dynamically returning views by a foreach loop
I have a foreach loop that runs by my database:
<div id="nav" >
@foreach(AppCategories::whereNull('parent_id')->get() as $category)
<a id="link1" href="{{ route('showCategory' , $category->id) }}" ><div class="link">{{ $category->name }}</div></a>
@endforeach
</div>
I want foreach link that adds by that it knows his path to the blades dynamically.
What should I do here?
My web.php:
Route::get('/category/{category}', 'PagesController@showCategory')->name('showCategory');
My controller:
public function showCategory(Categories $category) {
}
database laravel dynamic foreach controller
edited Nov 12 at 20:20
Mihai Chelaru
2,13291022
asked Nov 12 at 15:44
Bashar Al-Aswad
262
add a comment |
I have a foreach loop that runs by my database:
<div id="nav" >
@foreach(AppCategories::whereNull('parent_id')->get() as $category)
<a id="link1" href="{{ route('showCategory' , $category->id) }}" ><div class="link">{{ $category->name }}</div></a>
@endforeach
</div>
I want foreach link that adds by that it knows his path to the blades dynamically.
What should I do here?
My web.php:
Route::get('/category/{category}', 'PagesController@showCategory')->name('showCategory');
My controller:
public function showCategory(Categories $category) {
}
database laravel dynamic foreach controller
edited Nov 12 at 20:20
Mihai Chelaru
2,13291022
asked Nov 12 at 15:44
Bashar Al-Aswad
262
add a comment |
I have a foreach loop that runs by my database:
<div id="nav" >
@foreach(AppCategories::whereNull('parent_id')->get() as $category)
<a id="link1" href="{{ route('showCategory' , $category->id) }}" ><div class="link">{{ $category->name }}</div></a>
@endforeach
</div>
I want foreach link that adds by that it knows his path to the blades dynamically.
What should I do here?
My web.php:
Route::get('/category/{category}', 'PagesController@showCategory')->name('showCategory');
My controller:
public function showCategory(Categories $category) {
}
database laravel dynamic foreach controller
edited Nov 12 at 20:20
Mihai Chelaru
2,13291022
asked Nov 12 at 15:44
Bashar Al-Aswad
262
I have a foreach loop that runs by my database:
<div id="nav" >
@foreach(AppCategories::whereNull('parent_id')->get() as $category)
<a id="link1" href="{{ route('showCategory' , $category->id) }}" ><div class="link">{{ $category->name }}</div></a>
@endforeach
</div>
I want foreach link that adds by that it knows his path to the blades dynamically.
What should I do here?
My web.php:
Route::get('/category/{category}', 'PagesController@showCategory')->name('showCategory');
My controller:
public function showCategory(Categories $category) {
}
database laravel dynamic foreach controller
database laravel dynamic foreach controller
edited Nov 12 at 20:20
Mihai Chelaru
2,13291022
asked Nov 12 at 15:44
Bashar Al-Aswad
262
edited Nov 12 at 20:20
Mihai Chelaru
2,13291022
asked Nov 12 at 15:44
Bashar Al-Aswad
262
edited Nov 12 at 20:20
Mihai Chelaru
2,13291022
edited Nov 12 at 20:20
Mihai Chelaru
2,13291022
edited Nov 12 at 20:20
Mihai Chelaru
2,13291022
2,13291022
asked Nov 12 at 15:44
Bashar Al-Aswad
262
asked Nov 12 at 15:44
Bashar Al-Aswad
262
asked Nov 12 at 15:44
Bashar Al-Aswad
262
262
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
I'm guessing that you want to create a link for each category which goes to a page that displays more information about the selected category.
Your blade file in which you create the links for all the categories seems fine to me, but I'd recommend changing your route file to this:
Route::get('/category/{id}', 'PagesController@showCategory')->name('showCategory');
Then for your showCategory function, you would need something like this:
public function showCategory($id) {
$category = Categories::find($id);
// i used categories.show here, change it to whatever view you use
return view('categories.show')->with('category', $category);
}
Then in your categories.show view, you can access the properties of the category like so:
$category->id; // or whatever you want to display
As per OP's request: the first 5 categories in the database that lead to their pages:
In your controller:
public function myFunction()
{
$categories = Categories::all()->take(5)->get();
return view('your.view')->with('categories', $categories);
}
In your blade view (assuming that the view for the category is at: /category/id):
@foreach($categories as $category)
<a href="/category/{{$category->id}}">{{$category->name}}</a>
@endforeach
answered Nov 12 at 20:32
rpm192
1,1571417
Thank you for your answer.And if I have 5 different links and each one has a different 'href' how would you recommend to do it in the categories.show?
