Java sort List of objects with a hierarchy alphabetically












0














I have an entity called Item. Item can have parents and children.



Each Item has the following methods:





  • getParent() --> returns an Item


  • getChildren() --> returns a List<Item>


  • isLeaf() --> returns a Boolean


  • getName() --> returns a String


Each level in the hierarchy is a level in a construction site, for example level 1 is House 1, level 2 is Floor 1, level 3 is Room and level 4 is Window.



I have a List<Item and I need to sort them like this:




  • Item 1 (House 1 > Floor 1 > Room 1 > Bath)

  • Item 2 (House 1 > Floor 1 > Room 2 > Basement)

  • Item 3 (House 1 > Floor 1 > Room 2 > Door)

  • Item 4 (House 1 > Floor 1 > Room 2 > Window)

  • Item 5 (House 1 > Floor 2 > Room 1 > Door)


I think I need some kind of recursive function but I can't imagine how it has to be.



I've already researched for sorting objects with a hierarchy in Java but I don't find anything similar to my case.



I would appreciate any help and sorry if the question is not clear 100% but it is quite hard to describe.



Thanks.






java sorting recursion hierarchy comparator







share|improve this question
























  • Basically you want to sort the leaves then? I would imagine that you would sort when adding the elements to the house object and then do a depth first lookup of the leaves
    – SBylemans
    Nov 13 '18 at 11:00












  • What is an entity? You can't create a new class called Object. There is already an important class in Java called Object ;)
    – flakes
    Nov 13 '18 at 11:45










  • @flakes thanks for your comment but I don't think that's important and it doesn't add anything to the question. The real name of the "Object" is Objekt (Object in German). I omitted that detail to avoid confusing people with irrelevant information. If you feel happier I can rename Object to Item
    – Ale
    Nov 13 '18 at 11:55










  • You need to provide some code. It is unclear to me what is your implementation. Are all entities of type item (houses, floors, rooms) or are those different classes? Do they implement/extend item class?
    – Amongalen
    Nov 13 '18 at 12:03










  • When discussing class design/method implementation, having a class name is pretty crucial for communication! Further, you should be providing some code in your questions to show us at what point your stuck. Define as much of the solution as you can and you'll find that people understand your problem better and provide answers closer to what you expect. As an aside, names like Objekt and Item are pretty opaque names for a class.. try something more meaningful (makes it obvious as to the actual purpose, HouseNode, FloorplanTree, etc). Good naming is paramount to clean maintainable code
    – flakes
    Nov 13 '18 at 12:53
















0














I have an entity called Item. Item can have parents and children.



Each Item has the following methods:





  • getParent() --> returns an Item


  • getChildren() --> returns a List<Item>


  • isLeaf() --> returns a Boolean


  • getName() --> returns a String


Each level in the hierarchy is a level in a construction site, for example level 1 is House 1, level 2 is Floor 1, level 3 is Room and level 4 is Window.



I have a List<Item and I need to sort them like this:




  • Item 1 (House 1 > Floor 1 > Room 1 > Bath)

  • Item 2 (House 1 > Floor 1 > Room 2 > Basement)

  • Item 3 (House 1 > Floor 1 > Room 2 > Door)

  • Item 4 (House 1 > Floor 1 > Room 2 > Window)

  • Item 5 (House 1 > Floor 2 > Room 1 > Door)


I think I need some kind of recursive function but I can't imagine how it has to be.



I've already researched for sorting objects with a hierarchy in Java but I don't find anything similar to my case.



I would appreciate any help and sorry if the question is not clear 100% but it is quite hard to describe.



Thanks.






java sorting recursion hierarchy comparator







share|improve this question
























  • Basically you want to sort the leaves then? I would imagine that you would sort when adding the elements to the house object and then do a depth first lookup of the leaves
    – SBylemans
    Nov 13 '18 at 11:00












  • What is an entity? You can't create a new class called Object. There is already an important class in Java called Object ;)
    – flakes
    Nov 13 '18 at 11:45










  • @flakes thanks for your comment but I don't think that's important and it doesn't add anything to the question. The real name of the "Object" is Objekt (Object in German). I omitted that detail to avoid confusing people with irrelevant information. If you feel happier I can rename Object to Item
    – Ale
    Nov 13 '18 at 11:55










  • You need to provide some code. It is unclear to me what is your implementation. Are all entities of type item (houses, floors, rooms) or are those different classes? Do they implement/extend item class?
    – Amongalen
    Nov 13 '18 at 12:03










  • When discussing class design/method implementation, having a class name is pretty crucial for communication! Further, you should be providing some code in your questions to show us at what point your stuck. Define as much of the solution as you can and you'll find that people understand your problem better and provide answers closer to what you expect. As an aside, names like Objekt and Item are pretty opaque names for a class.. try something more meaningful (makes it obvious as to the actual purpose, HouseNode, FloorplanTree, etc). Good naming is paramount to clean maintainable code
    – flakes
    Nov 13 '18 at 12:53














0












0








0







I have an entity called Item. Item can have parents and children.



