Replacing a word begin with @ in php
I want to replace any word that starts with @ to another word.
Input is My value is @truth_word and bad
$myword = "My value is @truth_word and bad";
$newtext = preg_replace("/^@/", "good" , $myword);
echo $newtext; //My value is good and bad;
The output should be My value is good and bad
php preg-replace
asked Nov 16 '18 at 0:14
user4826347user4826347
3571322
add a comment |
I want to replace any word that starts with @ to another word.
Input is My value is @truth_word and bad
$myword = "My value is @truth_word and bad";
$newtext = preg_replace("/^@/", "good" , $myword);
echo $newtext; //My value is good and bad;
The output should be My value is good and bad
php preg-replace
asked Nov 16 '18 at 0:14
user4826347user4826347
3571322
add a comment |
I want to replace any word that starts with @ to another word.
Input is My value is @truth_word and bad
$myword = "My value is @truth_word and bad";
$newtext = preg_replace("/^@/", "good" , $myword);
echo $newtext; //My value is good and bad;
The output should be My value is good and bad
php preg-replace
asked Nov 16 '18 at 0:14
user4826347user4826347
3571322
I want to replace any word that starts with @ to another word.
Input is My value is @truth_word and bad
$myword = "My value is @truth_word and bad";
$newtext = preg_replace("/^@/", "good" , $myword);
echo $newtext; //My value is good and bad;
The output should be My value is good and bad
php preg-replace
php preg-replace
asked Nov 16 '18 at 0:14
user4826347user4826347
3571322
asked Nov 16 '18 at 0:14
user4826347user4826347
3571322
asked Nov 16 '18 at 0:14
user4826347user4826347
3571322
asked Nov 16 '18 at 0:14
user4826347user4826347
3571322
asked Nov 16 '18 at 0:14
user4826347user4826347
3571322
3571322
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
You need to use a positive lookbehind for either the beginning of the string (^) or a white-space character (s) before the @, then some number of word characters (w) after it:
$myword = "My value is @truth_word and bad";
$newtext = preg_replace("/(?<=^|s)@w+/", "good" , $myword);
echo $newtext;
Output
My value is good and bad
Demo on 3v4l.org
answered Nov 16 '18 at 0:28
NickNick
36k132243
Did this answer your question? If not, could you provide more information to help answer it? Otherwise, please consider marking the answer accepted. See stackoverflow.com/help/someone-answers
– Nick
Nov 17 '18 at 2:14
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
You need to use a positive lookbehind for either the beginning of the string (^) or a white-space character (s) before the @, then some number of word characters (w) after it:
$myword = "My value is @truth_word and bad";
$newtext = preg_replace("/(?<=^|s)@w+/", "good" , $myword);
echo $newtext;
Output
My value is good and bad
Demo on 3v4l.org
answered Nov 16 '18 at 0:28
NickNick
36k132243
Did this answer your question? If not, could you provide more information to help answer it? Otherwise, please consider marking the answer accepted. See stackoverflow.com/help/someone-answers
– Nick
Nov 17 '18 at 2:14
add a comment |
You need to use a positive lookbehind for either the beginning of the string (^) or a white-space character (s) before the @, then some number of word characters (w) after it:
$myword = "My value is @truth_word and bad";
$newtext = preg_replace("/(?<=^|s)@w+/", "good" , $myword);
echo $newtext;
Output
My value is good and bad
Demo on 3v4l.org
answered Nov 16 '18 at 0:28
NickNick
36k132243
Did this answer your question? If not, could you provide more information to help answer it? Otherwise, please consider marking the answer accepted. See stackoverflow.com/help/someone-answers
– Nick
Nov 17 '18 at 2:14
add a comment |
You need to use a positive lookbehind for either the beginning of the string (^) or a white-space character (s) before the @, then some number of word characters (w) after it:
$myword = "My value is @truth_word and bad";
$newtext = preg_replace("/(?<=^|s)@w+/", "good" , $myword);
echo $newtext;
Output
My value is good and bad
Demo on 3v4l.org
answered Nov 16 '18 at 0:28
NickNick
36k132243
You need to use a positive lookbehind for either the beginning of the string (^) or a white-space character (s) before the @, then some number of word characters (w) after it:
$myword = "My value is @truth_word and bad";
$newtext = preg_replace("/(?<=^|s)@w+/", "good" , $myword);
echo $newtext;
Output
My value is good and bad
Demo on 3v4l.org
answered Nov 16 '18 at 0:28
NickNick
36k132243
edited Nov 16 '18 at 8:38
answered Nov 16 '18 at 0:28
NickNick
36k132243
answered Nov 16 '18 at 0:28
NickNick
36k132243
answered Nov 16 '18 at 0:28
NickNick
36k132243
36k132243
Did this answer your question? If not, could you provide more information to help answer it? Otherwise, please consider marking the answer accepted. See stackoverflow.com/help/someone-answers
– Nick
Nov 17 '18 at 2:14
add a comment |
Did this answer your question? If not, could you provide more information to help answer it? Otherwise, please consider marking the answer accepted. See stackoverflow.com/help/someone-answers
– Nick
Nov 17 '18 at 2:14
Did this answer your question? If not, could you provide more information to help answer it? Otherwise, please consider marking the answer accepted. See stackoverflow.com/help/someone-answers
– Nick
Nov 17 '18 at 2:14
Did this answer your question? If not, could you provide more information to help answer it? Otherwise, please consider marking the answer accepted. See stackoverflow.com/help/someone-answers
– Nick
Nov 17 '18 at 2:14
add a comment |
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