How to put string values into string array obtained from user using while loop

-6

I am trying to get values from user and storing those values in string array. It can be achieved by for loop easily. But need to accomplish it using while loop. Help me out to solve this.

Scanner in = new Scanner(System.in); 

int testCases = Integer.parseInt(in.nextLine()); 

String arr1 = new String[testCases]; 



for(int i=0; i<testCases;i++) {

    String s = in.nextLine(); 

    arr1[i]=s; 

} 



for(int i=0; i<testCases;i++) { 

    try {

        Pattern.compile(arr1[i]); 

        System.out.println("Valid"); 

    } catch(Exception e) { 

        System.out.println("Invalid"); 

    }

}

edited Nov 15 '18 at 5:33

Adrian Shum

28.8k762107

asked Nov 15 '18 at 5:23

Aravind Arun

Scanner in = new Scanner(System.in); int testCases = Integer.parseInt(in.nextLine()); String arr1 = new String[testCases]; for(int i=0; i<testCases;i++) { String s = in.nextLine(); arr1[i]=s; } for(int i=0; i<testCases;i++) { try { Pattern.compile(arr1[i]); System.out.println("Valid"); } catch(Exception e) { System.out.println("Invalid"); } }

– Aravind Arun
Nov 15 '18 at 5:25

Put your code in the question

– Danish Ali
Nov 15 '18 at 5:28

@AravindArun Please update your question with the code (and properly format it), instead of putting it in comment

– Adrian Shum
Nov 15 '18 at 5:29

Just add some prompting and your code will be better, but what are you trying to do with Pattern

– Scary Wombat
Nov 15 '18 at 5:30

sorry i'm new to stack overflow. @Scary Wombat thanks for updating the code in question

– Aravind Arun
Nov 15 '18 at 5:31

|
show 4 more comments

-6

I am trying to get values from user and storing those values in string array. It can be achieved by for loop easily. But need to accomplish it using while loop. Help me out to solve this.

Scanner in = new Scanner(System.in); 

int testCases = Integer.parseInt(in.nextLine()); 

String arr1 = new String[testCases]; 



for(int i=0; i<testCases;i++) {

    String s = in.nextLine(); 

    arr1[i]=s; 

} 



for(int i=0; i<testCases;i++) { 

    try {

        Pattern.compile(arr1[i]); 

        System.out.println("Valid"); 

    } catch(Exception e) { 

        System.out.println("Invalid"); 

    }

}

edited Nov 15 '18 at 5:33

Adrian Shum

28.8k762107

asked Nov 15 '18 at 5:23

Aravind Arun

Scanner in = new Scanner(System.in); int testCases = Integer.parseInt(in.nextLine()); String arr1 = new String[testCases]; for(int i=0; i<testCases;i++) { String s = in.nextLine(); arr1[i]=s; } for(int i=0; i<testCases;i++) { try { Pattern.compile(arr1[i]); System.out.println("Valid"); } catch(Exception e) { System.out.println("Invalid"); } }

– Aravind Arun
Nov 15 '18 at 5:25

Put your code in the question

– Danish Ali
Nov 15 '18 at 5:28

@AravindArun Please update your question with the code (and properly format it), instead of putting it in comment

– Adrian Shum
Nov 15 '18 at 5:29

Just add some prompting and your code will be better, but what are you trying to do with Pattern

– Scary Wombat
Nov 15 '18 at 5:30

sorry i'm new to stack overflow. @Scary Wombat thanks for updating the code in question

– Aravind Arun
Nov 15 '18 at 5:31

|
show 4 more comments

-6

I am trying to get values from user and storing those values in string array. It can be achieved by for loop easily. But need to accomplish it using while loop. Help me out to solve this.

