Resolving 'list indices must be integers or slices, not str' in Python
up vote
0
down vote
favorite
list1
one is a dict of dfs
. data1
is a lone df.
I want to create another dict of dfs(d
) based off a crosstab
which will categorize each column in each df in 'list1' on specific questions in 'data1'. This is what I've tried:
d={}
for df in list1:
for col in list1[df]:
d[df]= pd.DataFrame(pd.concat([pd.crosstab([df][col],data1['column1']),
pd.crosstab([df][col],data1['column2'])],
axis=1))
I then get 'TypeError: list indices must be integers or slices, not str'.
I appreciate that there have been many questions on this before on stackoverflow, however I have struggled to apply any of the solutions to my problem.
python pandas
add a comment |
up vote
0
down vote
favorite
list1
one is a dict of dfs
. data1
is a lone df.
I want to create another dict of dfs(d
) based off a crosstab
which will categorize each column in each df in 'list1' on specific questions in 'data1'. This is what I've tried:
d={}
for df in list1:
for col in list1[df]:
d[df]= pd.DataFrame(pd.concat([pd.crosstab([df][col],data1['column1']),
pd.crosstab([df][col],data1['column2'])],
axis=1))
I then get 'TypeError: list indices must be integers or slices, not str'.
I appreciate that there have been many questions on this before on stackoverflow, however I have struggled to apply any of the solutions to my problem.
python pandas
add a comment |
up vote
0
down vote
favorite
up vote
0
down vote
favorite
list1
one is a dict of dfs
. data1
is a lone df.
I want to create another dict of dfs(d
) based off a crosstab
which will categorize each column in each df in 'list1' on specific questions in 'data1'. This is what I've tried:
d={}
for df in list1:
for col in list1[df]:
d[df]= pd.DataFrame(pd.concat([pd.crosstab([df][col],data1['column1']),
pd.crosstab([df][col],data1['column2'])],
axis=1))
I then get 'TypeError: list indices must be integers or slices, not str'.
I appreciate that there have been many questions on this before on stackoverflow, however I have struggled to apply any of the solutions to my problem.
python pandas
list1
one is a dict of dfs
. data1
is a lone df.
I want to create another dict of dfs(d
) based off a crosstab
which will categorize each column in each df in 'list1' on specific questions in 'data1'. This is what I've tried:
d={}
for df in list1:
for col in list1[df]:
d[df]= pd.DataFrame(pd.concat([pd.crosstab([df][col],data1['column1']),
pd.crosstab([df][col],data1['column2'])],
axis=1))
I then get 'TypeError: list indices must be integers or slices, not str'.
I appreciate that there have been many questions on this before on stackoverflow, however I have struggled to apply any of the solutions to my problem.
python pandas
python pandas
edited Nov 11 at 10:12
Kanak
2,63621223
2,63621223
asked Nov 11 at 10:00
zepaft
233
233
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add a comment |
1 Answer
1
active
oldest
votes
up vote
0
down vote
df
iterates over the keys of list1
when you do for df in list1
. So it is a string. Later, when you pass [df][col]
, it creates a list of one element which is a key, from which you try to get a string column. I suppose you meant d[df]
instead.
For clarity purpose I would also suggest renaming list1
and changing the for loop in for df in <new_name>.keys()
add a comment |
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
0
down vote
df
iterates over the keys of list1
when you do for df in list1
. So it is a string. Later, when you pass [df][col]
, it creates a list of one element which is a key, from which you try to get a string column. I suppose you meant d[df]
instead.
For clarity purpose I would also suggest renaming list1
and changing the for loop in for df in <new_name>.keys()
add a comment |
up vote
0
down vote
df
iterates over the keys of list1
when you do for df in list1
. So it is a string. Later, when you pass [df][col]
, it creates a list of one element which is a key, from which you try to get a string column. I suppose you meant d[df]
instead.
For clarity purpose I would also suggest renaming list1
and changing the for loop in for df in <new_name>.keys()
add a comment |
up vote
0
down vote
up vote
0
down vote
df
iterates over the keys of list1
when you do for df in list1
. So it is a string. Later, when you pass [df][col]
, it creates a list of one element which is a key, from which you try to get a string column. I suppose you meant d[df]
instead.
For clarity purpose I would also suggest renaming list1
and changing the for loop in for df in <new_name>.keys()
df
iterates over the keys of list1
when you do for df in list1
. So it is a string. Later, when you pass [df][col]
, it creates a list of one element which is a key, from which you try to get a string column. I suppose you meant d[df]
instead.
For clarity purpose I would also suggest renaming list1
and changing the for loop in for df in <new_name>.keys()
answered Nov 11 at 10:09
Arthur Havlicek
750411
750411
add a comment |
add a comment |
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