SQL Get the total count of registered user in day by day
-2
Can you help me to construct a query. The scenario is this, I want to get the total value of the registered users each day.
mysql sql mysqli pivot
asked Oct 8 '18 at 4:54
CAR
13
|
show 1 more comment
-2
Can you help me to construct a query. The scenario is this, I want to get the total value of the registered users each day.
mysql sql mysqli pivot
asked Oct 8 '18 at 4:54
CAR
13
2
provide your expected output and sample data
– fa06
Oct 8 '18 at 4:55
Where is your sample data?
– Noor A Shuvo
Oct 8 '18 at 5:10
Hello there! I've updated my post. I include that sample and output data
– CAR
Oct 8 '18 at 5:52
Sorry the output is wrong i want it day by day for a week maybe. Example This monday until Sunday
– CAR
Oct 8 '18 at 6:00
1
Which DBMS product are you using? "SQL" is just a query language, not the name of a specific database product. Please add a tag for the database product you are usingpostgresql,oracle,sql-server,db2, ...
– a_horse_with_no_name
Oct 8 '18 at 6:00
|
show 1 more comment
-2
-2
-2
Can you help me to construct a query. The scenario is this, I want to get the total value of the registered users each day.
mysql sql mysqli pivot
asked Oct 8 '18 at 4:54
CAR
13
Can you help me to construct a query. The scenario is this, I want to get the total value of the registered users each day.
mysql sql mysqli pivot
mysql sql mysqli pivot
asked Oct 8 '18 at 4:54
CAR
13
asked Oct 8 '18 at 4:54
CAR
13
edited Nov 13 '18 at 5:46
asked Oct 8 '18 at 4:54
CAR
13
asked Oct 8 '18 at 4:54
CAR
13
asked Oct 8 '18 at 4:54
CAR
13
13
2
provide your expected output and sample data
– fa06
Oct 8 '18 at 4:55
Where is your sample data?
– Noor A Shuvo
Oct 8 '18 at 5:10
Hello there! I've updated my post. I include that sample and output data
– CAR
Oct 8 '18 at 5:52
Sorry the output is wrong i want it day by day for a week maybe. Example This monday until Sunday
– CAR
Oct 8 '18 at 6:00
1
Which DBMS product are you using? "SQL" is just a query language, not the name of a specific database product. Please add a tag for the database product you are usingpostgresql,oracle,sql-server,db2, ...
– a_horse_with_no_name
Oct 8 '18 at 6:00
|
show 1 more comment
2
provide your expected output and sample data
– fa06
Oct 8 '18 at 4:55
Where is your sample data?
– Noor A Shuvo
Oct 8 '18 at 5:10
Hello there! I've updated my post. I include that sample and output data
– CAR
Oct 8 '18 at 5:52
Sorry the output is wrong i want it day by day for a week maybe. Example This monday until Sunday
– CAR
Oct 8 '18 at 6:00
1
Which DBMS product are you using? "SQL" is just a query language, not the name of a specific database product. Please add a tag for the database product you are usingpostgresql,oracle,sql-server,db2, ...
– a_horse_with_no_name
Oct 8 '18 at 6:00
2
2
provide your expected output and sample data
– fa06
Oct 8 '18 at 4:55
provide your expected output and sample data
– fa06
Oct 8 '18 at 4:55
Where is your sample data?
– Noor A Shuvo
Oct 8 '18 at 5:10
Where is your sample data?
– Noor A Shuvo
Oct 8 '18 at 5:10
Hello there! I've updated my post. I include that sample and output data
– CAR
Oct 8 '18 at 5:52
Hello there! I've updated my post. I include that sample and output data
– CAR
Oct 8 '18 at 5:52
Sorry the output is wrong i want it day by day for a week maybe. Example This monday until Sunday
– CAR
Oct 8 '18 at 6:00
Sorry the output is wrong i want it day by day for a week maybe. Example This monday until Sunday
– CAR
Oct 8 '18 at 6:00
1
1
Which DBMS product are you using? "SQL" is just a query language, not the name of a specific database product. Please add a tag for the database product you are using
postgresql, oracle, sql-server, db2, ...– a_horse_with_no_name
Oct 8 '18 at 6:00
Which DBMS product are you using? "SQL" is just a query language, not the name of a specific database product. Please add a tag for the database product you are using
postgresql, oracle, sql-server, db2, ...– a_horse_with_no_name
Oct 8 '18 at 6:00
|
show 1 more comment
4 Answers
4
active
oldest
votes
0
Select count(*)
from tableName
Where registered = true
Group by Date
answered Oct 8 '18 at 5:00
PrathapG
534418
add a comment |
0
Assuming that your registration timestamp is stored at created_at date-time field and table named say user:
SELECT created_at,COUNT(*) as `total registration` FROM `user` GROUP BY (DATE(`user`.`created_at`))
answered Oct 8 '18 at 5:02
Pratik Karmakar
22118
add a comment |
0
The former answers do neither cover the where part nor output the dayname.