Scanner in = new Scanner(System.in); 

int testCases = Integer.parseInt(in.nextLine()); 

String arr1 = new String[testCases]; 



for(int i=0; i<testCases;i++) {

    String s = in.nextLine(); 

    arr1[i]=s; 

} 



for(int i=0; i<testCases;i++) { 

    try {

        Pattern.compile(arr1[i]); 

        System.out.println("Valid"); 

    } catch(Exception e) { 

        System.out.println("Invalid"); 

    }

}

edited Nov 15 '18 at 5:33

Adrian Shum

28.8k762107

asked Nov 15 '18 at 5:23

Aravind Arun

I am trying to get values from user and storing those values in string array. It can be achieved by for loop easily. But need to accomplish it using while loop. Help me out to solve this.

Scanner in = new Scanner(System.in); 

int testCases = Integer.parseInt(in.nextLine()); 

String arr1 = new String[testCases]; 



for(int i=0; i<testCases;i++) {

    String s = in.nextLine(); 

    arr1[i]=s; 

} 



for(int i=0; i<testCases;i++) { 

    try {

        Pattern.compile(arr1[i]); 

        System.out.println("Valid"); 

    } catch(Exception e) { 

        System.out.println("Invalid"); 

    }

}

java while-loop

edited Nov 15 '18 at 5:33

Adrian Shum

28.8k762107

asked Nov 15 '18 at 5:23

Aravind Arun

edited Nov 15 '18 at 5:33

Adrian Shum

28.8k762107

asked Nov 15 '18 at 5:23

Aravind Arun

edited Nov 15 '18 at 5:33

Adrian Shum

28.8k762107

edited Nov 15 '18 at 5:33

Adrian Shum

28.8k762107

edited Nov 15 '18 at 5:33

Adrian Shum

28.8k762107

asked Nov 15 '18 at 5:23

Aravind Arun

asked Nov 15 '18 at 5:23

Aravind Arun

asked Nov 15 '18 at 5:23

Aravind Arun

Scanner in = new Scanner(System.in); int testCases = Integer.parseInt(in.nextLine()); String arr1 = new String[testCases]; for(int i=0; i<testCases;i++) { String s = in.nextLine(); arr1[i]=s; } for(int i=0; i<testCases;i++) { try { Pattern.compile(arr1[i]); System.out.println("Valid"); } catch(Exception e) { System.out.println("Invalid"); } }

– Aravind Arun
Nov 15 '18 at 5:25

Put your code in the question

– Danish Ali
Nov 15 '18 at 5:28

@AravindArun Please update your question with the code (and properly format it), instead of putting it in comment

– Adrian Shum
Nov 15 '18 at 5:29

Just add some prompting and your code will be better, but what are you trying to do with Pattern

– Scary Wombat
Nov 15 '18 at 5:30

sorry i'm new to stack overflow. @Scary Wombat thanks for updating the code in question

– Aravind Arun
Nov 15 '18 at 5:31

|
show 4 more comments

Scanner in = new Scanner(System.in); int testCases = Integer.parseInt(in.nextLine()); String arr1 = new String[testCases]; for(int i=0; i<testCases;i++) { String s = in.nextLine(); arr1[i]=s; } for(int i=0; i<testCases;i++) { try { Pattern.compile(arr1[i]); System.out.println("Valid"); } catch(Exception e) { System.out.println("Invalid"); } }

– Aravind Arun
Nov 15 '18 at 5:25

Put your code in the question

– Danish Ali
Nov 15 '18 at 5:28

@AravindArun Please update your question with the code (and properly format it), instead of putting it in comment

– Adrian Shum
Nov 15 '18 at 5:29

Just add some prompting and your code will be better, but what are you trying to do with Pattern

– Scary Wombat
Nov 15 '18 at 5:30

sorry i'm new to stack overflow. @Scary Wombat thanks for updating the code in question

– Aravind Arun
Nov 15 '18 at 5:31

Scanner in = new Scanner(System.in); int testCases = Integer.parseInt(in.nextLine()); String arr1 = new String[testCases]; for(int i=0; i<testCases;i++) { String s = in.nextLine(); arr1[i]=s; } for(int i=0; i<testCases;i++) { try { Pattern.compile(arr1[i]); System.out.println("Valid"); } catch(Exception e) { System.out.println("Invalid"); } }