Each Item has the following methods:





  • getParent() --> returns an Item


  • getChildren() --> returns a List<Item>


  • isLeaf() --> returns a Boolean


  • getName() --> returns a String


Each level in the hierarchy is a level in a construction site, for example level 1 is House 1, level 2 is Floor 1, level 3 is Room and level 4 is Window.



I have a List<Item and I need to sort them like this:




  • Item 1 (House 1 > Floor 1 > Room 1 > Bath)

  • Item 2 (House 1 > Floor 1 > Room 2 > Basement)

  • Item 3 (House 1 > Floor 1 > Room 2 > Door)

  • Item 4 (House 1 > Floor 1 > Room 2 > Window)

  • Item 5 (House 1 > Floor 2 > Room 1 > Door)


I think I need some kind of recursive function but I can't imagine how it has to be.



I've already researched for sorting objects with a hierarchy in Java but I don't find anything similar to my case.



I would appreciate any help and sorry if the question is not clear 100% but it is quite hard to describe.



Thanks.






java sorting recursion hierarchy comparator







share|improve this question















I have an entity called Item. Item can have parents and children.



Each Item has the following methods:





  • getParent() --> returns an Item


  • getChildren() --> returns a List<Item>


  • isLeaf() --> returns a Boolean


  • getName() --> returns a String


Each level in the hierarchy is a level in a construction site, for example level 1 is House 1, level 2 is Floor 1, level 3 is Room and level 4 is Window.



I have a List<Item and I need to sort them like this:




  • Item 1 (House 1 > Floor 1 > Room 1 > Bath)

  • Item 2 (House 1 > Floor 1 > Room 2 > Basement)

  • Item 3 (House 1 > Floor 1 > Room 2 > Door)

  • Item 4 (House 1 > Floor 1 > Room 2 > Window)

  • Item 5 (House 1 > Floor 2 > Room 1 > Door)


I think I need some kind of recursive function but I can't imagine how it has to be.



I've already researched for sorting objects with a hierarchy in Java but I don't find anything similar to my case.



I would appreciate any help and sorry if the question is not clear 100% but it is quite hard to describe.



Thanks.






java sorting recursion hierarchy comparator




java sorting recursion hierarchy comparator






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 13 '18 at 13:46









rghome

4,69152540




4,69152540










asked Nov 13 '18 at 10:44









AleAle

82322144




82322144












  • Basically you want to sort the leaves then? I would imagine that you would sort when adding the elements to the house object and then do a depth first lookup of the leaves
    – SBylemans
    Nov 13 '18 at 11:00












  • What is an entity? You can't create a new class called Object. There is already an important class in Java called Object ;)
    – flakes
    Nov 13 '18 at 11:45










  • @flakes thanks for your comment but I don't think that's important and it doesn't add anything to the question. The real name of the "Object" is Objekt (Object in German). I omitted that detail to avoid confusing people with irrelevant information. If you feel happier I can rename Object to Item
    – Ale
    Nov 13 '18 at 11:55










  • You need to provide some code. It is unclear to me what is your implementation. Are all entities of type item (houses, floors, rooms) or are those different classes? Do they implement/extend item class?
    – Amongalen
    Nov 13 '18 at 12:03










  • When discussing class design/method implementation, having a class name is pretty crucial for communication! Further, you should be providing some code in your questions to show us at what point your stuck. Define as much of the solution as you can and you'll find that people understand your problem better and provide answers closer to what you expect. As an aside, names like Objekt and Item are pretty opaque names for a class.. try something more meaningful (makes it obvious as to the actual purpose, HouseNode, FloorplanTree, etc). Good naming is paramount to clean maintainable code
    – flakes
    Nov 13 '18 at 12:53


















  • Basically you want to sort the leaves then? I would imagine that you would sort when adding the elements to the house object and then do a depth first lookup of the leaves
    – SBylemans
    Nov 13 '18 at 11:00












  • What is an entity? You can't create a new class called Object. There is already an important class in Java called Object ;)
    – flakes
    Nov 13 '18 at 11:45










