Python Gaussian Quadrature and the Trapezoid rule Integral error
Been trying to do this python. Question details are in the image link
Am getting this error when running the program
Any help is appreciated
File "C:/Users/User/Desktop/Python/tapez.py", line 9, in exactIntegral
integral = ((4(math.cos(0.4*b)** 2)) * ((5(math.exp( -0.5 * b))) +
TypeError: 'int' object is not callable
Here is the code
import math
import numpy
import scipy.integrate.quadrature as quad
def fun(x):
return x*numpy.sin(x)
def exactIntegral(a, b):
integral = (((9)+4(math.cos(0.4*b)** 2)) * ((5(math.exp( -0.5 * b))) +
(2(math.exp( 0.15 * b)))))+ (((9)+4(math.cos(0.4*a)** 2)) *
((5(math.exp( -0.5 * a))) + (2(math.exp( 0.15 * a)))))
return integral
a = 0.0
b = 8.0
exact = exactIntegral(a, b)
estimate = quad(fun,a,b)
print("Gaussian Quadrature: ", exact)
# Trapazoid Rule
n = 100
h = (b-a)/(n-1)
x = numpy.linspace(a,b,num=n)
area = 0
for i in range(n-1):
area = area + h*(fun(x[i]) + fun(x[i+1]))/2.0
print("Trapazoid rule: ", area)
python
asked Nov 12 at 18:54
denim
244
add a comment |
Been trying to do this python. Question details are in the image link
Am getting this error when running the program
Any help is appreciated
File "C:/Users/User/Desktop/Python/tapez.py", line 9, in exactIntegral
integral = ((4(math.cos(0.4*b)** 2)) * ((5(math.exp( -0.5 * b))) +
TypeError: 'int' object is not callable
Here is the code
import math
import numpy
import scipy.integrate.quadrature as quad
def fun(x):
return x*numpy.sin(x)
def exactIntegral(a, b):
integral = (((9)+4(math.cos(0.4*b)** 2)) * ((5(math.exp( -0.5 * b))) +
(2(math.exp( 0.15 * b)))))+ (((9)+4(math.cos(0.4*a)** 2)) *
((5(math.exp( -0.5 * a))) + (2(math.exp( 0.15 * a)))))
return integral
a = 0.0
b = 8.0
exact = exactIntegral(a, b)
estimate = quad(fun,a,b)
print("Gaussian Quadrature: ", exact)
# Trapazoid Rule
n = 100
h = (b-a)/(n-1)
x = numpy.linspace(a,b,num=n)
area = 0
for i in range(n-1):
area = area + h*(fun(x[i]) + fun(x[i+1]))/2.0
print("Trapazoid rule: ", area)
python
asked Nov 12 at 18:54
denim
244
2
5(math.expshould probably be5 * (math.exp, same with other places where you omitted the*
– Mike Scotty
Nov 12 at 18:57
add a comment |
Been trying to do this python. Question details are in the image link
Am getting this error when running the program
Any help is appreciated
File "C:/Users/User/Desktop/Python/tapez.py", line 9, in exactIntegral
integral = ((4(math.cos(0.4*b)** 2)) * ((5(math.exp( -0.5 * b))) +
TypeError: 'int' object is not callable
Here is the code
import math
import numpy
import scipy.integrate.quadrature as quad
def fun(x):
return x*numpy.sin(x)
def exactIntegral(a, b):
integral = (((9)+4(math.cos(0.4*b)** 2)) * ((5(math.exp( -0.5 * b))) +
(2(math.exp( 0.15 * b)))))+ (((9)+4(math.cos(0.4*a)** 2)) *
((5(math.exp( -0.5 * a))) + (2(math.exp( 0.15 * a)))))
return integral
a = 0.0
b = 8.0
exact = exactIntegral(a, b)
estimate = quad(fun,a,b)
print("Gaussian Quadrature: ", exact)
# Trapazoid Rule
n = 100
h = (b-a)/(n-1)
x = numpy.linspace(a,b,num=n)
area = 0
for i in range(n-1):
area = area + h*(fun(x[i]) + fun(x[i+1]))/2.0
print("Trapazoid rule: ", area)
python
asked Nov 12 at 18:54
denim
244
Been trying to do this python. Question details are in the image link
Am getting this error when running the program
Any help is appreciated
File "C:/Users/User/Desktop/Python/tapez.py", line 9, in exactIntegral
integral = ((4(math.cos(0.4*b)** 2)) * ((5(math.exp( -0.5 * b))) +
TypeError: 'int' object is not callable
Here is the code
import math
import numpy
import scipy.integrate.quadrature as quad
def fun(x):
return x*numpy.sin(x)
def exactIntegral(a, b):
integral = (((9)+4(math.cos(0.4*b)** 2)) * ((5(math.exp( -0.5 * b))) +
(2(math.exp( 0.15 * b)))))+ (((9)+4(math.cos(0.4*a)** 2)) *
((5(math.exp( -0.5 * a))) + (2(math.exp( 0.15 * a)))))
return integral
a = 0.0
b = 8.0
exact = exactIntegral(a, b)
estimate = quad(fun,a,b)
print("Gaussian Quadrature: ", exact)
# Trapazoid Rule
n = 100
h = (b-a)/(n-1)
x = numpy.linspace(a,b,num=n)
