mysqli: merge rows in 1 based on some parameters












1















i have a mysql table and there i have same text but in different language



ID, Lang, Text, number, chapter

1, English, Hello, 2, 1

4, German, Hallo, 2, 1

5, Spanish, Hola, 2, 1


so how can see those like this



Select * from table where chapter=1  (and language: english,german,spanish)

ID, lang1, lang2, lang3, number, chapter

5, Hello, Hallo, Hola, 2, 1


i want to join columns in 1 row










share|improve this question




















  • 1





    Possible duplicate of MySQL pivot table

    – Madhur Bhaiya
    Nov 14 '18 at 11:05











  • Consider handling data display related requirements in your application code (eg: PHP, C++. Java etc)

    – Madhur Bhaiya
    Nov 14 '18 at 11:05






  • 2





    If you don't mind to get one lang column with a comma separted string you can also consider GROUP_CONCAT (dev.mysql.com/doc/refman/8.0/en/…) instead.. Besides it's more eazy because the pivot query needs to be created dynamic to support more columns.

    – Raymond Nijland
    Nov 14 '18 at 11:12













  • @MadhurBhaiya PHP

    – Gloytos htyqo
    Nov 14 '18 at 11:33
















1















i have a mysql table and there i have same text but in different language



ID, Lang, Text, number, chapter

1, English, Hello, 2, 1

4, German, Hallo, 2, 1

5, Spanish, Hola, 2, 1


so how can see those like this



Select * from table where chapter=1  (and language: english,german,spanish)

ID, lang1, lang2, lang3, number, chapter

5, Hello, Hallo, Hola, 2, 1


i want to join columns in 1 row










share|improve this question




















  • 1





    Possible duplicate of MySQL pivot table

    – Madhur Bhaiya
    Nov 14 '18 at 11:05











  • Consider handling data display related requirements in your application code (eg: PHP, C++. Java etc)

    – Madhur Bhaiya
    Nov 14 '18 at 11:05






  • 2





    If you don't mind to get one lang column with a comma separted string you can also consider GROUP_CONCAT (dev.mysql.com/doc/refman/8.0/en/…) instead.. Besides it's more eazy because the pivot query needs to be created dynamic to support more columns.

    – Raymond Nijland
    Nov 14 '18 at 11:12













  • @MadhurBhaiya PHP

    – Gloytos htyqo
    Nov 14 '18 at 11:33














1












1








1








i have a mysql table and there i have same text but in different language



ID, Lang, Text, number, chapter

1, English, Hello, 2, 1

4, German, Hallo, 2, 1

5, Spanish, Hola, 2, 1


so how can see those like this



Select * from table where chapter=1  (and language: english,german,spanish)

ID, lang1, lang2, lang3, number, chapter

5, Hello, Hallo, Hola, 2, 1


i want to join columns in 1 row










share|improve this question
















i have a mysql table and there i have same text but in different language



ID, Lang, Text, number, chapter

1, English, Hello, 2, 1

4, German, Hallo, 2, 1

5, Spanish, Hola, 2, 1


so how can see those like this



Select * from table where chapter=1  (and language: english,german,spanish)

ID, lang1, lang2, lang3, number, chapter

5, Hello, Hallo, Hola, 2, 1


i want to join columns in 1 row







mysql sql






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 14 '18 at 12:28









D-Shih

25.8k61531




25.8k61531










asked Nov 14 '18 at 11:04









Gloytos htyqoGloytos htyqo

708




708








  • 1





    Possible duplicate of MySQL pivot table

    – Madhur Bhaiya
    Nov 14 '18 at 11:05











  • Consider handling data display related requirements in your application code (eg: PHP, C++. Java etc)

    – Madhur Bhaiya
    Nov 14 '18 at 11:05






  • 2





    If you don't mind to get one lang column with a comma separted string you can also consider GROUP_CONCAT (dev.mysql.com/doc/refman/8.0/en/…) instead.. Besides it's more eazy because the pivot query needs to be created dynamic to support more columns.

    – Raymond Nijland
    Nov 14 '18 at 11:12













  • @MadhurBhaiya PHP

    – Gloytos htyqo
    Nov 14 '18 at 11:33














  • 1





    Possible duplicate of MySQL pivot table

    – Madhur Bhaiya
    Nov 14 '18 at 11:05











  • Consider handling data display related requirements in your application code (eg: PHP, C++. Java etc)

    – Madhur Bhaiya
    Nov 14 '18 at 11:05






  • 2





    If you don't mind to get one lang column with a comma separted string you can also consider GROUP_CONCAT (dev.mysql.com/doc/refman/8.0/en/…) instead.. Besides it's more eazy because the pivot query needs to be created dynamic to support more columns.

