Dynamic proxy for suspend methods?





.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty{ height:90px;width:728px;box-sizing:border-box;
}







1















This is my interface:



interface BlogService {
suspend fun tag() : JsonObject
}


Is it possible to create a dynamic proxy for the suspend method and run coroutine inside?
I can't use "Proxy.newProxyInstance" from jdk because I get a compilation error (suspend function should be run from another suspend function)










share|improve this question





























    1















    This is my interface:



    interface BlogService {
    suspend fun tag() : JsonObject
    }


    Is it possible to create a dynamic proxy for the suspend method and run coroutine inside?
    I can't use "Proxy.newProxyInstance" from jdk because I get a compilation error (suspend function should be run from another suspend function)










    share|improve this question

























      1












      1








      1








      This is my interface:



      interface BlogService {
      suspend fun tag() : JsonObject
      }


      Is it possible to create a dynamic proxy for the suspend method and run coroutine inside?
      I can't use "Proxy.newProxyInstance" from jdk because I get a compilation error (suspend function should be run from another suspend function)










      share|improve this question














      This is my interface:



      interface BlogService {
      suspend fun tag() : JsonObject
      }


      Is it possible to create a dynamic proxy for the suspend method and run coroutine inside?
      I can't use "Proxy.newProxyInstance" from jdk because I get a compilation error (suspend function should be run from another suspend function)







      kotlin






      share|improve this question













      share|improve this question











      share|improve this question




      share|improve this question










      asked Nov 16 '18 at 19:48









      mystdeimmystdeim

      1,53652853




      1,53652853
























          1 Answer
          1






          active

          oldest

          votes


















          1














          I had the same problem. And I think the answer is Yes. Here's what I figured out.



          The following interface



          interface IService {
          suspend fun hello(arg: String): Int
          }


          is compiled into this



          interface IService {
          fun hello(var1: String, var2: Continuation<Int>) : Any
          }


          after compilation, there's no difference between a normal function and a suspend
          function, except that the latter one has an additional argument of type
          Continuation. Just return COROUTINE_SUSPENDED in the delegated
          InvocationHandler.invoke if you actually want it supended.



          Here's an example of creating an ISerivce instance via the java dynamic proxy
          facility Proxy.newProxyInstance



          import java.lang.reflect.InvocationHandler
          import java.lang.reflect.Proxy
          import kotlin.coroutines.Continuation
          import kotlin.coroutines.intrinsics.COROUTINE_SUSPENDED
          import kotlin.coroutines.resume

          fun getServiceDynamic(): IService {
          val proxy = InvocationHandler { _, method, args ->
          val lastArg = args?.lastOrNull()
          if (lastArg is Continuation<*>) {
          val cont = lastArg as Continuation<Int>
          val argsButLast = args.take(args.size - 1)
          doSomethingWith(method, argsButLast, onComplete = { result: Int ->
          cont.resume(result)
          })
          COROUTINE_SUSPENDED
          } else {
          0
          }
          }
          return Proxy.newProxyInstance(
          proxy.javaClass.classLoader,
          arrayOf(IService::class.java),
          proxy
          ) as IService
          }


          I believe this code snippet is simple enough and self-explaining.






          share|improve this answer
























            Your Answer






            StackExchange.ifUsing("editor", function () {
            StackExchange.using("externalEditor", function () {
            StackExchange.using("snippets", function () {
            StackExchange.snippets.init();
            });
            });
            }, "code-snippets");

            StackExchange.ready(function() {
            var channelOptions = {
            tags: "".split(" "),
            id: "1"
            };
            initTagRenderer("".split(" "), "".split(" "), channelOptions);

            StackExchange.using("externalEditor", function() {
            // Have to fire editor after snippets, if snippets enabled
            if (StackExchange.settings.snippets.snippetsEnabled) {
            StackExchange.using("snippets", function() {
            createEditor();
            });
            }
            else {
            createEditor();
            }
            });

            function createEditor() {
            StackExchange.prepareEditor({
            heartbeatType: 'answer',
            autoActivateHeartbeat: false,
            convertImagesToLinks: true,
            noModals: true,
            showLowRepImageUploadWarning: true,
            reputationToPostImages: 10,
            bindNavPrevention: true,
            postfix: "",
            imageUploader: {
            brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
            contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
            allowUrls: true
            },
            onDemand: true,
            discardSelector: ".discard-answer"
            ,immediatelyShowMarkdownHelp:true
            });


