How to map object to Array only for first level. JS
I have the object:
obj = {
a: 'aVal',
b: {
bSub_1: 'bSub_1_value',
bSub_2: 'bSub_2_value'
}
}
I need to map this object to an array
['aVal', {bSub_1: 'bSub_1_value', bSub_2: 'bSub_2_value'}]
I try to use Object.values(obj) but this approach cast all object levels to the array, however, I need casting only first.
How I can do this?
javascript arrays
asked Nov 14 '18 at 12:52
PavelPavel
449522
add a comment |
I have the object:
obj = {
a: 'aVal',
b: {
bSub_1: 'bSub_1_value',
bSub_2: 'bSub_2_value'
}
}
I need to map this object to an array
['aVal', {bSub_1: 'bSub_1_value', bSub_2: 'bSub_2_value'}]
I try to use Object.values(obj) but this approach cast all object levels to the array, however, I need casting only first.
How I can do this?
javascript arrays
asked Nov 14 '18 at 12:52
PavelPavel
449522
What is the output you are getting when usingObject.values(obj)?
– Hassan Imam
Nov 14 '18 at 13:01
add a comment |
I have the object:
obj = {
a: 'aVal',
b: {
bSub_1: 'bSub_1_value',
bSub_2: 'bSub_2_value'
}
}
I need to map this object to an array
['aVal', {bSub_1: 'bSub_1_value', bSub_2: 'bSub_2_value'}]
I try to use Object.values(obj) but this approach cast all object levels to the array, however, I need casting only first.
How I can do this?
javascript arrays
asked Nov 14 '18 at 12:52
PavelPavel
449522
I have the object:
obj = {
a: 'aVal',
b: {
bSub_1: 'bSub_1_value',
bSub_2: 'bSub_2_value'
}
}
I need to map this object to an array
['aVal', {bSub_1: 'bSub_1_value', bSub_2: 'bSub_2_value'}]
I try to use Object.values(obj) but this approach cast all object levels to the array, however, I need casting only first.
How I can do this?
javascript arrays
javascript arrays
asked Nov 14 '18 at 12:52
PavelPavel
449522
asked Nov 14 '18 at 12:52
PavelPavel
449522
asked Nov 14 '18 at 12:52
PavelPavel
449522
asked Nov 14 '18 at 12:52
PavelPavel
449522
asked Nov 14 '18 at 12:52
PavelPavel
449522
449522
What is the output you are getting when usingObject.values(obj)?
– Hassan Imam
Nov 14 '18 at 13:01
add a comment |
What is the output you are getting when usingObject.values(obj)?
– Hassan Imam
Nov 14 '18 at 13:01
What is the output you are getting when using
Object.values(obj) ?– Hassan Imam
Nov 14 '18 at 13:01
What is the output you are getting when using
Object.values(obj) ?– Hassan Imam
Nov 14 '18 at 13:01
add a comment |
2 Answers
2
active
oldest
votes
This answer is more of clarification rather than answer.
.....however, I need casting only first.
That is not quite clear.
It seems pretty straight with Object.values().
The
Object.values()method returns an array of a given object's own enumerable property values, in the same order as that provided by a for...in loop (the difference being that a for-in loop enumerates properties in the prototype chain as well).
Please notice how the below snippet produces the exact output you expect:
var obj = {
a: 'aVal',
b: {
bSub_1: 'bSub_1_value',
bSub_2: 'bSub_2_value'
}
}
var res = Object.values(obj);
console.log(res);answered Nov 14 '18 at 12:58
MamunMamun
26.9k71630
wow, you right! This not precisely quotes from my app because I wanted to make an easy example. But in reality, I make mistake. Probably I should delete this question. My first solution absolutely right but backend send invalid data in the deep of object and I missed it.
– Pavel
Nov 14 '18 at 16:28
add a comment |
Just another way of doing the same
Object.keys(obj).map(e => obj[e])
answered Nov 14 '18 at 13:05
Parnab SanyalParnab Sanyal
442313
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
This answer is more of clarification rather than answer.
.....however, I need casting only first.
That is not quite clear.
It seems pretty straight with Object.values().
The
Object.values()method returns an array of a given object's own enumerable property values, in the same order as that provided by a for...in loop (the difference being that a for-in loop enumerates properties in the prototype chain as well).
Please notice how the below snippet produces the exact output you expect:
var obj = {
a: 'aVal',
b: {
bSub_1: 'bSub_1_value',
bSub_2: 'bSub_2_value'
}
}
var res = Object.values(obj);
console.log(res);answered Nov 14 '18 at 12:58
MamunMamun
26.9k71630
wow, you right! This not precisely quotes from my app because I wanted to make an easy example. But in reality, I make mistake. Probably I should delete this question. My first solution absolutely right but backend send invalid data in the deep of object and I missed it.
– Pavel
Nov 14 '18 at 16:28
add a comment |
This answer is more of clarification rather than answer.
