Powershell: Why does Rename-Item not work as a piped command?












2















In this script, everything is working as I expect for the most part. However, the rename operation will only work outside of these piped commands



 Get-ChildItem -Path $folderpath -Filter $folderfile | Move-Item - 
Destination $destination | sleep 5 | Out-File -FilePath $logpath -Append


If I try to do the rename as part of the piped commands, it simply doesn't work. Anywhere outside of that and it will work for a single iteratrion of the filewatcher, and then no more. Why will the rename not work as a piped command?



Get-ChildItem -Path $folderpath -Filter $folderfile | Move-Item -Destination $destination | Rename-Item $destination$folderfile -NewName $newname  | Out-File -FilePath $logpath -Append









share|improve this question

























  • Can you reduce the code to only the relevant portion please?

    – marsze
    Nov 15 '18 at 14:36











  • Sure. No problem. Thanks for taking a look!

    – Steve Weaver
    Nov 15 '18 at 14:39
















2















In this script, everything is working as I expect for the most part. However, the rename operation will only work outside of these piped commands



 Get-ChildItem -Path $folderpath -Filter $folderfile | Move-Item - 
Destination $destination | sleep 5 | Out-File -FilePath $logpath -Append


If I try to do the rename as part of the piped commands, it simply doesn't work. Anywhere outside of that and it will work for a single iteratrion of the filewatcher, and then no more. Why will the rename not work as a piped command?



Get-ChildItem -Path $folderpath -Filter $folderfile | Move-Item -Destination $destination | Rename-Item $destination$folderfile -NewName $newname  | Out-File -FilePath $logpath -Append









share|improve this question

























  • Can you reduce the code to only the relevant portion please?

    – marsze
    Nov 15 '18 at 14:36











  • Sure. No problem. Thanks for taking a look!

    – Steve Weaver
    Nov 15 '18 at 14:39














2












2








2








In this script, everything is working as I expect for the most part. However, the rename operation will only work outside of these piped commands



 Get-ChildItem -Path $folderpath -Filter $folderfile | Move-Item - 
Destination $destination | sleep 5 | Out-File -FilePath $logpath -Append


If I try to do the rename as part of the piped commands, it simply doesn't work. Anywhere outside of that and it will work for a single iteratrion of the filewatcher, and then no more. Why will the rename not work as a piped command?



Get-ChildItem -Path $folderpath -Filter $folderfile | Move-Item -Destination $destination | Rename-Item $destination$folderfile -NewName $newname  | Out-File -FilePath $logpath -Append









share|improve this question
















In this script, everything is working as I expect for the most part. However, the rename operation will only work outside of these piped commands



 Get-ChildItem -Path $folderpath -Filter $folderfile | Move-Item - 
Destination $destination | sleep 5 | Out-File -FilePath $logpath -Append


If I try to do the rename as part of the piped commands, it simply doesn't work. Anywhere outside of that and it will work for a single iteratrion of the filewatcher, and then no more. Why will the rename not work as a piped command?



Get-ChildItem -Path $folderpath -Filter $folderfile | Move-Item -Destination $destination | Rename-Item $destination$folderfile -NewName $newname  | Out-File -FilePath $logpath -Append






powershell powershell-v2.0 pipeline






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share|improve this question













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edited Nov 16 '18 at 0:34









marsze

5,53232041




5,53232041










asked Nov 15 '18 at 14:15









Steve WeaverSteve Weaver

3411315




3411315













  • Can you reduce the code to only the relevant portion please?

    – marsze
    Nov 15 '18 at 14:36











  • Sure. No problem. Thanks for taking a look!

    – Steve Weaver
    Nov 15 '18 at 14:39



















  • Can you reduce the code to only the relevant portion please?

    – marsze
    Nov 15 '18 at 14:36











  • Sure. No problem. Thanks for taking a look!

    – Steve Weaver
    Nov 15 '18 at 14:39

















Can you reduce the code to only the relevant portion please?

– marsze
Nov 15 '18 at 14:36





Can you reduce the code to only the relevant portion please?

– marsze
Nov 15 '18 at 14:36













Sure. No problem. Thanks for taking a look!

– Steve Weaver
Nov 15 '18 at 14:39





Sure. No problem. Thanks for taking a look!