            }
            });














            draft saved

            draft discarded


















            StackExchange.ready(
            function () {
            StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53344451%2fdynamic-proxy-for-suspend-methods%23new-answer', 'question_page');
            }
            );

            Post as a guest















            Required, but never shown

























            1 Answer
            1






            active

            oldest

            votes








            1 Answer
            1






            active

            oldest

            votes









            active

            oldest

            votes






            active

            oldest

            votes









            1














            I had the same problem. And I think the answer is Yes. Here's what I figured out.



            The following interface



            interface IService {
            suspend fun hello(arg: String): Int
            }


            is compiled into this



            interface IService {
            fun hello(var1: String, var2: Continuation<Int>) : Any
            }


            after compilation, there's no difference between a normal function and a suspend
            function, except that the latter one has an additional argument of type
            Continuation. Just return COROUTINE_SUSPENDED in the delegated
            InvocationHandler.invoke if you actually want it supended.



            Here's an example of creating an ISerivce instance via the java dynamic proxy
            facility Proxy.newProxyInstance



            import java.lang.reflect.InvocationHandler
            import java.lang.reflect.Proxy
            import kotlin.coroutines.Continuation
            import kotlin.coroutines.intrinsics.COROUTINE_SUSPENDED
            import kotlin.coroutines.resume

            fun getServiceDynamic(): IService {
            val proxy = InvocationHandler { _, method, args ->
            val lastArg = args?.lastOrNull()
            if (lastArg is Continuation<*>) {
            val cont = lastArg as Continuation<Int>
            val argsButLast = args.take(args.size - 1)
            doSomethingWith(method, argsButLast, onComplete = { result: Int ->
            cont.resume(result)
            })
            COROUTINE_SUSPENDED
            } else {
            0
            }
            }
            return Proxy.newProxyInstance(
            proxy.javaClass.classLoader,
            arrayOf(IService::class.java),
            proxy
            ) as IService
            }


            I believe this code snippet is simple enough and self-explaining.






            share|improve this answer




























              1














              I had the same problem. And I think the answer is Yes. Here's what I figured out.



              The following interface



              interface IService {
              suspend fun hello(arg: String): Int
              }


              is compiled into this



              interface IService {
              fun hello(var1: String, var2: Continuation<Int>) : Any
              }


              after compilation, there's no difference between a normal function and a suspend
              function, except that the latter one has an additional argument of type
              Continuation. Just return COROUTINE_SUSPENDED in the delegated
              InvocationHandler.invoke if you actually want it supended.



              Here's an example of creating an ISerivce instance via the java dynamic proxy
              facility Proxy.newProxyInstance



              import java.lang.reflect.InvocationHandler
              import java.lang.reflect.Proxy
              import kotlin.coroutines.Continuation
              import kotlin.coroutines.intrinsics.COROUTINE_SUSPENDED
              import kotlin.coroutines.resume

              fun getServiceDynamic(): IService {
              val proxy = InvocationHandler { _, method, args ->
              val lastArg = args?.lastOrNull()
              if (lastArg is Continuation<*>) {
              val cont = lastArg as Continuation<Int>
              val argsButLast = args.take(args.size - 1)
              doSomethingWith(method, argsButLast, onComplete = { result: Int ->
              cont.resume(result)
              })
              COROUTINE_SUSPENDED
              } else {
              0
              }
              }
              return Proxy.newProxyInstance(
              proxy.javaClass.classLoader,
              arrayOf(IService::class.java),
              proxy
              ) as IService
              }


              I believe this code snippet is simple enough and self-explaining.






              share|improve this answer


























                1












                1








                1







                I had the same problem. And I think the answer is Yes. Here's what I figured out.



