summing 2 arrays to third array












0















i'm trying to make a program for my college task. it's about summing 2 arrays and the output into third array. but there's an error ArrayOutOfBoundsException but idk where's the error.

here's my source code 



Scanner sc = new Scanner(System.in);

    int arr1 = new int[3]; 

    int arr2 = new int[3]; 

    int i, j, k;

    for(i = 0; i < 3; i++) {

        System.out.print("Masukkan array pertama ke-" + i + ": ");

        arr1[i] = sc.nextInt();

    }



    for(j = 0; j < 3; j++) {

        System.out.print("Masukkan array kedua ke-" + j + ": ");

        arr2[j] = sc.nextInt();

    }



    for(k = 0; k < 4; k++) {

        int arr3 = new int[3];

        System.out.println(arr3[k] = arr1[i] + arr2[j]);

    }


the expected is like this 



arr1 = {1, 2, 3, 4}  

arr2 = {1, 2, 3, 4} 

arr3 = {2, 4, 6, 8}





java







share|improve this question

























  • arr3 is created on each loop iteration (which doesn't make sense) and surrounding for-loop has wrong conditional expression.

    – Michael Butscher
    Nov 13 '18 at 12:12











  • for(k = 0; k < 4; k++) is probably your issue. Shouldn't that be k < 3?

    – OldCurmudgeon
    Nov 13 '18 at 12:21
















0















i'm trying to make a program for my college task. it's about summing 2 arrays and the output into third array. but there's an error ArrayOutOfBoundsException but idk where's the error.

here's my source code 



Scanner sc = new Scanner(System.in);

    int arr1 = new int[3]; 

    int arr2 = new int[3]; 

    int i, j, k;

    for(i = 0; i < 3; i++) {

        System.out.print("Masukkan array pertama ke-" + i + ": ");

        arr1[i] = sc.nextInt();

    }



    for(j = 0; j < 3; j++) {

        System.out.print("Masukkan array kedua ke-" + j + ": ");

        arr2[j] = sc.nextInt();

    }



    for(k = 0; k < 4; k++) {

        int arr3 = new int[3];

        System.out.println(arr3[k] = arr1[i] + arr2[j]);

    }


the expected is like this 



arr1 = {1, 2, 3, 4}  

arr2 = {1, 2, 3, 4} 

arr3 = {2, 4, 6, 8}





java







share|improve this question

























  • arr3 is created on each loop iteration (which doesn't make sense) and surrounding for-loop has wrong conditional expression.

    – Michael Butscher
    Nov 13 '18 at 12:12











  • for(k = 0; k < 4; k++) is probably your issue. Shouldn't that be k < 3?

    – OldCurmudgeon
    Nov 13 '18 at 12:21














0












0








0








i'm trying to make a program for my college task. it's about summing 2 arrays and the output into third array. but there's an error ArrayOutOfBoundsException but idk where's the error.

here's my source code 



Scanner sc = new Scanner(System.in);

    int arr1 = new int[3]; 

    int arr2 = new int[3]; 

    int i, j, k;

    for(i = 0; i < 3; i++) {

        System.out.print("Masukkan array pertama ke-" + i + ": ");

        arr1[i] = sc.nextInt();

    }



    for(j = 0; j < 3; j++) {

        System.out.print("Masukkan array kedua ke-" + j + ": ");

        arr2[j] = sc.nextInt();

    }



    for(k = 0; k < 4; k++) {

        int arr3 = new int[3];

        System.out.println(arr3[k] = arr1[i] + arr2[j]);

    }


the expected is like this 



arr1 = {1, 2, 3, 4}  

arr2 = {1, 2, 3, 4} 

arr3 = {2, 4, 6, 8}





java







share|improve this question
















i'm trying to make a program for my college task. it's about summing 2 arrays and the output into third array. but there's an error ArrayOutOfBoundsException but idk where's the error.

here's my source code 



Scanner sc = new Scanner(System.in);

    int arr1 = new int[3]; 

    int arr2 = new int[3]; 

    int i, j, k;

    for(i = 0; i < 3; i++) {

        System.out.print("Masukkan array pertama ke-" + i + ": ");

        arr1[i] = sc.nextInt();

    }



    for(j = 0; j < 3; j++) {

        System.out.print("Masukkan array kedua ke-" + j + ": ");

        arr2[j] = sc.nextInt();

    }



    for(k = 0; k < 4; k++) {

        int arr3 = new int[3];

        System.out.println(arr3[k] = arr1[i] + arr2[j]);

    }


the expected is like this 



arr1 = {1, 2, 3, 4}  

arr2 = {1, 2, 3, 4} 

arr3 = {2, 4, 6, 8}





java




java






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 13 '18 at 12:29









Suraj Rao

22.8k75469




22.8k75469










asked Nov 13 '18 at 12:10









Rizky Putra Pradhana BudimanRizky Putra Pradhana Budiman

11




11













  • arr3 is created on each loop iteration (which doesn't make sense) and surrounding for-loop has wrong conditional expression.

