PHP/SQL - How can I display distinct values and the number of occurrences?












1














So I am currently using PHP to pull the bodies from emails, parse the data, and insert the data into a user-created DB. I want to display an overview of the data (that is inside the DB) using PHP. Here is an example of what I want to achieve:



This is my table:



Table Name: bldgSensors



 sensor_code | temp_limit | current_temp

 ---------------------------------------

 0102260100A |    55      |     45

 0102260100B |    55      |     50

 0102260100A |    55      |     48


Desired output using PHP:



 Sensors         Count

 0102260100A       2

 0102260100B       1


So far, I can find distinct values but cannot output the total count:



$result1 = mysqli_query($DBconn,"SELECT DISTINCT sensor_code FROM bldgSensors");



              echo "<table border='1'>

              <tr>

              <th>Distinct sensor codes</th>

              <th>Count</th>

              </tr>";



              while($row1 = mysqli_fetch_array($result1))

              {

                echo "<tr>";

                echo "<td>" . $row1['sensor_code'] ."</td>";

              }

              echo "</table>";

              mysqli_close($DBconn);


Thanks so much in advance! This will help tremendously!






php sql count distinct







share|improve this question
























  • Possible duplicate of stackoverflow.com/questions/1346345/…
    – misorude
    Nov 13 '18 at 9:07










  • That duplicate could btw. easily be found by copy&pasting the question title you have chosen into Google verbatim … So please make a proper research effort before asking next time.
    – misorude
    Nov 13 '18 at 9:08


















1














So I am currently using PHP to pull the bodies from emails, parse the data, and insert the data into a user-created DB. I want to display an overview of the data (that is inside the DB) using PHP. Here is an example of what I want to achieve:



This is my table:



Table Name: bldgSensors



 sensor_code | temp_limit | current_temp

 ---------------------------------------

 0102260100A |    55      |     45

 0102260100B |    55      |     50

 0102260100A |    55      |     48


Desired output using PHP:



 Sensors         Count

 0102260100A       2

 0102260100B       1


So far, I can find distinct values but cannot output the total count:



$result1 = mysqli_query($DBconn,"SELECT DISTINCT sensor_code FROM bldgSensors");



              echo "<table border='1'>

              <tr>

              <th>Distinct sensor codes</th>

              <th>Count</th>

              </tr>";



              while($row1 = mysqli_fetch_array($result1))

              {

                echo "<tr>";

                echo "<td>" . $row1['sensor_code'] ."</td>";

              }

              echo "</table>";

              mysqli_close($DBconn);


Thanks so much in advance! This will help tremendously!






php sql count distinct







share|improve this question
























  • Possible duplicate of stackoverflow.com/questions/1346345/…
    – misorude
    Nov 13 '18 at 9:07










  • That duplicate could btw. easily be found by copy&pasting the question title you have chosen into Google verbatim … So please make a proper research effort before asking next time.
    – misorude
    Nov 13 '18 at 9:08
















1












1








1







So I am currently using PHP to pull the bodies from emails, parse the data, and insert the data into a user-created DB. I want to display an overview of the data (that is inside the DB) using PHP. Here is an example of what I want to achieve:



This is my table:



Table Name: bldgSensors



 sensor_code | temp_limit | current_temp

 ---------------------------------------

 0102260100A |    55      |     45

 0102260100B |    55      |     50

 0102260100A |    55      |     48


Desired output using PHP:



 Sensors         Count

 0102260100A       2

 0102260100B       1


So far, I can find distinct values but cannot output the total count:



$result1 = mysqli_query($DBconn,"SELECT DISTINCT sensor_code FROM bldgSensors");



              echo "<table border='1'>

              <tr>

              <th>Distinct sensor codes</th>

              <th>Count</th>

              </tr>";



              while($row1 = mysqli_fetch_array($result1))

              {

                echo "<tr>";

                echo "<td>" . $row1['sensor_code'] ."</td>";

              }

              echo "</table>";

              mysqli_close($DBconn);


Thanks so much in advance! This will help tremendously!






php sql count distinct







share|improve this question















So I am currently using PHP to pull the bodies from emails, parse the data, and insert the data into a user-created DB. I want to display an overview of the data (that is inside the DB) using PHP. Here is an example of what I want to achieve:



This is my table:



Table Name: bldgSensors



 sensor_code | temp_limit | current_temp

 ---------------------------------------

 0102260100A |    55      |     45

 0102260100B |    55      |     50

 0102260100A |    55      |     48


Desired output using PHP:



 Sensors         Count

 0102260100A       2

 0102260100B       1


So far, I can find distinct values but cannot output the total count:



$result1 = mysqli_query($DBconn,"SELECT DISTINCT sensor_code FROM bldgSensors");



              echo "<table border='1'>

              <tr>

              <th>Distinct sensor codes</th>

              <th>Count</th>

              </tr>";



              while($row1 = mysqli_fetch_array($result1))

              {

                echo "<tr>";

                echo "<td>" . $row1['sensor_code'] ."</td>";

              }

              echo "</table>";

              mysqli_close($DBconn);


Thanks so much in advance! This will help tremendously!






php sql count distinct




php sql count distinct






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 13 '18 at 3:02

























asked Nov 13 '18 at 2:57









Chandler Phillips

92




92












  • Possible duplicate of stackoverflow.com/questions/1346345/…
    – misorude
    Nov 13 '18 at 9:07










  • That duplicate could btw. easily be found by copy&pasting the question title you have chosen into Google verbatim … So please make a proper research effort before asking next time.
    – misorude
    Nov 13 '18 at 9:08




















  • Possible duplicate of stackoverflow.com/questions/1346345/…
    – misorude
    Nov 13 '18 at 9:07










  • That duplicate could btw. easily be found by copy&pasting the question title you have chosen into Google verbatim … So please make a proper research effort before asking next time.
    – misorude
    Nov 13 '18 at 9:08


















Possible duplicate of stackoverflow.com/questions/1346345/…
– misorude
Nov 13 '18 at 9:07




Possible duplicate of stackoverflow.com/questions/1346345/…
– misorude
Nov 13 '18 at 9:07












That duplicate could btw. easily be found by copy&pasting the question title you have chosen into Google verbatim … So please make a proper research effort before asking next time.
– misorude
Nov 13 '18 at 9:08






That duplicate could btw. easily be found by copy&pasting the question title you have chosen into Google verbatim … So please make a proper research effort before asking next time.
– misorude
Nov 13 '18 at 9:08














1 Answer
1






active

oldest

votes


















3














You can do that by modifying your query. Use the COUNT and GROUP BY sql functions:



Try this:



$query = "SELECT 

sensor_code, 

COUNT(sensor_code) AS sensorCount

FROM bldgSensors 

GROUP BY sensor_code 

ORDER BY sensorCount DESC";



$result1 = mysqli_query($DBconn, $query);



echo 

'<table border="1">

  <tr>

    <th>Distinct sensor codes</th>

    <th>Count</th>

  </tr>';



  while($row1 = mysqli_fetch_array($result1)){



    echo 

    '<tr>' .



      '<td>' . $row1['sensor_code'] . '</td>' .

      '<td>' . $row1['sensorCount']  . '</td>' .



    '</tr>';



  }



  echo 

  '</table>';



  mysqli_close($DBconn);





share|improve this answer























  • Wow this worked. Thank you so much!! If I could upvote this 1000 times I would.
    – Chandler Phillips
    Nov 13 '18 at 3:44












  • Hey no problem :) Hope the rest of your project goes well. ~Cheers!
    – Joseph_J
    Nov 13 '18 at 3:46













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1 Answer
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oldest

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1 Answer
1






active

oldest

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oldest

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active

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3














You can do that by modifying your query. Use the COUNT and GROUP BY sql functions:



Try this:



$query = "SELECT 

sensor_code, 

COUNT(sensor_code) AS sensorCount

FROM bldgSensors 

GROUP BY sensor_code 

ORDER BY sensorCount DESC";



$result1 = mysqli_query($DBconn, $query);



echo 

'<table border="1">

  <tr>

    <th>Distinct sensor codes</th>

    <th>Count</th>

  </tr>';



  while($row1 = mysqli_fetch_array($result1)){



    echo 

    '<tr>' .



      '<td>' . $row1['sensor_code'] . '</td>' .

      '<td>' . $row1['sensorCount']  . '</td>' .