area = 0
for i in range(n-1):
area = area + h*(fun(x[i]) + fun(x[i+1]))/2.0
print("Trapazoid rule: ", area)
python
python
asked Nov 12 at 18:54
denim
244
asked Nov 12 at 18:54
denim
244
asked Nov 12 at 18:54
denim
244
asked Nov 12 at 18:54
denim
244
asked Nov 12 at 18:54
denim
244
244
2
5(math.expshould probably be5 * (math.exp, same with other places where you omitted the*
– Mike Scotty
Nov 12 at 18:57
add a comment |
2
5(math.expshould probably be5 * (math.exp, same with other places where you omitted the*
– Mike Scotty
Nov 12 at 18:57
2
2
5(math.exp should probably be 5 * (math.exp, same with other places where you omitted the *– Mike Scotty
Nov 12 at 18:57
5(math.exp should probably be 5 * (math.exp, same with other places where you omitted the *– Mike Scotty
Nov 12 at 18:57
add a comment |
1 Answer
1
active
oldest
votes
Your issue is here:
integral = (((9)+4(math.cos(0.4*b)** 2)) * ((5(math.exp( -0.5 * b))) +
(2(math.exp( 0.15 * b)))))+ (((9)+4(math.cos(0.4*a)** 2)) *
((5(math.exp( -0.5 * a))) + (2(math.exp( 0.15 * a))))
Python does not interpret things like 2(x+1) as 2*(x+1) automatically. You need to specify the multiplication operator * explicitly.
For Python 2() is a function call of a function named 2. But 2 is an int object and it cannot be called like a function
answered Nov 12 at 18:58
vencaslac
1,002217
add a comment |
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1 Answer
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active
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1 Answer
1
active
oldest
votes
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oldest
votes
active
oldest
votes
Your issue is here:
integral = (((9)+4(math.cos(0.4*b)** 2)) * ((5(math.exp( -0.5 * b))) +
(2(math.exp( 0.15 * b)))))+ (((9)+4(math.cos(0.4*a)** 2)) *
((5(math.exp( -0.5 * a))) + (2(math.exp( 0.15 * a))))
Python does not interpret things like 2(x+1) as 2*(x+1) automatically. You need to specify the multiplication operator * explicitly.
For Python 2() is a function call of a function named 2. But 2 is an int object and it cannot be called like a function
answered Nov 12 at 18:58
vencaslac
1,002217
add a comment |
Your issue is here:
integral = (((9)+4(math.cos(0.4*b)** 2)) * ((5(math.exp( -0.5 * b))) +
(2(math.exp( 0.15 * b)))))+ (((9)+4(math.cos(0.4*a)** 2)) *
((5(math.exp( -0.5 * a))) + (2(math.exp( 0.15 * a))))
Python does not interpret things like 2(x+1) as 2*(x+1) automatically. You need to specify the multiplication operator * explicitly.
For Python 2() is a function call of a function named 2. But 2 is an int object and it cannot be called like a function
answered Nov 12 at 18:58
vencaslac
1,002217
add a comment |
Your issue is here:
integral = (((9)+4(math.cos(0.4*b)** 2)) * ((5(math.exp( -0.5 * b))) +
(2(math.exp( 0.15 * b)))))+ (((9)+4(math.cos(0.4*a)** 2)) *
((5(math.exp( -0.5 * a))) + (2(math.exp( 0.15 * a))))
Python does not interpret things like 2(x+1) as 2*(x+1) automatically. You need to specify the multiplication operator * explicitly.
For Python 2() is a function call of a function named 2. But 2 is an int object and it cannot be called like a function
answered Nov 12 at 18:58
vencaslac
1,002217
Your issue is here:
integral = (((9)+4(math.cos(0.4*b)** 2)) * ((5(math.exp( -0.5 * b))) +
(2(math.exp( 0.15 * b)))))+ (((9)+4(math.cos(0.4*a)** 2)) *
((5(math.exp( -0.5 * a))) + (2(math.exp( 0.15 * a))))
Python does not interpret things like 2(x+1) as 2*(x+1) automatically. You need to specify the multiplication operator * explicitly.
For Python 2() is a function call of a function named 2. But 2 is an int object and it cannot be called like a function
answered Nov 12 at 18:58
vencaslac
1,002217
answered Nov 12 at 18:58
vencaslac
1,002217
answered Nov 12 at 18:58
vencaslac
1,002217
answered Nov 12 at 18:58
vencaslac
1,002217
1,002217
add a comment |
add a comment |
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2
5(math.expshould probably be5 * (math.exp, same with other places where you omitted the*– Mike Scotty
Nov 12 at 18:57