    – Michael Butscher
    Nov 13 '18 at 12:12











  • for(k = 0; k < 4; k++) is probably your issue. Shouldn't that be k < 3?

    – OldCurmudgeon
    Nov 13 '18 at 12:21



















  • arr3 is created on each loop iteration (which doesn't make sense) and surrounding for-loop has wrong conditional expression.

    – Michael Butscher
    Nov 13 '18 at 12:12











  • for(k = 0; k < 4; k++) is probably your issue. Shouldn't that be k < 3?

    – OldCurmudgeon
    Nov 13 '18 at 12:21

















arr3 is created on each loop iteration (which doesn't make sense) and surrounding for-loop has wrong conditional expression.

– Michael Butscher
Nov 13 '18 at 12:12





arr3 is created on each loop iteration (which doesn't make sense) and surrounding for-loop has wrong conditional expression.

– Michael Butscher
Nov 13 '18 at 12:12













for(k = 0; k < 4; k++) is probably your issue. Shouldn't that be k < 3?

– OldCurmudgeon
Nov 13 '18 at 12:21





for(k = 0; k < 4; k++) is probably your issue. Shouldn't that be k < 3?

– OldCurmudgeon
Nov 13 '18 at 12:21












3 Answers
3






active

oldest

votes


















0














for(k = 0; k < 4; k++) {

        int arr3 = new int[3];

        System.out.println(arr3[k] = arr1[i] + arr2[j]);

    }


two major mistakes here. You do k < 4, while you should do k < 3
Also, you shouldn't re-create the array each iteration. Try this:



int arr3 = new int[3];

for(k = 0; k < 3; k++) {

        arr3[k] = arr1[k] + arr2[k]; // i and j don't make sense here.

    }


Printing the arrays, you can do after this.






share|improve this answer


























  • thank you, silly me for doing such a simple mistake!

    – Rizky Putra Pradhana Budiman
    Nov 13 '18 at 12:31



















0














Based on your expected output, your array size should be 4 instead of 3. Your code should look like this



    int arr1 = new int[4]; 

    int arr2 = new int[4];


Your code received an ArrayOutOfBoundsException because the k in your 3rd for loop should be 3 instead of 4 since your k should be less than your array size which is 3. One thing to mention is that instead of hard-coding your array size, it is a better practice to assign a variable to store the size of the array so that you will not need to keep track of the size. Or you can just do this every time you use a for loop:



    k < array.length





share|improve this answer































    -1














    The problem is the input length is 3 and the output length is 4.



    Scanner sc = new Scanner(System.in);
    
int arr1 = new int[3];
    
int arr2 = new int[3];
    
int i, j, k;
    

    
//Changed 3 below to 4
    

    
for(i = 0; i < 4; i++) {
    
    System.out.print("Masukkan array pertama ke-" + i + ": ");
    
    arr1[i] = sc.nextInt();
    
}
    

    
//Changed 3 below to 4;
    

    
for(j = 0; j < 4; j++) {
    
    System.out.print("Masukkan array kedua ke-" + j + ": ");
    
    arr2[j] = sc.nextInt();
    
}
    

    
for(k = 0; k < 4; k++) {
    
    int arr3 = new int[3];
    
    System.out.println(arr3[k] = arr1[i] + arr2[j]);
    
}





    share|improve this answer



















    • 1





      this answer is plain wrong. your code would crash on arrayIndexOutOfBounds. The length of the arrays is still 3, while you are going to look for fourth elements

      – Stultuske
      Nov 13 '18 at 12:23











    • Using this data: arr1 = {1, 2, 3, 4} arr2 = {1, 2, 3, 4} arr3 = {2, 4, 6, 8} the length of each array is 4.

