Merging two text files to one gives a different output











up vote
1
down vote

favorite












One of the text files is rainfallToDate.txt, and it has:



0.01
1.74
0.19
0.65
0.50
0.10
0.00
0.02
0.01
0.06
1.57
7.76


while the other is averageRainfall.txt:



2.99
3.32
2.04
1.06
0.39
0.09
0.00
0.00
0.23
0.78
1.88
2.12


I am supposed to merge these two text files into a text file called rainfall.txt



Here is a sample output:



Rainfall for Cupertino: A Comparison

Month Average 2015

1 2.99 0.01
2 3.32 1.74
3 2.04 0.19
4 1.06 0.65
5 0.39 0.50
6 0.09 0.10
7 0.00 0.00
8 0.00 0.02
9 0.23 0.01
10 0.78 0.06
11 1.88 1.57
12 2.12 7.76


As you can see averageRainfall.txt is stored on the row "average" while the other text file rainfallToDate.txt is stored under 2015.



Well here is what I have so far and my attempt on "merging" the two text files.



My attempt:



#include <iostream>  // for cout
#include <fstream> // for file I/O
#include <cstdlib> // for exit()

using namespace std;

int main()
{
ifstream fin;
ofstream fout;

if (fin.fail())
{
cout << "Input file failed to open.n";
exit(-1);
}
fout.open("rainfall.txt");
if (fout.fail())
{
cout << "Output file failed to open.n";
exit(-1);
}

fout << "Rainfall for Cupertino: A Comparisonn" << endl;
fout << "MonthtAveraget 2015tDeficitn" << endl;

for (int i = 1; i <= 12; i++) { // counts the month from 1-12

fout << fixed << i << endl;

}
fin.close();
fout.close();


// averageRainfall under averages
ifstream average;
ofstream oaverage;
average.open("averageRainfall.txt");
if (average.fail())
{
cout << "Input file failed to open.n";
exit(-1);
}
oaverage.open("rainfall.txt");
if (fout.fail())
{
cout << "Output file failed to open.n";
exit(-1);
}

oaverage << "t" << average;


// rainfallToDate under 2015
average.close();
oaverage.close();

ifstream ToDate;
ofstream oToDate;
ToDate.open("rainfallToDate.txt");
if (ToDate.fail())
{
cout << "Input file failed to open.n";
exit(-1);
}
oToDate.open("rainfall.txt");
if (oToDate.fail())
{
cout << "Output file failed to open.n";
exit(-1);
}

oToDate << "t" << "t" << ToDate;

ToDate.close();
oToDate.close();

return 0;
}


Now for the problem, the code runs and all doesn't state any kind of error, however, when I open up the file where both the code merges the file prints out



0x29fe64


What I believe I did wrong is that I didn't put the two textfiles "averages" and the "rainfalltodate" into two separate arrays and stating it from there. Correct me if I am wrong not very sure if I am supposed two put both of them in two separate arrays.










share|improve this question
























  • You're doing a lot of things wrong: you're opening "rainfall.txt" for writing multiple times, and the default mode is "truncate" mode which wipes out existing content; you have multiple variables for the same output file which is pointless, but your bug is because you "oToDate << ToDate" doesn't copy the contents of one file to another, it just prints the address of the "ToDate" object into "oToDate".
    – kfsone
    Mar 19 '16 at 5:14















up vote
1
down vote

favorite












One of the text files is rainfallToDate.txt, and it has:



0.01
1.74
0.19
0.65
0.50
0.10
0.00
0.02
0.01
0.06
1.57
7.76


while the other is averageRainfall.txt:



2.99
3.32
2.04
1.06
0.39
0.09
0.00
0.00
0.23
0.78
1.88
2.12


I am supposed to merge these two text files into a text file called rainfall.txt



Here is a sample output:



Rainfall for Cupertino: A Comparison

Month Average 2015

1 2.99 0.01
2 3.32 1.74
3 2.04 0.19
4 1.06 0.65
5 0.39 0.50
6 0.09 0.10
7 0.00 0.00
8 0.00 0.02
9 0.23 0.01
10 0.78 0.06
11 1.88 1.57
12 2.12 7.76


As you can see averageRainfall.txt is stored on the row "average" while the other text file rainfallToDate.txt is stored under 2015.



Well here is what I have so far and my attempt on "merging" the two text files.



