authenticate user using form in the dialog window
I have implemented using OAuth.
Now I have a popup window with a form that supposed to allow a user to login by providing his credentials. The form is expected to submit its data to /login
url, where I should validate user parameters and authenticate him.
The thing is that I supposed to see a default page with limited functionality by default.
Originally I thought I should use formLogin
of Spring security
. In my configure
method of WebSecurityConfigurerAdapter
class I defined configuration
http
.antMatcher("/**").authorizeRequests()
.antMatchers(
"/",
"/csrf-token",
"/oauth**",
"/error**",
"/swagger-resources/**",
"/swagger-ui.html",
"/v2/api-docs",
"/webjars/**",
"/login")
.permitAll()
.anyRequest().authenticated()
.and().formLogin().permitAll().loginProcessingUrl("/login").defaultSuccessUrl("/")
...;
I am able to see a form on /login
page when I directly access it in the browser.
But how to implement the case when the form is not on a separate page and just a part of other functionally? Should I just implement a separate POST
handler for some url like /login
?
java spring-boot spring-security
add a comment |
I have implemented using OAuth.
Now I have a popup window with a form that supposed to allow a user to login by providing his credentials. The form is expected to submit its data to /login
url, where I should validate user parameters and authenticate him.
The thing is that I supposed to see a default page with limited functionality by default.
Originally I thought I should use formLogin
of Spring security
. In my configure
method of WebSecurityConfigurerAdapter
class I defined configuration
http
.antMatcher("/**").authorizeRequests()
.antMatchers(
"/",
"/csrf-token",
"/oauth**",
"/error**",
"/swagger-resources/**",
"/swagger-ui.html",
"/v2/api-docs",
"/webjars/**",
"/login")
.permitAll()
.anyRequest().authenticated()
.and().formLogin().permitAll().loginProcessingUrl("/login").defaultSuccessUrl("/")
...;
I am able to see a form on /login
page when I directly access it in the browser.
But how to implement the case when the form is not on a separate page and just a part of other functionally? Should I just implement a separate POST
handler for some url like /login
?
java spring-boot spring-security
add a comment |
I have implemented using OAuth.
Now I have a popup window with a form that supposed to allow a user to login by providing his credentials. The form is expected to submit its data to /login
url, where I should validate user parameters and authenticate him.
The thing is that I supposed to see a default page with limited functionality by default.
Originally I thought I should use formLogin
of Spring security
. In my configure
method of WebSecurityConfigurerAdapter
class I defined configuration
http
.antMatcher("/**").authorizeRequests()
.antMatchers(
"/",
"/csrf-token",
"/oauth**",
"/error**",
"/swagger-resources/**",
"/swagger-ui.html",
"/v2/api-docs",
"/webjars/**",
"/login")
.permitAll()
.anyRequest().authenticated()
.and().formLogin().permitAll().loginProcessingUrl("/login").defaultSuccessUrl("/")
...;
I am able to see a form on /login
page when I directly access it in the browser.
But how to implement the case when the form is not on a separate page and just a part of other functionally? Should I just implement a separate POST
handler for some url like /login
?
java spring-boot spring-security
I have implemented using OAuth.
Now I have a popup window with a form that supposed to allow a user to login by providing his credentials. The form is expected to submit its data to /login
url, where I should validate user parameters and authenticate him.
The thing is that I supposed to see a default page with limited functionality by default.
Originally I thought I should use formLogin
of Spring security
. In my configure
method of WebSecurityConfigurerAdapter
class I defined configuration
http
.antMatcher("/**").authorizeRequests()
.antMatchers(
"/",
"/csrf-token",
"/oauth**",
"/error**",
"/swagger-resources/**",
"/swagger-ui.html",
"/v2/api-docs",
"/webjars/**",
"/login")
.permitAll()
.anyRequest().authenticated()
.and().formLogin().permitAll().loginProcessingUrl("/login").defaultSuccessUrl("/")
...;
I am able to see a form on /login
page when I directly access it in the browser.
But how to implement the case when the form is not on a separate page and just a part of other functionally? Should I just implement a separate POST
handler for some url like /login
?
java spring-boot spring-security
java spring-boot spring-security
edited Nov 12 at 19:04
asked Nov 12 at 18:54
lapots
3,6251260127
3,6251260127
add a comment |
add a comment |
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