– Steve Weaver
Nov 15 '18 at 14:39












1 Answer
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oldest

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4














Move-Item does not output to the pipeline by default. Use the -PassThru switch:




-PassThru

Returns an object representing the item with which you are working. By default, this cmdlet does not generate any output.




That will pipe it directly into Rename-Item and you have to specify -NewName only:



Get-ChildItem -Path $folderpath -Filter $folderfile | 
Move-Item -Destination $destination -PassThru |
Rename-Item -NewName $newname -PassThru |
Out-File -FilePath $logpath -Append


Also, you don't even have to use Rename-Item at all but move it directly to the final target directory + name (assuming $destination is a directory path):



Get-ChildItem -Path $folderpath -Filter $folderfile | 
Move-Item -Destination (Join-Path $destination $newname) -PassThru |
Out-File -FilePath $logpath -Append





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    1 Answer
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    active

    oldest

    votes









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    oldest

    votes






    active

    oldest

    votes









    4














    Move-Item does not output to the pipeline by default. Use the -PassThru switch:




    -PassThru

    Returns an object representing the item with which you are working. By default, this cmdlet does not generate any output.




    That will pipe it directly into Rename-Item and you have to specify -NewName only:



    Get-ChildItem -Path $folderpath -Filter $folderfile | 
    Move-Item -Destination $destination -PassThru |
    Rename-Item -NewName $newname -PassThru |
    Out-File -FilePath $logpath -Append


    Also, you don't even have to use Rename-Item at all but move it directly to the final target directory + name (assuming $destination is a directory path):



    Get-ChildItem -Path $folderpath -Filter $folderfile | 
    Move-Item -Destination (Join-Path $destination $newname) -PassThru |
    Out-File -FilePath $logpath -Append





    share|improve this answer






























      4














      Move-Item does not output to the pipeline by default. Use the -PassThru switch:




      -PassThru

      Returns an object representing the item with which you are working. By default, this cmdlet does not generate any output.




      That will pipe it directly into Rename-Item and you have to specify -NewName only:



      Get-ChildItem -Path $folderpath -Filter $folderfile | 
      Move-Item -Destination $destination -PassThru |
      Rename-Item -NewName $newname -PassThru |
      Out-File -FilePath $logpath -Append


      Also, you don't even have to use Rename-Item at all but move it directly to the final target directory + name (assuming $destination is a directory path):



      Get-ChildItem -Path $folderpath -Filter $folderfile | 
      Move-Item -Destination (Join-Path $destination $newname) -PassThru |
      Out-File -FilePath $logpath -Append





      share|improve this answer




























        4












        4








        4







        Move-Item does not output to the pipeline by default. Use the -PassThru switch:




        -PassThru

        Returns an object representing the item with which you are working. By default, this cmdlet does not generate any output.




        That will pipe it directly into Rename-Item and you have to specify -NewName only:



        Get-ChildItem -Path $folderpath -Filter $folderfile | 
        Move-Item -Destination $destination -PassThru |
        Rename-Item -NewName $newname -PassThru |
        Out-File -FilePath $logpath -Append


        Also, you don't even have to use Rename-Item at all but move it directly to the final target directory + name (assuming $destination is a directory path):



        Get-ChildItem -Path $folderpath -Filter $folderfile | 
        Move-Item -Destination (Join-Path $destination $newname) -PassThru |
        Out-File -FilePath $logpath -Append





        share|improve this answer















        Move-Item does not output to the pipeline by default. Use the -PassThru switch:




        -PassThru

        Returns an object representing the item with which you are working. By default, this cmdlet does not generate any output.




        That will pipe it directly into Rename-Item and you have to specify -NewName only:



        Get-ChildItem -Path $folderpath -Filter $folderfile | 
        Move-Item -Destination $destination -PassThru |
        Rename-Item -NewName $newname -PassThru |
        Out-File -FilePath $logpath -Append


        Also, you don't even have to use Rename-Item at all but move it directly to the final target directory + name (assuming $destination is a directory path):



        Get-ChildItem -Path $folderpath -Filter $folderfile | 
        Move-Item -Destination (Join-Path $destination $newname) -PassThru |
        Out-File -FilePath $logpath -Append






        share|improve this answer














        share|improve this answer



        share|improve this answer








        edited Nov 15 '18 at 15:09

























        answered Nov 15 '18 at 15:02









        marszemarsze

        5,53232041




        5,53232041
































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