SVG rotation issue with JavaScript variables
Is there a way to use a variable inside the rotation function in JavaScript? The script below does not work (x and y will not assigned).
var x = 20;
var y = 20;
object.children[0].setAttribute('transform','rotate(-20, x, y)');
javascript svg
asked Nov 15 '18 at 23:02
JCssJCss
347
add a comment |
Is there a way to use a variable inside the rotation function in JavaScript? The script below does not work (x and y will not assigned).
var x = 20;
var y = 20;
object.children[0].setAttribute('transform','rotate(-20, x, y)');
javascript svg
asked Nov 15 '18 at 23:02
JCssJCss
347
add a comment |
Is there a way to use a variable inside the rotation function in JavaScript? The script below does not work (x and y will not assigned).
var x = 20;
var y = 20;
object.children[0].setAttribute('transform','rotate(-20, x, y)');
javascript svg
asked Nov 15 '18 at 23:02
JCssJCss
347
Is there a way to use a variable inside the rotation function in JavaScript? The script below does not work (x and y will not assigned).
var x = 20;
var y = 20;
object.children[0].setAttribute('transform','rotate(-20, x, y)');
javascript svg
javascript svg
asked Nov 15 '18 at 23:02
JCssJCss
347
asked Nov 15 '18 at 23:02
JCssJCss
347
asked Nov 15 '18 at 23:02
JCssJCss
347
asked Nov 15 '18 at 23:02
JCssJCss
347
asked Nov 15 '18 at 23:02
JCssJCss
347
347
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
As setAttribute takes as string you can either use string concatenation or template literals (as shown below).
var x = 20;
var y = 20;
object.children[0].setAttribute('transform',`rotate(-20, ${x}, ${y})`);
As commented this is ES6 syntax. Below is using string concatenation.
var x = 20;
var y = 20;
object.children[0].setAttribute('transform','rotate(-20, ' + x + ', ' + y + ')');
answered Nov 15 '18 at 23:05
pmkropmkro
1,483818
worth mentioning ES6 syntax is not supported on all browsers natively
– aug
Nov 15 '18 at 23:06
Thank you work's great!
– JCss
Nov 15 '18 at 23:30
add a comment |
While building the string in place with literals or concat is fine, if you are planning on doing this more than once, I would suggest creating a string builder function for rotate. For example:
function rotateStr(a, x, y) {
return `rotate(${a}, ${x}, ${y})`
// return 'rotate(' + x + ',' + y + ',' + z + ')' if you can't use templates
}
var x = 20;
var y = 20;
object.children[0].setAttribute('transform', rotateStr(-20, x, y))
answered Nov 15 '18 at 23:18
Matt WayMatt Way
23.2k76069
Work's great thanks!
– JCss
Nov 15 '18 at 23:30
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
As setAttribute takes as string you can either use string concatenation or template literals (as shown below).
var x = 20;
var y = 20;
object.children[0].setAttribute('transform',`rotate(-20, ${x}, ${y})`);
As commented this is ES6 syntax. Below is using string concatenation.
var x = 20;
var y = 20;
object.children[0].setAttribute('transform','rotate(-20, ' + x + ', ' + y + ')');
answered Nov 15 '18 at 23:05
pmkropmkro
1,483818
worth mentioning ES6 syntax is not supported on all browsers natively
– aug
Nov 15 '18 at 23:06
Thank you work's great!
– JCss
Nov 15 '18 at 23:30
add a comment |
As setAttribute takes as string you can either use string concatenation or template literals (as shown below).
var x = 20;
var y = 20;
object.children[0].setAttribute('transform',`rotate(-20, ${x}, ${y})`);
As commented this is ES6 syntax. Below is using string concatenation.
var x = 20;
var y = 20;
object.children[0].setAttribute('transform','rotate(-20, ' + x + ', ' + y + ')');
answered Nov 15 '18 at 23:05
pmkropmkro
1,483818
worth mentioning ES6 syntax is not supported on all browsers natively
– aug
Nov 15 '18 at 23:06
Thank you work's great!