    – Raymond Nijland
    Nov 14 '18 at 11:12













  • @MadhurBhaiya PHP

    – Gloytos htyqo
    Nov 14 '18 at 11:33








1




1





Possible duplicate of MySQL pivot table

– Madhur Bhaiya
Nov 14 '18 at 11:05





Possible duplicate of MySQL pivot table

– Madhur Bhaiya
Nov 14 '18 at 11:05













Consider handling data display related requirements in your application code (eg: PHP, C++. Java etc)

– Madhur Bhaiya
Nov 14 '18 at 11:05





Consider handling data display related requirements in your application code (eg: PHP, C++. Java etc)

– Madhur Bhaiya
Nov 14 '18 at 11:05




2




2





If you don't mind to get one lang column with a comma separted string you can also consider GROUP_CONCAT (dev.mysql.com/doc/refman/8.0/en/…) instead.. Besides it's more eazy because the pivot query needs to be created dynamic to support more columns.

– Raymond Nijland
Nov 14 '18 at 11:12







If you don't mind to get one lang column with a comma separted string you can also consider GROUP_CONCAT (dev.mysql.com/doc/refman/8.0/en/…) instead.. Besides it's more eazy because the pivot query needs to be created dynamic to support more columns.

– Raymond Nijland
Nov 14 '18 at 11:12















@MadhurBhaiya PHP

– Gloytos htyqo
Nov 14 '18 at 11:33





@MadhurBhaiya PHP

– Gloytos htyqo
Nov 14 '18 at 11:33












3 Answers
3






active

oldest

votes


















1














You can try to use condition aggregate function to make it.



Schema (MySQL v5.7)



CREATE TABLE T(
ID int,
Lang varchar(50),
Text varchar(50),
number int,
chapter int
);



INSERT INTO T VALUES (1, 'English', 'Hello', 2, 1);
INSERT INTO T VALUES (4, 'German', 'Hallo', 2, 1);
INSERT INTO T VALUES (5, 'Spanish', 'Hola', 2, 1);




Query #1



SELECT MAX(ID) id,
MAX(CASE WHEN Lang ='English' THEN Text END) lang1,
MAX(CASE WHEN Lang ='German' THEN Text END) lang2,
MAX(CASE WHEN Lang ='Spanish' THEN Text END) lang3,
number,
chapter
FROM T
GROUP BY number, chapter;

| id | lang1 | lang2 | lang3 | number | chapter |
| --- | ----- | ----- | ----- | ------ | ------- |
| 5 | Hello | Hallo | Hola | 2 | 1 |




View on DB Fiddle






share|improve this answer































    2














    Create table test :



     CREATE TABLE test (
    id INT(6) UNSIGNED AUTO_INCREMENT PRIMARY KEY,
    Lang VARCHAR(30) NOT NULL,
    Text VARCHAR(30) NOT NULL,
    number VARCHAR(50),
    chapter INT(10))


    Insert records:



    insert into test values(1,'English','Hello','2',1);
    insert into test values(4,'German','Hallo','2',1);
    insert into test values(5,'Spanish','Hola','2',1);


    +----+---------+-------+--------+---------+
    | id | Lang | Text | number | chapter |
    +----+---------+-------+--------+---------+
    | 1 | English | Hello | 2 | 1 |
    | 4 | German | Hallo | 2 | 1 |
    | 5 | Spanish | Hola | 2 | 1 |
    +----+---------+-------+--------+---------+



    SELECT MAX(id) id, MAX(CASE WHEN Lang ='English' THEN Text END) lang1,
    MAX(CASE WHEN Lang ='German' THEN Text END) lang2,
    MAX(CASE WHEN Lang ='Spanish' THEN Text END) lang3, number, chapter
    FROM test GROUP BY number, chapter;

    +------+-------+-------+-------+--------+---------+
    | id | lang1 | lang2 | lang3 | number | chapter |
    +------+-------+-------+-------+--------+---------+
    | 5 | Hello | Hallo | Hola | 2 | 1 |
    +------+-------+-------+-------+--------+---------+





    share|improve this answer

































      1














      SELECT * FROM
      (SELECT LangAS t1, vargu FROM table LANG=114 AND chapter=1) as A,
      (SELECT LangAS t2 FROM table WHERE LANG=115 AND chapter=1) AS B,
      (SELECT LangAS t3 FROM table WHERE LANG=116 AND chapter=1) AS C;





      share|improve this answer























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        3 Answers
        3






        active

        oldest

        votes








        3 Answers
        3






        active

        oldest

        votes









        active

        oldest

        votes






        active

        oldest

        votes









        1














        You can try to use condition aggregate function to make it.



