SQL sum from single table with join
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I have two table orders and orderitems.
order table has id,order_total,recieved_amount
orderitems table has id,order_id,name,total_item
I want the sum of recieved_amount, order_total from the order table and sum of total_item from orderitems. so I used
SELECT SUM(`received_amount`) as totalRecieved,
SUM(`order_total`) as orderTotal
FROM `orders` AS `Order`
LEFT JOIN `order_items` AS `OrderItems`
ON (`OrderItems`.`order_id`=`Order`.`id`)
and
SELECT SUM(`received_amount`) as totalRecieved,
SUM(`order_total`) as orderTotal
FROM `orders` AS `Order`
LEFT JOIN `order_items` AS `OrderItems`
ON (`OrderItems`.`order_id`=`Order`.`id`)
group by order.id
but none of them is giving me the correct result.
sql
edited Nov 16 '18 at 13:35
Robert Kock
4,5281818
asked Nov 16 '18 at 13:29
Rafi AhmadRafi Ahmad
2513
add a comment |
I have two table orders and orderitems.
order table has id,order_total,recieved_amount
orderitems table has id,order_id,name,total_item
I want the sum of recieved_amount, order_total from the order table and sum of total_item from orderitems. so I used
SELECT SUM(`received_amount`) as totalRecieved,
SUM(`order_total`) as orderTotal
FROM `orders` AS `Order`
LEFT JOIN `order_items` AS `OrderItems`
ON (`OrderItems`.`order_id`=`Order`.`id`)
and
SELECT SUM(`received_amount`) as totalRecieved,
SUM(`order_total`) as orderTotal
FROM `orders` AS `Order`
LEFT JOIN `order_items` AS `OrderItems`
ON (`OrderItems`.`order_id`=`Order`.`id`)
group by order.id
but none of them is giving me the correct result.
sql
edited Nov 16 '18 at 13:35
Robert Kock
4,5281818
asked Nov 16 '18 at 13:29
Rafi AhmadRafi Ahmad
2513
add a comment |
I have two table orders and orderitems.
order table has id,order_total,recieved_amount
orderitems table has id,order_id,name,total_item
I want the sum of recieved_amount, order_total from the order table and sum of total_item from orderitems. so I used
SELECT SUM(`received_amount`) as totalRecieved,
SUM(`order_total`) as orderTotal
FROM `orders` AS `Order`
LEFT JOIN `order_items` AS `OrderItems`
ON (`OrderItems`.`order_id`=`Order`.`id`)
and
SELECT SUM(`received_amount`) as totalRecieved,
SUM(`order_total`) as orderTotal
FROM `orders` AS `Order`
LEFT JOIN `order_items` AS `OrderItems`
ON (`OrderItems`.`order_id`=`Order`.`id`)
group by order.id
but none of them is giving me the correct result.
sql
edited Nov 16 '18 at 13:35
Robert Kock
4,5281818
asked Nov 16 '18 at 13:29
Rafi AhmadRafi Ahmad
2513
I have two table orders and orderitems.
order table has id,order_total,recieved_amount
orderitems table has id,order_id,name,total_item
I want the sum of recieved_amount, order_total from the order table and sum of total_item from orderitems. so I used
SELECT SUM(`received_amount`) as totalRecieved,
SUM(`order_total`) as orderTotal
FROM `orders` AS `Order`
LEFT JOIN `order_items` AS `OrderItems`
ON (`OrderItems`.`order_id`=`Order`.`id`)
and
SELECT SUM(`received_amount`) as totalRecieved,
SUM(`order_total`) as orderTotal
FROM `orders` AS `Order`
LEFT JOIN `order_items` AS `OrderItems`
ON (`OrderItems`.`order_id`=`Order`.`id`)
group by order.id
but none of them is giving me the correct result.
sql
sql
edited Nov 16 '18 at 13:35
Robert Kock
4,5281818
asked Nov 16 '18 at 13:29
Rafi AhmadRafi Ahmad
2513
edited Nov 16 '18 at 13:35
Robert Kock
4,5281818
asked Nov 16 '18 at 13:29
Rafi AhmadRafi Ahmad
2513
edited Nov 16 '18 at 13:35
Robert Kock
4,5281818
edited Nov 16 '18 at 13:35
Robert Kock
4,5281818
edited Nov 16 '18 at 13:35
Robert Kock
4,5281818
4,5281818
asked Nov 16 '18 at 13:29
Rafi AhmadRafi Ahmad
2513
asked Nov 16 '18 at 13:29
Rafi AhmadRafi Ahmad
2513
asked Nov 16 '18 at 13:29
Rafi AhmadRafi Ahmad
2513
2513
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
You are aggregating at two levels of your data hierarchy. This causes a problem with Cartesian products, for each order.
The solution is to aggregate along order_items before doing the join:
SELECT SUM(received_amount) as totalRecieved,
SUM(order_total) as orderTotal
FROM orders o LEFT JOIN
(SELECT oi.order_id, SUM(total_items) as total_items
FROM order_items oi
GROUP BY oi.order_id
) oi
ON oi.order_id = o.id;
answered Nov 16 '18 at 13:32
Gordon LinoffGordon Linoff
794k37318422
add a comment |
As an alternative, you can benefit from cte structure or a temp table like below:
;with cte (order_id, SumTotalItems) as (
SELECT oi.order_id, SUM(total_items) as SumTotalItems
FROM order_items oi
GROUP BY oi.order_id
)
select sum(o.receivedamount) as SumReceivedAmount
, sum(o.order_total) as SumOrderTotal
, cte.SumTotalItems
from orders o
left outer join cte on o.id = cte.order_id
answered Nov 16 '18 at 14:10
Eray BalkanliEray Balkanli
4,56652347
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
You are aggregating at two levels of your data hierarchy. This causes a problem with Cartesian products, for each order.
