Multiple select statement on single table
What I want to achieve is give a user the ability to query the database for particular transactions of value say "34666" & name within a given period. Something like:
SELECT * FROM (SELECT * FROM Ledger WHERE transactiondate BETWEEN '2018-01-01' AND '2018-10-10') WHERE name='Customer' OR surnname='Customer' OR fullnames LIKE %Customer% AND (credit="34666" OR debit="34666") sub ORDER BY transactionid ASC;
But the above obviously is not right statement. Just to give an idea of what I want to achieve. Getting an "#1248 - Every derived table must have its own alias" error message with above. Tried using alias but am not really good with complex MySql queries and got it all muddled up.
Table has columns:
transactionid
transactiondate
name
surname
fullnames
credit
debit
amount
reference
Want to loop through and output every row matching the query.
Thanks.
mysql statements
edited Nov 13 '18 at 6:47
Mayur
3,57762652
asked Nov 13 '18 at 6:29
Cmail Ultimate
1616
add a comment |
What I want to achieve is give a user the ability to query the database for particular transactions of value say "34666" & name within a given period. Something like:
SELECT * FROM (SELECT * FROM Ledger WHERE transactiondate BETWEEN '2018-01-01' AND '2018-10-10') WHERE name='Customer' OR surnname='Customer' OR fullnames LIKE %Customer% AND (credit="34666" OR debit="34666") sub ORDER BY transactionid ASC;
But the above obviously is not right statement. Just to give an idea of what I want to achieve. Getting an "#1248 - Every derived table must have its own alias" error message with above. Tried using alias but am not really good with complex MySql queries and got it all muddled up.
Table has columns:
transactionid
transactiondate
name
surname
fullnames
credit
debit
amount
reference
Want to loop through and output every row matching the query.
Thanks.
mysql statements
edited Nov 13 '18 at 6:47
Mayur
3,57762652
asked Nov 13 '18 at 6:29
Cmail Ultimate
1616
Thanks Mayur for the edits that made my question better outlined. You guys have been of more help than I thought possible.
– Cmail Ultimate
Nov 13 '18 at 7:10
add a comment |
What I want to achieve is give a user the ability to query the database for particular transactions of value say "34666" & name within a given period. Something like:
SELECT * FROM (SELECT * FROM Ledger WHERE transactiondate BETWEEN '2018-01-01' AND '2018-10-10') WHERE name='Customer' OR surnname='Customer' OR fullnames LIKE %Customer% AND (credit="34666" OR debit="34666") sub ORDER BY transactionid ASC;
But the above obviously is not right statement. Just to give an idea of what I want to achieve. Getting an "#1248 - Every derived table must have its own alias" error message with above. Tried using alias but am not really good with complex MySql queries and got it all muddled up.
Table has columns:
transactionid
transactiondate
name
surname
fullnames
credit
debit
amount
reference
Want to loop through and output every row matching the query.
Thanks.
mysql statements
edited Nov 13 '18 at 6:47
Mayur
3,57762652
asked Nov 13 '18 at 6:29
Cmail Ultimate
1616
What I want to achieve is give a user the ability to query the database for particular transactions of value say "34666" & name within a given period. Something like:
SELECT * FROM (SELECT * FROM Ledger WHERE transactiondate BETWEEN '2018-01-01' AND '2018-10-10') WHERE name='Customer' OR surnname='Customer' OR fullnames LIKE %Customer% AND (credit="34666" OR debit="34666") sub ORDER BY transactionid ASC;
But the above obviously is not right statement. Just to give an idea of what I want to achieve. Getting an "#1248 - Every derived table must have its own alias" error message with above. Tried using alias but am not really good with complex MySql queries and got it all muddled up.
Table has columns:
transactionid
transactiondate
name
surname
fullnames
credit
debit
amount
reference
Want to loop through and output every row matching the query.
Thanks.
mysql statements
mysql statements
edited Nov 13 '18 at 6:47
Mayur
3,57762652
asked Nov 13 '18 at 6:29
Cmail Ultimate
1616
edited Nov 13 '18 at 6:47
Mayur
3,57762652
asked Nov 13 '18 at 6:29
Cmail Ultimate
1616
edited Nov 13 '18 at 6:47
Mayur
3,57762652
edited Nov 13 '18 at 6:47
Mayur
3,57762652
edited Nov 13 '18 at 6:47
Mayur
3,57762652
3,57762652
asked Nov 13 '18 at 6:29
Cmail Ultimate
1616
asked Nov 13 '18 at 6:29
Cmail Ultimate
1616
asked Nov 13 '18 at 6:29
Cmail Ultimate
1616
1616
Thanks Mayur for the edits that made my question better outlined. You guys have been of more help than I thought possible.