        Schema (MySQL v5.7)



        CREATE TABLE T(
        ID int,
        Lang varchar(50),
        Text varchar(50),
        number int,
        chapter int
        );



        INSERT INTO T VALUES (1, 'English', 'Hello', 2, 1);
        INSERT INTO T VALUES (4, 'German', 'Hallo', 2, 1);
        INSERT INTO T VALUES (5, 'Spanish', 'Hola', 2, 1);




        Query #1



        SELECT MAX(ID) id,
        MAX(CASE WHEN Lang ='English' THEN Text END) lang1,
        MAX(CASE WHEN Lang ='German' THEN Text END) lang2,
        MAX(CASE WHEN Lang ='Spanish' THEN Text END) lang3,
        number,
        chapter
        FROM T
        GROUP BY number, chapter;

        | id | lang1 | lang2 | lang3 | number | chapter |
        | --- | ----- | ----- | ----- | ------ | ------- |
        | 5 | Hello | Hallo | Hola | 2 | 1 |




        View on DB Fiddle






        share|improve this answer




























          1














          You can try to use condition aggregate function to make it.



          Schema (MySQL v5.7)



          CREATE TABLE T(
          ID int,
          Lang varchar(50),
          Text varchar(50),
          number int,
          chapter int
          );



          INSERT INTO T VALUES (1, 'English', 'Hello', 2, 1);
          INSERT INTO T VALUES (4, 'German', 'Hallo', 2, 1);
          INSERT INTO T VALUES (5, 'Spanish', 'Hola', 2, 1);




          Query #1



          SELECT MAX(ID) id,
          MAX(CASE WHEN Lang ='English' THEN Text END) lang1,
          MAX(CASE WHEN Lang ='German' THEN Text END) lang2,
          MAX(CASE WHEN Lang ='Spanish' THEN Text END) lang3,
          number,
          chapter
          FROM T
          GROUP BY number, chapter;

          | id | lang1 | lang2 | lang3 | number | chapter |
          | --- | ----- | ----- | ----- | ------ | ------- |
          | 5 | Hello | Hallo | Hola | 2 | 1 |




          View on DB Fiddle






          share|improve this answer


























            1












            1








            1







            You can try to use condition aggregate function to make it.



            Schema (MySQL v5.7)



            CREATE TABLE T(
            ID int,
            Lang varchar(50),
            Text varchar(50),
            number int,
            chapter int
            );



            INSERT INTO T VALUES (1, 'English', 'Hello', 2, 1);
            INSERT INTO T VALUES (4, 'German', 'Hallo', 2, 1);
            INSERT INTO T VALUES (5, 'Spanish', 'Hola', 2, 1);




            Query #1



            SELECT MAX(ID) id,
            MAX(CASE WHEN Lang ='English' THEN Text END) lang1,
            MAX(CASE WHEN Lang ='German' THEN Text END) lang2,
            MAX(CASE WHEN Lang ='Spanish' THEN Text END) lang3,
            number,
            chapter
            FROM T
            GROUP BY number, chapter;

            | id | lang1 | lang2 | lang3 | number | chapter |
            | --- | ----- | ----- | ----- | ------ | ------- |
            | 5 | Hello | Hallo | Hola | 2 | 1 |




            View on DB Fiddle






            share|improve this answer













            You can try to use condition aggregate function to make it.