– Bashar Al-Aswad
Nov 12 at 21:11
5 different links in one category? Or 5 different categories leading to their pages?
– rpm192
Nov 12 at 21:18
5 different categories leiding to their pages is what I mean.
– Bashar Al-Aswad
Nov 13 at 8:07
Do you want 5 random categories from you database? All of them? Or the 5 first or 5 last.
– rpm192
Nov 13 at 8:18
First 5 categories.
– Bashar Al-Aswad
Nov 13 at 8:46
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
I'm guessing that you want to create a link for each category which goes to a page that displays more information about the selected category.
Your blade file in which you create the links for all the categories seems fine to me, but I'd recommend changing your route file to this:
Route::get('/category/{id}', 'PagesController@showCategory')->name('showCategory');
Then for your showCategory function, you would need something like this:
public function showCategory($id) {
$category = Categories::find($id);
// i used categories.show here, change it to whatever view you use
return view('categories.show')->with('category', $category);
}
Then in your categories.show view, you can access the properties of the category like so:
$category->id; // or whatever you want to display
As per OP's request: the first 5 categories in the database that lead to their pages:
In your controller:
public function myFunction()
{
$categories = Categories::all()->take(5)->get();
return view('your.view')->with('categories', $categories);
}
In your blade view (assuming that the view for the category is at: /category/id):
@foreach($categories as $category)
<a href="/category/{{$category->id}}">{{$category->name}}</a>
@endforeach
answered Nov 12 at 20:32
rpm192
1,1571417
Thank you for your answer.And if I have 5 different links and each one has a different 'href' how would you recommend to do it in the categories.show?
– Bashar Al-Aswad
Nov 12 at 21:11
5 different links in one category? Or 5 different categories leading to their pages?
– rpm192
Nov 12 at 21:18
5 different categories leiding to their pages is what I mean.
– Bashar Al-Aswad
Nov 13 at 8:07
Do you want 5 random categories from you database? All of them? Or the 5 first or 5 last.
– rpm192
Nov 13 at 8:18
First 5 categories.
– Bashar Al-Aswad
Nov 13 at 8:46
add a comment |
I'm guessing that you want to create a link for each category which goes to a page that displays more information about the selected category.
Your blade file in which you create the links for all the categories seems fine to me, but I'd recommend changing your route file to this:
Route::get('/category/{id}', 'PagesController@showCategory')->name('showCategory');
Then for your showCategory function, you would need something like this:
public function showCategory($id) {
$category = Categories::find($id);
// i used categories.show here, change it to whatever view you use
return view('categories.show')->with('category', $category);
}
Then in your categories.show view, you can access the properties of the category like so:
$category->id; // or whatever you want to display
As per OP's request: the first 5 categories in the database that lead to their pages:
In your controller:
public function myFunction()
{
$categories = Categories::all()->take(5)->get();
return view('your.view')->with('categories', $categories);
}
In your blade view (assuming that the view for the category is at: /category/id):
@foreach($categories as $category)
<a href="/category/{{$category->id}}">{{$category->name}}</a>
@endforeach
answered Nov 12 at 20:32
rpm192
1,1571417
Thank you for your answer.And if I have 5 different links and each one has a different 'href' how would you recommend to do it in the categories.show?
– Bashar Al-Aswad
Nov 12 at 21:11
5 different links in one category? Or 5 different categories leading to their pages?
– rpm192
Nov 12 at 21:18
5 different categories leiding to their pages is what I mean.
– Bashar Al-Aswad
Nov 13 at 8:07
Do you want 5 random categories from you database? All of them? Or the 5 first or 5 last.
– rpm192
Nov 13 at 8:18
First 5 categories.
– Bashar Al-Aswad
Nov 13 at 8:46
add a comment |
I'm guessing that you want to create a link for each category which goes to a page that displays more information about the selected category.