  • @flakes thanks for your comment but I don't think that's important and it doesn't add anything to the question. The real name of the "Object" is Objekt (Object in German). I omitted that detail to avoid confusing people with irrelevant information. If you feel happier I can rename Object to Item
    – Ale
    Nov 13 '18 at 11:55










  • You need to provide some code. It is unclear to me what is your implementation. Are all entities of type item (houses, floors, rooms) or are those different classes? Do they implement/extend item class?
    – Amongalen
    Nov 13 '18 at 12:03










  • When discussing class design/method implementation, having a class name is pretty crucial for communication! Further, you should be providing some code in your questions to show us at what point your stuck. Define as much of the solution as you can and you'll find that people understand your problem better and provide answers closer to what you expect. As an aside, names like Objekt and Item are pretty opaque names for a class.. try something more meaningful (makes it obvious as to the actual purpose, HouseNode, FloorplanTree, etc). Good naming is paramount to clean maintainable code
    – flakes
    Nov 13 '18 at 12:53
















Basically you want to sort the leaves then? I would imagine that you would sort when adding the elements to the house object and then do a depth first lookup of the leaves
– SBylemans
Nov 13 '18 at 11:00






Basically you want to sort the leaves then? I would imagine that you would sort when adding the elements to the house object and then do a depth first lookup of the leaves
– SBylemans
Nov 13 '18 at 11:00














What is an entity? You can't create a new class called Object. There is already an important class in Java called Object ;)
– flakes
Nov 13 '18 at 11:45




What is an entity? You can't create a new class called Object. There is already an important class in Java called Object ;)
– flakes
Nov 13 '18 at 11:45












@flakes thanks for your comment but I don't think that's important and it doesn't add anything to the question. The real name of the "Object" is Objekt (Object in German). I omitted that detail to avoid confusing people with irrelevant information. If you feel happier I can rename Object to Item
– Ale
Nov 13 '18 at 11:55




@flakes thanks for your comment but I don't think that's important and it doesn't add anything to the question. The real name of the "Object" is Objekt (Object in German). I omitted that detail to avoid confusing people with irrelevant information. If you feel happier I can rename Object to Item
– Ale
Nov 13 '18 at 11:55












You need to provide some code. It is unclear to me what is your implementation. Are all entities of type item (houses, floors, rooms) or are those different classes? Do they implement/extend item class?
– Amongalen
Nov 13 '18 at 12:03




You need to provide some code. It is unclear to me what is your implementation. Are all entities of type item (houses, floors, rooms) or are those different classes? Do they implement/extend item class?
– Amongalen
Nov 13 '18 at 12:03












When discussing class design/method implementation, having a class name is pretty crucial for communication! Further, you should be providing some code in your questions to show us at what point your stuck. Define as much of the solution as you can and you'll find that people understand your problem better and provide answers closer to what you expect. As an aside, names like Objekt and Item are pretty opaque names for a class.. try something more meaningful (makes it obvious as to the actual purpose, HouseNode, FloorplanTree, etc). Good naming is paramount to clean maintainable code
– flakes
Nov 13 '18 at 12:53




When discussing class design/method implementation, having a class name is pretty crucial for communication! Further, you should be providing some code in your questions to show us at what point your stuck. Define as much of the solution as you can and you'll find that people understand your problem better and provide answers closer to what you expect. As an aside, names like Objekt and Item are pretty opaque names for a class.. try something more meaningful (makes it obvious as to the actual purpose, HouseNode, FloorplanTree, etc). Good naming is paramount to clean maintainable code
– flakes
Nov 13 '18 at 12:53












2 Answers
2






active

oldest

votes


















0














It would indeed be recursive. The trouble is that a simple recursive compare would only work if the two nodes were on the same level.



// Same level compare

int compareSameLevel(Item item) {

    int c = 0;

    if (this.getParent != null) {

        c = compare(this.getParent(), item.getParent());

    }

    return (c != 0) ? c : getName().compare(item.getName());

}


But you could adjust the levels to find a common level and assume that the children go after the parent:



// Compare on any level

int compare(Item item) {

    Item thisItem = this;

    int thisLevel = thisItem.level();

    int itemLevel = item.level();



    for (int i = thisLevel; i > itemLevel; i--) {

        thisItem = thisItem.getParent();

    }



    for (int j = itemLevel; j > thisLevel; j--) {

        item = item.getParent();

    }



    int c = compareSameLevel(thisItem, item);



    return c != 0 ? c : (thisLevel > itemLevel ? -1 : 1);

