How to compare 24hrs time format in php?
I have time in 24hrs date format. For example
$after = 9;
$before = 17;
and my enter time is
$enterTime = 15;
I want to know my enter time $enterTime is outside of $after and $before time.
For this, I am using this code.
if(strtotime($enterTime) > strtotime($before) && strtotime($enterTime) < strtotime($after))
{
echo $enterTime;
} else {
echo"jghj";
}
php time
edited Nov 15 '18 at 5:42
Yogesh Patel
5942824
asked Nov 15 '18 at 5:10
amit joshiamit joshi
11
add a comment |
I have time in 24hrs date format. For example
$after = 9;
$before = 17;
and my enter time is
$enterTime = 15;
I want to know my enter time $enterTime is outside of $after and $before time.
For this, I am using this code.
if(strtotime($enterTime) > strtotime($before) && strtotime($enterTime) < strtotime($after))
{
echo $enterTime;
} else {
echo"jghj";
}
php time
edited Nov 15 '18 at 5:42
Yogesh Patel
5942824
asked Nov 15 '18 at 5:10
amit joshiamit joshi
11
What is the actual format you get the$after,$beforeand$enterTimetimes? Because AFAIK if you dostrtotimewith those values in your question it will simple return false.
– Prix
Nov 15 '18 at 6:05
add a comment |
I have time in 24hrs date format. For example
$after = 9;
$before = 17;
and my enter time is
$enterTime = 15;
I want to know my enter time $enterTime is outside of $after and $before time.
For this, I am using this code.
if(strtotime($enterTime) > strtotime($before) && strtotime($enterTime) < strtotime($after))
{
echo $enterTime;
} else {
echo"jghj";
}
php time
edited Nov 15 '18 at 5:42
Yogesh Patel
5942824
asked Nov 15 '18 at 5:10
amit joshiamit joshi
11
I have time in 24hrs date format. For example
$after = 9;
$before = 17;
and my enter time is
$enterTime = 15;
I want to know my enter time $enterTime is outside of $after and $before time.
For this, I am using this code.
if(strtotime($enterTime) > strtotime($before) && strtotime($enterTime) < strtotime($after))
{
echo $enterTime;
} else {
echo"jghj";
}
php time
php time
edited Nov 15 '18 at 5:42
Yogesh Patel
5942824
asked Nov 15 '18 at 5:10
amit joshiamit joshi
11
edited Nov 15 '18 at 5:42
Yogesh Patel
5942824
asked Nov 15 '18 at 5:10
amit joshiamit joshi
11
edited Nov 15 '18 at 5:42
Yogesh Patel
5942824
edited Nov 15 '18 at 5:42
Yogesh Patel
5942824
edited Nov 15 '18 at 5:42
Yogesh Patel
5942824
5942824
asked Nov 15 '18 at 5:10
amit joshiamit joshi
11
asked Nov 15 '18 at 5:10
amit joshiamit joshi
11
asked Nov 15 '18 at 5:10
amit joshiamit joshi
11
11
What is the actual format you get the$after,$beforeand$enterTimetimes? Because AFAIK if you dostrtotimewith those values in your question it will simple return false.
– Prix
Nov 15 '18 at 6:05
add a comment |
What is the actual format you get the$after,$beforeand$enterTimetimes? Because AFAIK if you dostrtotimewith those values in your question it will simple return false.
– Prix
Nov 15 '18 at 6:05
What is the actual format you get the
$after, $before and $enterTime times? Because AFAIK if you do strtotime with those values in your question it will simple return false.– Prix
Nov 15 '18 at 6:05
What is the actual format you get the
$after, $before and $enterTime times? Because AFAIK if you do strtotime with those values in your question it will simple return false.– Prix
Nov 15 '18 at 6:05
add a comment |
1 Answer
1
active
oldest
votes
You can't compare like this
if(strtotime($enterTime) > strtotime($before) && strtotime($enterTime) <
strtotime($after))
{
echo $enterTime;
} else {
echo"jghj";
}
because, strtotime() function takes parameters
Parameters ¶
time:
A date/time string. Valid formats are explained in Date and Time Formats.
