Loop for variable names in R
0
I'm trying to do a loop in the following way:
for(i in 1:38){
brdf$g[[i]]<-ifelse(brdf$C[[i]]==4,brdf$P[[i]],0)
brdf$g[[i]]<-max(brdf$g_[[i]])
}
In the data frame brdf, I already have C1, C2...,C38 and P1, P2...,P38. Now I want to create variables g1, g2,...g38 so that g1=P1 if C1==4, g2=P2 if C2==4 ,...g38=P38 if C38==4.
When i try to run the code above the error is:
Error in g_[i] <- ifelse(brdf$C[i] == 4, brdf$P[i], 0) :
replacement has length zero
What is the problem?
r loops for-loop
asked Nov 16 '18 at 0:42
arabeloarabelo
255
|
show 1 more comment
0
I'm trying to do a loop in the following way:
for(i in 1:38){
brdf$g[[i]]<-ifelse(brdf$C[[i]]==4,brdf$P[[i]],0)
brdf$g[[i]]<-max(brdf$g_[[i]])
}
In the data frame brdf, I already have C1, C2...,C38 and P1, P2...,P38. Now I want to create variables g1, g2,...g38 so that g1=P1 if C1==4, g2=P2 if C2==4 ,...g38=P38 if C38==4.
When i try to run the code above the error is:
Error in g_[i] <- ifelse(brdf$C[i] == 4, brdf$P[i], 0) :
replacement has length zero
What is the problem?
r loops for-loop
asked Nov 16 '18 at 0:42
arabeloarabelo
255
Creating variables iteratively is usually unadvised (cluttering of the environment / potential instability?). Perhaps you meant to append values to an existing vector? You can do so via:g <- c(g, new_value). If you're dealing with a lot of data, pre-allocating the vector before the for loop might be beneficial.
– 12b345b6b78
Nov 16 '18 at 0:45
1
Replace your single square brackets by double brackets
– prosoitos
Nov 16 '18 at 0:47
Solve the error, but the variables were not created in the data frame
– arabelo
Nov 16 '18 at 0:57
it only apperas g_ in data, with values of "logic()". Is there a better way that can i loop this?
– arabelo
Nov 16 '18 at 1:38
Can you post an example of your data? Just a toy example would suffice, with what's expected.
– RLave
Nov 16 '18 at 8:25
|
show 1 more comment
0
0
0
I'm trying to do a loop in the following way:
for(i in 1:38){
brdf$g[[i]]<-ifelse(brdf$C[[i]]==4,brdf$P[[i]],0)
brdf$g[[i]]<-max(brdf$g_[[i]])
}
In the data frame brdf, I already have C1, C2...,C38 and P1, P2...,P38. Now I want to create variables g1, g2,...g38 so that g1=P1 if C1==4, g2=P2 if C2==4 ,...g38=P38 if C38==4.
When i try to run the code above the error is:
Error in g_[i] <- ifelse(brdf$C[i] == 4, brdf$P[i], 0) :
replacement has length zero
What is the problem?
r loops for-loop
asked Nov 16 '18 at 0:42
arabeloarabelo
255
I'm trying to do a loop in the following way:
for(i in 1:38){
brdf$g[[i]]<-ifelse(brdf$C[[i]]==4,brdf$P[[i]],0)
brdf$g[[i]]<-max(brdf$g_[[i]])
}
In the data frame brdf, I already have C1, C2...,C38 and P1, P2...,P38. Now I want to create variables g1, g2,...g38 so that g1=P1 if C1==4, g2=P2 if C2==4 ,...g38=P38 if C38==4.
When i try to run the code above the error is:
Error in g_[i] <- ifelse(brdf$C[i] == 4, brdf$P[i], 0) :
replacement has length zero
What is the problem?
r loops for-loop
r loops for-loop
asked Nov 16 '18 at 0:42
arabeloarabelo
255
asked Nov 16 '18 at 0:42
arabeloarabelo
255
edited Nov 16 '18 at 0:50
arabelo
asked Nov 16 '18 at 0:42
arabeloarabelo
255
asked Nov 16 '18 at 0:42
arabeloarabelo
255
asked Nov 16 '18 at 0:42
arabeloarabelo
255
255
Creating variables iteratively is usually unadvised (cluttering of the environment / potential instability?). Perhaps you meant to append values to an existing vector? You can do so via:g <- c(g, new_value). If you're dealing with a lot of data, pre-allocating the vector before the for loop might be beneficial.