    '</tr>';



  }



  echo 

  '</table>';



  mysqli_close($DBconn);





share|improve this answer























  • Wow this worked. Thank you so much!! If I could upvote this 1000 times I would.
    – Chandler Phillips
    Nov 13 '18 at 3:44












  • Hey no problem :) Hope the rest of your project goes well. ~Cheers!
    – Joseph_J
    Nov 13 '18 at 3:46


















3














You can do that by modifying your query. Use the COUNT and GROUP BY sql functions:



Try this:



$query = "SELECT 

sensor_code, 

COUNT(sensor_code) AS sensorCount

FROM bldgSensors 

GROUP BY sensor_code 

ORDER BY sensorCount DESC";



$result1 = mysqli_query($DBconn, $query);



echo 

'<table border="1">

  <tr>

    <th>Distinct sensor codes</th>

    <th>Count</th>

  </tr>';



  while($row1 = mysqli_fetch_array($result1)){



    echo 

    '<tr>' .



      '<td>' . $row1['sensor_code'] . '</td>' .

      '<td>' . $row1['sensorCount']  . '</td>' .



    '</tr>';



  }



  echo 

  '</table>';



  mysqli_close($DBconn);





share|improve this answer























  • Wow this worked. Thank you so much!! If I could upvote this 1000 times I would.
    – Chandler Phillips
    Nov 13 '18 at 3:44












  • Hey no problem :) Hope the rest of your project goes well. ~Cheers!
    – Joseph_J
    Nov 13 '18 at 3:46
















3












3








3






You can do that by modifying your query. Use the COUNT and GROUP BY sql functions:



Try this:



$query = "SELECT 

sensor_code, 

COUNT(sensor_code) AS sensorCount

FROM bldgSensors 

GROUP BY sensor_code 

ORDER BY sensorCount DESC";



$result1 = mysqli_query($DBconn, $query);



echo 

'<table border="1">

  <tr>

    <th>Distinct sensor codes</th>

    <th>Count</th>

  </tr>';



  while($row1 = mysqli_fetch_array($result1)){



    echo 

    '<tr>' .



      '<td>' . $row1['sensor_code'] . '</td>' .

      '<td>' . $row1['sensorCount']  . '</td>' .



    '</tr>';



  }



  echo 

  '</table>';



  mysqli_close($DBconn);





share|improve this answer














You can do that by modifying your query. Use the COUNT and GROUP BY sql functions:



Try this:



$query = "SELECT 

sensor_code, 

COUNT(sensor_code) AS sensorCount

FROM bldgSensors 

GROUP BY sensor_code 

ORDER BY sensorCount DESC";



$result1 = mysqli_query($DBconn, $query);



echo 

'<table border="1">

  <tr>

    <th>Distinct sensor codes</th>

    <th>Count</th>

  </tr>';



  while($row1 = mysqli_fetch_array($result1)){



    echo 

    '<tr>' .



      '<td>' . $row1['sensor_code'] . '</td>' .

      '<td>' . $row1['sensorCount']  . '</td>' .



    '</tr>';



  }



  echo 

  '</table>';



  mysqli_close($DBconn);






share|improve this answer














share|improve this answer



share|improve this answer








edited Nov 13 '18 at 3:44

























answered Nov 13 '18 at 3:26









Joseph_J

3,0322620




3,0322620












  • Wow this worked. Thank you so much!! If I could upvote this 1000 times I would.
    – Chandler Phillips
    Nov 13 '18 at 3:44












  • Hey no problem :) Hope the rest of your project goes well. ~Cheers!
    – Joseph_J
    Nov 13 '18 at 3:46




















  • Wow this worked. Thank you so much!! If I could upvote this 1000 times I would.
    – Chandler Phillips
    Nov 13 '18 at 3:44












  • Hey no problem :) Hope the rest of your project goes well. ~Cheers!
    – Joseph_J
    Nov 13 '18 at 3:46


















Wow this worked. Thank you so much!! If I could upvote this 1000 times I would.
– Chandler Phillips
Nov 13 '18 at 3:44






Wow this worked. Thank you so much!! If I could upvote this 1000 times I would.
– Chandler Phillips
Nov 13 '18 at 3:44














Hey no problem :) Hope the rest of your project goes well. ~Cheers!
– Joseph_J
Nov 13 '18 at 3:46






Hey no problem :) Hope the rest of your project goes well. ~Cheers!
– Joseph_J
Nov 13 '18 at 3:46




















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