This should do both and produce what you want:
create table #data (
reg_id int,
reg_email nvarchar(255),
reg_date datetimeoffset(7)
)
insert into #data(reg_id, reg_email, reg_date)
VALUES
(1, 'a', '2018-10-01'),
(2, 'b', '2018-10-01'),
(3, 'c', '2018-10-02'),
(4, 'd', '2018-10-03'),
(5, 'e', '2018-10-01'),
(6, 'f', '2018-10-02'),
(7, 'g', '2018-10-04'),
(8, 'h', '2018-10-05'),
(9, 'i', '2018-10-05'),
(10, 'j', '2018-10-06')
SELECT count(*), datename(dw, reg_date) from #data
where datepart(week, reg_date) = 40
group by reg_date
drop table #data
assuming that you are using sql server greater or equal 2008!
answered Oct 8 '18 at 6:23
Josef Biehler
15710
add a comment |
0
I finally get the correct data for today and last 7 days. Please refer below query.
SELECT
a.JourneyName,
a.BonusName,
a.Status,
a."Timestamp",
a.MID,
COUNT(CASE WHEN DATEDIFF(DD, a."Timestamp", GETDATE()) = 0 THEN 1 ELSE NULL END) as "Day_1",
COUNT(CASE WHEN DATEDIFF(DD, a."Timestamp", GETDATE()) = 1 THEN 1 ELSE NULL END) as "Day_2",
COUNT(CASE WHEN DATEDIFF(DD, a."Timestamp", GETDATE()) = 2 THEN 1 ELSE NULL END) as "Day_3",
COUNT(CASE WHEN DATEDIFF(DD, a."Timestamp", GETDATE()) = 3 THEN 1 ELSE NULL END) as "Day_4",
COUNT(CASE WHEN DATEDIFF(DD, a."Timestamp", GETDATE()) = 4 THEN 1 ELSE NULL END) as "Day_5",
COUNT(CASE WHEN DATEDIFF(DD, a."Timestamp", GETDATE()) = 5 THEN 1 ELSE NULL END) as "Day_6",
COUNT(CASE WHEN DATEDIFF(DD, a."Timestamp", GETDATE()) = 6 THEN 1 ELSE NULL END) as "Day_7"
FROM
TableName a
WHERE
a."Timestamp" >= DATEADD(DD, -7, GETDATE())
AND a."Timestamp" <= GETDATE()
GROUP BY``
a.JourneyName, a.BonusName, a.Status, a."Timestamp", a.MID
Total Count per day where Day_1 is today, Day_2 is yesterday and so on.
edited Nov 13 '18 at 6:34
Thilina Nakkawita
789927
answered Nov 13 '18 at 5:45
CAR
13
add a comment |
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4 Answers
4
active
oldest
votes
4 Answers
4
active
oldest
votes
active
oldest
votes
active
oldest
votes
0
Select count(*)
from tableName
Where registered = true
Group by Date
answered Oct 8 '18 at 5:00
PrathapG
534418
add a comment |
0
Select count(*)
from tableName
Where registered = true
Group by Date
answered Oct 8 '18 at 5:00
PrathapG
534418
add a comment |
0
0
0
Select count(*)
from tableName
Where registered = true
Group by Date
answered Oct 8 '18 at 5:00
PrathapG
534418
Select count(*)
from tableName
Where registered = true
Group by Date
answered Oct 8 '18 at 5:00
PrathapG
534418
answered Oct 8 '18 at 5:00
PrathapG
534418
answered Oct 8 '18 at 5:00
PrathapG
534418
answered Oct 8 '18 at 5:00
PrathapG
534418
534418
add a comment |
add a comment |
0
Assuming that your registration timestamp is stored at created_at date-time field and table named say user:
SELECT created_at,COUNT(*) as `total registration` FROM `user` GROUP BY (DATE(`user`.`created_at`))
answered Oct 8 '18 at 5:02
Pratik Karmakar
22118
add a comment |
0
Assuming that your registration timestamp is stored at created_at date-time field and table named say user:
SELECT created_at,COUNT(*) as `total registration` FROM `user` GROUP BY (DATE(`user`.`created_at`))
answered Oct 8 '18 at 5:02
Pratik Karmakar
22118
add a comment |
0
0
0
Assuming that your registration timestamp is stored at created_at date-time field and table named say user:
SELECT created_at,COUNT(*) as `total registration` FROM `user` GROUP BY (DATE(`user`.`created_at`))
answered Oct 8 '18 at 5:02
Pratik Karmakar
22118
Assuming that your registration timestamp is stored at created_at date-time field and table named say user:
SELECT created_at,COUNT(*) as `total registration` FROM `user` GROUP BY (DATE(`user`.`created_at`))
answered Oct 8 '18 at 5:02
Pratik Karmakar
22118
answered Oct 8 '18 at 5:02
Pratik Karmakar
22118
answered Oct 8 '18 at 5:02
Pratik Karmakar
22118
answered Oct 8 '18 at 5:02
Pratik Karmakar
22118
22118
add a comment |
add a comment |
0
The former answers do neither cover the where part nor output the dayname.