My attempt:



#include <iostream>  // for cout
#include <fstream> // for file I/O
#include <cstdlib> // for exit()

using namespace std;

int main()
{
ifstream fin;
ofstream fout;

if (fin.fail())
{
cout << "Input file failed to open.n";
exit(-1);
}
fout.open("rainfall.txt");
if (fout.fail())
{
cout << "Output file failed to open.n";
exit(-1);
}

fout << "Rainfall for Cupertino: A Comparisonn" << endl;
fout << "MonthtAveraget 2015tDeficitn" << endl;

for (int i = 1; i <= 12; i++) { // counts the month from 1-12

fout << fixed << i << endl;

}
fin.close();
fout.close();


// averageRainfall under averages
ifstream average;
ofstream oaverage;
average.open("averageRainfall.txt");
if (average.fail())
{
cout << "Input file failed to open.n";
exit(-1);
}
oaverage.open("rainfall.txt");
if (fout.fail())
{
cout << "Output file failed to open.n";
exit(-1);
}

oaverage << "t" << average;


// rainfallToDate under 2015
average.close();
oaverage.close();

ifstream ToDate;
ofstream oToDate;
ToDate.open("rainfallToDate.txt");
if (ToDate.fail())
{
cout << "Input file failed to open.n";
exit(-1);
}
oToDate.open("rainfall.txt");
if (oToDate.fail())
{
cout << "Output file failed to open.n";
exit(-1);
}

oToDate << "t" << "t" << ToDate;

ToDate.close();
oToDate.close();

return 0;
}


Now for the problem, the code runs and all doesn't state any kind of error, however, when I open up the file where both the code merges the file prints out



0x29fe64


What I believe I did wrong is that I didn't put the two textfiles "averages" and the "rainfalltodate" into two separate arrays and stating it from there. Correct me if I am wrong not very sure if I am supposed two put both of them in two separate arrays.










share|improve this question
























  • You're doing a lot of things wrong: you're opening "rainfall.txt" for writing multiple times, and the default mode is "truncate" mode which wipes out existing content; you have multiple variables for the same output file which is pointless, but your bug is because you "oToDate << ToDate" doesn't copy the contents of one file to another, it just prints the address of the "ToDate" object into "oToDate".
    – kfsone
    Mar 19 '16 at 5:14













up vote
1
down vote

favorite









up vote
1
down vote

favorite











One of the text files is rainfallToDate.txt, and it has:



0.01
1.74
0.19
0.65
0.50
0.10
0.00
0.02
0.01
0.06
1.57
7.76


while the other is averageRainfall.txt:



2.99
3.32
2.04
1.06
0.39
0.09
0.00
0.00
0.23
0.78
1.88
2.12


I am supposed to merge these two text files into a text file called rainfall.txt



Here is a sample output:



Rainfall for Cupertino: A Comparison

Month Average 2015

1 2.99 0.01
2 3.32 1.74
3 2.04 0.19
4 1.06 0.65
5 0.39 0.50
6 0.09 0.10
7 0.00 0.00
8 0.00 0.02
9 0.23 0.01
10 0.78 0.06
11 1.88 1.57
12 2.12 7.76


As you can see averageRainfall.txt is stored on the row "average" while the other text file rainfallToDate.txt is stored under 2015.



Well here is what I have so far and my attempt on "merging" the two text files.



My attempt:



#include <iostream>  // for cout
#include <fstream> // for file I/O
#include <cstdlib> // for exit()

using namespace std;

int main()
{
ifstream fin;
ofstream fout;

if (fin.fail())
{
cout << "Input file failed to open.n";
exit(-1);
}
fout.open("rainfall.txt");
if (fout.fail())
{
cout << "Output file failed to open.n";
exit(-1);
}

fout << "Rainfall for Cupertino: A Comparisonn" << endl;
fout << "MonthtAveraget 2015tDeficitn" << endl;

for (int i = 1; i <= 12; i++) { // counts the month from 1-12

fout << fixed << i << endl;

}
fin.close();
fout.close();


// averageRainfall under averages
ifstream average;
ofstream oaverage;
average.open("averageRainfall.txt");
if (average.fail())
{
cout << "Input file failed to open.n";
exit(-1);
}
oaverage.open("rainfall.txt");
if (fout.fail())
{
cout << "Output file failed to open.n";
exit(-1);
}

oaverage << "t" << average;


