Levenshtein distance in Swift3
I'm using a tutorial from Rosetta Code to calculate Levenshtein distance. It seems their code is in Swift2 so I get this error Binary operator '+' cannot be applied to operands of type '[Int]' and 'Repeated<String.CharacterView>' when doing this: var cur = [i + 2] + empty where let empty = repeatElement(s, count: 0). How can I go about this?
swift swift3 levenshtein-distance rosetta-code
add a comment |
I'm using a tutorial from Rosetta Code to calculate Levenshtein distance. It seems their code is in Swift2 so I get this error Binary operator '+' cannot be applied to operands of type '[Int]' and 'Repeated<String.CharacterView>' when doing this: var cur = [i + 2] + empty where let empty = repeatElement(s, count: 0). How can I go about this?
swift swift3 levenshtein-distance rosetta-code
1
Not a direct answer to your question, but here stackoverflow.com/questions/26990394/… is an implementation which should require only minor modifications for Swift 3.
– Martin R
May 21 '17 at 22:06
Thanks, worked but would still love to use their(Rosetta) method since it seems shorter.
– styl3r
May 21 '17 at 22:25
add a comment |
I'm using a tutorial from Rosetta Code to calculate Levenshtein distance. It seems their code is in Swift2 so I get this error Binary operator '+' cannot be applied to operands of type '[Int]' and 'Repeated<String.CharacterView>' when doing this: var cur = [i + 2] + empty where let empty = repeatElement(s, count: 0). How can I go about this?
swift swift3 levenshtein-distance rosetta-code
I'm using a tutorial from Rosetta Code to calculate Levenshtein distance. It seems their code is in Swift2 so I get this error Binary operator '+' cannot be applied to operands of type '[Int]' and 'Repeated<String.CharacterView>' when doing this: var cur = [i + 2] + empty where let empty = repeatElement(s, count: 0). How can I go about this?
swift swift3 levenshtein-distance rosetta-code
swift swift3 levenshtein-distance rosetta-code
asked May 21 '17 at 21:58
styl3rstyl3r
417619
417619
1
Not a direct answer to your question, but here stackoverflow.com/questions/26990394/… is an implementation which should require only minor modifications for Swift 3.
– Martin R
May 21 '17 at 22:06
Thanks, worked but would still love to use their(Rosetta) method since it seems shorter.
– styl3r
May 21 '17 at 22:25
add a comment |
1
Not a direct answer to your question, but here stackoverflow.com/questions/26990394/… is an implementation which should require only minor modifications for Swift 3.
– Martin R
May 21 '17 at 22:06
Thanks, worked but would still love to use their(Rosetta) method since it seems shorter.
– styl3r
May 21 '17 at 22:25
1
1
Not a direct answer to your question, but here stackoverflow.com/questions/26990394/… is an implementation which should require only minor modifications for Swift 3.
– Martin R
May 21 '17 at 22:06
Not a direct answer to your question, but here stackoverflow.com/questions/26990394/… is an implementation which should require only minor modifications for Swift 3.
– Martin R
May 21 '17 at 22:06
Thanks, worked but would still love to use their(Rosetta) method since it seems shorter.
– styl3r
May 21 '17 at 22:25
Thanks, worked but would still love to use their(Rosetta) method since it seems shorter.
– styl3r
May 21 '17 at 22:25
add a comment |
3 Answers
3
active
oldest
votes
There were a couple of changes to make.
- The construction of the Array empty.
- enumerate() is now enumerated()
- successor() doesn't exist anymore so I replaced it with +1
So the function is now
Swift 4:
func levDis(_ w1: String, _ w2: String) -> Int {
let empty = [Int](repeating:0, count: w2.count)
var last = [Int](0...w2.count)
for (i, char1) in w1.enumerated() {
var cur = [i + 1] + empty
for (j, char2) in w2.enumerated() {
cur[j + 1] = char1 == char2 ? last[j] : min(last[j], last[j + 1], cur[j]) + 1
}
last = cur
}
return last.last!