                The following interface



                interface IService {
                suspend fun hello(arg: String): Int
                }


                is compiled into this



                interface IService {
                fun hello(var1: String, var2: Continuation<Int>) : Any
                }


                after compilation, there's no difference between a normal function and a suspend
                function, except that the latter one has an additional argument of type
                Continuation. Just return COROUTINE_SUSPENDED in the delegated
                InvocationHandler.invoke if you actually want it supended.



                Here's an example of creating an ISerivce instance via the java dynamic proxy
                facility Proxy.newProxyInstance



                import java.lang.reflect.InvocationHandler
                import java.lang.reflect.Proxy
                import kotlin.coroutines.Continuation
                import kotlin.coroutines.intrinsics.COROUTINE_SUSPENDED
                import kotlin.coroutines.resume

                fun getServiceDynamic(): IService {
                val proxy = InvocationHandler { _, method, args ->
                val lastArg = args?.lastOrNull()
                if (lastArg is Continuation<*>) {
                val cont = lastArg as Continuation<Int>
                val argsButLast = args.take(args.size - 1)
                doSomethingWith(method, argsButLast, onComplete = { result: Int ->
                cont.resume(result)
                })
                COROUTINE_SUSPENDED
                } else {
                0
                }
                }
                return Proxy.newProxyInstance(
                proxy.javaClass.classLoader,
                arrayOf(IService::class.java),
                proxy
                ) as IService
                }


                I believe this code snippet is simple enough and self-explaining.






                share|improve this answer













                I had the same problem. And I think the answer is Yes. Here's what I figured out.



                The following interface



                interface IService {
                suspend fun hello(arg: String): Int
                }


                is compiled into this



                interface IService {
                fun hello(var1: String, var2: Continuation<Int>) : Any
                }


                after compilation, there's no difference between a normal function and a suspend
                function, except that the latter one has an additional argument of type
                Continuation. Just return COROUTINE_SUSPENDED in the delegated
                InvocationHandler.invoke if you actually want it supended.



                Here's an example of creating an ISerivce instance via the java dynamic proxy
                facility Proxy.newProxyInstance



                import java.lang.reflect.InvocationHandler
                import java.lang.reflect.Proxy
                import kotlin.coroutines.Continuation
                import kotlin.coroutines.intrinsics.COROUTINE_SUSPENDED
                import kotlin.coroutines.resume

                fun getServiceDynamic(): IService {
                val proxy = InvocationHandler { _, method, args ->
                val lastArg = args?.lastOrNull()
                if (lastArg is Continuation<*>) {
                val cont = lastArg as Continuation<Int>
                val argsButLast = args.take(args.size - 1)
                doSomethingWith(method, argsButLast, onComplete = { result: Int ->
                cont.resume(result)
                })
                COROUTINE_SUSPENDED
                } else {
                0
                }
                }
                return Proxy.newProxyInstance(
                proxy.javaClass.classLoader,
                arrayOf(IService::class.java),
                proxy
                ) as IService
                }


                I believe this code snippet is simple enough and self-explaining.







                share|improve this answer












                share|improve this answer



                share|improve this answer










                answered Jan 3 at 12:28









                Jinxin ZhengJinxin Zheng

                112




                112
































                    draft saved

                    draft discarded




















































                    Thanks for contributing an answer to Stack Overflow!


                    • Please be sure to answer the question. Provide details and share your research!

                    But avoid



                    • Asking for help, clarification, or responding to other answers.

                    • Making statements based on opinion; back them up with references or personal experience.


                    To learn more, see our tips on writing great answers.




                    draft saved


                    draft discarded














                    StackExchange.ready(
                    function () {
                    StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53344451%2fdynamic-proxy-for-suspend-methods%23new-answer', 'question_page');
                    }
                    );

                    Post as a guest















                    Required, but never shown





















































                    Required, but never shown














                    Required, but never shown












                    Required, but never shown







                    Required, but never shown

































                    Required, but never shown














                    Required, but never shown












                    Required, but never shown







                    Required, but never shown







                    Popular posts from this blog

                    Xamarin.iOS Cant Deploy on Iphone

                    Glorious Revolution

                    Dulmage-Mendelsohn matrix decomposition in Python