This should do both and produce what you want:
create table #data (
reg_id int,
reg_email nvarchar(255),
reg_date datetimeoffset(7)
)
insert into #data(reg_id, reg_email, reg_date)
VALUES
(1, 'a', '2018-10-01'),
(2, 'b', '2018-10-01'),
(3, 'c', '2018-10-02'),
(4, 'd', '2018-10-03'),
(5, 'e', '2018-10-01'),
(6, 'f', '2018-10-02'),
(7, 'g', '2018-10-04'),
(8, 'h', '2018-10-05'),
(9, 'i', '2018-10-05'),
(10, 'j', '2018-10-06')
SELECT count(*), datename(dw, reg_date) from #data
where datepart(week, reg_date) = 40
group by reg_date
drop table #data
assuming that you are using sql server greater or equal 2008!
answered Oct 8 '18 at 6:23
Josef Biehler
15710
add a comment |
0
The former answers do neither cover the where part nor output the dayname.
This should do both and produce what you want:
create table #data (
reg_id int,
reg_email nvarchar(255),
reg_date datetimeoffset(7)
)
insert into #data(reg_id, reg_email, reg_date)
VALUES
(1, 'a', '2018-10-01'),
(2, 'b', '2018-10-01'),
(3, 'c', '2018-10-02'),
(4, 'd', '2018-10-03'),
(5, 'e', '2018-10-01'),
(6, 'f', '2018-10-02'),
(7, 'g', '2018-10-04'),
(8, 'h', '2018-10-05'),
(9, 'i', '2018-10-05'),
(10, 'j', '2018-10-06')
SELECT count(*), datename(dw, reg_date) from #data
where datepart(week, reg_date) = 40
group by reg_date
drop table #data
assuming that you are using sql server greater or equal 2008!
answered Oct 8 '18 at 6:23
Josef Biehler
15710
add a comment |
0
0
0
The former answers do neither cover the where part nor output the dayname.
This should do both and produce what you want:
create table #data (
reg_id int,
reg_email nvarchar(255),
reg_date datetimeoffset(7)
)
insert into #data(reg_id, reg_email, reg_date)
VALUES
(1, 'a', '2018-10-01'),
(2, 'b', '2018-10-01'),
(3, 'c', '2018-10-02'),
(4, 'd', '2018-10-03'),
(5, 'e', '2018-10-01'),
(6, 'f', '2018-10-02'),
(7, 'g', '2018-10-04'),
(8, 'h', '2018-10-05'),
(9, 'i', '2018-10-05'),
(10, 'j', '2018-10-06')
SELECT count(*), datename(dw, reg_date) from #data
where datepart(week, reg_date) = 40
group by reg_date
drop table #data
assuming that you are using sql server greater or equal 2008!
answered Oct 8 '18 at 6:23
Josef Biehler
15710
The former answers do neither cover the where part nor output the dayname.
