Pass a percent (%) sign in a url and get exact value of it using php
I am trying to pass percent (%) sign in url like
%B6011000995504101^SB
but when I echo, it returns
♦011000995504101^SB
I want exact same value as I pass it in URL.
I have tried to use urlencode() function, but it give me output like this...
%B6011000995504101%5ESB
please help me regarding this
php urlencode
asked Jun 27 '13 at 12:04
Sumit BijvaniSumit Bijvani
5,995163975
add a comment |
I am trying to pass percent (%) sign in url like
%B6011000995504101^SB
but when I echo, it returns
♦011000995504101^SB
I want exact same value as I pass it in URL.
I have tried to use urlencode() function, but it give me output like this...
%B6011000995504101%5ESB
please help me regarding this
php urlencode
asked Jun 27 '13 at 12:04
Sumit BijvaniSumit Bijvani
5,995163975
2
use url_encode() and url_decode() may also require htmlentities() %B6 for example is the code for the blob you got. passing the % is actually a really bad idea you'd be better off passing a different character for percent or not passing it at all and assume that the % is always there and assign it i nyour script after.
– Dave
Jun 27 '13 at 12:06
% is used for urlencode, better to pass a specific pattern like $$ or something else and decode it in the php code.
– Sudip Pal
Jun 27 '13 at 12:07
possible duplicate of urlencode but ignore certain chars
– Simon M
Jun 27 '13 at 12:08
add a comment |
I am trying to pass percent (%) sign in url like
%B6011000995504101^SB
but when I echo, it returns
♦011000995504101^SB
I want exact same value as I pass it in URL.
I have tried to use urlencode() function, but it give me output like this...
%B6011000995504101%5ESB
please help me regarding this
php urlencode
asked Jun 27 '13 at 12:04
Sumit BijvaniSumit Bijvani
5,995163975
I am trying to pass percent (%) sign in url like
%B6011000995504101^SB
but when I echo, it returns
♦011000995504101^SB
I want exact same value as I pass it in URL.
I have tried to use urlencode() function, but it give me output like this...
%B6011000995504101%5ESB
please help me regarding this
php urlencode
php urlencode
asked Jun 27 '13 at 12:04
Sumit BijvaniSumit Bijvani
5,995163975
asked Jun 27 '13 at 12:04
Sumit BijvaniSumit Bijvani
5,995163975
asked Jun 27 '13 at 12:04
Sumit BijvaniSumit Bijvani
5,995163975
asked Jun 27 '13 at 12:04
Sumit BijvaniSumit Bijvani
5,995163975
asked Jun 27 '13 at 12:04
Sumit BijvaniSumit Bijvani
5,995163975
5,995163975
2
use url_encode() and url_decode() may also require htmlentities() %B6 for example is the code for the blob you got. passing the % is actually a really bad idea you'd be better off passing a different character for percent or not passing it at all and assume that the % is always there and assign it i nyour script after.
– Dave
Jun 27 '13 at 12:06
% is used for urlencode, better to pass a specific pattern like $$ or something else and decode it in the php code.
– Sudip Pal
Jun 27 '13 at 12:07
possible duplicate of urlencode but ignore certain chars
– Simon M
Jun 27 '13 at 12:08
add a comment |
2
use url_encode() and url_decode() may also require htmlentities() %B6 for example is the code for the blob you got. passing the % is actually a really bad idea you'd be better off passing a different character for percent or not passing it at all and assume that the % is always there and assign it i nyour script after.
– Dave
Jun 27 '13 at 12:06
% is used for urlencode, better to pass a specific pattern like $$ or something else and decode it in the php code.
– Sudip Pal
Jun 27 '13 at 12:07
possible duplicate of urlencode but ignore certain chars
– Simon M
Jun 27 '13 at 12:08
2
2
use url_encode() and url_decode() may also require htmlentities() %B6 for example is the code for the blob you got. passing the % is actually a really bad idea you'd be better off passing a different character for percent or not passing it at all and assume that the % is always there and assign it i nyour script after.
– Dave
Jun 27 '13 at 12:06
use url_encode() and url_decode() may also require htmlentities() %B6 for example is the code for the blob you got. passing the % is actually a really bad idea you'd be better off passing a different character for percent or not passing it at all and assume that the % is always there and assign it i nyour script after.
– Dave
Jun 27 '13 at 12:06
% is used for urlencode, better to pass a specific pattern like $$ or something else and decode it in the php code.
– Sudip Pal
Jun 27 '13 at 12:07
% is used for urlencode, better to pass a specific pattern like $$ or something else and decode it in the php code.
– Sudip Pal
Jun 27 '13 at 12:07
possible duplicate of urlencode but ignore certain chars
– Simon M
Jun 27 '13 at 12:08
possible duplicate of urlencode but ignore certain chars
– Simon M
Jun 27 '13 at 12:08
add a comment |
2 Answers
2
active
oldest
votes
Answer:
To send a % sign in a url, instead send %25.