// rainfallToDate under 2015
average.close();
oaverage.close();

ifstream ToDate;
ofstream oToDate;
ToDate.open("rainfallToDate.txt");
if (ToDate.fail())
{
cout << "Input file failed to open.n";
exit(-1);
}
oToDate.open("rainfall.txt");
if (oToDate.fail())
{
cout << "Output file failed to open.n";
exit(-1);
}

oToDate << "t" << "t" << ToDate;

ToDate.close();
oToDate.close();

return 0;
}


Now for the problem, the code runs and all doesn't state any kind of error, however, when I open up the file where both the code merges the file prints out



0x29fe64


What I believe I did wrong is that I didn't put the two textfiles "averages" and the "rainfalltodate" into two separate arrays and stating it from there. Correct me if I am wrong not very sure if I am supposed two put both of them in two separate arrays.










share|improve this question















One of the text files is rainfallToDate.txt, and it has:



0.01
1.74
0.19
0.65
0.50
0.10
0.00
0.02
0.01
0.06
1.57
7.76


while the other is averageRainfall.txt:



2.99
3.32
2.04
1.06
0.39
0.09
0.00
0.00
0.23
0.78
1.88
2.12


I am supposed to merge these two text files into a text file called rainfall.txt



Here is a sample output:



Rainfall for Cupertino: A Comparison

Month Average 2015

1 2.99 0.01
2 3.32 1.74
3 2.04 0.19
4 1.06 0.65
5 0.39 0.50
6 0.09 0.10
7 0.00 0.00
8 0.00 0.02
9 0.23 0.01
10 0.78 0.06
11 1.88 1.57
12 2.12 7.76


As you can see averageRainfall.txt is stored on the row "average" while the other text file rainfallToDate.txt is stored under 2015.



Well here is what I have so far and my attempt on "merging" the two text files.



My attempt:



#include <iostream>  // for cout
#include <fstream> // for file I/O
#include <cstdlib> // for exit()

using namespace std;

int main()
{
ifstream fin;
ofstream fout;

if (fin.fail())
{
cout << "Input file failed to open.n";
exit(-1);
}
fout.open("rainfall.txt");
if (fout.fail())
{
cout << "Output file failed to open.n";
exit(-1);
}

fout << "Rainfall for Cupertino: A Comparisonn" << endl;
fout << "MonthtAveraget 2015tDeficitn" << endl;

for (int i = 1; i <= 12; i++) { // counts the month from 1-12

fout << fixed << i << endl;

}
fin.close();
fout.close();


// averageRainfall under averages
ifstream average;
ofstream oaverage;
average.open("averageRainfall.txt");
if (average.fail())
{
cout << "Input file failed to open.n";
exit(-1);
}
oaverage.open("rainfall.txt");
if (fout.fail())
{
cout << "Output file failed to open.n";
exit(-1);
}

oaverage << "t" << average;


// rainfallToDate under 2015
average.close();
oaverage.close();

ifstream ToDate;
ofstream oToDate;
ToDate.open("rainfallToDate.txt");
if (ToDate.fail())
{
cout << "Input file failed to open.n";
exit(-1);
}
oToDate.open("rainfall.txt");
if (oToDate.fail())
{
cout << "Output file failed to open.n";
exit(-1);
}

oToDate << "t" << "t" << ToDate;

ToDate.close();
oToDate.close();

return 0;
}


Now for the problem, the code runs and all doesn't state any kind of error, however, when I open up the file where both the code merges the file prints out



0x29fe64


What I believe I did wrong is that I didn't put the two textfiles "averages" and the "rainfalltodate" into two separate arrays and stating it from there. Correct me if I am wrong not very sure if I am supposed two put both of them in two separate arrays.







c++






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share|improve this question













share|improve this question




share|improve this question








edited Nov 11 at 8:26









Flimzy

36.5k96496




36.5k96496










asked Mar 19 '16 at 4:55









NaritaDogFight

254




254












  • You're doing a lot of things wrong: you're opening "rainfall.txt" for writing multiple times, and the default mode is "truncate" mode which wipes out existing content; you have multiple variables for the same output file which is pointless, but your bug is because you "oToDate << ToDate" doesn't copy the contents of one file to another, it just prints the address of the "ToDate" object into "oToDate".
    – kfsone
    Mar 19 '16 at 5:14


