This should do both and produce what you want:
create table #data (
reg_id int,
reg_email nvarchar(255),
reg_date datetimeoffset(7)
)
insert into #data(reg_id, reg_email, reg_date)
VALUES
(1, 'a', '2018-10-01'),
(2, 'b', '2018-10-01'),
(3, 'c', '2018-10-02'),
(4, 'd', '2018-10-03'),
(5, 'e', '2018-10-01'),
(6, 'f', '2018-10-02'),
(7, 'g', '2018-10-04'),
(8, 'h', '2018-10-05'),
(9, 'i', '2018-10-05'),
(10, 'j', '2018-10-06')
SELECT count(*), datename(dw, reg_date) from #data
where datepart(week, reg_date) = 40
group by reg_date
drop table #data
assuming that you are using sql server greater or equal 2008!
answered Oct 8 '18 at 6:23
Josef Biehler
15710
answered Oct 8 '18 at 6:23
Josef Biehler
15710
answered Oct 8 '18 at 6:23
Josef Biehler
15710
answered Oct 8 '18 at 6:23
Josef Biehler
15710
15710
add a comment |
add a comment |
0
I finally get the correct data for today and last 7 days. Please refer below query.
SELECT
a.JourneyName,
a.BonusName,
a.Status,
a."Timestamp",
a.MID,
COUNT(CASE WHEN DATEDIFF(DD, a."Timestamp", GETDATE()) = 0 THEN 1 ELSE NULL END) as "Day_1",
COUNT(CASE WHEN DATEDIFF(DD, a."Timestamp", GETDATE()) = 1 THEN 1 ELSE NULL END) as "Day_2",
COUNT(CASE WHEN DATEDIFF(DD, a."Timestamp", GETDATE()) = 2 THEN 1 ELSE NULL END) as "Day_3",
COUNT(CASE WHEN DATEDIFF(DD, a."Timestamp", GETDATE()) = 3 THEN 1 ELSE NULL END) as "Day_4",
COUNT(CASE WHEN DATEDIFF(DD, a."Timestamp", GETDATE()) = 4 THEN 1 ELSE NULL END) as "Day_5",
COUNT(CASE WHEN DATEDIFF(DD, a."Timestamp", GETDATE()) = 5 THEN 1 ELSE NULL END) as "Day_6",
COUNT(CASE WHEN DATEDIFF(DD, a."Timestamp", GETDATE()) = 6 THEN 1 ELSE NULL END) as "Day_7"
FROM
TableName a
WHERE
a."Timestamp" >= DATEADD(DD, -7, GETDATE())
AND a."Timestamp" <= GETDATE()
GROUP BY``
a.JourneyName, a.BonusName, a.Status, a."Timestamp", a.MID
Total Count per day where Day_1 is today, Day_2 is yesterday and so on.
edited Nov 13 '18 at 6:34
Thilina Nakkawita
789927
answered Nov 13 '18 at 5:45
CAR
13
add a comment |
0
I finally get the correct data for today and last 7 days. Please refer below query.
SELECT
a.JourneyName,
a.BonusName,
a.Status,
a."Timestamp",
a.MID,
COUNT(CASE WHEN DATEDIFF(DD, a."Timestamp", GETDATE()) = 0 THEN 1 ELSE NULL END) as "Day_1",
COUNT(CASE WHEN DATEDIFF(DD, a."Timestamp", GETDATE()) = 1 THEN 1 ELSE NULL END) as "Day_2",
COUNT(CASE WHEN DATEDIFF(DD, a."Timestamp", GETDATE()) = 2 THEN 1 ELSE NULL END) as "Day_3",
COUNT(CASE WHEN DATEDIFF(DD, a."Timestamp", GETDATE()) = 3 THEN 1 ELSE NULL END) as "Day_4",
COUNT(CASE WHEN DATEDIFF(DD, a."Timestamp", GETDATE()) = 4 THEN 1 ELSE NULL END) as "Day_5",
COUNT(CASE WHEN DATEDIFF(DD, a."Timestamp", GETDATE()) = 5 THEN 1 ELSE NULL END) as "Day_6",
COUNT(CASE WHEN DATEDIFF(DD, a."Timestamp", GETDATE()) = 6 THEN 1 ELSE NULL END) as "Day_7"
FROM
TableName a
WHERE
a."Timestamp" >= DATEADD(DD, -7, GETDATE())
AND a."Timestamp" <= GETDATE()
GROUP BY``
a.JourneyName, a.BonusName, a.Status, a."Timestamp", a.MID
Total Count per day where Day_1 is today, Day_2 is yesterday and so on.
edited Nov 13 '18 at 6:34
Thilina Nakkawita
789927
answered Nov 13 '18 at 5:45
CAR
13
add a comment |
0
0
0
I finally get the correct data for today and last 7 days. Please refer below query.