            Schema (MySQL v5.7)



            CREATE TABLE T(
            ID int,
            Lang varchar(50),
            Text varchar(50),
            number int,
            chapter int
            );



            INSERT INTO T VALUES (1, 'English', 'Hello', 2, 1);
            INSERT INTO T VALUES (4, 'German', 'Hallo', 2, 1);
            INSERT INTO T VALUES (5, 'Spanish', 'Hola', 2, 1);




            Query #1



            SELECT MAX(ID) id,
            MAX(CASE WHEN Lang ='English' THEN Text END) lang1,
            MAX(CASE WHEN Lang ='German' THEN Text END) lang2,
            MAX(CASE WHEN Lang ='Spanish' THEN Text END) lang3,
            number,
            chapter
            FROM T
            GROUP BY number, chapter;

            | id | lang1 | lang2 | lang3 | number | chapter |
            | --- | ----- | ----- | ----- | ------ | ------- |
            | 5 | Hello | Hallo | Hola | 2 | 1 |




            View on DB Fiddle







            share|improve this answer












            share|improve this answer



            share|improve this answer










            answered Nov 14 '18 at 11:54









            D-ShihD-Shih

            25.8k61531




            25.8k61531

























                2














                Create table test :



                 CREATE TABLE test (
                id INT(6) UNSIGNED AUTO_INCREMENT PRIMARY KEY,
                Lang VARCHAR(30) NOT NULL,
                Text VARCHAR(30) NOT NULL,
                number VARCHAR(50),
                chapter INT(10))


                Insert records:



                insert into test values(1,'English','Hello','2',1);
                insert into test values(4,'German','Hallo','2',1);
                insert into test values(5,'Spanish','Hola','2',1);


                +----+---------+-------+--------+---------+
                | id | Lang | Text | number | chapter |
                +----+---------+-------+--------+---------+
                | 1 | English | Hello | 2 | 1 |
                | 4 | German | Hallo | 2 | 1 |
                | 5 | Spanish | Hola | 2 | 1 |
                +----+---------+-------+--------+---------+



                SELECT MAX(id) id, MAX(CASE WHEN Lang ='English' THEN Text END) lang1,
                MAX(CASE WHEN Lang ='German' THEN Text END) lang2,
                MAX(CASE WHEN Lang ='Spanish' THEN Text END) lang3, number, chapter
                FROM test GROUP BY number, chapter;

                +------+-------+-------+-------+--------+---------+
                | id | lang1 | lang2 | lang3 | number | chapter |
                +------+-------+-------+-------+--------+---------+
                | 5 | Hello | Hallo | Hola | 2 | 1 |
                +------+-------+-------+-------+--------+---------+





                share|improve this answer






























                  2














                  Create table test :



                   CREATE TABLE test (
                  id INT(6) UNSIGNED AUTO_INCREMENT PRIMARY KEY,
                  Lang VARCHAR(30) NOT NULL,
                  Text VARCHAR(30) NOT NULL,
                  number VARCHAR(50),
                  chapter INT(10))


                  Insert records:



                  insert into test values(1,'English','Hello','2',1);
                  insert into test values(4,'German','Hallo','2',1);
                  insert into test values(5,'Spanish','Hola','2',1);


                  +----+---------+-------+--------+---------+
                  | id | Lang | Text | number | chapter |
                  +----+---------+-------+--------+---------+
                  | 1 | English | Hello | 2 | 1 |
                  | 4 | German | Hallo | 2 | 1 |
                  | 5 | Spanish | Hola | 2 | 1 |
                  +----+---------+-------+--------+---------+



                  SELECT MAX(id) id, MAX(CASE WHEN Lang ='English' THEN Text END) lang1,
                  MAX(CASE WHEN Lang ='German' THEN Text END) lang2,
                  MAX(CASE WHEN Lang ='Spanish' THEN Text END) lang3, number, chapter
                  FROM test GROUP BY number, chapter;

                  +------+-------+-------+-------+--------+---------+
                  | id | lang1 | lang2 | lang3 | number | chapter |
                  +------+-------+-------+-------+--------+---------+
                  | 5 | Hello | Hallo | Hola | 2 | 1 |
                  +------+-------+-------+-------+--------+---------+





                  share|improve this answer




























                    2












                    2








                    2







                    Create table test :



                     CREATE TABLE test (
                    id INT(6) UNSIGNED AUTO_INCREMENT PRIMARY KEY,
                    Lang VARCHAR(30) NOT NULL,
                    Text VARCHAR(30) NOT NULL,
                    number VARCHAR(50),
                    chapter INT(10))


                    Insert records:



                    insert into test values(1,'English','Hello','2',1);
                    insert into test values(4,'German','Hallo','2',1);
                    insert into test values(5,'Spanish','Hola','2',1);