  • You're doing a lot of things wrong: you're opening "rainfall.txt" for writing multiple times, and the default mode is "truncate" mode which wipes out existing content; you have multiple variables for the same output file which is pointless, but your bug is because you "oToDate << ToDate" doesn't copy the contents of one file to another, it just prints the address of the "ToDate" object into "oToDate".
    – kfsone
    Mar 19 '16 at 5:14
















You're doing a lot of things wrong: you're opening "rainfall.txt" for writing multiple times, and the default mode is "truncate" mode which wipes out existing content; you have multiple variables for the same output file which is pointless, but your bug is because you "oToDate << ToDate" doesn't copy the contents of one file to another, it just prints the address of the "ToDate" object into "oToDate".
– kfsone
Mar 19 '16 at 5:14




You're doing a lot of things wrong: you're opening "rainfall.txt" for writing multiple times, and the default mode is "truncate" mode which wipes out existing content; you have multiple variables for the same output file which is pointless, but your bug is because you "oToDate << ToDate" doesn't copy the contents of one file to another, it just prints the address of the "ToDate" object into "oToDate".
– kfsone
Mar 19 '16 at 5:14












3 Answers
3






active

oldest

votes

















up vote
1
down vote



accepted










oToDate << "t" << "t" << ToDate;


I guess your intention here is to copy everything from the ToDate stream to the oToDate stream, but that's not quite what's happening. Instead, this is just attempting to write out a single value which represents ToDate -- which turns out to be the (meaningless) pointer address of the variable.



However, even if we fix this we can't quite do what you want at the moment. It looks like you're trying to first copy the average rainfall data, then in the second pass, skip what you've just written and put the rainfall to date next to it. But this isn't going to work -- the second pass is just going to overwrite the existing line.



Instead, what you need to do is to load up both datasets, and write them out in one go. One option is to load the two datasets separately and use a std::vector to hold the values before you write them back out. Let's see how we can do this:



std::ifstream average{"averageRainfall.txt"};
std::vector<double> average_data;

std::copy(std::istream_iterator<double>{average},
std::istream_iterator<double>{},
std::back_inserter(average_data));


This will copy all the data from the input file into a vector (make sure you look up these functions if you haven't seen them before so you know what's going on here!). We can do exactly the same for the second data set, so let's say we save that into a vector called to_date_data.



We then need to write both values out to a file at the same time. First, we open the output file:



std::ofstream rainfall{"rainfall.txt"};


Then we loop through the two vectors, copying the data to the output stream:



auto last = std::min(average_data.size(), to_date_data.size());

for (int i = 0; i < last; i++) {
rainfall << average_data[i] << "t" << to_date_data[i] << "n";
}


and you're all done :-)






share|improve this answer




























    up vote
    0
    down vote













    Your strange output comes from this line:



    oaverage << "t" << average;


    average is a stream, and not a numerical value. When you try to print the stream, the stream ends up being converted to a pointer, and you are seeing a pointer value instead.



    There's a similar issue on this line:



    oToDate << "t" << "t" << ToDate;





    share|improve this answer




























      up vote
      0
      down vote













      maybe you should read some basic C++ programming book,here is my code:



      #include <iostream>  // for cout
      #include <fstream> // for file I/O
      #include <cstdlib> // for exit()
      using namespace std;
      int main()
      {
      std::ifstream fin_rain_date("rainfallToDate.txt");
      std::ifstream fin_rain_ave("averageRainfall.txt");
      if(fin_rain_ave==NULL||fin_rain_date==NULL)
      {
      std::cout<<"can not open file"<<std::endl;
      }
      std::ofstream fout("rainfall.txt");
      fout<<"Rainfall for Cupertino: A Comparison"<<std::endl;
      fout<<"MonthtAveraget 2015tDeficit"<<std::endl;
      for(int i=0;i<12;i++)
      {
      fout<<i<<"t";
      char tmpstr[256];
      fin_rain_ave.getline(tmpstr,256);
      fout<<tmpstr<<"t";
      fin_rain_date.getline(tmpstr,256);
      fout<<tmpstr<<std::endl;
      }
      return 0;
      }





      share|improve this answer





















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        3 Answers
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        3 Answers
        3






        active

        oldest

        votes









        active

        oldest

        votes






        active

        oldest

        votes








        up vote
        1
        down vote



        accepted










        oToDate << "t" << "t" << ToDate;


        I guess your intention here is to copy everything from the ToDate stream to the oToDate stream, but that's not quite what's happening. Instead, this is just attempting to write out a single value which represents ToDate -- which turns out to be the (meaningless) pointer address of the variable.



