.endswith('-TMP1'): ?– Austin
Nov 13 '18 at 14:25
if not <string>.endswith('-TMP1'): ?– Austin
Nov 13 '18 at 14:25
add a comment |
1 Answer
1
active
oldest
votes
Python re does not support z, it supports Z as equivalent pattern matching the very end of the string. Your pattern requires the literal z char to be there at the end of the pattern.
See Rexegg.com reference:
✽ In Python, the token
Zdoes whatzdoes in other engines: it only matches at the very end of the string.
Thus you may use
A(d{5}[A-Z]{2}[a-zA-Z0-9]{3,7}-TMP|d{5}[A-Z]{2}d{3,7}(-?d{2})*)Z
See the regex demo
Note that starting with Python 3.6 you would even get an exception:
re.error: bad escape z at position 68
See Python re docs:
Changed in version 3.6: Unknown escapes consisting of
''and an ASCII letter now are errors.
answered Nov 13 '18 at 14:25
Wiktor StribiżewWiktor Stribiżew
311k16131207
1
Thanks.. was stuck in this for so long :)
– themaster
Nov 13 '18 at 14:30
add a comment |
Your Answer
StackExchange.ifUsing("editor", function () {
StackExchange.using("externalEditor", function () {
StackExchange.using("snippets", function () {
StackExchange.snippets.init();
});
});
}, "code-snippets");
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "1"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53283160%2fchecking-a-regex-against-a-string%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
Python re does not support z, it supports Z as equivalent pattern matching the very end of the string. Your pattern requires the literal z char to be there at the end of the pattern.
See Rexegg.com reference:
✽ In Python, the token
Zdoes whatzdoes in other engines: it only matches at the very end of the string.
Thus you may use
A(d{5}[A-Z]{2}[a-zA-Z0-9]{3,7}-TMP|d{5}[A-Z]{2}d{3,7}(-?d{2})*)Z
See the regex demo
Note that starting with Python 3.6 you would even get an exception:
re.error: bad escape z at position 68
See Python re docs:
Changed in version 3.6: Unknown escapes consisting of
''and an ASCII letter now are errors.
answered Nov 13 '18 at 14:25
Wiktor StribiżewWiktor Stribiżew
311k16131207
1
Thanks.. was stuck in this for so long :)
– themaster
Nov 13 '18 at 14:30
add a comment |
Python re does not support z, it supports Z as equivalent pattern matching the very end of the string. Your pattern requires the literal z char to be there at the end of the pattern.
See Rexegg.com reference:
✽ In Python, the token
Zdoes whatzdoes in other engines: it only matches at the very end of the string.
Thus you may use
A(d{5}[A-Z]{2}[a-zA-Z0-9]{3,7}-TMP|d{5}[A-Z]{2}d{3,7}(-?d{2})*)Z
See the regex demo
Note that starting with Python 3.6 you would even get an exception:
re.error: bad escape z at position 68
See Python re docs:
Changed in version 3.6: Unknown escapes consisting of
''and an ASCII letter now are errors.
answered Nov 13 '18 at 14:25
Wiktor StribiżewWiktor Stribiżew
311k16131207
1
Thanks.. was stuck in this for so long :)
– themaster
Nov 13 '18 at 14:30
add a comment |
Python re does not support z, it supports Z as equivalent pattern matching the very end of the string. Your pattern requires the literal z char to be there at the end of the pattern.
See Rexegg.com reference:
✽ In Python, the token
Zdoes whatzdoes in other engines: it only matches at the very end of the string.
Thus you may use
A(d{5}[A-Z]{2}[a-zA-Z0-9]{3,7}-TMP|d{5}[A-Z]{2}d{3,7}(-?d{2})*)Z
See the regex demo
Note that starting with Python 3.6 you would even get an exception:
re.error: bad escape z at position 68
See Python re docs:
Changed in version 3.6: Unknown escapes consisting of
''and an ASCII letter now are errors.
answered Nov 13 '18 at 14:25
Wiktor StribiżewWiktor Stribiżew
311k16131207
Python re does not support z, it supports Z as equivalent pattern matching the very end of the string. Your pattern requires the literal z char to be there at the end of the pattern.
See Rexegg.com reference:
✽ In Python, the token
Zdoes whatzdoes in other engines: it only matches at the very end of the string.
Thus you may use
A(d{5}[A-Z]{2}[a-zA-Z0-9]{3,7}-TMP|d{5}[A-Z]{2}d{3,7}(-?d{2})*)Z
See the regex demo
Note that starting with Python 3.6 you would even get an exception:
re.error: bad escape z at position 68
See Python re docs:
Changed in version 3.6: Unknown escapes consisting of
''and an ASCII letter now are errors.
answered Nov 13 '18 at 14:25
Wiktor StribiżewWiktor Stribiżew
311k16131207
edited Nov 13 '18 at 14:31
answered Nov 13 '18 at 14:25
Wiktor StribiżewWiktor Stribiżew
311k16131207
answered Nov 13 '18 at 14:25
Wiktor StribiżewWiktor Stribiżew
311k16131207
answered Nov 13 '18 at 14:25
Wiktor StribiżewWiktor Stribiżew
311k16131207
311k16131207
1
Thanks.. was stuck in this for so long :)
– themaster
Nov 13 '18 at 14:30
add a comment |
1
Thanks.. was stuck in this for so long :)
– themaster
Nov 13 '18 at 14:30
1
1
Thanks.. was stuck in this for so long :)
– themaster
Nov 13 '18 at 14:30
Thanks.. was stuck in this for so long :)
– themaster
Nov 13 '18 at 14:30
add a comment |
Thanks for contributing an answer to Stack Overflow!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53283160%2fchecking-a-regex-against-a-string%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Python
redoes not supportz, it supportsZas equivalent pattern– Wiktor Stribiżew
Nov 13 '18 at 14:24
1
if not <string>.endswith('-TMP1'):?– Austin
Nov 13 '18 at 14:25