The solution is to aggregate along order_items before doing the join:
SELECT SUM(received_amount) as totalRecieved,
SUM(order_total) as orderTotal
FROM orders o LEFT JOIN
(SELECT oi.order_id, SUM(total_items) as total_items
FROM order_items oi
GROUP BY oi.order_id
) oi
ON oi.order_id = o.id;
answered Nov 16 '18 at 13:32
Gordon LinoffGordon Linoff
794k37318422
add a comment |
You are aggregating at two levels of your data hierarchy. This causes a problem with Cartesian products, for each order.
The solution is to aggregate along order_items before doing the join:
SELECT SUM(received_amount) as totalRecieved,
SUM(order_total) as orderTotal
FROM orders o LEFT JOIN
(SELECT oi.order_id, SUM(total_items) as total_items
FROM order_items oi
GROUP BY oi.order_id
) oi
ON oi.order_id = o.id;
answered Nov 16 '18 at 13:32
Gordon LinoffGordon Linoff
794k37318422
add a comment |
You are aggregating at two levels of your data hierarchy. This causes a problem with Cartesian products, for each order.
The solution is to aggregate along order_items before doing the join:
SELECT SUM(received_amount) as totalRecieved,
SUM(order_total) as orderTotal
FROM orders o LEFT JOIN
(SELECT oi.order_id, SUM(total_items) as total_items
FROM order_items oi
GROUP BY oi.order_id
) oi
ON oi.order_id = o.id;
answered Nov 16 '18 at 13:32
Gordon LinoffGordon Linoff
794k37318422
You are aggregating at two levels of your data hierarchy. This causes a problem with Cartesian products, for each order.
The solution is to aggregate along order_items before doing the join:
SELECT SUM(received_amount) as totalRecieved,
SUM(order_total) as orderTotal
FROM orders o LEFT JOIN
(SELECT oi.order_id, SUM(total_items) as total_items
FROM order_items oi
GROUP BY oi.order_id
) oi
ON oi.order_id = o.id;
answered Nov 16 '18 at 13:32
Gordon LinoffGordon Linoff
794k37318422
answered Nov 16 '18 at 13:32
Gordon LinoffGordon Linoff
794k37318422
answered Nov 16 '18 at 13:32
Gordon LinoffGordon Linoff
794k37318422
answered Nov 16 '18 at 13:32
Gordon LinoffGordon Linoff
794k37318422
794k37318422
add a comment |
add a comment |
As an alternative, you can benefit from cte structure or a temp table like below:
;with cte (order_id, SumTotalItems) as (
SELECT oi.order_id, SUM(total_items) as SumTotalItems
FROM order_items oi
GROUP BY oi.order_id
)
select sum(o.receivedamount) as SumReceivedAmount
, sum(o.order_total) as SumOrderTotal
, cte.SumTotalItems
from orders o
left outer join cte on o.id = cte.order_id
answered Nov 16 '18 at 14:10
Eray BalkanliEray Balkanli
4,56652347
add a comment |
As an alternative, you can benefit from cte structure or a temp table like below:
;with cte (order_id, SumTotalItems) as (
SELECT oi.order_id, SUM(total_items) as SumTotalItems
FROM order_items oi
GROUP BY oi.order_id
)
select sum(o.receivedamount) as SumReceivedAmount
, sum(o.order_total) as SumOrderTotal
, cte.SumTotalItems
from orders o
left outer join cte on o.id = cte.order_id
answered Nov 16 '18 at 14:10
Eray BalkanliEray Balkanli
4,56652347
add a comment |
As an alternative, you can benefit from cte structure or a temp table like below:
;with cte (order_id, SumTotalItems) as (
SELECT oi.order_id, SUM(total_items) as SumTotalItems
FROM order_items oi
GROUP BY oi.order_id
)
select sum(o.receivedamount) as SumReceivedAmount
, sum(o.order_total) as SumOrderTotal
, cte.SumTotalItems
from orders o
left outer join cte on o.id = cte.order_id
answered Nov 16 '18 at 14:10
Eray BalkanliEray Balkanli
4,56652347
As an alternative, you can benefit from cte structure or a temp table like below:
;with cte (order_id, SumTotalItems) as (
SELECT oi.order_id, SUM(total_items) as SumTotalItems
FROM order_items oi
GROUP BY oi.order_id
)
select sum(o.receivedamount) as SumReceivedAmount
, sum(o.order_total) as SumOrderTotal
, cte.SumTotalItems
from orders o
left outer join cte on o.id = cte.order_id
answered Nov 16 '18 at 14:10
Eray BalkanliEray Balkanli
4,56652347
answered Nov 16 '18 at 14:10
Eray BalkanliEray Balkanli
4,56652347
answered Nov 16 '18 at 14:10
Eray BalkanliEray Balkanli
4,56652347
answered Nov 16 '18 at 14:10
Eray BalkanliEray Balkanli
4,56652347
4,56652347
add a comment |
add a comment |
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