– Cmail Ultimate
Nov 13 '18 at 7:10
add a comment |
Thanks Mayur for the edits that made my question better outlined. You guys have been of more help than I thought possible.
– Cmail Ultimate
Nov 13 '18 at 7:10
Thanks Mayur for the edits that made my question better outlined. You guys have been of more help than I thought possible.
– Cmail Ultimate
Nov 13 '18 at 7:10
Thanks Mayur for the edits that made my question better outlined. You guys have been of more help than I thought possible.
– Cmail Ultimate
Nov 13 '18 at 7:10
add a comment |
2 Answers
2
active
oldest
votes
I don't think you need a subquery here at all, I don't know why you thought to use one:
SELECT *
FROM Ledger
WHERE
transactiondate BETWEEN '2018-01-01' AND '2018-10-10' AND
(name = 'Customer' OR surnname = 'Customer' OR fullnames LIKE '%Customer%') AND
(credit = '34666' OR debit = '34666')
ORDER BY
transactionid;
The exact cause of your error is that your query has a subquery without an alias. There does appear to be an alias sub in there, but it is out place. It should have appeared right after the end of the subquery. But again, I don't think you need a subquery here.
answered Nov 13 '18 at 6:33
Tim Biegeleisen
218k1387140
You Legend! Respects unlimited. Thanks Tim. Obviously could have saved myself much headache if I asked for help hours ago. Thanks.
– Cmail Ultimate
Nov 13 '18 at 7:06
add a comment |
SELECT * FROM
Ledger
WHERE
transactiondate BETWEEN ('2018-01-01') AND ('2018-10-10')
and (name='Customer' OR surnname='Customer' OR fullnames LIKE '%Customer%')
AND (credit='34666' OR debit='34666') ORDER BY transactionid ASC;
answered Nov 13 '18 at 6:57
yusuf hayırsever
1877
Thanks. Am good to go. Tim had it same earlier and solved my nightmare.
– Cmail Ultimate
Nov 13 '18 at 7:08
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
I don't think you need a subquery here at all, I don't know why you thought to use one:
SELECT *
FROM Ledger
WHERE
transactiondate BETWEEN '2018-01-01' AND '2018-10-10' AND
(name = 'Customer' OR surnname = 'Customer' OR fullnames LIKE '%Customer%') AND
(credit = '34666' OR debit = '34666')
ORDER BY
transactionid;
The exact cause of your error is that your query has a subquery without an alias. There does appear to be an alias sub in there, but it is out place. It should have appeared right after the end of the subquery. But again, I don't think you need a subquery here.
answered Nov 13 '18 at 6:33
Tim Biegeleisen
218k1387140
You Legend! Respects unlimited. Thanks Tim. Obviously could have saved myself much headache if I asked for help hours ago. Thanks.
– Cmail Ultimate
Nov 13 '18 at 7:06
add a comment |
I don't think you need a subquery here at all, I don't know why you thought to use one:
SELECT *
FROM Ledger
WHERE
transactiondate BETWEEN '2018-01-01' AND '2018-10-10' AND
(name = 'Customer' OR surnname = 'Customer' OR fullnames LIKE '%Customer%') AND
(credit = '34666' OR debit = '34666')
ORDER BY
transactionid;
The exact cause of your error is that your query has a subquery without an alias. There does appear to be an alias sub in there, but it is out place. It should have appeared right after the end of the subquery. But again, I don't think you need a subquery here.
answered Nov 13 '18 at 6:33
Tim Biegeleisen
218k1387140
You Legend! Respects unlimited. Thanks Tim. Obviously could have saved myself much headache if I asked for help hours ago. Thanks.
– Cmail Ultimate
Nov 13 '18 at 7:06
add a comment |
I don't think you need a subquery here at all, I don't know why you thought to use one:
SELECT *
FROM Ledger
WHERE
transactiondate BETWEEN '2018-01-01' AND '2018-10-10' AND
(name = 'Customer' OR surnname = 'Customer' OR fullnames LIKE '%Customer%') AND
(credit = '34666' OR debit = '34666')
ORDER BY
transactionid;
The exact cause of your error is that your query has a subquery without an alias. There does appear to be an alias sub in there, but it is out place. It should have appeared right after the end of the subquery. But again, I don't think you need a subquery here.