.....however, I need casting only first.
That is not quite clear.
It seems pretty straight with Object.values().
The
Object.values()method returns an array of a given object's own enumerable property values, in the same order as that provided by a for...in loop (the difference being that a for-in loop enumerates properties in the prototype chain as well).
Please notice how the below snippet produces the exact output you expect:
var obj = {
a: 'aVal',
b: {
bSub_1: 'bSub_1_value',
bSub_2: 'bSub_2_value'
}
}
var res = Object.values(obj);
console.log(res);answered Nov 14 '18 at 12:58
MamunMamun
26.9k71630
wow, you right! This not precisely quotes from my app because I wanted to make an easy example. But in reality, I make mistake. Probably I should delete this question. My first solution absolutely right but backend send invalid data in the deep of object and I missed it.
– Pavel
Nov 14 '18 at 16:28
add a comment |
This answer is more of clarification rather than answer.
.....however, I need casting only first.
That is not quite clear.
It seems pretty straight with Object.values().
The
Object.values()method returns an array of a given object's own enumerable property values, in the same order as that provided by a for...in loop (the difference being that a for-in loop enumerates properties in the prototype chain as well).
Please notice how the below snippet produces the exact output you expect:
var obj = {
a: 'aVal',
b: {
bSub_1: 'bSub_1_value',
bSub_2: 'bSub_2_value'
}
}
var res = Object.values(obj);
console.log(res);answered Nov 14 '18 at 12:58
MamunMamun
26.9k71630
This answer is more of clarification rather than answer.
.....however, I need casting only first.
That is not quite clear.
It seems pretty straight with Object.values().
The
Object.values()method returns an array of a given object's own enumerable property values, in the same order as that provided by a for...in loop (the difference being that a for-in loop enumerates properties in the prototype chain as well).
Please notice how the below snippet produces the exact output you expect:
var obj = {
a: 'aVal',
b: {
bSub_1: 'bSub_1_value',
bSub_2: 'bSub_2_value'
}
}
var res = Object.values(obj);
console.log(res);var obj = {
a: 'aVal',
b: {
bSub_1: 'bSub_1_value',
bSub_2: 'bSub_2_value'
}
}
var res = Object.values(obj);
console.log(res);var obj = {
a: 'aVal',
b: {
bSub_1: 'bSub_1_value',
bSub_2: 'bSub_2_value'
}
}
var res = Object.values(obj);
console.log(res);answered Nov 14 '18 at 12:58
MamunMamun
26.9k71630
edited Nov 14 '18 at 13:17
answered Nov 14 '18 at 12:58
MamunMamun
26.9k71630
answered Nov 14 '18 at 12:58
MamunMamun
26.9k71630
answered Nov 14 '18 at 12:58
MamunMamun
26.9k71630
26.9k71630
wow, you right! This not precisely quotes from my app because I wanted to make an easy example. But in reality, I make mistake. Probably I should delete this question. My first solution absolutely right but backend send invalid data in the deep of object and I missed it.
– Pavel
Nov 14 '18 at 16:28
add a comment |
wow, you right! This not precisely quotes from my app because I wanted to make an easy example. But in reality, I make mistake. Probably I should delete this question. My first solution absolutely right but backend send invalid data in the deep of object and I missed it.
– Pavel
Nov 14 '18 at 16:28
wow, you right! This not precisely quotes from my app because I wanted to make an easy example. But in reality, I make mistake. Probably I should delete this question. My first solution absolutely right but backend send invalid data in the deep of object and I missed it.
– Pavel
Nov 14 '18 at 16:28
wow, you right! This not precisely quotes from my app because I wanted to make an easy example. But in reality, I make mistake. Probably I should delete this question. My first solution absolutely right but backend send invalid data in the deep of object and I missed it.
– Pavel
Nov 14 '18 at 16:28
add a comment |
Just another way of doing the same
Object.keys(obj).map(e => obj[e])
answered Nov 14 '18 at 13:05
Parnab SanyalParnab Sanyal
442313
add a comment |
Just another way of doing the same
Object.keys(obj).map(e => obj[e])
answered Nov 14 '18 at 13:05
Parnab SanyalParnab Sanyal
442313
add a comment |
Just another way of doing the same
Object.keys(obj).map(e => obj[e])
answered Nov 14 '18 at 13:05
Parnab SanyalParnab Sanyal
442313
Just another way of doing the same
Object.keys(obj).map(e => obj[e])
answered Nov 14 '18 at 13:05
Parnab SanyalParnab Sanyal
442313
answered Nov 14 '18 at 13:05
Parnab SanyalParnab Sanyal
442313
answered Nov 14 '18 at 13:05
Parnab SanyalParnab Sanyal
442313
answered Nov 14 '18 at 13:05
Parnab SanyalParnab Sanyal
442313
442313
add a comment |
add a comment |
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What is the output you are getting when using
Object.values(obj)?– Hassan Imam
Nov 14 '18 at 13:01