SELECT
a.JourneyName,
a.BonusName,
a.Status,
a."Timestamp",
a.MID,
COUNT(CASE WHEN DATEDIFF(DD, a."Timestamp", GETDATE()) = 0 THEN 1 ELSE NULL END) as "Day_1",
COUNT(CASE WHEN DATEDIFF(DD, a."Timestamp", GETDATE()) = 1 THEN 1 ELSE NULL END) as "Day_2",
COUNT(CASE WHEN DATEDIFF(DD, a."Timestamp", GETDATE()) = 2 THEN 1 ELSE NULL END) as "Day_3",
COUNT(CASE WHEN DATEDIFF(DD, a."Timestamp", GETDATE()) = 3 THEN 1 ELSE NULL END) as "Day_4",
COUNT(CASE WHEN DATEDIFF(DD, a."Timestamp", GETDATE()) = 4 THEN 1 ELSE NULL END) as "Day_5",
COUNT(CASE WHEN DATEDIFF(DD, a."Timestamp", GETDATE()) = 5 THEN 1 ELSE NULL END) as "Day_6",
COUNT(CASE WHEN DATEDIFF(DD, a."Timestamp", GETDATE()) = 6 THEN 1 ELSE NULL END) as "Day_7"
FROM
TableName a
WHERE
a."Timestamp" >= DATEADD(DD, -7, GETDATE())
AND a."Timestamp" <= GETDATE()
GROUP BY``
a.JourneyName, a.BonusName, a.Status, a."Timestamp", a.MID
Total Count per day where Day_1 is today, Day_2 is yesterday and so on.
edited Nov 13 '18 at 6:34
Thilina Nakkawita
789927
answered Nov 13 '18 at 5:45
CAR
13
I finally get the correct data for today and last 7 days. Please refer below query.
SELECT
a.JourneyName,
a.BonusName,
a.Status,
a."Timestamp",
a.MID,
COUNT(CASE WHEN DATEDIFF(DD, a."Timestamp", GETDATE()) = 0 THEN 1 ELSE NULL END) as "Day_1",
COUNT(CASE WHEN DATEDIFF(DD, a."Timestamp", GETDATE()) = 1 THEN 1 ELSE NULL END) as "Day_2",
COUNT(CASE WHEN DATEDIFF(DD, a."Timestamp", GETDATE()) = 2 THEN 1 ELSE NULL END) as "Day_3",
COUNT(CASE WHEN DATEDIFF(DD, a."Timestamp", GETDATE()) = 3 THEN 1 ELSE NULL END) as "Day_4",
COUNT(CASE WHEN DATEDIFF(DD, a."Timestamp", GETDATE()) = 4 THEN 1 ELSE NULL END) as "Day_5",
COUNT(CASE WHEN DATEDIFF(DD, a."Timestamp", GETDATE()) = 5 THEN 1 ELSE NULL END) as "Day_6",
COUNT(CASE WHEN DATEDIFF(DD, a."Timestamp", GETDATE()) = 6 THEN 1 ELSE NULL END) as "Day_7"
FROM
TableName a
WHERE
a."Timestamp" >= DATEADD(DD, -7, GETDATE())
AND a."Timestamp" <= GETDATE()
GROUP BY``
a.JourneyName, a.BonusName, a.Status, a."Timestamp", a.MID
Total Count per day where Day_1 is today, Day_2 is yesterday and so on.
edited Nov 13 '18 at 6:34
Thilina Nakkawita
789927
answered Nov 13 '18 at 5:45
CAR
13
edited Nov 13 '18 at 6:34
Thilina Nakkawita
789927
edited Nov 13 '18 at 6:34
Thilina Nakkawita
789927
edited Nov 13 '18 at 6:34
Thilina Nakkawita
789927
789927
answered Nov 13 '18 at 5:45
CAR
13
answered Nov 13 '18 at 5:45
CAR
13
answered Nov 13 '18 at 5:45
CAR
13
13
add a comment |
add a comment |
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2
provide your expected output and sample data
– fa06
Oct 8 '18 at 4:55
Where is your sample data?
– Noor A Shuvo
Oct 8 '18 at 5:10
Hello there! I've updated my post. I include that sample and output data
– CAR
Oct 8 '18 at 5:52
Sorry the output is wrong i want it day by day for a week maybe. Example This monday until Sunday
– CAR
Oct 8 '18 at 6:00
1
Which DBMS product are you using? "SQL" is just a query language, not the name of a specific database product. Please add a tag for the database product you are using
postgresql,oracle,sql-server,db2, ...– a_horse_with_no_name
Oct 8 '18 at 6:00