}


This is just to give you an idea. It is not tested or compiled.






share|improve this answer





























    -1














    Pseudo code: Try like this



        private static void printChildElements(List<Object> childNodes) {
    
    for(Object childNode : childNodes) {
    

    
        List<Object > childElements = childNode .....;
    
        if(childElements.size() > 0) {
    
            printChildElements( childElements);
    
        }
    
    }





    share|improve this answer





















    • The question is about sorting, not about printing the whole tree.
      – rghome
      Nov 13 '18 at 12:41











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    2 Answers
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    2 Answers
    2






    active

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    active

    oldest

    votes









    0














    It would indeed be recursive. The trouble is that a simple recursive compare would only work if the two nodes were on the same level.



    // Same level compare
    
int compareSameLevel(Item item) {
    
    int c = 0;
    
    if (this.getParent != null) {
    
        c = compare(this.getParent(), item.getParent());
    
    }
    
    return (c != 0) ? c : getName().compare(item.getName());
    
}


    But you could adjust the levels to find a common level and assume that the children go after the parent:



    // Compare on any level
    
int compare(Item item) {
    
    Item thisItem = this;
    
    int thisLevel = thisItem.level();
    
    int itemLevel = item.level();
    

    
    for (int i = thisLevel; i > itemLevel; i--) {
    
        thisItem = thisItem.getParent();
    
    }
    

    
    for (int j = itemLevel; j > thisLevel; j--) {
    
        item = item.getParent();
    
    }
    

    
    int c = compareSameLevel(thisItem, item);
    

    
    return c != 0 ? c : (thisLevel > itemLevel ? -1 : 1);
    
}


    This is just to give you an idea. It is not tested or compiled.






    share|improve this answer


























      0














      It would indeed be recursive. The trouble is that a simple recursive compare would only work if the two nodes were on the same level.



      // Same level compare
      
int compareSameLevel(Item item) {
      
    int c = 0;
      
    if (this.getParent != null) {
      
        c = compare(this.getParent(), item.getParent());
      
    }
      
    return (c != 0) ? c : getName().compare(item.getName());
      
}


      But you could adjust the levels to find a common level and assume that the children go after the parent:



      // Compare on any level
      
int compare(Item item) {
      
    Item thisItem = this;
      
    int thisLevel = thisItem.level();
      
    int itemLevel = item.level();
      

      
    for (int i = thisLevel; i > itemLevel; i--) {
      
        thisItem = thisItem.getParent();
      
    }
      

      
    for (int j = itemLevel; j > thisLevel; j--) {
      
        item = item.getParent();
      
    }
      

      
    int c = compareSameLevel(thisItem, item);
      

      
    return c != 0 ? c : (thisLevel > itemLevel ? -1 : 1);
      
}


      This is just to give you an idea. It is not tested or compiled.






      share|improve this answer
























        0












        0








        0






        It would indeed be recursive. The trouble is that a simple recursive compare would only work if the two nodes were on the same level.



        // Same level compare
        
int compareSameLevel(Item item) {
        
    int c = 0;
        
    if (this.getParent != null) {
        
        c = compare(this.getParent(), item.getParent());
        
    }
        
    return (c != 0) ? c : getName().compare(item.getName());
        
}


        But you could adjust the levels to find a common level and assume that the children go after the parent:



        // Compare on any level
        
int compare(Item item) {
        
    Item thisItem = this;
        
    int thisLevel = thisItem.level();
        
    int itemLevel = item.level();
        

        
    for (int i = thisLevel; i > itemLevel; i--) {
        
        thisItem = thisItem.getParent();
        
    }
        

        
    for (int j = itemLevel; j > thisLevel; j--) {
        
        item = item.getParent();
        
    }
        

        
    int c = compareSameLevel(thisItem, item);
        

        
    return c != 0 ? c : (thisLevel > itemLevel ? -1 : 1);
        
}


        This is just to give you an idea. It is not tested or compiled.






        share|improve this answer












        It would indeed be recursive. The trouble is that a simple recursive compare would only work if the two nodes were on the same level.



