Reuse Fragment with flexible listeners
I have a Fragment which contains a Button. I want to reuse this Fragment, so the OnClickListener isn't hard coded but defined by the activity which calls this Fragment. The Activity implements the needed interface for this and the Fragment gets a reference in its oncreate method.
I have two questions on this below
public void TestFragment extends Fragment {
...
private IAction mAction = null;
@Override
public void OnAttach(Context ctx) {
mAction = (Action) getActivity();
}
@Override
public void onClickListener() {
action(this);
}
public interface IAction {
void action(Fragment f);
}
...
}
public class MainActivity extends AppCompatActivity implements IAction {
...
public void onCreate() {
getSupportFragmentManager().beginTransaction()
.add(R.id.content, Testfragment.gestInstance()
.commit();
}
public void IAction(Fragment f) {
f.doSomething()...
}
...
}
Is this a good practice to build reusable fragments?
I would to extend this: If this fragment is opened by an activity it uses the action defined in the activity. Ok, this works. It's the current behaviour.
But maybe this fragment is opened by another fragment (nested), so getActivity is wrong. Is there something like
if(parent.isActivity) {
mAction = (Action) getActivity()
} else if(parent.isFragment) {
mAction = (Action) getParentFragment()
}
android 
android-fragments asked Nov 13 '18 at 10:32
HomerHomer
312
add a comment |
I have a Fragment which contains a Button. I want to reuse this Fragment, so the OnClickListener isn't hard coded but defined by the activity which calls this Fragment. The Activity implements the needed interface for this and the Fragment gets a reference in its oncreate method.
I have two questions on this below
public void TestFragment extends Fragment {
...
private IAction mAction = null;
@Override
public void OnAttach(Context ctx) {
mAction = (Action) getActivity();
}
@Override
public void onClickListener() {
action(this);
}
public interface IAction {
void action(Fragment f);
}
...
}
public class MainActivity extends AppCompatActivity implements IAction {
...
public void onCreate() {
getSupportFragmentManager().beginTransaction()
.add(R.id.content, Testfragment.gestInstance()
.commit();
}
public void IAction(Fragment f) {
f.doSomething()...
}
...
}
Is this a good practice to build reusable fragments?
I would to extend this: If this fragment is opened by an activity it uses the action defined in the activity. Ok, this works. It's the current behaviour.
But maybe this fragment is opened by another fragment (nested), so getActivity is wrong. Is there something like
if(parent.isActivity) {
mAction = (Action) getActivity()
} else if(parent.isFragment) {
mAction = (Action) getParentFragment()
}
asked Nov 13 '18 at 10:32
HomerHomer
312
add a comment |
I have a Fragment which contains a Button. I want to reuse this Fragment, so the OnClickListener isn't hard coded but defined by the activity which calls this Fragment. The Activity implements the needed interface for this and the Fragment gets a reference in its oncreate method.
I have two questions on this below
public void TestFragment extends Fragment {
...
private IAction mAction = null;
@Override
public void OnAttach(Context ctx) {
mAction = (Action) getActivity();
}
@Override
public void onClickListener() {
action(this);
}
public interface IAction {
void action(Fragment f);
}
...
}
public class MainActivity extends AppCompatActivity implements IAction {
...
public void onCreate() {
getSupportFragmentManager().beginTransaction()
.add(R.id.content, Testfragment.gestInstance()
.commit();
}
public void IAction(Fragment f) {
f.doSomething()...
}
...
}
Is this a good practice to build reusable fragments?
I would to extend this: If this fragment is opened by an activity it uses the action defined in the activity. Ok, this works. It's the current behaviour.
But maybe this fragment is opened by another fragment (nested), so getActivity is wrong. Is there something like
if(parent.isActivity) {
mAction = (Action) getActivity()
} else if(parent.isFragment) {
mAction = (Action) getParentFragment()
}
asked Nov 13 '18 at 10:32
HomerHomer
312
I have a Fragment which contains a Button. I want to reuse this Fragment, so the OnClickListener isn't hard coded but defined by the activity which calls this Fragment. The Activity implements the needed interface for this and the Fragment gets a reference in its oncreate method.
I have two questions on this below
public void TestFragment extends Fragment {
...
private IAction mAction = null;
@Override
public void OnAttach(Context ctx) {
mAction = (Action) getActivity();
}
@Override
public void onClickListener() {
action(this);
}
public interface IAction {
void action(Fragment f);
}
...
}
public class MainActivity extends AppCompatActivity implements IAction {
...
public void onCreate() {
getSupportFragmentManager().beginTransaction()
.add(R.id.content, Testfragment.gestInstance()
.commit();
}
public void IAction(Fragment f) {
f.doSomething()...
}
...
}
Is this a good practice to build reusable fragments?
I would to extend this: If this fragment is opened by an activity it uses the action defined in the activity. Ok, this works. It's the current behaviour.
But maybe this fragment is opened by another fragment (nested), so getActivity is wrong. Is there something like
if(parent.isActivity) {
mAction = (Action) getActivity()
} else if(parent.isFragment) {
mAction = (Action) getParentFragment()
}
asked Nov 13 '18 at 10:32
HomerHomer
312
asked Nov 13 '18 at 10:32
HomerHomer
312
asked Nov 13 '18 at 10:32
HomerHomer
312
asked Nov 13 '18 at 10:32
HomerHomer
312
asked Nov 13 '18 at 10:32
HomerHomer
312
312
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
getActivity() will still work even if the fragment is nested within another one.
But if you want to deligate it on the parent fragment, you can use getParentFragment()
if (getParentFragment() != null) {
// fragment is nested
} else {
// not nested
}
answered Nov 13 '18 at 10:44
Samuel RobertSamuel Robert
3,32052034
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
getActivity() will still work even if the fragment is nested within another one.
But if you want to deligate it on the parent fragment, you can use getParentFragment()
if (getParentFragment() != null) {
// fragment is nested
} else {
// not nested
}
answered Nov 13 '18 at 10:44
Samuel RobertSamuel Robert
3,32052034
add a comment |
getActivity() will still work even if the fragment is nested within another one.
But if you want to deligate it on the parent fragment, you can use getParentFragment()
if (getParentFragment() != null) {
// fragment is nested
} else {
// not nested
}
answered Nov 13 '18 at 10:44
Samuel RobertSamuel Robert
3,32052034
add a comment |
getActivity() will still work even if the fragment is nested within another one.
But if you want to deligate it on the parent fragment, you can use getParentFragment()
if (getParentFragment() != null) {
// fragment is nested
} else {
// not nested
}
answered Nov 13 '18 at 10:44
Samuel RobertSamuel Robert
3,32052034
getActivity() will still work even if the fragment is nested within another one.
But if you want to deligate it on the parent fragment, you can use getParentFragment()
if (getParentFragment() != null) {
// fragment is nested
} else {
// not nested
}
answered Nov 13 '18 at 10:44
Samuel RobertSamuel Robert
3,32052034
edited Nov 13 '18 at 10:58
answered Nov 13 '18 at 10:44
Samuel RobertSamuel Robert
3,32052034
answered Nov 13 '18 at 10:44
Samuel RobertSamuel Robert
3,32052034
answered Nov 13 '18 at 10:44
Samuel RobertSamuel Robert
3,32052034
3,32052034
add a comment |
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