– Aravind Arun
Nov 15 '18 at 5:25

Put your code in the question

– Danish Ali
Nov 15 '18 at 5:28

@AravindArun Please update your question with the code (and properly format it), instead of putting it in comment

– Adrian Shum
Nov 15 '18 at 5:29

Just add some prompting and your code will be better, but what are you trying to do with Pattern

– Scary Wombat
Nov 15 '18 at 5:30

sorry i'm new to stack overflow. @Scary Wombat thanks for updating the code in question

– Aravind Arun
Nov 15 '18 at 5:31

|
show 4 more comments

3 Answers
3

active

oldest

votes

As C/C++/Java-101: For loop and While loop can be (mostly) inter-translated by:

for (initialization; condition; increment) {

  logic;

}

is (mostly) equivalent to

initialization;

while(condition) {

    logic;

    increment;

}

(the biggest difference is how continue behave. However it is not affecting you in this case)

answered Nov 15 '18 at 5:42

Adrian Shum

28.8k762107

add a comment |

Just using while loop:

Scanner in = new Scanner(System.in); 

int testCases = Integer.parseInt(in.nextLine()); 

String arr1 = new String[testCases];

int i = 0; 

int n = testCases;

while(i < n)

{

    String s = in.nextLine(); 

    arr1[i] = s;

    testCases--;

    i++;

} 

while(testCases < n)

{ 

    try { 

      Pattern.compile(arr1[testCases]); 

      System.out.println("Valid"); 

    } catch(Exception e) { 

      System.out.println("Invalid"); 

    }

    testCases++;

    i--;

}

edited Nov 15 '18 at 5:43

answered Nov 15 '18 at 5:36

Zico

1,76611620

add a comment |

You can again set the value of i to 0 before running second while loop.

        Scanner in = new Scanner(System.in); 

        int testCases = Integer.parseInt(in.nextLine()); 

        String arr1 = new String[testCases]; 

        int i=0;

        while(i<testCases)

        {

            String s = in.nextLine(); 

            arr1[i]=s; 

            i++;

        } 

        i=0;

        while(i<testCases)

        { 

            try { Pattern.compile(arr1[i]); 

            System.out.println("Valid"); 

            } catch(Exception e) 

            { 

                System.out.println("Invalid"); 

            }

            i++;

        }

answered Nov 15 '18 at 5:46

Charu Agarwal

add a comment |

Your Answer

StackExchange.ifUsing("editor", function () {
StackExchange.using("externalEditor", function () {
StackExchange.using("snippets", function () {
StackExchange.snippets.init();
});
});
}, "code-snippets");

StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "1"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);

StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});

function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});

}
});

draft saved

draft discarded

Sign up or log in

StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});

Post as a guest

Name

Required, but never shown

StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53312928%2fhow-to-put-string-values-into-string-array-obtained-from-user-using-while-loop%23new-answer', 'question_page');
}
);

Post as a guest

Name

Required, but never shown

3 Answers
3

active

oldest

votes

3 Answers
3

active

oldest

votes

As C/C++/Java-101: For loop and While loop can be (mostly) inter-translated by:

for (initialization; condition; increment) {

  logic;

}

is (mostly) equivalent to

initialization;

while(condition) {

    logic;

    increment;

}

(the biggest difference is how continue behave. However it is not affecting you in this case)

answered Nov 15 '18 at 5:42

Adrian Shum

28.8k762107

add a comment |

As C/C++/Java-101: For loop and While loop can be (mostly) inter-translated by:

for (initialization; condition; increment) {

  logic;

}

is (mostly) equivalent to

initialization;

while(condition) {

    logic;

    increment;