        However, even if we fix this we can't quite do what you want at the moment. It looks like you're trying to first copy the average rainfall data, then in the second pass, skip what you've just written and put the rainfall to date next to it. But this isn't going to work -- the second pass is just going to overwrite the existing line.



        Instead, what you need to do is to load up both datasets, and write them out in one go. One option is to load the two datasets separately and use a std::vector to hold the values before you write them back out. Let's see how we can do this:



        std::ifstream average{"averageRainfall.txt"};
        std::vector<double> average_data;

        std::copy(std::istream_iterator<double>{average},
        std::istream_iterator<double>{},
        std::back_inserter(average_data));


        This will copy all the data from the input file into a vector (make sure you look up these functions if you haven't seen them before so you know what's going on here!). We can do exactly the same for the second data set, so let's say we save that into a vector called to_date_data.



        We then need to write both values out to a file at the same time. First, we open the output file:



        std::ofstream rainfall{"rainfall.txt"};


        Then we loop through the two vectors, copying the data to the output stream:



        auto last = std::min(average_data.size(), to_date_data.size());

        for (int i = 0; i < last; i++) {
        rainfall << average_data[i] << "t" << to_date_data[i] << "n";
        }


        and you're all done :-)






        share|improve this answer

























          up vote
          1
          down vote



          accepted










          oToDate << "t" << "t" << ToDate;


          I guess your intention here is to copy everything from the ToDate stream to the oToDate stream, but that's not quite what's happening. Instead, this is just attempting to write out a single value which represents ToDate -- which turns out to be the (meaningless) pointer address of the variable.



          However, even if we fix this we can't quite do what you want at the moment. It looks like you're trying to first copy the average rainfall data, then in the second pass, skip what you've just written and put the rainfall to date next to it. But this isn't going to work -- the second pass is just going to overwrite the existing line.



          Instead, what you need to do is to load up both datasets, and write them out in one go. One option is to load the two datasets separately and use a std::vector to hold the values before you write them back out. Let's see how we can do this:



          std::ifstream average{"averageRainfall.txt"};
          std::vector<double> average_data;

          std::copy(std::istream_iterator<double>{average},
          std::istream_iterator<double>{},
          std::back_inserter(average_data));


          This will copy all the data from the input file into a vector (make sure you look up these functions if you haven't seen them before so you know what's going on here!). We can do exactly the same for the second data set, so let's say we save that into a vector called to_date_data.



          We then need to write both values out to a file at the same time. First, we open the output file:



          std::ofstream rainfall{"rainfall.txt"};


          Then we loop through the two vectors, copying the data to the output stream:



          auto last = std::min(average_data.size(), to_date_data.size());

          for (int i = 0; i < last; i++) {
          rainfall << average_data[i] << "t" << to_date_data[i] << "n";
          }


          and you're all done :-)






          share|improve this answer























            up vote
            1
            down vote



            accepted







            up vote
            1
            down vote



            accepted






            oToDate << "t" << "t" << ToDate;


            I guess your intention here is to copy everything from the ToDate stream to the oToDate stream, but that's not quite what's happening. Instead, this is just attempting to write out a single value which represents ToDate -- which turns out to be the (meaningless) pointer address of the variable.



            However, even if we fix this we can't quite do what you want at the moment. It looks like you're trying to first copy the average rainfall data, then in the second pass, skip what you've just written and put the rainfall to date next to it. But this isn't going to work -- the second pass is just going to overwrite the existing line.



            Instead, what you need to do is to load up both datasets, and write them out in one go. One option is to load the two datasets separately and use a std::vector to hold the values before you write them back out. Let's see how we can do this:



            std::ifstream average{"averageRainfall.txt"};
            std::vector<double> average_data;

            std::copy(std::istream_iterator<double>{average},
            std::istream_iterator<double>{},
            std::back_inserter(average_data));


            This will copy all the data from the input file into a vector (make sure you look up these functions if you haven't seen them before so you know what's going on here!). We can do exactly the same for the second data set, so let's say we save that into a vector called to_date_data.