now:
The timestamp which is used as a base for the calculation of relative dates.
but you are passing integer value in strtotime(). which is invalid value.
you can compare like so
$beforeTime ="14:08:10";
$afterTime ="15:10:00";
if (strtotime(afterTime ) >= strtotime($beforeTime)) {
echo "ok";
}
answered Nov 15 '18 at 7:35
Zeeshan TanveerZeeshan Tanveer
313
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
You can't compare like this
if(strtotime($enterTime) > strtotime($before) && strtotime($enterTime) <
strtotime($after))
{
echo $enterTime;
} else {
echo"jghj";
}
because, strtotime() function takes parameters
Parameters ¶
time:
A date/time string. Valid formats are explained in Date and Time Formats.
now:
The timestamp which is used as a base for the calculation of relative dates.
but you are passing integer value in strtotime(). which is invalid value.
you can compare like so
$beforeTime ="14:08:10";
$afterTime ="15:10:00";
if (strtotime(afterTime ) >= strtotime($beforeTime)) {
echo "ok";
}
answered Nov 15 '18 at 7:35
Zeeshan TanveerZeeshan Tanveer
313
add a comment |
You can't compare like this
if(strtotime($enterTime) > strtotime($before) && strtotime($enterTime) <
strtotime($after))
{
echo $enterTime;
} else {
echo"jghj";
}
because, strtotime() function takes parameters
Parameters ¶
time:
A date/time string. Valid formats are explained in Date and Time Formats.
now:
The timestamp which is used as a base for the calculation of relative dates.
but you are passing integer value in strtotime(). which is invalid value.
you can compare like so
$beforeTime ="14:08:10";
$afterTime ="15:10:00";
if (strtotime(afterTime ) >= strtotime($beforeTime)) {
echo "ok";
}
answered Nov 15 '18 at 7:35
Zeeshan TanveerZeeshan Tanveer
313
add a comment |
You can't compare like this
if(strtotime($enterTime) > strtotime($before) && strtotime($enterTime) <
strtotime($after))
{
echo $enterTime;
} else {
echo"jghj";
}
because, strtotime() function takes parameters
Parameters ¶
time:
A date/time string. Valid formats are explained in Date and Time Formats.
now:
The timestamp which is used as a base for the calculation of relative dates.
but you are passing integer value in strtotime(). which is invalid value.
you can compare like so
$beforeTime ="14:08:10";
$afterTime ="15:10:00";
if (strtotime(afterTime ) >= strtotime($beforeTime)) {
echo "ok";
}
answered Nov 15 '18 at 7:35
Zeeshan TanveerZeeshan Tanveer
313
You can't compare like this
if(strtotime($enterTime) > strtotime($before) && strtotime($enterTime) <
strtotime($after))
{
echo $enterTime;
} else {
echo"jghj";
}
because, strtotime() function takes parameters
Parameters ¶
time:
A date/time string. Valid formats are explained in Date and Time Formats.
now:
The timestamp which is used as a base for the calculation of relative dates.
but you are passing integer value in strtotime(). which is invalid value.
you can compare like so
$beforeTime ="14:08:10";
$afterTime ="15:10:00";
if (strtotime(afterTime ) >= strtotime($beforeTime)) {
echo "ok";
}
answered Nov 15 '18 at 7:35
Zeeshan TanveerZeeshan Tanveer
313
answered Nov 15 '18 at 7:35
Zeeshan TanveerZeeshan Tanveer
313
answered Nov 15 '18 at 7:35
Zeeshan TanveerZeeshan Tanveer
313
answered Nov 15 '18 at 7:35
Zeeshan TanveerZeeshan Tanveer
313
313
add a comment |
add a comment |
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What is the actual format you get the
$after,$beforeand$enterTimetimes? Because AFAIK if you dostrtotimewith those values in your question it will simple return false.– Prix
Nov 15 '18 at 6:05