}

(the biggest difference is how continue behave. However it is not affecting you in this case)

answered Nov 15 '18 at 5:42

Adrian Shum

28.8k762107

add a comment |

As C/C++/Java-101: For loop and While loop can be (mostly) inter-translated by:

for (initialization; condition; increment) {

  logic;

}

is (mostly) equivalent to

initialization;

while(condition) {

    logic;

    increment;

}

(the biggest difference is how continue behave. However it is not affecting you in this case)

answered Nov 15 '18 at 5:42

Adrian Shum

28.8k762107

As C/C++/Java-101: For loop and While loop can be (mostly) inter-translated by:

for (initialization; condition; increment) {

  logic;

}

is (mostly) equivalent to

initialization;

while(condition) {

    logic;

    increment;

}

(the biggest difference is how continue behave. However it is not affecting you in this case)

answered Nov 15 '18 at 5:42

Adrian Shum

28.8k762107

answered Nov 15 '18 at 5:42

Adrian Shum

28.8k762107

answered Nov 15 '18 at 5:42

Adrian Shum

28.8k762107

answered Nov 15 '18 at 5:42

Adrian Shum

28.8k762107

add a comment |

Just using while loop:

Scanner in = new Scanner(System.in); 

int testCases = Integer.parseInt(in.nextLine()); 

String arr1 = new String[testCases];

int i = 0; 

int n = testCases;

while(i < n)

{

    String s = in.nextLine(); 

    arr1[i] = s;

    testCases--;

    i++;

} 

while(testCases < n)

{ 

    try { 

      Pattern.compile(arr1[testCases]); 

      System.out.println("Valid"); 

    } catch(Exception e) { 

      System.out.println("Invalid"); 

    }

    testCases++;

    i--;

}

edited Nov 15 '18 at 5:43

answered Nov 15 '18 at 5:36

Zico

1,76611620

add a comment |

Just using while loop:

Scanner in = new Scanner(System.in); 

int testCases = Integer.parseInt(in.nextLine()); 

String arr1 = new String[testCases];

int i = 0; 

int n = testCases;

while(i < n)

{

    String s = in.nextLine(); 

    arr1[i] = s;

    testCases--;

    i++;

} 

while(testCases < n)

{ 

    try { 

      Pattern.compile(arr1[testCases]); 

      System.out.println("Valid"); 

    } catch(Exception e) { 

      System.out.println("Invalid"); 

    }

    testCases++;

    i--;

}

edited Nov 15 '18 at 5:43

answered Nov 15 '18 at 5:36

Zico

1,76611620

add a comment |

Just using while loop:

Scanner in = new Scanner(System.in); 

int testCases = Integer.parseInt(in.nextLine()); 

String arr1 = new String[testCases];

int i = 0; 

int n = testCases;

while(i < n)

{

    String s = in.nextLine(); 

    arr1[i] = s;

    testCases--;

    i++;

} 

while(testCases < n)

{ 

    try { 

      Pattern.compile(arr1[testCases]); 

      System.out.println("Valid"); 

    } catch(Exception e) { 

      System.out.println("Invalid"); 

    }

    testCases++;

    i--;

}

edited Nov 15 '18 at 5:43

answered Nov 15 '18 at 5:36

Zico

1,76611620

Just using while loop:

Scanner in = new Scanner(System.in); 

int testCases = Integer.parseInt(in.nextLine()); 

String arr1 = new String[testCases];

int i = 0; 

int n = testCases;

while(i < n)

{

    String s = in.nextLine(); 

    arr1[i] = s;

    testCases--;

    i++;

} 

while(testCases < n)

{ 

    try { 

      Pattern.compile(arr1[testCases]); 

      System.out.println("Valid"); 

    } catch(Exception e) { 

      System.out.println("Invalid"); 

    }

    testCases++;

    i--;

}

edited Nov 15 '18 at 5:43

answered Nov 15 '18 at 5:36

Zico

1,76611620

edited Nov 15 '18 at 5:43

answered Nov 15 '18 at 5:36

Zico

1,76611620

answered Nov 15 '18 at 5:36

Zico

1,76611620

answered Nov 15 '18 at 5:36

Zico

1,76611620

add a comment |

You can again set the value of i to 0 before running second while loop.

