Filter firebase records by the array value of a specific property












0














I am playing around with firebase functions and I have a question. The structure of my firebase DB is as follows:



 myDb
|
Users
|
000001
|
Name: Sam
|
Items: [1,2,3]
|
000002
|
Name: Jim
|
Items: [3,4,5]


And what I want to do is to filter all of the users which have 3 inside of their Items value. I didn't find anything similar to: this SO post on their documentations for filtering data. Maybe because it is not a simple value. I don't know. I am now wondering how to perform this particular filtering.










share|improve this question






















  • How do you store the array? Is the index of the element the key property: items: { 0: 1, 1: 2, 2:3 }
    – Hristo Eftimov
    Nov 13 '18 at 8:47
















0














I am playing around with firebase functions and I have a question. The structure of my firebase DB is as follows:



 myDb
|
Users
|
000001
|
Name: Sam
|
Items: [1,2,3]
|
000002
|
Name: Jim
|
Items: [3,4,5]


And what I want to do is to filter all of the users which have 3 inside of their Items value. I didn't find anything similar to: this SO post on their documentations for filtering data. Maybe because it is not a simple value. I don't know. I am now wondering how to perform this particular filtering.










share|improve this question






















  • How do you store the array? Is the index of the element the key property: items: { 0: 1, 1: 2, 2:3 }
    – Hristo Eftimov
    Nov 13 '18 at 8:47














0












0








0







I am playing around with firebase functions and I have a question. The structure of my firebase DB is as follows:



 myDb
|
Users
|
000001
|
Name: Sam
|
Items: [1,2,3]
|
000002
|
Name: Jim
|
Items: [3,4,5]


And what I want to do is to filter all of the users which have 3 inside of their Items value. I didn't find anything similar to: this SO post on their documentations for filtering data. Maybe because it is not a simple value. I don't know. I am now wondering how to perform this particular filtering.










share|improve this question













I am playing around with firebase functions and I have a question. The structure of my firebase DB is as follows:



 myDb
|
Users
|
000001
|
Name: Sam
|
Items: [1,2,3]
|
000002
|
Name: Jim
|
Items: [3,4,5]


And what I want to do is to filter all of the users which have 3 inside of their Items value. I didn't find anything similar to: this SO post on their documentations for filtering data. Maybe because it is not a simple value. I don't know. I am now wondering how to perform this particular filtering.







firebase react-native google-cloud-functions






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asked Nov 13 '18 at 7:37









user2128702user2128702

5161831




5161831












  • How do you store the array? Is the index of the element the key property: items: { 0: 1, 1: 2, 2:3 }
    – Hristo Eftimov
    Nov 13 '18 at 8:47


















  • How do you store the array? Is the index of the element the key property: items: { 0: 1, 1: 2, 2:3 }
    – Hristo Eftimov
    Nov 13 '18 at 8:47
















How do you store the array? Is the index of the element the key property: items: { 0: 1, 1: 2, 2:3 }
– Hristo Eftimov
Nov 13 '18 at 8:47




How do you store the array? Is the index of the element the key property: items: { 0: 1, 1: 2, 2:3 }
– Hristo Eftimov
Nov 13 '18 at 8:47












1 Answer
1






active

oldest

votes


















0














Array contain filters aren't possible in Firebase Realtime Database but it is a recent addition to Firestore.



firebase.firestore().collection('users').where('items', 'array-contains', 3)


In the Firebase Realtime Database you would want to structure them as an object which you could query on



{
name: "Jim",
items: {
1: true,
2: true,
3: true
}
}


and then the query would be like this



firebase.database().ref('users').orderByChild('items/3').equalTo(true);





share|improve this answer





















  • Would it be possible to have the keys as strings (e.g. {"str1":1, "str2":2}) and then to have .orderByChild('items/str1').equalTo(1); ?
    – user2128702
    Nov 13 '18 at 19:30










  • No reason why not, it will work
    – Jack Woodward
    Nov 13 '18 at 20:05











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1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes









0














Array contain filters aren't possible in Firebase Realtime Database but it is a recent addition to Firestore.



firebase.firestore().collection('users').where('items', 'array-contains', 3)


In the Firebase Realtime Database you would want to structure them as an object which you could query on



{
name: "Jim",
items: {
1: true,
2: true,
3: true
}
}


and then the query would be like this



firebase.database().ref('users').orderByChild('items/3').equalTo(true);





share|improve this answer





















  • Would it be possible to have the keys as strings (e.g. {"str1":1, "str2":2}) and then to have .orderByChild('items/str1').equalTo(1); ?
    – user2128702
    Nov 13 '18 at 19:30










  • No reason why not, it will work
    – Jack Woodward
    Nov 13 '18 at 20:05
















0














Array contain filters aren't possible in Firebase Realtime Database but it is a recent addition to Firestore.



firebase.firestore().collection('users').where('items', 'array-contains', 3)


In the Firebase Realtime Database you would want to structure them as an object which you could query on



{
name: "Jim",
items: {
1: true,
2: true,
3: true
}
}


and then the query would be like this



firebase.database().ref('users').orderByChild('items/3').equalTo(true);





share|improve this answer





















  • Would it be possible to have the keys as strings (e.g. {"str1":1, "str2":2}) and then to have .orderByChild('items/str1').equalTo(1); ?
    – user2128702
    Nov 13 '18 at 19:30










  • No reason why not, it will work
    – Jack Woodward
    Nov 13 '18 at 20:05














0












0








0






Array contain filters aren't possible in Firebase Realtime Database but it is a recent addition to Firestore.



firebase.firestore().collection('users').where('items', 'array-contains', 3)


In the Firebase Realtime Database you would want to structure them as an object which you could query on



{
name: "Jim",
items: {
1: true,
2: true,
3: true
}
}


and then the query would be like this



firebase.database().ref('users').orderByChild('items/3').equalTo(true);





share|improve this answer












Array contain filters aren't possible in Firebase Realtime Database but it is a recent addition to Firestore.



firebase.firestore().collection('users').where('items', 'array-contains', 3)


In the Firebase Realtime Database you would want to structure them as an object which you could query on



{
name: "Jim",
items: {
1: true,
2: true,
3: true
}
}


and then the query would be like this



firebase.database().ref('users').orderByChild('items/3').equalTo(true);






share|improve this answer












share|improve this answer



share|improve this answer










answered Nov 13 '18 at 9:56









Jack WoodwardJack Woodward

61139




61139












  • Would it be possible to have the keys as strings (e.g. {"str1":1, "str2":2}) and then to have .orderByChild('items/str1').equalTo(1); ?
    – user2128702
    Nov 13 '18 at 19:30










  • No reason why not, it will work
    – Jack Woodward
    Nov 13 '18 at 20:05


















  • Would it be possible to have the keys as strings (e.g. {"str1":1, "str2":2}) and then to have .orderByChild('items/str1').equalTo(1); ?
    – user2128702
    Nov 13 '18 at 19:30










  • No reason why not, it will work
    – Jack Woodward
    Nov 13 '18 at 20:05
















Would it be possible to have the keys as strings (e.g. {"str1":1, "str2":2}) and then to have .orderByChild('items/str1').equalTo(1); ?
– user2128702
Nov 13 '18 at 19:30




Would it be possible to have the keys as strings (e.g. {"str1":1, "str2":2}) and then to have .orderByChild('items/str1').equalTo(1); ?
– user2128702
Nov 13 '18 at 19:30












No reason why not, it will work
– Jack Woodward
Nov 13 '18 at 20:05




No reason why not, it will work
– Jack Woodward
Nov 13 '18 at 20:05


















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