}
Swift 3:
func levDis(w1: String, w2: String) -> Int {
let (t, s) = (w1.characters, w2.characters)
let empty = Array<Int>(repeating:0, count: s.count)
var last = [Int](0...s.count)
for (i, tLett) in t.enumerated() {
var cur = [i + 1] + empty
for (j, sLett) in s.enumerated() {
cur[j + 1] = tLett == sLett ? last[j] : min(last[j], last[j + 1], cur[j])+1
}
last = cur
}
return last.last!
}
add a comment |
Updated and improved answer to Swift 4, based on @Spads answer.
extension String {
func levenshteinDistanceScore(to string: String, ignoreCase: Bool = true, trimWhiteSpacesAndNewLines: Bool = true) -> Float {
var firstString = self
var secondString = string
if ignoreCase {
firstString = firstString.lowercased()
secondString = secondString.lowercased()
}
if trimWhiteSpacesAndNewLines {
firstString = firstString.trimmingCharacters(in: .whitespacesAndNewlines)
secondString = secondString.trimmingCharacters(in: .whitespacesAndNewlines)
}
let empty = [Int](repeating:0, count: secondString.count)
var last = [Int](0...secondString.count)
for (i, tLett) in firstString.enumerated() {
var cur = [i + 1] + empty
for (j, sLett) in secondString.enumerated() {
cur[j + 1] = tLett == sLett ? last[j] : Swift.min(last[j], last[j + 1], cur[j])+1
}
last = cur
}
// maximum string length between the two
let lowestScore = max(firstString.count, secondString.count)
if let validDistance = last.last {
return 1 - (Float(validDistance) / Float(lowestScore))
}
return 0.0
}
}
infix operator =~
func =~(string: String, otherString: String) -> Bool {
return string.levenshteinDistanceScore(to: otherString) >= 0.85
}
What does this actually calculate? As far as I know the Levenshtein Distance is an Int, not a float.
– hashier
Dec 2 '18 at 8:20
add a comment |
func ~=(string: String, otherString: String) -> Bool {
return string.levenshteinDistanceScore(to: otherString) >= 0.85
}
This is the correct operator Overloading for levenshteinDistanceScore String Extension. stackoverflow.com/a/48976605/9991497
– akash soni
Nov 16 '18 at 8:13
add a comment |
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3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
There were a couple of changes to make.
- The construction of the Array empty.
- enumerate() is now enumerated()
- successor() doesn't exist anymore so I replaced it with +1
So the function is now
Swift 4:
func levDis(_ w1: String, _ w2: String) -> Int {
let empty = [Int](repeating:0, count: w2.count)
var last = [Int](0...w2.count)
for (i, char1) in w1.enumerated() {
var cur = [i + 1] + empty
for (j, char2) in w2.enumerated() {
cur[j + 1] = char1 == char2 ? last[j] : min(last[j], last[j + 1], cur[j]) + 1
}
last = cur
}
return last.last!
}
Swift 3:
func levDis(w1: String, w2: String) -> Int {
let (t, s) = (w1.characters, w2.characters)
let empty = Array<Int>(repeating:0, count: s.count)
var last = [Int](0...s.count)
for (i, tLett) in t.enumerated() {
var cur = [i + 1] + empty
for (j, sLett) in s.enumerated() {
cur[j + 1] = tLett == sLett ? last[j] : min(last[j], last[j + 1], cur[j])+1
}
last = cur
}
return last.last!
}
add a comment |
There were a couple of changes to make.
- The construction of the Array empty.
- enumerate() is now enumerated()
- successor() doesn't exist anymore so I replaced it with +1
So the function is now
Swift 4:
func levDis(_ w1: String, _ w2: String) -> Int {
let empty = [Int](repeating:0, count: w2.count)
var last = [Int](0...w2.count)
for (i, char1) in w1.enumerated() {
var cur = [i + 1] + empty
for (j, char2) in w2.enumerated() {
cur[j + 1] = char1 == char2 ? last[j] : min(last[j], last[j + 1], cur[j]) + 1
}
last = cur
}
return last.last!
}
Swift 3:
func levDis(w1: String, w2: String) -> Int {
let (t, s) = (w1.characters, w2.characters)
let empty = Array<Int>(repeating:0, count: s.count)
var last = [Int](0...s.count)
for (i, tLett) in t.enumerated() {
var cur = [i + 1] + empty
for (j, sLett) in s.enumerated() {
cur[j + 1] = tLett == sLett ? last[j] : min(last[j], last[j + 1], cur[j])+1
}
last = cur
}
return last.last!
