MongoDB: $sum after $lookup array
2
I have this query and I'm using $lookup, after this I want to sum the value in the array that lookup provides.
My Query(i'm using mongoose):
User.aggregate([{
$match: {
storeKey: req.body.store,
}
},
{
$group: {
_id: {
id: "$_id",
name: "$name",
cpf: "$cpf",
phone: "$phone",
email: "$email",
birthday: "$birthday"
},
totalServices: {
$sum: "$services"
}
}
},
{
$lookup: {
from: "schedules",
localField: "_id.phone",
foreignField: "customer.phone",
as: "user_detail"
}
},
{ $project: { "user_detail.value": 1 } },
])
The result of my query (a sample collection):
{
"_id": {
"id": "5bd89899bda5c343749d00f0",
"name": "marcio",
"cpf": null,
"phone": "11999999999",
"email": "marcio@gmail.com",
"birthday": "2018-10-30T17:44:57.834Z"
},
"user_detail": [
{
"value": 50
},
{
"value": 50
},
{
"value": 40
},
{
"value": 20
},
{
"value": 20
},
{
"value": 50
},
{
"value": 18
},
{
"value": 20
},
{
"value": 20
},
{
"value": 10
},
{
"value": 120
},
{
"value": 50
},
{
"value": 120
},
{
"value": 20
},
{
"value": 20
},
{
"value": 25
},
{
"value": 20
},
{
"value": 20
},
{
"value": 20
},
{
"value": 10
},
{
"value": 20
},
{
"value": 20
},
{
"value": 35
},
{
"value": 20
},
{
"value": 20
}
]
}
How can I sum all that fields of value and show that result of this sum with the result of my first $group?
node.js mongodb mongoose mongodb-query aggregation-framework
edited Nov 12 at 18:58
Anthony Winzlet
13.8k41239
asked Nov 12 at 18:47
Matheus
383216
add a comment |
2
I have this query and I'm using $lookup, after this I want to sum the value in the array that lookup provides.
My Query(i'm using mongoose):
User.aggregate([{
$match: {
storeKey: req.body.store,
}
},
{
$group: {
_id: {
id: "$_id",
name: "$name",
cpf: "$cpf",
phone: "$phone",
email: "$email",
birthday: "$birthday"
},
totalServices: {
$sum: "$services"
}
}
},
{
$lookup: {
from: "schedules",
localField: "_id.phone",
foreignField: "customer.phone",
as: "user_detail"
}
},
{ $project: { "user_detail.value": 1 } },
])
The result of my query (a sample collection):
{
"_id": {
"id": "5bd89899bda5c343749d00f0",
"name": "marcio",
"cpf": null,
"phone": "11999999999",
"email": "marcio@gmail.com",
"birthday": "2018-10-30T17:44:57.834Z"
},
"user_detail": [
{
"value": 50
},
{
"value": 50
},
{
"value": 40
},
{
"value": 20
},
{
"value": 20
},
{
"value": 50
},
{
"value": 18
},
{
"value": 20
},
{
"value": 20
},
{
"value": 10
},
{
"value": 120
},
{
"value": 50
},
{
"value": 120
},
{
"value": 20
},
{
"value": 20
},
{
"value": 25
},
{
"value": 20
},
{
"value": 20
},
{
"value": 20
},
{
"value": 10
},
{
"value": 20
},
{
"value": 20
},
{
"value": 35
},
{
"value": 20
},
{
"value": 20
}
]
}
How can I sum all that fields of value and show that result of this sum with the result of my first $group?
node.js mongodb mongoose mongodb-query aggregation-framework
edited Nov 12 at 18:58
Anthony Winzlet
13.8k41239
asked Nov 12 at 18:47
Matheus
383216
add a comment |
2
2
2
I have this query and I'm using $lookup, after this I want to sum the value in the array that lookup provides.
My Query(i'm using mongoose):
User.aggregate([{
$match: {
storeKey: req.body.store,
}
},
{
$group: {
_id: {
id: "$_id",
name: "$name",
cpf: "$cpf",
phone: "$phone",
email: "$email",
birthday: "$birthday"
},
totalServices: {
$sum: "$services"
}
}
},
{
$lookup: {
from: "schedules",
localField: "_id.phone",
foreignField: "customer.phone",
as: "user_detail"
}
},
{ $project: { "user_detail.value": 1 } },
])
The result of my query (a sample collection):
{
"_id": {
"id": "5bd89899bda5c343749d00f0",
"name": "marcio",
"cpf": null,
"phone": "11999999999",
"email": "marcio@gmail.com",
"birthday": "2018-10-30T17:44:57.834Z"
},
"user_detail": [
{
"value": 50
},
{
"value": 50
},
{
"value": 40
},
{
"value": 20
},
{
"value": 20
},
{
"value": 50
},
{
"value": 18
},
{
"value": 20
},
{
"value": 20
},
{
"value": 10
},
{
"value": 120
},
{
"value": 50
},
{
"value": 120
},
{
"value": 20
},
{
"value": 20
},
{
"value": 25
},
{
"value": 20
},
{
"value": 20
},
{
"value": 20
},
{
"value": 10
},
{
"value": 20
},
{
"value": 20
},
{
"value": 35
},
{
"value": 20
},
{
"value": 20
}
]
}
How can I sum all that fields of value and show that result of this sum with the result of my first $group?
node.js mongodb mongoose mongodb-query aggregation-framework
edited Nov 12 at 18:58
Anthony Winzlet
13.8k41239
asked Nov 12 at 18:47
Matheus
383216
I have this query and I'm using $lookup, after this I want to sum the value in the array that lookup provides.