answered Nov 13 '18 at 6:33
Tim Biegeleisen
218k1387140
I don't think you need a subquery here at all, I don't know why you thought to use one:
SELECT *
FROM Ledger
WHERE
transactiondate BETWEEN '2018-01-01' AND '2018-10-10' AND
(name = 'Customer' OR surnname = 'Customer' OR fullnames LIKE '%Customer%') AND
(credit = '34666' OR debit = '34666')
ORDER BY
transactionid;
The exact cause of your error is that your query has a subquery without an alias. There does appear to be an alias sub in there, but it is out place. It should have appeared right after the end of the subquery. But again, I don't think you need a subquery here.
answered Nov 13 '18 at 6:33
Tim Biegeleisen
218k1387140
answered Nov 13 '18 at 6:33
Tim Biegeleisen
218k1387140
answered Nov 13 '18 at 6:33
Tim Biegeleisen
218k1387140
answered Nov 13 '18 at 6:33
Tim Biegeleisen
218k1387140
218k1387140
You Legend! Respects unlimited. Thanks Tim. Obviously could have saved myself much headache if I asked for help hours ago. Thanks.
– Cmail Ultimate
Nov 13 '18 at 7:06
add a comment |
You Legend! Respects unlimited. Thanks Tim. Obviously could have saved myself much headache if I asked for help hours ago. Thanks.
– Cmail Ultimate
Nov 13 '18 at 7:06
You Legend! Respects unlimited. Thanks Tim. Obviously could have saved myself much headache if I asked for help hours ago. Thanks.
– Cmail Ultimate
Nov 13 '18 at 7:06
You Legend! Respects unlimited. Thanks Tim. Obviously could have saved myself much headache if I asked for help hours ago. Thanks.
– Cmail Ultimate
Nov 13 '18 at 7:06
add a comment |
SELECT * FROM
Ledger
WHERE
transactiondate BETWEEN ('2018-01-01') AND ('2018-10-10')
and (name='Customer' OR surnname='Customer' OR fullnames LIKE '%Customer%')
AND (credit='34666' OR debit='34666') ORDER BY transactionid ASC;
answered Nov 13 '18 at 6:57
yusuf hayırsever
1877
Thanks. Am good to go. Tim had it same earlier and solved my nightmare.
– Cmail Ultimate
Nov 13 '18 at 7:08
add a comment |
SELECT * FROM
Ledger
WHERE
transactiondate BETWEEN ('2018-01-01') AND ('2018-10-10')
and (name='Customer' OR surnname='Customer' OR fullnames LIKE '%Customer%')
AND (credit='34666' OR debit='34666') ORDER BY transactionid ASC;
answered Nov 13 '18 at 6:57
yusuf hayırsever
1877
Thanks. Am good to go. Tim had it same earlier and solved my nightmare.
– Cmail Ultimate
Nov 13 '18 at 7:08
add a comment |
SELECT * FROM
Ledger
WHERE
transactiondate BETWEEN ('2018-01-01') AND ('2018-10-10')
and (name='Customer' OR surnname='Customer' OR fullnames LIKE '%Customer%')
AND (credit='34666' OR debit='34666') ORDER BY transactionid ASC;
answered Nov 13 '18 at 6:57
yusuf hayırsever
1877
SELECT * FROM
Ledger
WHERE
transactiondate BETWEEN ('2018-01-01') AND ('2018-10-10')
and (name='Customer' OR surnname='Customer' OR fullnames LIKE '%Customer%')
AND (credit='34666' OR debit='34666') ORDER BY transactionid ASC;
answered Nov 13 '18 at 6:57
yusuf hayırsever
1877
answered Nov 13 '18 at 6:57
yusuf hayırsever
1877
answered Nov 13 '18 at 6:57
yusuf hayırsever
1877
answered Nov 13 '18 at 6:57
yusuf hayırsever
1877
1877
Thanks. Am good to go. Tim had it same earlier and solved my nightmare.
– Cmail Ultimate
Nov 13 '18 at 7:08
add a comment |
Thanks. Am good to go. Tim had it same earlier and solved my nightmare.
– Cmail Ultimate
Nov 13 '18 at 7:08
Thanks. Am good to go. Tim had it same earlier and solved my nightmare.
– Cmail Ultimate
Nov 13 '18 at 7:08
Thanks. Am good to go. Tim had it same earlier and solved my nightmare.
– Cmail Ultimate
Nov 13 '18 at 7:08
add a comment |
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Thanks Mayur for the edits that made my question better outlined. You guys have been of more help than I thought possible.
– Cmail Ultimate
Nov 13 '18 at 7:10