In your case, in order for php to see a percent sign, you must pass the character string %25B6011000995504101^SB to the server.
Why:
In URLs, the percent sign has special meaning. Is used to encode special characters. For example, & is the separator between parameters, so if you want your parameter to actually contain an &, you instead write %26. Because the percent sign is used to encode special characters, it is also a special character, and so if you want to actually send a percent sign, it must also be encoded. The encoding for a percent sign is %25.
answered Jun 27 '13 at 12:09
IanPudneyIanPudney
4,73211630
it adds another 25 like %2525
– Anonymous
Mar 8 '18 at 13:20
Awesome!! I was beating myself up because of this problem... thx
– Paulo Künzel
Dec 12 '18 at 21:38
add a comment |
Before including a raw string in a URL it's a good idea to pass it through urlencode like so:
<?php
$original='%B6011000995504101^SB';
$updated=urlencode($original);
echo "<a href="some_page.php?$updated">Link here</a>";
?>
The receiving page will know what to do - give this example a try on your webserver:
<?php
if($_GET['argument']) {
echo "<p>You passed in the argument "$_GET[argument]"</p>";
}else {
echo "<p>No argument was passed.</p>";
}
$original='%B6011000995504101^SB';
$updated=urlencode($original);
echo "<a href="urlencode.php?argument=$updated">Link here</a>";
?>
(name the file urlencode.php)
answered Jun 27 '13 at 12:10
Nate from KalamazooNate from Kalamazoo
38616
I have already tried it..
– Sumit Bijvani
Jun 27 '13 at 12:11
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
Answer:
To send a % sign in a url, instead send %25.
In your case, in order for php to see a percent sign, you must pass the character string %25B6011000995504101^SB to the server.
Why:
In URLs, the percent sign has special meaning. Is used to encode special characters. For example, & is the separator between parameters, so if you want your parameter to actually contain an &, you instead write %26. Because the percent sign is used to encode special characters, it is also a special character, and so if you want to actually send a percent sign, it must also be encoded. The encoding for a percent sign is %25.
answered Jun 27 '13 at 12:09
IanPudneyIanPudney
4,73211630
it adds another 25 like %2525
– Anonymous
Mar 8 '18 at 13:20
Awesome!! I was beating myself up because of this problem... thx
– Paulo Künzel
Dec 12 '18 at 21:38
add a comment |
Answer:
To send a % sign in a url, instead send %25.
In your case, in order for php to see a percent sign, you must pass the character string %25B6011000995504101^SB to the server.
Why:
In URLs, the percent sign has special meaning. Is used to encode special characters. For example, & is the separator between parameters, so if you want your parameter to actually contain an &, you instead write %26. Because the percent sign is used to encode special characters, it is also a special character, and so if you want to actually send a percent sign, it must also be encoded. The encoding for a percent sign is %25.
answered Jun 27 '13 at 12:09
IanPudneyIanPudney
4,73211630
it adds another 25 like %2525
– Anonymous
Mar 8 '18 at 13:20
Awesome!! I was beating myself up because of this problem... thx
– Paulo Künzel
Dec 12 '18 at 21:38
add a comment |
Answer:
To send a % sign in a url, instead send %25.
In your case, in order for php to see a percent sign, you must pass the character string %25B6011000995504101^SB to the server.
Why:
In URLs, the percent sign has special meaning. Is used to encode special characters. For example, & is the separator between parameters, so if you want your parameter to actually contain an &, you instead write %26. Because the percent sign is used to encode special characters, it is also a special character, and so if you want to actually send a percent sign, it must also be encoded. The encoding for a percent sign is %25.
answered Jun 27 '13 at 12:09
IanPudneyIanPudney
4,73211630
Answer:
To send a % sign in a url, instead send %25.
In your case, in order for php to see a percent sign, you must pass the character string %25B6011000995504101^SB to the server.
Why:
In URLs, the percent sign has special meaning. Is used to encode special characters. For example, & is the separator between parameters, so if you want your parameter to actually contain an &, you instead write %26. Because the percent sign is used to encode special characters, it is also a special character, and so if you want to actually send a percent sign, it must also be encoded. The encoding for a percent sign is %25.
