Does Typescript support extracted interface by excluding another interface's properties?












1














I wonder if it has any of the following features. I tried Google but I couldn't find it out. Thanks!



interface Numbers {
number: number;
number2: number;
number3: number;
}

const numbers:Numbers - { number3 } = {
number: 1,
number2: 2
};









share|improve this question






















  • Have you read the documentation of TypeScript? It explains (with examples) what one can and cannot do with interfaces.
    – axiac
    Apr 1 at 8:04










  • @axiac Thanks! I've already read it before, but not entirely. and I've read the interface section once more according to your advice. :)
    – left click
    Apr 1 at 8:30






  • 1




    Based on the answer you get, it seems reading the release notes of each version is required to be up to date with the language: typescriptlang.org/docs/handbook/release-notes/…. I started reading them too.
    – axiac
    Apr 1 at 8:40










  • @axiac I appreciate your kindness.
    – left click
    Apr 1 at 8:55
















1














I wonder if it has any of the following features. I tried Google but I couldn't find it out. Thanks!



interface Numbers {
number: number;
number2: number;
number3: number;
}

const numbers:Numbers - { number3 } = {
number: 1,
number2: 2
};









share|improve this question






















  • Have you read the documentation of TypeScript? It explains (with examples) what one can and cannot do with interfaces.
    – axiac
    Apr 1 at 8:04










  • @axiac Thanks! I've already read it before, but not entirely. and I've read the interface section once more according to your advice. :)
    – left click
    Apr 1 at 8:30






  • 1




    Based on the answer you get, it seems reading the release notes of each version is required to be up to date with the language: typescriptlang.org/docs/handbook/release-notes/…. I started reading them too.
    – axiac
    Apr 1 at 8:40










  • @axiac I appreciate your kindness.
    – left click
    Apr 1 at 8:55














1












1








1







I wonder if it has any of the following features. I tried Google but I couldn't find it out. Thanks!



interface Numbers {
number: number;
number2: number;
number3: number;
}

const numbers:Numbers - { number3 } = {
number: 1,
number2: 2
};









share|improve this question













I wonder if it has any of the following features. I tried Google but I couldn't find it out. Thanks!



interface Numbers {
number: number;
number2: number;
number3: number;
}

const numbers:Numbers - { number3 } = {
number: 1,
number2: 2
};






typescript






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share|improve this question




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asked Apr 1 at 8:00









left click

26829




26829












  • Have you read the documentation of TypeScript? It explains (with examples) what one can and cannot do with interfaces.
    – axiac
    Apr 1 at 8:04










  • @axiac Thanks! I've already read it before, but not entirely. and I've read the interface section once more according to your advice. :)
    – left click
    Apr 1 at 8:30






  • 1




    Based on the answer you get, it seems reading the release notes of each version is required to be up to date with the language: typescriptlang.org/docs/handbook/release-notes/…. I started reading them too.
    – axiac
    Apr 1 at 8:40










  • @axiac I appreciate your kindness.
    – left click
    Apr 1 at 8:55


















  • Have you read the documentation of TypeScript? It explains (with examples) what one can and cannot do with interfaces.
    – axiac
    Apr 1 at 8:04










  • @axiac Thanks! I've already read it before, but not entirely. and I've read the interface section once more according to your advice. :)
    – left click
    Apr 1 at 8:30






  • 1




    Based on the answer you get, it seems reading the release notes of each version is required to be up to date with the language: typescriptlang.org/docs/handbook/release-notes/…. I started reading them too.
    – axiac
    Apr 1 at 8:40










  • @axiac I appreciate your kindness.
    – left click
    Apr 1 at 8:55
















Have you read the documentation of TypeScript? It explains (with examples) what one can and cannot do with interfaces.
– axiac
Apr 1 at 8:04




Have you read the documentation of TypeScript? It explains (with examples) what one can and cannot do with interfaces.
– axiac
Apr 1 at 8:04












@axiac Thanks! I've already read it before, but not entirely. and I've read the interface section once more according to your advice. :)
– left click
Apr 1 at 8:30




@axiac Thanks! I've already read it before, but not entirely. and I've read the interface section once more according to your advice. :)
– left click
Apr 1 at 8:30




1




1




Based on the answer you get, it seems reading the release notes of each version is required to be up to date with the language: typescriptlang.org/docs/handbook/release-notes/…. I started reading them too.
– axiac
Apr 1 at 8:40




Based on the answer you get, it seems reading the release notes of each version is required to be up to date with the language: typescriptlang.org/docs/handbook/release-notes/…. I started reading them too.
– axiac
Apr 1 at 8:40