            We then need to write both values out to a file at the same time. First, we open the output file:



            std::ofstream rainfall{"rainfall.txt"};


            Then we loop through the two vectors, copying the data to the output stream:



            auto last = std::min(average_data.size(), to_date_data.size());

            for (int i = 0; i < last; i++) {
            rainfall << average_data[i] << "t" << to_date_data[i] << "n";
            }


            and you're all done :-)






            share|improve this answer












            oToDate << "t" << "t" << ToDate;


            I guess your intention here is to copy everything from the ToDate stream to the oToDate stream, but that's not quite what's happening. Instead, this is just attempting to write out a single value which represents ToDate -- which turns out to be the (meaningless) pointer address of the variable.



            However, even if we fix this we can't quite do what you want at the moment. It looks like you're trying to first copy the average rainfall data, then in the second pass, skip what you've just written and put the rainfall to date next to it. But this isn't going to work -- the second pass is just going to overwrite the existing line.



            Instead, what you need to do is to load up both datasets, and write them out in one go. One option is to load the two datasets separately and use a std::vector to hold the values before you write them back out. Let's see how we can do this:



            std::ifstream average{"averageRainfall.txt"};
            std::vector<double> average_data;

            std::copy(std::istream_iterator<double>{average},
            std::istream_iterator<double>{},
            std::back_inserter(average_data));


            This will copy all the data from the input file into a vector (make sure you look up these functions if you haven't seen them before so you know what's going on here!). We can do exactly the same for the second data set, so let's say we save that into a vector called to_date_data.



            We then need to write both values out to a file at the same time. First, we open the output file:



            std::ofstream rainfall{"rainfall.txt"};


            Then we loop through the two vectors, copying the data to the output stream:



            auto last = std::min(average_data.size(), to_date_data.size());

            for (int i = 0; i < last; i++) {
            rainfall << average_data[i] << "t" << to_date_data[i] << "n";
            }


            and you're all done :-)







            share|improve this answer












            share|improve this answer



            share|improve this answer










            answered Mar 19 '16 at 5:18









            Tristan Brindle

            10.9k12065




            10.9k12065
























                up vote
                0
                down vote













                Your strange output comes from this line:



                oaverage << "t" << average;


                average is a stream, and not a numerical value. When you try to print the stream, the stream ends up being converted to a pointer, and you are seeing a pointer value instead.



                There's a similar issue on this line:



                oToDate << "t" << "t" << ToDate;





                share|improve this answer

























                  up vote
                  0
                  down vote













                  Your strange output comes from this line:



                  oaverage << "t" << average;


                  average is a stream, and not a numerical value. When you try to print the stream, the stream ends up being converted to a pointer, and you are seeing a pointer value instead.



                  There's a similar issue on this line:



                  oToDate << "t" << "t" << ToDate;





                  share|improve this answer























                    up vote
                    0
                    down vote










                    up vote
                    0
                    down vote









                    Your strange output comes from this line:



                    oaverage << "t" << average;


                    average is a stream, and not a numerical value. When you try to print the stream, the stream ends up being converted to a pointer, and you are seeing a pointer value instead.



                    There's a similar issue on this line:



                    oToDate << "t" << "t" << ToDate;





                    share|improve this answer












                    Your strange output comes from this line:



                    oaverage << "t" << average;


                    average is a stream, and not a numerical value. When you try to print the stream, the stream ends up being converted to a pointer, and you are seeing a pointer value instead.



                    There's a similar issue on this line:



                    oToDate << "t" << "t" << ToDate;






                    share|improve this answer












                    share|improve this answer



                    share|improve this answer










                    answered Mar 19 '16 at 5:05









                    Vaughn Cato

                    52.5k45997




                    52.5k45997






















                        up vote
                        0
                        down vote













                        maybe you should read some basic C++ programming book,here is my code:



                        #include <iostream>  // for cout
                        #include <fstream> // for file I/O
                        #include <cstdlib> // for exit()
                        using namespace std;
                        int main()
                        {
                        std::ifstream fin_rain_date("rainfallToDate.txt");
                        std::ifstream fin_rain_ave("averageRainfall.txt");
                        if(fin_rain_ave==NULL||fin_rain_date==NULL)
                        {
                        std::cout<<"can not open file"<<std::endl;
                        }
                        std::ofstream fout("rainfall.txt");
                        fout<<"Rainfall for Cupertino: A Comparison"<<std::endl;
                        fout<<"MonthtAveraget 2015tDeficit"<<std::endl;
                        for(int i=0;i<12;i++)
                        {
                        fout<<i<<"t";
                        char tmpstr[256];
                        fin_rain_ave.getline(tmpstr,256);
                        fout<<tmpstr<<"t";
                        fin_rain_date.getline(tmpstr,256);
                        fout<<tmpstr<<std::endl;
                        }
                        return 0;
                        }





                        share|improve this answer

























                          up vote
                          0
                          down vote













                          maybe you should read some basic C++ programming book,here is my code:



                          #include <iostream>  // for cout
                          #include <fstream> // for file I/O
                          #include <cstdlib> // for exit()
                          using namespace std;
                          int main()
                          {
                          std::ifstream fin_rain_date("rainfallToDate.txt");
                          std::ifstream fin_rain_ave("averageRainfall.txt");
                          if(fin_rain_ave==NULL||fin_rain_date==NULL)
                          {
                          std::cout<<"can not open file"<<std::endl;
                          }
                          std::ofstream fout("rainfall.txt");
                          fout<<"Rainfall for Cupertino: A Comparison"<<std::endl;
                          fout<<"MonthtAveraget 2015tDeficit"<<std::endl;
                          for(int i=0;i<12;i++)
                          {
                          fout<<i<<"t";
                          char tmpstr[256];
                          fin_rain_ave.getline(tmpstr,256);
                          fout<<tmpstr<<"t";
                          fin_rain_date.getline(tmpstr,256);
                          fout<<tmpstr<<std::endl;
                          }
                          return 0;
                          }





                          share|improve this answer























                            up vote
                            0
                            down vote










                            up vote
                            0
                            down vote









                            maybe you should read some basic C++ programming book,here is my code:



                            #include <iostream>  // for cout
                            #include <fstream> // for file I/O
                            #include <cstdlib> // for exit()
                            using namespace std;
                            int main()
                            {
                            std::ifstream fin_rain_date("rainfallToDate.txt");
                            std::ifstream fin_rain_ave("averageRainfall.txt");
                            if(fin_rain_ave==NULL||fin_rain_date==NULL)
                            {
                            std::cout<<"can not open file"<<std::endl;
                            }
                            std::ofstream fout("rainfall.txt");
                            fout<<"Rainfall for Cupertino: A Comparison"<<std::endl;
                            fout<<"MonthtAveraget 2015tDeficit"<<std::endl;
                            for(int i=0;i<12;i++)
                            {
                            fout<<i<<"t";
                            char tmpstr[256];
                            fin_rain_ave.getline(tmpstr,256);
                            fout<<tmpstr<<"t";
                            fin_rain_date.getline(tmpstr,256);
                            fout<<tmpstr<<std::endl;
                            }
                            return 0;
                            }





                            share|improve this answer












                            maybe you should read some basic C++ programming book,here is my code:



                            #include <iostream>  // for cout
                            #include <fstream> // for file I/O
                            #include <cstdlib> // for exit()
                            using namespace std;
                            int main()
                            {
                            std::ifstream fin_rain_date("rainfallToDate.txt");
                            std::ifstream fin_rain_ave("averageRainfall.txt");
                            if(fin_rain_ave==NULL||fin_rain_date==NULL)
                            {
                            std::cout<<"can not open file"<<std::endl;
                            }
                            std::ofstream fout("rainfall.txt");
                            fout<<"Rainfall for Cupertino: A Comparison"<<std::endl;
                            fout<<"MonthtAveraget 2015tDeficit"<<std::endl;
                            for(int i=0;i<12;i++)
                            {
                            fout<<i<<"t";
                            char tmpstr[256];
                            fin_rain_ave.getline(tmpstr,256);
                            fout<<tmpstr<<"t";
                            fin_rain_date.getline(tmpstr,256);
                            fout<<tmpstr<<std::endl;
                            }
                            return 0;
                            }






                            share|improve this answer












                            share|improve this answer



                            share|improve this answer










                            answered Mar 19 '16 at 5:11









                            an unique monkey

                            33319




                            33319






























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