answered Jun 27 '13 at 12:09
IanPudneyIanPudney
4,73211630
edited Jan 13 '17 at 3:17
answered Jun 27 '13 at 12:09
IanPudneyIanPudney
4,73211630
answered Jun 27 '13 at 12:09
IanPudneyIanPudney
4,73211630
answered Jun 27 '13 at 12:09
IanPudneyIanPudney
4,73211630
4,73211630
it adds another 25 like %2525
– Anonymous
Mar 8 '18 at 13:20
Awesome!! I was beating myself up because of this problem... thx
– Paulo Künzel
Dec 12 '18 at 21:38
add a comment |
it adds another 25 like %2525
– Anonymous
Mar 8 '18 at 13:20
Awesome!! I was beating myself up because of this problem... thx
– Paulo Künzel
Dec 12 '18 at 21:38
it adds another 25 like %2525
– Anonymous
Mar 8 '18 at 13:20
it adds another 25 like %2525
– Anonymous
Mar 8 '18 at 13:20
Awesome!! I was beating myself up because of this problem... thx
– Paulo Künzel
Dec 12 '18 at 21:38
Awesome!! I was beating myself up because of this problem... thx
– Paulo Künzel
Dec 12 '18 at 21:38
add a comment |
Before including a raw string in a URL it's a good idea to pass it through urlencode like so:
<?php
$original='%B6011000995504101^SB';
$updated=urlencode($original);
echo "<a href="some_page.php?$updated">Link here</a>";
?>
The receiving page will know what to do - give this example a try on your webserver:
<?php
if($_GET['argument']) {
echo "<p>You passed in the argument "$_GET[argument]"</p>";
}else {
echo "<p>No argument was passed.</p>";
}
$original='%B6011000995504101^SB';
$updated=urlencode($original);
echo "<a href="urlencode.php?argument=$updated">Link here</a>";
?>
(name the file urlencode.php)
answered Jun 27 '13 at 12:10
Nate from KalamazooNate from Kalamazoo
38616
I have already tried it..
– Sumit Bijvani
Jun 27 '13 at 12:11
add a comment |
Before including a raw string in a URL it's a good idea to pass it through urlencode like so:
<?php
$original='%B6011000995504101^SB';
$updated=urlencode($original);
echo "<a href="some_page.php?$updated">Link here</a>";
?>
The receiving page will know what to do - give this example a try on your webserver:
<?php
if($_GET['argument']) {
echo "<p>You passed in the argument "$_GET[argument]"</p>";
}else {
echo "<p>No argument was passed.</p>";
}
$original='%B6011000995504101^SB';
$updated=urlencode($original);
echo "<a href="urlencode.php?argument=$updated">Link here</a>";
?>
(name the file urlencode.php)
answered Jun 27 '13 at 12:10
Nate from KalamazooNate from Kalamazoo
38616
I have already tried it..
– Sumit Bijvani
Jun 27 '13 at 12:11
add a comment |
Before including a raw string in a URL it's a good idea to pass it through urlencode like so:
<?php
$original='%B6011000995504101^SB';
$updated=urlencode($original);
echo "<a href="some_page.php?$updated">Link here</a>";
?>
The receiving page will know what to do - give this example a try on your webserver:
<?php
if($_GET['argument']) {
echo "<p>You passed in the argument "$_GET[argument]"</p>";
}else {
echo "<p>No argument was passed.</p>";
}
$original='%B6011000995504101^SB';
$updated=urlencode($original);
echo "<a href="urlencode.php?argument=$updated">Link here</a>";
?>
(name the file urlencode.php)
answered Jun 27 '13 at 12:10
Nate from KalamazooNate from Kalamazoo
38616
Before including a raw string in a URL it's a good idea to pass it through urlencode like so:
<?php
$original='%B6011000995504101^SB';
$updated=urlencode($original);
echo "<a href="some_page.php?$updated">Link here</a>";
?>
The receiving page will know what to do - give this example a try on your webserver:
<?php
if($_GET['argument']) {
echo "<p>You passed in the argument "$_GET[argument]"</p>";
}else {
echo "<p>No argument was passed.</p>";
}
$original='%B6011000995504101^SB';
$updated=urlencode($original);
echo "<a href="urlencode.php?argument=$updated">Link here</a>";
?>
(name the file urlencode.php)
answered Jun 27 '13 at 12:10
Nate from KalamazooNate from Kalamazoo
38616
answered Jun 27 '13 at 12:10
Nate from KalamazooNate from Kalamazoo
38616
answered Jun 27 '13 at 12:10
Nate from KalamazooNate from Kalamazoo
38616
answered Jun 27 '13 at 12:10
Nate from KalamazooNate from Kalamazoo
38616
38616
I have already tried it..
– Sumit Bijvani
Jun 27 '13 at 12:11
add a comment |
I have already tried it..
– Sumit Bijvani
Jun 27 '13 at 12:11
I have already tried it..
– Sumit Bijvani
Jun 27 '13 at 12:11
I have already tried it..
– Sumit Bijvani
Jun 27 '13 at 12:11
add a comment |
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2
use url_encode() and url_decode() may also require htmlentities() %B6 for example is the code for the blob you got. passing the % is actually a really bad idea you'd be better off passing a different character for percent or not passing it at all and assume that the % is always there and assign it i nyour script after.
– Dave
Jun 27 '13 at 12:06
% is used for urlencode, better to pass a specific pattern like $$ or something else and decode it in the php code.
– Sudip Pal
Jun 27 '13 at 12:07
possible duplicate of urlencode but ignore certain chars
– Simon M
Jun 27 '13 at 12:08