How to chose options in a while loop
My program --> I Will ask the user to introduce a number and I want to make that if the number is not in a random sequence (I choose 1,2,3) of numbers, the user need to write again a number until the number they enter is in the sequence:
a = (1,2,3)
option = int(input(''))
while option != a:
print('Enter a number between 1 and 3 !!')
option = int(input(''))
So as you can see I use the variable as a tuple but I don't know how to do it.. =(
while-loop python-3.6
asked Nov 14 '18 at 9:59
Álvaro Romero MatoÁlvaro Romero Mato
82
add a comment |
My program --> I Will ask the user to introduce a number and I want to make that if the number is not in a random sequence (I choose 1,2,3) of numbers, the user need to write again a number until the number they enter is in the sequence:
a = (1,2,3)
option = int(input(''))
while option != a:
print('Enter a number between 1 and 3 !!')
option = int(input(''))
So as you can see I use the variable as a tuple but I don't know how to do it.. =(
while-loop python-3.6
asked Nov 14 '18 at 9:59
Álvaro Romero MatoÁlvaro Romero Mato
82
add a comment |
My program --> I Will ask the user to introduce a number and I want to make that if the number is not in a random sequence (I choose 1,2,3) of numbers, the user need to write again a number until the number they enter is in the sequence:
a = (1,2,3)
option = int(input(''))
while option != a:
print('Enter a number between 1 and 3 !!')
option = int(input(''))
So as you can see I use the variable as a tuple but I don't know how to do it.. =(
while-loop python-3.6
asked Nov 14 '18 at 9:59
Álvaro Romero MatoÁlvaro Romero Mato
82
My program --> I Will ask the user to introduce a number and I want to make that if the number is not in a random sequence (I choose 1,2,3) of numbers, the user need to write again a number until the number they enter is in the sequence:
a = (1,2,3)
option = int(input(''))
while option != a:
print('Enter a number between 1 and 3 !!')
option = int(input(''))
So as you can see I use the variable as a tuple but I don't know how to do it.. =(
while-loop python-3.6
while-loop python-3.6
asked Nov 14 '18 at 9:59
Álvaro Romero MatoÁlvaro Romero Mato
82
asked Nov 14 '18 at 9:59
Álvaro Romero MatoÁlvaro Romero Mato
82
asked Nov 14 '18 at 9:59
Álvaro Romero MatoÁlvaro Romero Mato
82
asked Nov 14 '18 at 9:59
Álvaro Romero MatoÁlvaro Romero Mato
82
asked Nov 14 '18 at 9:59
Álvaro Romero MatoÁlvaro Romero Mato
82
82
add a comment |
add a comment |
1 Answer
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Assuming the use of a tuple is obligatory, you will need to get input as a string, because it is iterable type. It will alow you easily convert to int, sign by sign, thru list comprehension. Now you have a list of ints, which you simply convert to a tuple. The final option variable looks:
option = tuple([int(sign) for sign in str(input(''))])
But consider keeping your signature in int instead of tuple. Int number is also unequivocal if its about sequence. In python 123 == 132 returns False. That way, you need only to replace:
a = (1,2,3)
by a:
a = 123
And script will works.
answered Nov 16 '18 at 16:54
bloniaqbloniaq
195
add a comment |
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1 Answer
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active
oldest
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1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
Assuming the use of a tuple is obligatory, you will need to get input as a string, because it is iterable type. It will alow you easily convert to int, sign by sign, thru list comprehension. Now you have a list of ints, which you simply convert to a tuple. The final option variable looks:
option = tuple([int(sign) for sign in str(input(''))])
But consider keeping your signature in int instead of tuple. Int number is also unequivocal if its about sequence. In python 123 == 132 returns False. That way, you need only to replace:
a = (1,2,3)
by a:
a = 123
And script will works.
answered Nov 16 '18 at 16:54
bloniaqbloniaq
195
add a comment |
Assuming the use of a tuple is obligatory, you will need to get input as a string, because it is iterable type. It will alow you easily convert to int, sign by sign, thru list comprehension. Now you have a list of ints, which you simply convert to a tuple. The final option variable looks:
option = tuple([int(sign) for sign in str(input(''))])
But consider keeping your signature in int instead of tuple. Int number is also unequivocal if its about sequence. In python 123 == 132 returns False. That way, you need only to replace:
a = (1,2,3)
by a:
a = 123
And script will works.
answered Nov 16 '18 at 16:54
bloniaqbloniaq
195
add a comment |
Assuming the use of a tuple is obligatory, you will need to get input as a string, because it is iterable type. It will alow you easily convert to int, sign by sign, thru list comprehension. Now you have a list of ints, which you simply convert to a tuple. The final option variable looks:
option = tuple([int(sign) for sign in str(input(''))])
But consider keeping your signature in int instead of tuple. Int number is also unequivocal if its about sequence. In python 123 == 132 returns False. That way, you need only to replace:
a = (1,2,3)
by a:
a = 123
And script will works.
answered Nov 16 '18 at 16:54
bloniaqbloniaq
195
Assuming the use of a tuple is obligatory, you will need to get input as a string, because it is iterable type. It will alow you easily convert to int, sign by sign, thru list comprehension. Now you have a list of ints, which you simply convert to a tuple. The final option variable looks:
option = tuple([int(sign) for sign in str(input(''))])
But consider keeping your signature in int instead of tuple. Int number is also unequivocal if its about sequence. In python 123 == 132 returns False. That way, you need only to replace:
a = (1,2,3)
by a:
a = 123
And script will works.
answered Nov 16 '18 at 16:54
bloniaqbloniaq
195
answered Nov 16 '18 at 16:54
bloniaqbloniaq
195
answered Nov 16 '18 at 16:54
bloniaqbloniaq
195
answered Nov 16 '18 at 16:54
bloniaqbloniaq
195
195
add a comment |
add a comment |
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