Your blade file in which you create the links for all the categories seems fine to me, but I'd recommend changing your route file to this:
Route::get('/category/{id}', 'PagesController@showCategory')->name('showCategory');
Then for your showCategory function, you would need something like this:
public function showCategory($id) {
$category = Categories::find($id);
// i used categories.show here, change it to whatever view you use
return view('categories.show')->with('category', $category);
}
Then in your categories.show view, you can access the properties of the category like so:
$category->id; // or whatever you want to display
As per OP's request: the first 5 categories in the database that lead to their pages:
In your controller:
public function myFunction()
{
$categories = Categories::all()->take(5)->get();
return view('your.view')->with('categories', $categories);
}
In your blade view (assuming that the view for the category is at: /category/id):
@foreach($categories as $category)
<a href="/category/{{$category->id}}">{{$category->name}}</a>
@endforeach
answered Nov 12 at 20:32
rpm192
1,1571417
I'm guessing that you want to create a link for each category which goes to a page that displays more information about the selected category.
Your blade file in which you create the links for all the categories seems fine to me, but I'd recommend changing your route file to this:
Route::get('/category/{id}', 'PagesController@showCategory')->name('showCategory');
Then for your showCategory function, you would need something like this:
public function showCategory($id) {
$category = Categories::find($id);
// i used categories.show here, change it to whatever view you use
return view('categories.show')->with('category', $category);
}
Then in your categories.show view, you can access the properties of the category like so:
$category->id; // or whatever you want to display
As per OP's request: the first 5 categories in the database that lead to their pages:
In your controller:
public function myFunction()
{
$categories = Categories::all()->take(5)->get();
return view('your.view')->with('categories', $categories);
}
In your blade view (assuming that the view for the category is at: /category/id):
@foreach($categories as $category)
<a href="/category/{{$category->id}}">{{$category->name}}</a>
@endforeach
answered Nov 12 at 20:32
rpm192
1,1571417
edited Nov 13 at 8:51
answered Nov 12 at 20:32
rpm192
1,1571417
answered Nov 12 at 20:32
rpm192
1,1571417
answered Nov 12 at 20:32
rpm192
1,1571417
1,1571417
Thank you for your answer.And if I have 5 different links and each one has a different 'href' how would you recommend to do it in the categories.show?
– Bashar Al-Aswad
Nov 12 at 21:11
5 different links in one category? Or 5 different categories leading to their pages?
– rpm192
Nov 12 at 21:18
5 different categories leiding to their pages is what I mean.
– Bashar Al-Aswad
Nov 13 at 8:07
Do you want 5 random categories from you database? All of them? Or the 5 first or 5 last.
– rpm192
Nov 13 at 8:18
First 5 categories.
– Bashar Al-Aswad
Nov 13 at 8:46
add a comment |
Thank you for your answer.And if I have 5 different links and each one has a different 'href' how would you recommend to do it in the categories.show?
– Bashar Al-Aswad
Nov 12 at 21:11
5 different links in one category? Or 5 different categories leading to their pages?
– rpm192
Nov 12 at 21:18
5 different categories leiding to their pages is what I mean.
– Bashar Al-Aswad
Nov 13 at 8:07
Do you want 5 random categories from you database? All of them? Or the 5 first or 5 last.
– rpm192
Nov 13 at 8:18
First 5 categories.
– Bashar Al-Aswad
Nov 13 at 8:46
Thank you for your answer.And if I have 5 different links and each one has a different 'href' how would you recommend to do it in the categories.show?
– Bashar Al-Aswad
Nov 12 at 21:11
Thank you for your answer.And if I have 5 different links and each one has a different 'href' how would you recommend to do it in the categories.show?
– Bashar Al-Aswad
Nov 12 at 21:11
5 different links in one category? Or 5 different categories leading to their pages?
– rpm192
Nov 12 at 21:18
5 different links in one category? Or 5 different categories leading to their pages?
– rpm192
Nov 12 at 21:18
5 different categories leiding to their pages is what I mean.
– Bashar Al-Aswad
Nov 13 at 8:07
5 different categories leiding to their pages is what I mean.
– Bashar Al-Aswad
Nov 13 at 8:07
Do you want 5 random categories from you database? All of them? Or the 5 first or 5 last.
– rpm192
Nov 13 at 8:18
Do you want 5 random categories from you database? All of them? Or the 5 first or 5 last.
– rpm192
Nov 13 at 8:18
First 5 categories.
– Bashar Al-Aswad
Nov 13 at 8:46
First 5 categories.
– Bashar Al-Aswad
Nov 13 at 8:46
add a comment |
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