– JCss
Nov 15 '18 at 23:30
add a comment |
As setAttribute takes as string you can either use string concatenation or template literals (as shown below).
var x = 20;
var y = 20;
object.children[0].setAttribute('transform',`rotate(-20, ${x}, ${y})`);
As commented this is ES6 syntax. Below is using string concatenation.
var x = 20;
var y = 20;
object.children[0].setAttribute('transform','rotate(-20, ' + x + ', ' + y + ')');
answered Nov 15 '18 at 23:05
pmkropmkro
1,483818
As setAttribute takes as string you can either use string concatenation or template literals (as shown below).
var x = 20;
var y = 20;
object.children[0].setAttribute('transform',`rotate(-20, ${x}, ${y})`);
As commented this is ES6 syntax. Below is using string concatenation.
var x = 20;
var y = 20;
object.children[0].setAttribute('transform','rotate(-20, ' + x + ', ' + y + ')');
answered Nov 15 '18 at 23:05
pmkropmkro
1,483818
edited Nov 15 '18 at 23:17
answered Nov 15 '18 at 23:05
pmkropmkro
1,483818
answered Nov 15 '18 at 23:05
pmkropmkro
1,483818
answered Nov 15 '18 at 23:05
pmkropmkro
1,483818
1,483818
worth mentioning ES6 syntax is not supported on all browsers natively
– aug
Nov 15 '18 at 23:06
Thank you work's great!
– JCss
Nov 15 '18 at 23:30
add a comment |
worth mentioning ES6 syntax is not supported on all browsers natively
– aug
Nov 15 '18 at 23:06
Thank you work's great!
– JCss
Nov 15 '18 at 23:30
worth mentioning ES6 syntax is not supported on all browsers natively
– aug
Nov 15 '18 at 23:06
worth mentioning ES6 syntax is not supported on all browsers natively
– aug
Nov 15 '18 at 23:06
Thank you work's great!
– JCss
Nov 15 '18 at 23:30
Thank you work's great!
– JCss
Nov 15 '18 at 23:30
add a comment |
While building the string in place with literals or concat is fine, if you are planning on doing this more than once, I would suggest creating a string builder function for rotate. For example:
function rotateStr(a, x, y) {
return `rotate(${a}, ${x}, ${y})`
// return 'rotate(' + x + ',' + y + ',' + z + ')' if you can't use templates
}
var x = 20;
var y = 20;
object.children[0].setAttribute('transform', rotateStr(-20, x, y))
answered Nov 15 '18 at 23:18
Matt WayMatt Way
23.2k76069
Work's great thanks!
– JCss
Nov 15 '18 at 23:30
add a comment |
While building the string in place with literals or concat is fine, if you are planning on doing this more than once, I would suggest creating a string builder function for rotate. For example:
function rotateStr(a, x, y) {
return `rotate(${a}, ${x}, ${y})`
// return 'rotate(' + x + ',' + y + ',' + z + ')' if you can't use templates
}
var x = 20;
var y = 20;
object.children[0].setAttribute('transform', rotateStr(-20, x, y))
answered Nov 15 '18 at 23:18
Matt WayMatt Way
23.2k76069
Work's great thanks!
– JCss
Nov 15 '18 at 23:30
add a comment |
While building the string in place with literals or concat is fine, if you are planning on doing this more than once, I would suggest creating a string builder function for rotate. For example:
function rotateStr(a, x, y) {
return `rotate(${a}, ${x}, ${y})`
// return 'rotate(' + x + ',' + y + ',' + z + ')' if you can't use templates
}
var x = 20;
var y = 20;
object.children[0].setAttribute('transform', rotateStr(-20, x, y))
answered Nov 15 '18 at 23:18
Matt WayMatt Way
23.2k76069
While building the string in place with literals or concat is fine, if you are planning on doing this more than once, I would suggest creating a string builder function for rotate. For example:
function rotateStr(a, x, y) {
return `rotate(${a}, ${x}, ${y})`
// return 'rotate(' + x + ',' + y + ',' + z + ')' if you can't use templates
}
var x = 20;
var y = 20;
object.children[0].setAttribute('transform', rotateStr(-20, x, y))
answered Nov 15 '18 at 23:18
Matt WayMatt Way
23.2k76069
answered Nov 15 '18 at 23:18
Matt WayMatt Way
23.2k76069
answered Nov 15 '18 at 23:18
Matt WayMatt Way
23.2k76069
answered Nov 15 '18 at 23:18
Matt WayMatt Way
23.2k76069
23.2k76069
Work's great thanks!
– JCss
Nov 15 '18 at 23:30
add a comment |
Work's great thanks!
– JCss
Nov 15 '18 at 23:30
Work's great thanks!
– JCss
Nov 15 '18 at 23:30
Work's great thanks!
– JCss
Nov 15 '18 at 23:30
add a comment |
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