– 12b345b6b78
Nov 16 '18 at 0:45
1
Replace your single square brackets by double brackets
– prosoitos
Nov 16 '18 at 0:47
Solve the error, but the variables were not created in the data frame
– arabelo
Nov 16 '18 at 0:57
it only apperas g_ in data, with values of "logic()". Is there a better way that can i loop this?
– arabelo
Nov 16 '18 at 1:38
Can you post an example of your data? Just a toy example would suffice, with what's expected.
– RLave
Nov 16 '18 at 8:25
|
show 1 more comment
Creating variables iteratively is usually unadvised (cluttering of the environment / potential instability?). Perhaps you meant to append values to an existing vector? You can do so via:g <- c(g, new_value). If you're dealing with a lot of data, pre-allocating the vector before the for loop might be beneficial.
– 12b345b6b78
Nov 16 '18 at 0:45
1
Replace your single square brackets by double brackets
– prosoitos
Nov 16 '18 at 0:47
Solve the error, but the variables were not created in the data frame
– arabelo
Nov 16 '18 at 0:57
it only apperas g_ in data, with values of "logic()". Is there a better way that can i loop this?
– arabelo
Nov 16 '18 at 1:38
Can you post an example of your data? Just a toy example would suffice, with what's expected.
– RLave
Nov 16 '18 at 8:25
Creating variables iteratively is usually unadvised (cluttering of the environment / potential instability?). Perhaps you meant to append values to an existing vector? You can do so via:
g <- c(g, new_value). If you're dealing with a lot of data, pre-allocating the vector before the for loop might be beneficial.– 12b345b6b78
Nov 16 '18 at 0:45
Creating variables iteratively is usually unadvised (cluttering of the environment / potential instability?). Perhaps you meant to append values to an existing vector? You can do so via:
g <- c(g, new_value). If you're dealing with a lot of data, pre-allocating the vector before the for loop might be beneficial.– 12b345b6b78
Nov 16 '18 at 0:45
1
1
Replace your single square brackets by double brackets
– prosoitos
Nov 16 '18 at 0:47
Replace your single square brackets by double brackets
– prosoitos
Nov 16 '18 at 0:47
Solve the error, but the variables were not created in the data frame
– arabelo
Nov 16 '18 at 0:57
Solve the error, but the variables were not created in the data frame
– arabelo
Nov 16 '18 at 0:57
it only apperas g_ in data, with values of "logic()". Is there a better way that can i loop this?
– arabelo
Nov 16 '18 at 1:38
it only apperas g_ in data, with values of "logic()". Is there a better way that can i loop this?
– arabelo
Nov 16 '18 at 1:38
Can you post an example of your data? Just a toy example would suffice, with what's expected.
– RLave
Nov 16 '18 at 8:25
Can you post an example of your data? Just a toy example would suffice, with what's expected.
– RLave
Nov 16 '18 at 8:25
|
show 1 more comment
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Creating variables iteratively is usually unadvised (cluttering of the environment / potential instability?). Perhaps you meant to append values to an existing vector? You can do so via:
g <- c(g, new_value). If you're dealing with a lot of data, pre-allocating the vector before the for loop might be beneficial.– 12b345b6b78
Nov 16 '18 at 0:45
1
Replace your single square brackets by double brackets
– prosoitos
Nov 16 '18 at 0:47
Solve the error, but the variables were not created in the data frame
– arabelo
Nov 16 '18 at 0:57
it only apperas g_ in data, with values of "logic()". Is there a better way that can i loop this?
– arabelo
Nov 16 '18 at 1:38
Can you post an example of your data? Just a toy example would suffice, with what's expected.
– RLave
Nov 16 '18 at 8:25