Vfrdtyky

I want to print function argument in the printf command. Please help to suggest.

void printline(char ch, int len);

value(float, float, int);



main()

{

    double amount;

    printline('=', 30);

    amount = value(500, 0.12, 5); //  I want to print argument of function value. please help

    printf("The total amount is: %f n", amount);

    //printf("%ft%ft%dt%f n", 500, 0.12, 5, amount);

    printline('=', 30);

    _getch();

}



void printline(char ch, int len)

{

    int i;

    for (i = 0; i < len; i++)

        printf("%c", ch);

    printf("n");

}



value(float p, float r, int n)

{

    int year;

    float sum;

    sum = p;

    year = 1;

    while (year <= 5)

    {

        sum = sum * (1 + r);

        year = year + 1;

    }

    return(sum);

}

In your printline function you only have one character as an argument. So there is no purpose in iterating through it. If you want to print a string or array of characters you want to use char * or char and iterate through it. So your function printline could look like this:

void printline(char *ch, int len)

{

    int i;

    for (i = 0; i<len; i++)

        printf("%c", ch[i]);

    printf("n");

}

just make sure that len isn't bigger then the length of *ch.

Even better solution, where you don't have to worry about the value of len is to print the characters one by one until you come across the character indicating the end of an array.

 void printline(char *ch)

    {

        int i;

        for (i = 0; ch[i] != ''; ++i)

            printf("%c", ch[i]);

        printf("n");

    }

Or even better

If the string is null terminated, use printf("%s", ch). If the string is not null terminated but the length is supplied, use printf("%.*s", len, ch). In both cases, there's no loop in the user code; the loop is buried inside the printf() function. Further, since there's a newline printed after the loops, use printf("%sn", ch) or printf("%.*sn", len, ch) and skip the extra printf() after the loop.

value(500, 0.12, 5); //  I want to print argument of function value. please help

You can add a printf to the beginning of the function:

value(float p, float r, int n)

{

    printf("%s(%f, %f, %d)n", __func__, f, r, n);