      – Jolaosho batmat
      Nov 13 '18 at 12:35













    • int arr1 = new int[3]; int arr2 = new int[3];

      – Stultuske
      Nov 13 '18 at 14:20











    Your Answer






    StackExchange.ifUsing("editor", function () {
    StackExchange.using("externalEditor", function () {
    StackExchange.using("snippets", function () {
    StackExchange.snippets.init();
    });
    });
    }, "code-snippets");

    StackExchange.ready(function() {
    var channelOptions = {
    tags: "".split(" "),
    id: "1"
    };
    initTagRenderer("".split(" "), "".split(" "), channelOptions);

    StackExchange.using("externalEditor", function() {
    // Have to fire editor after snippets, if snippets enabled
    if (StackExchange.settings.snippets.snippetsEnabled) {
    StackExchange.using("snippets", function() {
    createEditor();
    });
    }
    else {
    createEditor();
    }
    });

    function createEditor() {
    StackExchange.prepareEditor({
    heartbeatType: 'answer',
    autoActivateHeartbeat: false,
    convertImagesToLinks: true,
    noModals: true,
    showLowRepImageUploadWarning: true,
    reputationToPostImages: 10,
    bindNavPrevention: true,
    postfix: "",
    imageUploader: {
    brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
    contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
    allowUrls: true
    },
    onDemand: true,
    discardSelector: ".discard-answer"
    ,immediatelyShowMarkdownHelp:true
    });


    }
    });














    draft saved

    draft discarded


















    StackExchange.ready(
    function () {
    StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53280742%2fsumming-2-arrays-to-third-array%23new-answer', 'question_page');
    }
    );

    Post as a guest















    Required, but never shown

























    3 Answers
    3






    active

    oldest

    votes








    3 Answers
    3






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    0














    for(k = 0; k < 4; k++) {
    
        int arr3 = new int[3];
    
        System.out.println(arr3[k] = arr1[i] + arr2[j]);
    
    }


    two major mistakes here. You do k < 4, while you should do k < 3
    Also, you shouldn't re-create the array each iteration. Try this:



    int arr3 = new int[3];
    
for(k = 0; k < 3; k++) {
    
        arr3[k] = arr1[k] + arr2[k]; // i and j don't make sense here.
    
    }


    Printing the arrays, you can do after this.






    share|improve this answer


























    • thank you, silly me for doing such a simple mistake!

      – Rizky Putra Pradhana Budiman
      Nov 13 '18 at 12:31
















    0














    for(k = 0; k < 4; k++) {
    
        int arr3 = new int[3];
    
        System.out.println(arr3[k] = arr1[i] + arr2[j]);
    
    }


    two major mistakes here. You do k < 4, while you should do k < 3
    Also, you shouldn't re-create the array each iteration. Try this:



    int arr3 = new int[3];
    
for(k = 0; k < 3; k++) {
    
        arr3[k] = arr1[k] + arr2[k]; // i and j don't make sense here.
    
    }


    Printing the arrays, you can do after this.






    share|improve this answer


























    • thank you, silly me for doing such a simple mistake!

      – Rizky Putra Pradhana Budiman
      Nov 13 '18 at 12:31














    0












    0








    0







    for(k = 0; k < 4; k++) {
    
        int arr3 = new int[3];
    
        System.out.println(arr3[k] = arr1[i] + arr2[j]);
    
    }


    two major mistakes here. You do k < 4, while you should do k < 3
    Also, you shouldn't re-create the array each iteration. Try this:



    int arr3 = new int[3];
    
for(k = 0; k < 3; k++) {
    
        arr3[k] = arr1[k] + arr2[k]; // i and j don't make sense here.
    
    }


    Printing the arrays, you can do after this.






    share|improve this answer















    for(k = 0; k < 4; k++) {
    
        int arr3 = new int[3];
    
        System.out.println(arr3[k] = arr1[i] + arr2[j]);
    
    }


    two major mistakes here. You do k < 4, while you should do k < 3
    Also, you shouldn't re-create the array each iteration. Try this:



    int arr3 = new int[3];
    
for(k = 0; k < 3; k++) {
    
        arr3[k] = arr1[k] + arr2[k]; // i and j don't make sense here.
    
    }


    Printing the arrays, you can do after this.







    share|improve this answer














    share|improve this answer



    share|improve this answer








    edited Nov 13 '18 at 12:23

























    answered Nov 13 '18 at 12:12









    StultuskeStultuske

    6,06811626




    6,06811626













    • thank you, silly me for doing such a simple mistake!

      – Rizky Putra Pradhana Budiman
      Nov 13 '18 at 12:31



















    • thank you, silly me for doing such a simple mistake!