                    +----+---------+-------+--------+---------+
                    | id | Lang | Text | number | chapter |
                    +----+---------+-------+--------+---------+
                    | 1 | English | Hello | 2 | 1 |
                    | 4 | German | Hallo | 2 | 1 |
                    | 5 | Spanish | Hola | 2 | 1 |
                    +----+---------+-------+--------+---------+



                    SELECT MAX(id) id, MAX(CASE WHEN Lang ='English' THEN Text END) lang1,
                    MAX(CASE WHEN Lang ='German' THEN Text END) lang2,
                    MAX(CASE WHEN Lang ='Spanish' THEN Text END) lang3, number, chapter
                    FROM test GROUP BY number, chapter;

                    +------+-------+-------+-------+--------+---------+
                    | id | lang1 | lang2 | lang3 | number | chapter |
                    +------+-------+-------+-------+--------+---------+
                    | 5 | Hello | Hallo | Hola | 2 | 1 |
                    +------+-------+-------+-------+--------+---------+





                    share|improve this answer















                    Create table test :



                     CREATE TABLE test (
                    id INT(6) UNSIGNED AUTO_INCREMENT PRIMARY KEY,
                    Lang VARCHAR(30) NOT NULL,
                    Text VARCHAR(30) NOT NULL,
                    number VARCHAR(50),
                    chapter INT(10))


                    Insert records:



                    insert into test values(1,'English','Hello','2',1);
                    insert into test values(4,'German','Hallo','2',1);
                    insert into test values(5,'Spanish','Hola','2',1);


                    +----+---------+-------+--------+---------+
                    | id | Lang | Text | number | chapter |
                    +----+---------+-------+--------+---------+
                    | 1 | English | Hello | 2 | 1 |
                    | 4 | German | Hallo | 2 | 1 |
                    | 5 | Spanish | Hola | 2 | 1 |
                    +----+---------+-------+--------+---------+



                    SELECT MAX(id) id, MAX(CASE WHEN Lang ='English' THEN Text END) lang1,
                    MAX(CASE WHEN Lang ='German' THEN Text END) lang2,
                    MAX(CASE WHEN Lang ='Spanish' THEN Text END) lang3, number, chapter
                    FROM test GROUP BY number, chapter;

                    +------+-------+-------+-------+--------+---------+
                    | id | lang1 | lang2 | lang3 | number | chapter |
                    +------+-------+-------+-------+--------+---------+
                    | 5 | Hello | Hallo | Hola | 2 | 1 |
                    +------+-------+-------+-------+--------+---------+






                    share|improve this answer














                    share|improve this answer



                    share|improve this answer








                    edited Nov 14 '18 at 12:57









                    Mihai Chelaru

                    2,210101122




                    2,210101122










                    answered Nov 14 '18 at 12:23









                    Atul AkabariAtul Akabari

                    954




                    954























                        1














                        SELECT * FROM
                        (SELECT LangAS t1, vargu FROM table LANG=114 AND chapter=1) as A,
                        (SELECT LangAS t2 FROM table WHERE LANG=115 AND chapter=1) AS B,
                        (SELECT LangAS t3 FROM table WHERE LANG=116 AND chapter=1) AS C;





                        share|improve this answer




























                          1














                          SELECT * FROM
                          (SELECT LangAS t1, vargu FROM table LANG=114 AND chapter=1) as A,
                          (SELECT LangAS t2 FROM table WHERE LANG=115 AND chapter=1) AS B,
                          (SELECT LangAS t3 FROM table WHERE LANG=116 AND chapter=1) AS C;





                          share|improve this answer


























                            1












                            1








                            1







                            SELECT * FROM
                            (SELECT LangAS t1, vargu FROM table LANG=114 AND chapter=1) as A,
                            (SELECT LangAS t2 FROM table WHERE LANG=115 AND chapter=1) AS B,
                            (SELECT LangAS t3 FROM table WHERE LANG=116 AND chapter=1) AS C;





                            share|improve this answer













                            SELECT * FROM
                            (SELECT LangAS t1, vargu FROM table LANG=114 AND chapter=1) as A,
                            (SELECT LangAS t2 FROM table WHERE LANG=115 AND chapter=1) AS B,
                            (SELECT LangAS t3 FROM table WHERE LANG=116 AND chapter=1) AS C;






                            share|improve this answer












                            share|improve this answer



                            share|improve this answer










                            answered Nov 14 '18 at 12:05









                            arlindarlind

                            931212




                            931212






























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