How to count two different values and not stopping the same time











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I am using jquery.countTo to count two different values but the issue is, the count start at the same time and stop at the same time even though the values are different. How can I start the count at the same time and stop when the value reaches its peak. for example, 216 should stop when it reaches 216 whilst 249 keeps counting until it reaches 249. Thanks



$('#cat-'+catNum+' span#asp-1-ev').countTo({from: 1,to: 249,speed:50000});
$('#cat-'+catNum+' span#asp-2-ev').countTo({from: 1,to: 216,speed:50000});









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  • 1




    Numeric-indexed IDs are a code smell - consider using classes instead.
    – CertainPerformance
    Nov 11 at 8:46










  • Ok got that, but any help about the question asked
    – Big Pee
    Nov 11 at 8:51















up vote
0
down vote

favorite












I am using jquery.countTo to count two different values but the issue is, the count start at the same time and stop at the same time even though the values are different. How can I start the count at the same time and stop when the value reaches its peak. for example, 216 should stop when it reaches 216 whilst 249 keeps counting until it reaches 249. Thanks



$('#cat-'+catNum+' span#asp-1-ev').countTo({from: 1,to: 249,speed:50000});
$('#cat-'+catNum+' span#asp-2-ev').countTo({from: 1,to: 216,speed:50000});









share|improve this question


















  • 1




    Numeric-indexed IDs are a code smell - consider using classes instead.
    – CertainPerformance
    Nov 11 at 8:46










  • Ok got that, but any help about the question asked
    – Big Pee
    Nov 11 at 8:51













up vote
0
down vote

favorite









up vote
0
down vote

favorite











I am using jquery.countTo to count two different values but the issue is, the count start at the same time and stop at the same time even though the values are different. How can I start the count at the same time and stop when the value reaches its peak. for example, 216 should stop when it reaches 216 whilst 249 keeps counting until it reaches 249. Thanks



$('#cat-'+catNum+' span#asp-1-ev').countTo({from: 1,to: 249,speed:50000});
$('#cat-'+catNum+' span#asp-2-ev').countTo({from: 1,to: 216,speed:50000});









share|improve this question













I am using jquery.countTo to count two different values but the issue is, the count start at the same time and stop at the same time even though the values are different. How can I start the count at the same time and stop when the value reaches its peak. for example, 216 should stop when it reaches 216 whilst 249 keeps counting until it reaches 249. Thanks



$('#cat-'+catNum+' span#asp-1-ev').countTo({from: 1,to: 249,speed:50000});
$('#cat-'+catNum+' span#asp-2-ev').countTo({from: 1,to: 216,speed:50000});






jquery






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asked Nov 11 at 8:45









Big Pee

54




54








  • 1




    Numeric-indexed IDs are a code smell - consider using classes instead.
    – CertainPerformance
    Nov 11 at 8:46










  • Ok got that, but any help about the question asked
    – Big Pee
    Nov 11 at 8:51














  • 1




    Numeric-indexed IDs are a code smell - consider using classes instead.
    – CertainPerformance
    Nov 11 at 8:46










  • Ok got that, but any help about the question asked
    – Big Pee
    Nov 11 at 8:51








1




1




Numeric-indexed IDs are a code smell - consider using classes instead.
– CertainPerformance
Nov 11 at 8:46




Numeric-indexed IDs are a code smell - consider using classes instead.
– CertainPerformance
Nov 11 at 8:46












Ok got that, but any help about the question asked
– Big Pee
Nov 11 at 8:51




Ok got that, but any help about the question asked
– Big Pee
Nov 11 at 8:51












1 Answer
1






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up vote
0
down vote



accepted










The speed option defines how long it should take to reach the finish. Since you put the same value for both counters, they will finish at the same time.



See documentation:




speed | data-speed | The number of milliseconds it should take to finish counting. (default: 1000)




If you want the increments in both widgets to happen with equal intervals, then you could calculate this speed option dynamically:



const speed = 200;
$('#a').countTo({from: 1, to: 249, speed: 249*speed});
$('#b').countTo({from: 1, to: 216, speed: 216*speed});





share|improve this answer





















  • Thanks. I tried your solution and it worked perfectly.
    – Big Pee
    Nov 11 at 9:00












  • You're welcome ;-)
    – trincot
    Nov 11 at 9:14











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1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes








up vote
0
down vote



accepted










The speed option defines how long it should take to reach the finish. Since you put the same value for both counters, they will finish at the same time.



See documentation:




speed | data-speed | The number of milliseconds it should take to finish counting. (default: 1000)




If you want the increments in both widgets to happen with equal intervals, then you could calculate this speed option dynamically:



const speed = 200;
$('#a').countTo({from: 1, to: 249, speed: 249*speed});
$('#b').countTo({from: 1, to: 216, speed: 216*speed});





share|improve this answer





















  • Thanks. I tried your solution and it worked perfectly.
    – Big Pee
    Nov 11 at 9:00












  • You're welcome ;-)
    – trincot
    Nov 11 at 9:14















up vote
0
down vote



accepted










The speed option defines how long it should take to reach the finish. Since you put the same value for both counters, they will finish at the same time.



See documentation:




speed | data-speed | The number of milliseconds it should take to finish counting. (default: 1000)




If you want the increments in both widgets to happen with equal intervals, then you could calculate this speed option dynamically:



const speed = 200;
$('#a').countTo({from: 1, to: 249, speed: 249*speed});
$('#b').countTo({from: 1, to: 216, speed: 216*speed});





share|improve this answer





















  • Thanks. I tried your solution and it worked perfectly.
    – Big Pee
    Nov 11 at 9:00












  • You're welcome ;-)
    – trincot
    Nov 11 at 9:14













up vote
0
down vote



accepted







up vote
0
down vote



accepted






The speed option defines how long it should take to reach the finish. Since you put the same value for both counters, they will finish at the same time.



See documentation:




speed | data-speed | The number of milliseconds it should take to finish counting. (default: 1000)




If you want the increments in both widgets to happen with equal intervals, then you could calculate this speed option dynamically:



const speed = 200;
$('#a').countTo({from: 1, to: 249, speed: 249*speed});
$('#b').countTo({from: 1, to: 216, speed: 216*speed});





share|improve this answer












The speed option defines how long it should take to reach the finish. Since you put the same value for both counters, they will finish at the same time.



See documentation:




speed | data-speed | The number of milliseconds it should take to finish counting. (default: 1000)




If you want the increments in both widgets to happen with equal intervals, then you could calculate this speed option dynamically:



const speed = 200;
$('#a').countTo({from: 1, to: 249, speed: 249*speed});
$('#b').countTo({from: 1, to: 216, speed: 216*speed});






share|improve this answer












share|improve this answer



share|improve this answer










answered Nov 11 at 8:53









trincot

114k1477109




114k1477109












  • Thanks. I tried your solution and it worked perfectly.
    – Big Pee
    Nov 11 at 9:00












  • You're welcome ;-)
    – trincot
    Nov 11 at 9:14


















  • Thanks. I tried your solution and it worked perfectly.
    – Big Pee
    Nov 11 at 9:00












  • You're welcome ;-)
    – trincot
    Nov 11 at 9:14
















Thanks. I tried your solution and it worked perfectly.
– Big Pee
Nov 11 at 9:00






Thanks. I tried your solution and it worked perfectly.
– Big Pee
Nov 11 at 9:00














You're welcome ;-)
– trincot
Nov 11 at 9:14




You're welcome ;-)
– trincot
Nov 11 at 9:14


















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