R compare group to full sample
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Sample data
df <- data.frame("id"=c(1,2,3,4,5), "group"=c(0,0,1,1,1), "score"=c(10,14,15,13,12))
My goal is to compare the scores for group = 1 to the complete sample.
I figured how to do the t test:
t.test(df$score ~ df$group)
But is this for group = 1 versus group = 0?
r testing statistics t-test
asked Nov 16 '18 at 19:49
bvowebvowe
39119
add a comment |
Sample data
df <- data.frame("id"=c(1,2,3,4,5), "group"=c(0,0,1,1,1), "score"=c(10,14,15,13,12))
My goal is to compare the scores for group = 1 to the complete sample.
I figured how to do the t test:
t.test(df$score ~ df$group)
But is this for group = 1 versus group = 0?
r testing statistics t-test
asked Nov 16 '18 at 19:49
bvowebvowe
39119
yes that is group 1 vs group 0
– Mike
Nov 16 '18 at 19:57
add a comment |
Sample data
df <- data.frame("id"=c(1,2,3,4,5), "group"=c(0,0,1,1,1), "score"=c(10,14,15,13,12))
My goal is to compare the scores for group = 1 to the complete sample.
I figured how to do the t test:
t.test(df$score ~ df$group)
But is this for group = 1 versus group = 0?
r testing statistics t-test
asked Nov 16 '18 at 19:49
bvowebvowe
39119
Sample data
df <- data.frame("id"=c(1,2,3,4,5), "group"=c(0,0,1,1,1), "score"=c(10,14,15,13,12))
My goal is to compare the scores for group = 1 to the complete sample.
I figured how to do the t test:
t.test(df$score ~ df$group)
But is this for group = 1 versus group = 0?
r testing statistics t-test
r testing statistics t-test
asked Nov 16 '18 at 19:49
bvowebvowe
39119
asked Nov 16 '18 at 19:49
bvowebvowe
39119
asked Nov 16 '18 at 19:49
bvowebvowe
39119
asked Nov 16 '18 at 19:49
bvowebvowe
39119
asked Nov 16 '18 at 19:49
bvowebvowe
39119
39119
yes that is group 1 vs group 0
– Mike
Nov 16 '18 at 19:57
add a comment |
yes that is group 1 vs group 0
– Mike
Nov 16 '18 at 19:57
yes that is group 1 vs group 0
– Mike
Nov 16 '18 at 19:57
yes that is group 1 vs group 0
– Mike
Nov 16 '18 at 19:57
add a comment |
2 Answers
2
active
oldest
votes
You can subset your df to only keep one group and then in the original data make all the groups the same. Combine the two data.frames so now you have the complete sample as one group and group one still separate. Then do the t-test.
library(dplyr)
df <- data.frame("id"=c(1,2,3,4,5),
"group"=c(0,0,1,1,1),
"score"=c(10,14,15,13,12))
#make group = 2 so this is the 'complete sample'
df2 <- mutate(df, group = 2)
#keep only group 1
df1 <- filter(df, group == 1)
#put together so that you have group 1 vs complete sample
df3 <- rbind(df1,df2)
#do t-test
t.test(df3$score,df3$group)
answered Nov 16 '18 at 19:54
MikeMike
1,0411519
add a comment |
Alternately, you could just
t.test(df$score[df$group==1], df$score)
answered Nov 17 '18 at 0:47
Matt TyersMatt Tyers
1,5531516
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
You can subset your df to only keep one group and then in the original data make all the groups the same. Combine the two data.frames so now you have the complete sample as one group and group one still separate. Then do the t-test.
library(dplyr)
df <- data.frame("id"=c(1,2,3,4,5),
"group"=c(0,0,1,1,1),
"score"=c(10,14,15,13,12))
#make group = 2 so this is the 'complete sample'
df2 <- mutate(df, group = 2)
#keep only group 1
df1 <- filter(df, group == 1)
#put together so that you have group 1 vs complete sample
df3 <- rbind(df1,df2)
#do t-test
t.test(df3$score,df3$group)
answered Nov 16 '18 at 19:54
MikeMike
1,0411519
add a comment |
You can subset your df to only keep one group and then in the original data make all the groups the same. Combine the two data.frames so now you have the complete sample as one group and group one still separate. Then do the t-test.
library(dplyr)
df <- data.frame("id"=c(1,2,3,4,5),
"group"=c(0,0,1,1,1),
"score"=c(10,14,15,13,12))
#make group = 2 so this is the 'complete sample'
df2 <- mutate(df, group = 2)
#keep only group 1
df1 <- filter(df, group == 1)
#put together so that you have group 1 vs complete sample
df3 <- rbind(df1,df2)
#do t-test
t.test(df3$score,df3$group)
answered Nov 16 '18 at 19:54
MikeMike
1,0411519
add a comment |
You can subset your df to only keep one group and then in the original data make all the groups the same. Combine the two data.frames so now you have the complete sample as one group and group one still separate. Then do the t-test.
library(dplyr)
df <- data.frame("id"=c(1,2,3,4,5),
"group"=c(0,0,1,1,1),
"score"=c(10,14,15,13,12))
#make group = 2 so this is the 'complete sample'
df2 <- mutate(df, group = 2)
#keep only group 1
df1 <- filter(df, group == 1)
#put together so that you have group 1 vs complete sample
df3 <- rbind(df1,df2)
#do t-test
t.test(df3$score,df3$group)
answered Nov 16 '18 at 19:54
MikeMike
1,0411519
You can subset your df to only keep one group and then in the original data make all the groups the same. Combine the two data.frames so now you have the complete sample as one group and group one still separate. Then do the t-test.
library(dplyr)
df <- data.frame("id"=c(1,2,3,4,5),
"group"=c(0,0,1,1,1),
"score"=c(10,14,15,13,12))
#make group = 2 so this is the 'complete sample'
df2 <- mutate(df, group = 2)
#keep only group 1
df1 <- filter(df, group == 1)
#put together so that you have group 1 vs complete sample
df3 <- rbind(df1,df2)
#do t-test
t.test(df3$score,df3$group)
answered Nov 16 '18 at 19:54
MikeMike
1,0411519
answered Nov 16 '18 at 19:54
MikeMike
1,0411519
answered Nov 16 '18 at 19:54
MikeMike
1,0411519
answered Nov 16 '18 at 19:54
MikeMike
1,0411519
1,0411519
add a comment |
add a comment |
Alternately, you could just
t.test(df$score[df$group==1], df$score)
answered Nov 17 '18 at 0:47
Matt TyersMatt Tyers
1,5531516
add a comment |
Alternately, you could just
t.test(df$score[df$group==1], df$score)
answered Nov 17 '18 at 0:47
Matt TyersMatt Tyers
1,5531516
add a comment |
Alternately, you could just
t.test(df$score[df$group==1], df$score)
answered Nov 17 '18 at 0:47
Matt TyersMatt Tyers
1,5531516
Alternately, you could just
t.test(df$score[df$group==1], df$score)
answered Nov 17 '18 at 0:47
Matt TyersMatt Tyers
1,5531516
answered Nov 17 '18 at 0:47
Matt TyersMatt Tyers
1,5531516
answered Nov 17 '18 at 0:47
Matt TyersMatt Tyers
1,5531516
answered Nov 17 '18 at 0:47
Matt TyersMatt Tyers
1,5531516
1,5531516
add a comment |
add a comment |
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yes that is group 1 vs group 0
– Mike
Nov 16 '18 at 19:57