How to fetch attendance report from attendance table through mysql query?
I create an attendances table. I insert data success fully but when fetch the data from attendances table, data not show of my needs attendance table.
in_out column keeps reference for in and out time. Value "1" is for in time and value "2" for out time.
This is my query.
SELECT t.person_id,
t.date,
Substring_index(t.in_out, '#', 1) am_in,
Substring_index(Substring_index(t.in_out, '#', 2), '#', -1) am_out
FROM (SELECT h.person_id,
h.date,
Group_concat(h.timedata ORDER BY h.in_out SEPARATOR '#') in_out
FROM attendances h
GROUP BY h.person_id,
h.date) t
When person out time dose not enter the vale of in time show in time_out column
I want to show null column instead of same repeating time.
I want this result.
mysql sql
edited Nov 13 '18 at 12:29
Gordon Linoff
760k35294399
asked Nov 13 '18 at 6:23
AHMED NISAR
82
add a comment |
I create an attendances table. I insert data success fully but when fetch the data from attendances table, data not show of my needs attendance table.
in_out column keeps reference for in and out time. Value "1" is for in time and value "2" for out time.
This is my query.
SELECT t.person_id,
t.date,
Substring_index(t.in_out, '#', 1) am_in,
Substring_index(Substring_index(t.in_out, '#', 2), '#', -1) am_out
FROM (SELECT h.person_id,
h.date,
Group_concat(h.timedata ORDER BY h.in_out SEPARATOR '#') in_out
FROM attendances h
GROUP BY h.person_id,
h.date) t
When person out time dose not enter the vale of in time show in time_out column
I want to show null column instead of same repeating time.
I want this result.
mysql sql
edited Nov 13 '18 at 12:29
Gordon Linoff
760k35294399
asked Nov 13 '18 at 6:23
AHMED NISAR
82
Can you provide table data so that it will be easy to understand
– Nakul
Nov 13 '18 at 6:51
add a comment |
I create an attendances table. I insert data success fully but when fetch the data from attendances table, data not show of my needs attendance table.
in_out column keeps reference for in and out time. Value "1" is for in time and value "2" for out time.
This is my query.
SELECT t.person_id,
t.date,
Substring_index(t.in_out, '#', 1) am_in,
Substring_index(Substring_index(t.in_out, '#', 2), '#', -1) am_out
FROM (SELECT h.person_id,
h.date,
Group_concat(h.timedata ORDER BY h.in_out SEPARATOR '#') in_out
FROM attendances h
GROUP BY h.person_id,
h.date) t
When person out time dose not enter the vale of in time show in time_out column
I want to show null column instead of same repeating time.
I want this result.
mysql sql
edited Nov 13 '18 at 12:29
Gordon Linoff
760k35294399
asked Nov 13 '18 at 6:23
AHMED NISAR
82
I create an attendances table. I insert data success fully but when fetch the data from attendances table, data not show of my needs attendance table.
in_out column keeps reference for in and out time. Value "1" is for in time and value "2" for out time.
This is my query.
SELECT t.person_id,
t.date,
Substring_index(t.in_out, '#', 1) am_in,
Substring_index(Substring_index(t.in_out, '#', 2), '#', -1) am_out
FROM (SELECT h.person_id,
h.date,
Group_concat(h.timedata ORDER BY h.in_out SEPARATOR '#') in_out
FROM attendances h
GROUP BY h.person_id,
h.date) t
When person out time dose not enter the vale of in time show in time_out column
I want to show null column instead of same repeating time.