      – Rizky Putra Pradhana Budiman
      Nov 13 '18 at 12:31

















    thank you, silly me for doing such a simple mistake!

    – Rizky Putra Pradhana Budiman
    Nov 13 '18 at 12:31





    thank you, silly me for doing such a simple mistake!

    – Rizky Putra Pradhana Budiman
    Nov 13 '18 at 12:31













    0














    Based on your expected output, your array size should be 4 instead of 3. Your code should look like this



        int arr1 = new int[4]; 
    
    int arr2 = new int[4];


    Your code received an ArrayOutOfBoundsException because the k in your 3rd for loop should be 3 instead of 4 since your k should be less than your array size which is 3. One thing to mention is that instead of hard-coding your array size, it is a better practice to assign a variable to store the size of the array so that you will not need to keep track of the size. Or you can just do this every time you use a for loop:



        k < array.length





    share|improve this answer




























      0














      Based on your expected output, your array size should be 4 instead of 3. Your code should look like this



          int arr1 = new int[4]; 
      
    int arr2 = new int[4];


      Your code received an ArrayOutOfBoundsException because the k in your 3rd for loop should be 3 instead of 4 since your k should be less than your array size which is 3. One thing to mention is that instead of hard-coding your array size, it is a better practice to assign a variable to store the size of the array so that you will not need to keep track of the size. Or you can just do this every time you use a for loop:



          k < array.length





      share|improve this answer


























        0












        0








        0







        Based on your expected output, your array size should be 4 instead of 3. Your code should look like this



            int arr1 = new int[4]; 
        
    int arr2 = new int[4];


        Your code received an ArrayOutOfBoundsException because the k in your 3rd for loop should be 3 instead of 4 since your k should be less than your array size which is 3. One thing to mention is that instead of hard-coding your array size, it is a better practice to assign a variable to store the size of the array so that you will not need to keep track of the size. Or you can just do this every time you use a for loop:



            k < array.length





        share|improve this answer













        Based on your expected output, your array size should be 4 instead of 3. Your code should look like this



            int arr1 = new int[4]; 
        
    int arr2 = new int[4];


        Your code received an ArrayOutOfBoundsException because the k in your 3rd for loop should be 3 instead of 4 since your k should be less than your array size which is 3. One thing to mention is that instead of hard-coding your array size, it is a better practice to assign a variable to store the size of the array so that you will not need to keep track of the size. Or you can just do this every time you use a for loop:



            k < array.length






        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Nov 13 '18 at 23:25









        siang swee kongsiang swee kong

        663




        663























            -1














            The problem is the input length is 3 and the output length is 4.



            Scanner sc = new Scanner(System.in);
            
int arr1 = new int[3];
            
int arr2 = new int[3];
            
int i, j, k;
            

            
//Changed 3 below to 4
            

            
for(i = 0; i < 4; i++) {
            
    System.out.print("Masukkan array pertama ke-" + i + ": ");
            
    arr1[i] = sc.nextInt();
            
}
            

            
//Changed 3 below to 4;
            

            
for(j = 0; j < 4; j++) {
            
    System.out.print("Masukkan array kedua ke-" + j + ": ");
            
    arr2[j] = sc.nextInt();
            
}
            

            
for(k = 0; k < 4; k++) {
            
    int arr3 = new int[3];
            
    System.out.println(arr3[k] = arr1[i] + arr2[j]);
            
}





            share|improve this answer



















            • 1





              this answer is plain wrong. your code would crash on arrayIndexOutOfBounds. The length of the arrays is still 3, while you are going to look for fourth elements

              – Stultuske
              Nov 13 '18 at 12:23











            • Using this data: arr1 = {1, 2, 3, 4} arr2 = {1, 2, 3, 4} arr3 = {2, 4, 6, 8} the length of each array is 4.

              – Jolaosho batmat
              Nov 13 '18 at 12:35













            • int arr1 = new int[3]; int arr2 = new int[3];

              – Stultuske
              Nov 13 '18 at 14:20
















            -1














            The problem is the input length is 3 and the output length is 4.