My Query(i'm using mongoose):
User.aggregate([{
$match: {
storeKey: req.body.store,
}
},
{
$group: {
_id: {
id: "$_id",
name: "$name",
cpf: "$cpf",
phone: "$phone",
email: "$email",
birthday: "$birthday"
},
totalServices: {
$sum: "$services"
}
}
},
{
$lookup: {
from: "schedules",
localField: "_id.phone",
foreignField: "customer.phone",
as: "user_detail"
}
},
{ $project: { "user_detail.value": 1 } },
])
The result of my query (a sample collection):
{
"_id": {
"id": "5bd89899bda5c343749d00f0",
"name": "marcio",
"cpf": null,
"phone": "11999999999",
"email": "marcio@gmail.com",
"birthday": "2018-10-30T17:44:57.834Z"
},
"user_detail": [
{
"value": 50
},
{
"value": 50
},
{
"value": 40
},
{
"value": 20
},
{
"value": 20
},
{
"value": 50
},
{
"value": 18
},
{
"value": 20
},
{
"value": 20
},
{
"value": 10
},
{
"value": 120
},
{
"value": 50
},
{
"value": 120
},
{
"value": 20
},
{
"value": 20
},
{
"value": 25
},
{
"value": 20
},
{
"value": 20
},
{
"value": 20
},
{
"value": 10
},
{
"value": 20
},
{
"value": 20
},
{
"value": 35
},
{
"value": 20
},
{
"value": 20
}
]
}
How can I sum all that fields of value and show that result of this sum with the result of my first $group?
node.js mongodb mongoose mongodb-query aggregation-framework
node.js mongodb mongoose mongodb-query aggregation-framework
edited Nov 12 at 18:58
Anthony Winzlet
13.8k41239
asked Nov 12 at 18:47
Matheus
383216
edited Nov 12 at 18:58
Anthony Winzlet
13.8k41239
asked Nov 12 at 18:47
Matheus
383216
edited Nov 12 at 18:58
Anthony Winzlet
13.8k41239
edited Nov 12 at 18:58
Anthony Winzlet
13.8k41239
edited Nov 12 at 18:58
Anthony Winzlet
13.8k41239
13.8k41239
asked Nov 12 at 18:47
Matheus
383216
asked Nov 12 at 18:47
Matheus
383216
asked Nov 12 at 18:47
Matheus
383216
383216
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
3
You can use $sum aggregation with the array values
db.user.aggregate([
// $group stage
{ "$lookup": {
"from": "schedule",
"localField": "_id.phone",
"foreignField": "customer.phone",
"as": "user_detail"
}},
{ "$project": {
"total": { "$sum": "$user_detail.value" }
}}
])
answered Nov 12 at 18:51
Anthony Winzlet
13.8k41239
1
Work perfect! thanks!
– Matheus
Nov 12 at 18:57
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
3
You can use $sum aggregation with the array values
db.user.aggregate([
// $group stage
{ "$lookup": {
"from": "schedule",
"localField": "_id.phone",
"foreignField": "customer.phone",
"as": "user_detail"
}},
{ "$project": {
"total": { "$sum": "$user_detail.value" }
}}
])
answered Nov 12 at 18:51
Anthony Winzlet
13.8k41239
1
Work perfect! thanks!
– Matheus
Nov 12 at 18:57
add a comment |
3
You can use $sum aggregation with the array values
db.user.aggregate([
// $group stage
{ "$lookup": {
"from": "schedule",
"localField": "_id.phone",
"foreignField": "customer.phone",
"as": "user_detail"
}},
{ "$project": {
"total": { "$sum": "$user_detail.value" }
}}
])
answered Nov 12 at 18:51
Anthony Winzlet
13.8k41239
1
Work perfect! thanks!
– Matheus
Nov 12 at 18:57
add a comment |
3
3
3
You can use $sum aggregation with the array values
db.user.aggregate([
// $group stage
{ "$lookup": {
"from": "schedule",
"localField": "_id.phone",
"foreignField": "customer.phone",
"as": "user_detail"
}},
{ "$project": {
"total": { "$sum": "$user_detail.value" }
}}
])
answered Nov 12 at 18:51
Anthony Winzlet
13.8k41239
You can use $sum aggregation with the array values
db.user.aggregate([
// $group stage
{ "$lookup": {
"from": "schedule",
"localField": "_id.phone",
"foreignField": "customer.phone",
"as": "user_detail"
}},
{ "$project": {
"total": { "$sum": "$user_detail.value" }
}}
])
answered Nov 12 at 18:51
Anthony Winzlet
13.8k41239
answered Nov 12 at 18:51
Anthony Winzlet
13.8k41239
answered Nov 12 at 18:51
Anthony Winzlet
13.8k41239
answered Nov 12 at 18:51
Anthony Winzlet
13.8k41239
13.8k41239
1
Work perfect! thanks!
– Matheus
Nov 12 at 18:57
add a comment |
1
Work perfect! thanks!
– Matheus
Nov 12 at 18:57
1
1
Work perfect! thanks!
– Matheus
Nov 12 at 18:57
Work perfect! thanks!
– Matheus
Nov 12 at 18:57
add a comment |
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