How to omit conditional field of struct within marshal











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1
down vote

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There is struct of MyStruct.



type MyStruct struct {
Code int `json:"Code"`
Flags uint8 `json:"Flags"`
OptionField int `json:",omitempty"`
}


Following code convert it to json.



f := MyStruct{Code:500, OptionField:41}
r, _ := json.Marshal(f)
fmt.Println(string(r)


I need to "OptionField" be optional. Some time it should exist in json with one of values [0, 1, 2, 3, ]. and in the other time it should exclude from json.



My problem is: omitempty will exclude it when the value is zero, and the default value of int is zero. Is there any way to omit field in condition (ex: omit if value is -1). Or there is any way to do it.










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  • 2




    Possible duplicate of How to not marshal an empty struct into JSON with Go?
    – aerokite
    Nov 11 at 9:50















up vote
1
down vote

favorite












There is struct of MyStruct.



type MyStruct struct {
Code int `json:"Code"`
Flags uint8 `json:"Flags"`
OptionField int `json:",omitempty"`
}


Following code convert it to json.



f := MyStruct{Code:500, OptionField:41}
r, _ := json.Marshal(f)
fmt.Println(string(r)


I need to "OptionField" be optional. Some time it should exist in json with one of values [0, 1, 2, 3, ]. and in the other time it should exclude from json.



My problem is: omitempty will exclude it when the value is zero, and the default value of int is zero. Is there any way to omit field in condition (ex: omit if value is -1). Or there is any way to do it.










share|improve this question




















  • 2




    Possible duplicate of How to not marshal an empty struct into JSON with Go?
    – aerokite
    Nov 11 at 9:50













up vote
1
down vote

favorite









up vote
1
down vote

favorite











There is struct of MyStruct.



type MyStruct struct {
Code int `json:"Code"`
Flags uint8 `json:"Flags"`
OptionField int `json:",omitempty"`
}


Following code convert it to json.



f := MyStruct{Code:500, OptionField:41}
r, _ := json.Marshal(f)
fmt.Println(string(r)


I need to "OptionField" be optional. Some time it should exist in json with one of values [0, 1, 2, 3, ]. and in the other time it should exclude from json.



My problem is: omitempty will exclude it when the value is zero, and the default value of int is zero. Is there any way to omit field in condition (ex: omit if value is -1). Or there is any way to do it.










share|improve this question















There is struct of MyStruct.



type MyStruct struct {
Code int `json:"Code"`
Flags uint8 `json:"Flags"`
OptionField int `json:",omitempty"`
}


Following code convert it to json.



f := MyStruct{Code:500, OptionField:41}
r, _ := json.Marshal(f)
fmt.Println(string(r)


I need to "OptionField" be optional. Some time it should exist in json with one of values [0, 1, 2, 3, ]. and in the other time it should exclude from json.



My problem is: omitempty will exclude it when the value is zero, and the default value of int is zero. Is there any way to omit field in condition (ex: omit if value is -1). Or there is any way to do it.







go






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edited Nov 11 at 10:35









Flimzy

36.5k96496




36.5k96496










asked Nov 11 at 8:41









irmorteza

51311023




51311023








  • 2




    Possible duplicate of How to not marshal an empty struct into JSON with Go?
    – aerokite
    Nov 11 at 9:50














  • 2




    Possible duplicate of How to not marshal an empty struct into JSON with Go?
    – aerokite
    Nov 11 at 9:50








2




2




Possible duplicate of How to not marshal an empty struct into JSON with Go?
– aerokite
Nov 11 at 9:50




Possible duplicate of How to not marshal an empty struct into JSON with Go?
– aerokite
Nov 11 at 9:50












1 Answer
1






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oldest

votes

















up vote
5
down vote



accepted










You could use *int instead of int and set the pointer value to nil in order to omit this.



package main

import (
"encoding/json"
"fmt"
)

type MyStruct struct {
Code int `json:"Code"`
Flags uint8 `json:"Flags"`
OptionField *int `json:",omitempty"`
}

func format(s MyStruct) string {
r, _ := json.Marshal(s)
return string(r)
}

func main() {
f := MyStruct{Code: 500, Flags: 10, OptionField: new(int)}
fmt.Println(format(f)) // {"Code":500,"Flags":10,"OptionField":0}
f.OptionField = nil
fmt.Println(format(f)) // {"Code":500,"Flags":10}
}





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    1 Answer
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    active

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    active

    oldest

    votes








    up vote
    5
    down vote



    accepted










    You could use *int instead of int and set the pointer value to nil in order to omit this.



    package main

    import (
    "encoding/json"
    "fmt"
    )

    type MyStruct struct {
    Code int `json:"Code"`
    Flags uint8 `json:"Flags"`
    OptionField *int `json:",omitempty"`
    }

    func format(s MyStruct) string {
    r, _ := json.Marshal(s)
    return string(r)
    }

    func main() {
    f := MyStruct{Code: 500, Flags: 10, OptionField: new(int)}
    fmt.Println(format(f)) // {"Code":500,"Flags":10,"OptionField":0}
    f.OptionField = nil
    fmt.Println(format(f)) // {"Code":500,"Flags":10}
    }





    share|improve this answer

























      up vote
      5
      down vote



      accepted










      You could use *int instead of int and set the pointer value to nil in order to omit this.



      package main

      import (
      "encoding/json"
      "fmt"
      )

      type MyStruct struct {
      Code int `json:"Code"`
      Flags uint8 `json:"Flags"`
      OptionField *int `json:",omitempty"`
      }

      func format(s MyStruct) string {
      r, _ := json.Marshal(s)
      return string(r)
      }

      func main() {
      f := MyStruct{Code: 500, Flags: 10, OptionField: new(int)}
      fmt.Println(format(f)) // {"Code":500,"Flags":10,"OptionField":0}
      f.OptionField = nil
      fmt.Println(format(f)) // {"Code":500,"Flags":10}
      }





      share|improve this answer























        up vote
        5
        down vote



        accepted







        up vote
        5
        down vote



        accepted






        You could use *int instead of int and set the pointer value to nil in order to omit this.



        package main

        import (
        "encoding/json"
        "fmt"
        )

        type MyStruct struct {
        Code int `json:"Code"`
        Flags uint8 `json:"Flags"`
        OptionField *int `json:",omitempty"`
        }

        func format(s MyStruct) string {
        r, _ := json.Marshal(s)
        return string(r)
        }

        func main() {
        f := MyStruct{Code: 500, Flags: 10, OptionField: new(int)}
        fmt.Println(format(f)) // {"Code":500,"Flags":10,"OptionField":0}
        f.OptionField = nil
        fmt.Println(format(f)) // {"Code":500,"Flags":10}
        }





        share|improve this answer












        You could use *int instead of int and set the pointer value to nil in order to omit this.



        package main

        import (
        "encoding/json"
        "fmt"
        )

        type MyStruct struct {
        Code int `json:"Code"`
        Flags uint8 `json:"Flags"`
        OptionField *int `json:",omitempty"`
        }

        func format(s MyStruct) string {
        r, _ := json.Marshal(s)
        return string(r)
        }

        func main() {
        f := MyStruct{Code: 500, Flags: 10, OptionField: new(int)}
        fmt.Println(format(f)) // {"Code":500,"Flags":10,"OptionField":0}
        f.OptionField = nil
        fmt.Println(format(f)) // {"Code":500,"Flags":10}
        }






        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Nov 11 at 8:50









        Eternal_flame-AD

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