@axiac I appreciate your kindness.
– left click
Apr 1 at 8:55




@axiac I appreciate your kindness.
– left click
Apr 1 at 8:55












1 Answer
1






active

oldest

votes


















4














You can do this in 2.8 using the new Exclude conditional type and the Pick mapped type



type Omit<T, K extends keyof T> = Pick<T, Exclude<keyof T, K>>; 

interface Numbers {
number: number;
number2: number;
number3: number;
}

const numbers:Omit<Numbers, 'number3'> = {
number: 1,
number2: 2
};


Before 2.8 Omit could be defined like this:



type Diff<T extends string, U extends string> = ({[P in T]: P } & {[P in U]: never } & { [x: string]: never })[T];  
type Omit<T, K extends keyof T> = Pick<T, Diff<keyof T, K>>;





share|improve this answer

















  • 1




    I was trying to figure out by Exclude was introduced in 2.8, but it did not work to me. Good solution. Thank you for teaching me. :)
    – left click
    Apr 1 at 8:37











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1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

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active

oldest

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4














You can do this in 2.8 using the new Exclude conditional type and the Pick mapped type



type Omit<T, K extends keyof T> = Pick<T, Exclude<keyof T, K>>; 

interface Numbers {
number: number;
number2: number;
number3: number;
}

const numbers:Omit<Numbers, 'number3'> = {
number: 1,
number2: 2
};


Before 2.8 Omit could be defined like this:



type Diff<T extends string, U extends string> = ({[P in T]: P } & {[P in U]: never } & { [x: string]: never })[T];  
type Omit<T, K extends keyof T> = Pick<T, Diff<keyof T, K>>;





share|improve this answer

















  • 1




    I was trying to figure out by Exclude was introduced in 2.8, but it did not work to me. Good solution. Thank you for teaching me. :)
    – left click
    Apr 1 at 8:37
















4














You can do this in 2.8 using the new Exclude conditional type and the Pick mapped type



type Omit<T, K extends keyof T> = Pick<T, Exclude<keyof T, K>>; 

interface Numbers {
number: number;
number2: number;
number3: number;
}

const numbers:Omit<Numbers, 'number3'> = {
number: 1,
number2: 2
};


Before 2.8 Omit could be defined like this:



type Diff<T extends string, U extends string> = ({[P in T]: P } & {[P in U]: never } & { [x: string]: never })[T];  
type Omit<T, K extends keyof T> = Pick<T, Diff<keyof T, K>>;





share|improve this answer

















  • 1




    I was trying to figure out by Exclude was introduced in 2.8, but it did not work to me. Good solution. Thank you for teaching me. :)
    – left click
    Apr 1 at 8:37














4












4








4






You can do this in 2.8 using the new Exclude conditional type and the Pick mapped type



type Omit<T, K extends keyof T> = Pick<T, Exclude<keyof T, K>>; 

interface Numbers {
number: number;
number2: number;
number3: number;
}

const numbers:Omit<Numbers, 'number3'> = {
number: 1,
number2: 2
};


Before 2.8 Omit could be defined like this:



type Diff<T extends string, U extends string> = ({[P in T]: P } & {[P in U]: never } & { [x: string]: never })[T];  
type Omit<T, K extends keyof T> = Pick<T, Diff<keyof T, K>>;





share|improve this answer












You can do this in 2.8 using the new Exclude conditional type and the Pick mapped type



type Omit<T, K extends keyof T> = Pick<T, Exclude<keyof T, K>>; 

interface Numbers {
number: number;
number2: number;
number3: number;
}

const numbers:Omit<Numbers, 'number3'> = {
number: 1,
number2: 2
};


Before 2.8 Omit could be defined like this:



type Diff<T extends string, U extends string> = ({[P in T]: P } & {[P in U]: never } & { [x: string]: never })[T];  
type Omit<T, K extends keyof T> = Pick<T, Diff<keyof T, K>>;






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answered Apr 1 at 8:25









Titian Cernicova-Dragomir

56.2k33452




56.2k33452








  • 1




    I was trying to figure out by Exclude was introduced in 2.8, but it did not work to me. Good solution. Thank you for teaching me. :)
    – left click
    Apr 1 at 8:37














  • 1




    I was trying to figure out by Exclude was introduced in 2.8, but it did not work to me. Good solution. Thank you for teaching me. :)
    – left click
    Apr 1 at 8:37








1




1




I was trying to figure out by Exclude was introduced in 2.8, but it did not work to me. Good solution. Thank you for teaching me. :)
– left click
Apr 1 at 8:37




I was trying to figure out by Exclude was introduced in 2.8, but it did not work to me. Good solution. Thank you for teaching me. :)
– left click
Apr 1 at 8:37


















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