            Scanner sc = new Scanner(System.in);
            
int arr1 = new int[3];
            
int arr2 = new int[3];
            
int i, j, k;
            

            
//Changed 3 below to 4
            

            
for(i = 0; i < 4; i++) {
            
    System.out.print("Masukkan array pertama ke-" + i + ": ");
            
    arr1[i] = sc.nextInt();
            
}
            

            
//Changed 3 below to 4;
            

            
for(j = 0; j < 4; j++) {
            
    System.out.print("Masukkan array kedua ke-" + j + ": ");
            
    arr2[j] = sc.nextInt();
            
}
            

            
for(k = 0; k < 4; k++) {
            
    int arr3 = new int[3];
            
    System.out.println(arr3[k] = arr1[i] + arr2[j]);
            
}





            share|improve this answer



















            • 1





              this answer is plain wrong. your code would crash on arrayIndexOutOfBounds. The length of the arrays is still 3, while you are going to look for fourth elements

              – Stultuske
              Nov 13 '18 at 12:23











            • Using this data: arr1 = {1, 2, 3, 4} arr2 = {1, 2, 3, 4} arr3 = {2, 4, 6, 8} the length of each array is 4.

              – Jolaosho batmat
              Nov 13 '18 at 12:35













            • int arr1 = new int[3]; int arr2 = new int[3];

              – Stultuske
              Nov 13 '18 at 14:20














            -1












            -1








            -1







            The problem is the input length is 3 and the output length is 4.



            Scanner sc = new Scanner(System.in);
            
int arr1 = new int[3];
            
int arr2 = new int[3];
            
int i, j, k;
            

            
//Changed 3 below to 4
            

            
for(i = 0; i < 4; i++) {
            
    System.out.print("Masukkan array pertama ke-" + i + ": ");
            
    arr1[i] = sc.nextInt();
            
}
            

            
//Changed 3 below to 4;
            

            
for(j = 0; j < 4; j++) {
            
    System.out.print("Masukkan array kedua ke-" + j + ": ");
            
    arr2[j] = sc.nextInt();
            
}
            

            
for(k = 0; k < 4; k++) {
            
    int arr3 = new int[3];
            
    System.out.println(arr3[k] = arr1[i] + arr2[j]);
            
}





            share|improve this answer













            The problem is the input length is 3 and the output length is 4.



            Scanner sc = new Scanner(System.in);
            
int arr1 = new int[3];
            
int arr2 = new int[3];
            
int i, j, k;
            

            
//Changed 3 below to 4
            

            
for(i = 0; i < 4; i++) {
            
    System.out.print("Masukkan array pertama ke-" + i + ": ");
            
    arr1[i] = sc.nextInt();
            
}
            

            
//Changed 3 below to 4;
            

            
for(j = 0; j < 4; j++) {
            
    System.out.print("Masukkan array kedua ke-" + j + ": ");
            
    arr2[j] = sc.nextInt();
            
}
            

            
for(k = 0; k < 4; k++) {
            
    int arr3 = new int[3];
            
    System.out.println(arr3[k] = arr1[i] + arr2[j]);
            
}






            share|improve this answer












            share|improve this answer



            share|improve this answer










            answered Nov 13 '18 at 12:20









            Jolaosho batmatJolaosho batmat

            94




            94








            • 1





              this answer is plain wrong. your code would crash on arrayIndexOutOfBounds. The length of the arrays is still 3, while you are going to look for fourth elements

              – Stultuske
              Nov 13 '18 at 12:23











            • Using this data: arr1 = {1, 2, 3, 4} arr2 = {1, 2, 3, 4} arr3 = {2, 4, 6, 8} the length of each array is 4.

              – Jolaosho batmat
              Nov 13 '18 at 12:35













            • int arr1 = new int[3]; int arr2 = new int[3];

              – Stultuske
              Nov 13 '18 at 14:20














            • 1





              this answer is plain wrong. your code would crash on arrayIndexOutOfBounds. The length of the arrays is still 3, while you are going to look for fourth elements

              – Stultuske
              Nov 13 '18 at 12:23











            • Using this data: arr1 = {1, 2, 3, 4} arr2 = {1, 2, 3, 4} arr3 = {2, 4, 6, 8} the length of each array is 4.

              – Jolaosho batmat
              Nov 13 '18 at 12:35













            • int arr1 = new int[3]; int arr2 = new int[3];

              – Stultuske
              Nov 13 '18 at 14:20








            1




            1





            this answer is plain wrong. your code would crash on arrayIndexOutOfBounds. The length of the arrays is still 3, while you are going to look for fourth elements

            – Stultuske
            Nov 13 '18 at 12:23





            this answer is plain wrong. your code would crash on arrayIndexOutOfBounds. The length of the arrays is still 3, while you are going to look for fourth elements

            – Stultuske
            Nov 13 '18 at 12:23













            Using this data: arr1 = {1, 2, 3, 4} arr2 = {1, 2, 3, 4} arr3 = {2, 4, 6, 8} the length of each array is 4.