        Scanner in = new Scanner(System.in); 

        int testCases = Integer.parseInt(in.nextLine()); 

        String arr1 = new String[testCases]; 

        int i=0;

        while(i<testCases)

        {

            String s = in.nextLine(); 

            arr1[i]=s; 

            i++;

        } 

        i=0;

        while(i<testCases)

        { 

            try { Pattern.compile(arr1[i]); 

            System.out.println("Valid"); 

            } catch(Exception e) 

            { 

                System.out.println("Invalid"); 

            }

            i++;

        }

answered Nov 15 '18 at 5:46

Charu Agarwal

add a comment |

You can again set the value of i to 0 before running second while loop.

        Scanner in = new Scanner(System.in); 

        int testCases = Integer.parseInt(in.nextLine()); 

        String arr1 = new String[testCases]; 

        int i=0;

        while(i<testCases)

        {

            String s = in.nextLine(); 

            arr1[i]=s; 

            i++;

        } 

        i=0;

        while(i<testCases)

        { 

            try { Pattern.compile(arr1[i]); 

            System.out.println("Valid"); 

            } catch(Exception e) 

            { 

                System.out.println("Invalid"); 

            }

            i++;

        }

answered Nov 15 '18 at 5:46

Charu Agarwal

add a comment |

You can again set the value of i to 0 before running second while loop.

        Scanner in = new Scanner(System.in); 

        int testCases = Integer.parseInt(in.nextLine()); 

        String arr1 = new String[testCases]; 

        int i=0;

        while(i<testCases)

        {

            String s = in.nextLine(); 

            arr1[i]=s; 

            i++;

        } 

        i=0;

        while(i<testCases)

        { 

            try { Pattern.compile(arr1[i]); 

            System.out.println("Valid"); 

            } catch(Exception e) 

            { 

                System.out.println("Invalid"); 

            }

            i++;

        }

answered Nov 15 '18 at 5:46

Charu Agarwal

You can again set the value of i to 0 before running second while loop.

        Scanner in = new Scanner(System.in); 

        int testCases = Integer.parseInt(in.nextLine()); 

        String arr1 = new String[testCases]; 

        int i=0;

        while(i<testCases)

        {

            String s = in.nextLine(); 

            arr1[i]=s; 

            i++;

        } 

        i=0;

        while(i<testCases)

        { 

            try { Pattern.compile(arr1[i]); 

            System.out.println("Valid"); 

            } catch(Exception e) 

            { 

                System.out.println("Invalid"); 

            }

            i++;

        }

answered Nov 15 '18 at 5:46

Charu Agarwal

answered Nov 15 '18 at 5:46

Charu Agarwal

answered Nov 15 '18 at 5:46

Charu Agarwal

answered Nov 15 '18 at 5:46

Charu Agarwal

add a comment |

draft saved

draft discarded

Thanks for contributing an answer to Stack Overflow!

Please be sure to answer the question. Provide details and share your research!

But avoid …

Asking for help, clarification, or responding to other answers.

Making statements based on opinion; back them up with references or personal experience.

To learn more, see our tips on writing great answers.

draft saved

draft discarded

Sign up or log in

StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});

Post as a guest

Name

Required, but never shown

Post as a guest

Name

Required, but never shown

Sign up or log in

StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});

Post as a guest

Name

Required, but never shown

Sign up or log in

StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});

Post as a guest

Name

Required, but never shown

Sign up or log in

StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});

Post as a guest

Name

Required, but never shown

Name

Required, but never shown

Name

Required, but never shown

This page is only for reference, If you need detailed information, please check here

搜尋此網誌

Vfrdtyky