I want this result.
mysql sql
mysql sql
edited Nov 13 '18 at 12:29
Gordon Linoff
760k35294399
asked Nov 13 '18 at 6:23
AHMED NISAR
82
edited Nov 13 '18 at 12:29
Gordon Linoff
760k35294399
asked Nov 13 '18 at 6:23
AHMED NISAR
82
edited Nov 13 '18 at 12:29
Gordon Linoff
760k35294399
edited Nov 13 '18 at 12:29
Gordon Linoff
760k35294399
edited Nov 13 '18 at 12:29
Gordon Linoff
760k35294399
760k35294399
asked Nov 13 '18 at 6:23
AHMED NISAR
82
asked Nov 13 '18 at 6:23
AHMED NISAR
82
asked Nov 13 '18 at 6:23
AHMED NISAR
82
82
Can you provide table data so that it will be easy to understand
– Nakul
Nov 13 '18 at 6:51
add a comment |
Can you provide table data so that it will be easy to understand
– Nakul
Nov 13 '18 at 6:51
Can you provide table data so that it will be easy to understand
– Nakul
Nov 13 '18 at 6:51
Can you provide table data so that it will be easy to understand
– Nakul
Nov 13 '18 at 6:51
add a comment |
1 Answer
1
active
oldest
votes
You can try using CASE WHEN Expression
select t.person_id,t.date,
substring_index(t.in_out,'#',1) am_in,
case when substring_index(t.in_out,'#',1)=substring_index(substring_index(t.in_out,'#',2),'#',-1) then 'Can not scan' else substring_index(substring_index(t.in_out,'#',2),'#',-1) end as am_out
from
(
select h.person_id,h.date,group_concat(h.timedata order by h.in_out separator '#') in_out from attendances h group by h.person_id,h.date
) t
answered Nov 13 '18 at 6:32
fa06
11.3k2917
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
You can try using CASE WHEN Expression
select t.person_id,t.date,
substring_index(t.in_out,'#',1) am_in,
case when substring_index(t.in_out,'#',1)=substring_index(substring_index(t.in_out,'#',2),'#',-1) then 'Can not scan' else substring_index(substring_index(t.in_out,'#',2),'#',-1) end as am_out
from
(
select h.person_id,h.date,group_concat(h.timedata order by h.in_out separator '#') in_out from attendances h group by h.person_id,h.date
) t
answered Nov 13 '18 at 6:32
fa06
11.3k2917
add a comment |
You can try using CASE WHEN Expression
select t.person_id,t.date,
substring_index(t.in_out,'#',1) am_in,
case when substring_index(t.in_out,'#',1)=substring_index(substring_index(t.in_out,'#',2),'#',-1) then 'Can not scan' else substring_index(substring_index(t.in_out,'#',2),'#',-1) end as am_out
from
(
select h.person_id,h.date,group_concat(h.timedata order by h.in_out separator '#') in_out from attendances h group by h.person_id,h.date
) t
answered Nov 13 '18 at 6:32
fa06
11.3k2917
add a comment |
You can try using CASE WHEN Expression
select t.person_id,t.date,
substring_index(t.in_out,'#',1) am_in,
case when substring_index(t.in_out,'#',1)=substring_index(substring_index(t.in_out,'#',2),'#',-1) then 'Can not scan' else substring_index(substring_index(t.in_out,'#',2),'#',-1) end as am_out
from
(
select h.person_id,h.date,group_concat(h.timedata order by h.in_out separator '#') in_out from attendances h group by h.person_id,h.date
) t
answered Nov 13 '18 at 6:32
fa06
11.3k2917
You can try using CASE WHEN Expression
select t.person_id,t.date,
substring_index(t.in_out,'#',1) am_in,
case when substring_index(t.in_out,'#',1)=substring_index(substring_index(t.in_out,'#',2),'#',-1) then 'Can not scan' else substring_index(substring_index(t.in_out,'#',2),'#',-1) end as am_out
from
(
select h.person_id,h.date,group_concat(h.timedata order by h.in_out separator '#') in_out from attendances h group by h.person_id,h.date
) t
answered Nov 13 '18 at 6:32
fa06
11.3k2917
answered Nov 13 '18 at 6:32
fa06
11.3k2917
answered Nov 13 '18 at 6:32
fa06
11.3k2917
answered Nov 13 '18 at 6:32
fa06
11.3k2917
11.3k2917
add a comment |
add a comment |
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Can you provide table data so that it will be easy to understand
– Nakul
Nov 13 '18 at 6:51