        // Same level compare
        
int compareSameLevel(Item item) {
        
    int c = 0;
        
    if (this.getParent != null) {
        
        c = compare(this.getParent(), item.getParent());
        
    }
        
    return (c != 0) ? c : getName().compare(item.getName());
        
}


        But you could adjust the levels to find a common level and assume that the children go after the parent:



        // Compare on any level
        
int compare(Item item) {
        
    Item thisItem = this;
        
    int thisLevel = thisItem.level();
        
    int itemLevel = item.level();
        

        
    for (int i = thisLevel; i > itemLevel; i--) {
        
        thisItem = thisItem.getParent();
        
    }
        

        
    for (int j = itemLevel; j > thisLevel; j--) {
        
        item = item.getParent();
        
    }
        

        
    int c = compareSameLevel(thisItem, item);
        

        
    return c != 0 ? c : (thisLevel > itemLevel ? -1 : 1);
        
}


        This is just to give you an idea. It is not tested or compiled.







        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Nov 13 '18 at 12:37









        rghomerghome

        4,69152540




        4,69152540

























            -1














            Pseudo code: Try like this



                private static void printChildElements(List<Object> childNodes) {
            
    for(Object childNode : childNodes) {
            

            
        List<Object > childElements = childNode .....;
            
        if(childElements.size() > 0) {
            
            printChildElements( childElements);
            
        }
            
    }





            share|improve this answer





















            • The question is about sorting, not about printing the whole tree.
              – rghome
              Nov 13 '18 at 12:41
















            -1














            Pseudo code: Try like this



                private static void printChildElements(List<Object> childNodes) {
            
    for(Object childNode : childNodes) {
            

            
        List<Object > childElements = childNode .....;
            
        if(childElements.size() > 0) {
            
            printChildElements( childElements);
            
        }
            
    }





            share|improve this answer





















            • The question is about sorting, not about printing the whole tree.
              – rghome
              Nov 13 '18 at 12:41














            -1












            -1








            -1






            Pseudo code: Try like this



                private static void printChildElements(List<Object> childNodes) {
            
    for(Object childNode : childNodes) {
            

            
        List<Object > childElements = childNode .....;
            
        if(childElements.size() > 0) {
            
            printChildElements( childElements);
            
        }
            
    }





            share|improve this answer












            Pseudo code: Try like this



                private static void printChildElements(List<Object> childNodes) {
            
    for(Object childNode : childNodes) {
            

            
        List<Object > childElements = childNode .....;
            
        if(childElements.size() > 0) {
            
            printChildElements( childElements);
            
        }
            
    }






            share|improve this answer












            share|improve this answer



            share|improve this answer










            answered Nov 13 '18 at 12:23









            Prakash NPrakash N

            347




            347












            • The question is about sorting, not about printing the whole tree.
              – rghome
              Nov 13 '18 at 12:41


















            • The question is about sorting, not about printing the whole tree.
              – rghome
              Nov 13 '18 at 12:41
















            The question is about sorting, not about printing the whole tree.
            – rghome
            Nov 13 '18 at 12:41




            The question is about sorting, not about printing the whole tree.
            – rghome
            Nov 13 '18 at 12:41


















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            Vorschmack

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            Vorschmack Ukrainian Jewish-style vorschmack served on rye bread Course Hors d'oeuvre Region or state Eastern Europe Associated national cuisine Ashkenazi Jewish, Finnish, German, Ukrainian, Polish, Russian Main ingredients Ground meat and/or fish Cookbook: Vorschmack   Media: Vorschmack Vorschmack or forshmak (Yiddish: פֿאָרשמאַק ‎, from archaic German Vorschmack , "foretaste" [1] or "appetizer" [2] ) is an originally East European dish made of salty minced fish or meat. Different variants of this dish are especially common in Ashkenazi Jewish and Finnish cuisine. Some varieties are also known in Russian and Polish cuisine. Contents 1 In Jewish cuisine 2 In Russian cuisine 3 In Polish cuisine 4 In Finnish cuisine 5 See also 6 References In Jewish cuisine According to Gil Marks, the German name points to the possible Germanic origin of this dish. [1] William Pokhlyobkin descr
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            Quarantine

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            For other uses, see Quarantine (disambiguation). Signal flag "Lima" called the "Yellow Jack" which when flown in harbor means ship is under quarantine. A simple yellow flag (also called the "Yellow Jack") had historically been used to signal quarantine (it stands for Q among signal flags), but now indicates the opposite, as a signal of a ship free of disease that requests boarding and inspection. A quarantine is used to separate and restrict the movement of people; it is 'a restraint upon the activities or communication of persons or the transport of goods designed to prevent the spread of disease or pests', for a certain period of time. [1] This is often used in connection to disease and illness, such as those who may possibly have been exposed to a communicable disease. [2] The term is often erroneously used to mean medical isolation, which is "to separate ill persons who have a communicable disease from those who are healthy
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