            – Jolaosho batmat
            Nov 13 '18 at 12:35







            Using this data: arr1 = {1, 2, 3, 4} arr2 = {1, 2, 3, 4} arr3 = {2, 4, 6, 8} the length of each array is 4.

            – Jolaosho batmat
            Nov 13 '18 at 12:35















            int arr1 = new int[3]; int arr2 = new int[3];

            – Stultuske
            Nov 13 '18 at 14:20





            int arr1 = new int[3]; int arr2 = new int[3];

            – Stultuske
            Nov 13 '18 at 14:20


















            draft saved

            draft discarded




















































            Thanks for contributing an answer to Stack Overflow!


            • Please be sure to answer the question. Provide details and share your research!

            But avoid …



            • Asking for help, clarification, or responding to other answers.

            • Making statements based on opinion; back them up with references or personal experience.


            To learn more, see our tips on writing great answers.




            draft saved


            draft discarded














            StackExchange.ready(
            function () {
            StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53280742%2fsumming-2-arrays-to-third-array%23new-answer', 'question_page');
            }
            );

            Post as a guest















            Required, but never shown





















































            Required, but never shown














            Required, but never shown












            Required, but never shown







            Required, but never shown

































            Required, but never shown














            Required, but never shown












            Required, but never shown







            Required, but never shown







            -

            Popular posts from this blog

            Bressuire

            Image
            Subprefecture and commune in Nouvelle-Aquitaine, France Bressuire Subprefecture and commune Chateau de Bressuire and the Eglise Notre-Dame Coat of arms Location of Bressuire Bressuire Show map of France Bressuire Show map of Nouvelle-Aquitaine Coordinates: 46°50′27″N 0°29′14″W  /  46.8408°N 0.4872°W  / 46.8408; -0.4872 Coordinates: 46°50′27″N 0°29′14″W  /  46.8408°N 0.4872°W  / 46.8408; -0.4872 Country France Region Nouvelle-Aquitaine Department Deux-Sèvres Arrondissement Bressuire Canton Bressuire Government  • Mayor .mw-parser-output .nobold{font-weight:normal} (2014–20) Jean Michel Bernier Area 1 180.59 km 2 (69.73 sq mi) Population (2014) 2 19,300  • Density 110/km 2 (280/sq mi) Time zone UTC+01:00 (CET)  • Summer (DST) UTC+02:00 (CEST) INSEE/Postal code 79049 /79300 Elevation 98–236 m (322–774 ft) (avg. 173 m or 568 ft) 1 French Land Register data, which exclude
            Read more

            Vorschmack

            Image
            Vorschmack Ukrainian Jewish-style vorschmack served on rye bread Course Hors d'oeuvre Region or state Eastern Europe Associated national cuisine Ashkenazi Jewish, Finnish, German, Ukrainian, Polish, Russian Main ingredients Ground meat and/or fish Cookbook: Vorschmack   Media: Vorschmack Vorschmack or forshmak (Yiddish: פֿאָרשמאַק ‎, from archaic German Vorschmack , "foretaste" [1] or "appetizer" [2] ) is an originally East European dish made of salty minced fish or meat. Different variants of this dish are especially common in Ashkenazi Jewish and Finnish cuisine. Some varieties are also known in Russian and Polish cuisine. Contents 1 In Jewish cuisine 2 In Russian cuisine 3 In Polish cuisine 4 In Finnish cuisine 5 See also 6 References In Jewish cuisine According to Gil Marks, the German name points to the possible Germanic origin of this dish. [1] William Pokhlyobkin descr
            Read more

            Quarantine

            Image
            For other uses, see Quarantine (disambiguation). Signal flag "Lima" called the "Yellow Jack" which when flown in harbor means ship is under quarantine. A simple yellow flag (also called the "Yellow Jack") had historically been used to signal quarantine (it stands for Q among signal flags), but now indicates the opposite, as a signal of a ship free of disease that requests boarding and inspection. A quarantine is used to separate and restrict the movement of people; it is 'a restraint upon the activities or communication of persons or the transport of goods designed to prevent the spread of disease or pests', for a certain period of time. [1] This is often used in connection to disease and illness, such as those who may possibly have been exposed to a communicable disease. [2] The term is often erroneously used to mean medical isolation, which is "to separate ill persons who have a communicable disease from those who are healthy
            Read more