}
add a comment |
There were a couple of changes to make.
- The construction of the Array empty.
- enumerate() is now enumerated()
- successor() doesn't exist anymore so I replaced it with +1
So the function is now
Swift 4:
func levDis(_ w1: String, _ w2: String) -> Int {
let empty = [Int](repeating:0, count: w2.count)
var last = [Int](0...w2.count)
for (i, char1) in w1.enumerated() {
var cur = [i + 1] + empty
for (j, char2) in w2.enumerated() {
cur[j + 1] = char1 == char2 ? last[j] : min(last[j], last[j + 1], cur[j]) + 1
}
last = cur
}
return last.last!
}
Swift 3:
func levDis(w1: String, w2: String) -> Int {
let (t, s) = (w1.characters, w2.characters)
let empty = Array<Int>(repeating:0, count: s.count)
var last = [Int](0...s.count)
for (i, tLett) in t.enumerated() {
var cur = [i + 1] + empty
for (j, sLett) in s.enumerated() {
cur[j + 1] = tLett == sLett ? last[j] : min(last[j], last[j + 1], cur[j])+1
}
last = cur
}
return last.last!
}
There were a couple of changes to make.
- The construction of the Array empty.
- enumerate() is now enumerated()
- successor() doesn't exist anymore so I replaced it with +1
So the function is now
Swift 4:
func levDis(_ w1: String, _ w2: String) -> Int {
let empty = [Int](repeating:0, count: w2.count)
var last = [Int](0...w2.count)
for (i, char1) in w1.enumerated() {
var cur = [i + 1] + empty
for (j, char2) in w2.enumerated() {
cur[j + 1] = char1 == char2 ? last[j] : min(last[j], last[j + 1], cur[j]) + 1
}
last = cur
}
return last.last!
}
Swift 3:
func levDis(w1: String, w2: String) -> Int {
let (t, s) = (w1.characters, w2.characters)
let empty = Array<Int>(repeating:0, count: s.count)
var last = [Int](0...s.count)
for (i, tLett) in t.enumerated() {
var cur = [i + 1] + empty
for (j, sLett) in s.enumerated() {
cur[j + 1] = tLett == sLett ? last[j] : min(last[j], last[j + 1], cur[j])+1
}
last = cur
}
return last.last!
}
edited Dec 2 '18 at 9:16
hashier
3,87612041
3,87612041
answered May 21 '17 at 22:28
SpadsSpads
1,6511520
1,6511520
add a comment |
add a comment |
Updated and improved answer to Swift 4, based on @Spads answer.
extension String {
func levenshteinDistanceScore(to string: String, ignoreCase: Bool = true, trimWhiteSpacesAndNewLines: Bool = true) -> Float {
var firstString = self
var secondString = string
if ignoreCase {
firstString = firstString.lowercased()
secondString = secondString.lowercased()
}
if trimWhiteSpacesAndNewLines {
firstString = firstString.trimmingCharacters(in: .whitespacesAndNewlines)
secondString = secondString.trimmingCharacters(in: .whitespacesAndNewlines)
}
let empty = [Int](repeating:0, count: secondString.count)
var last = [Int](0...secondString.count)
for (i, tLett) in firstString.enumerated() {
var cur = [i + 1] + empty
for (j, sLett) in secondString.enumerated() {
cur[j + 1] = tLett == sLett ? last[j] : Swift.min(last[j], last[j + 1], cur[j])+1
}
last = cur
}
// maximum string length between the two
let lowestScore = max(firstString.count, secondString.count)
if let validDistance = last.last {
return 1 - (Float(validDistance) / Float(lowestScore))
}
return 0.0
}
}
infix operator =~
func =~(string: String, otherString: String) -> Bool {
return string.levenshteinDistanceScore(to: otherString) >= 0.85
}
What does this actually calculate? As far as I know the Levenshtein Distance is an Int, not a float.
– hashier
Dec 2 '18 at 8:20
add a comment |
Updated and improved answer to Swift 4, based on @Spads answer.
extension String {
func levenshteinDistanceScore(to string: String, ignoreCase: Bool = true, trimWhiteSpacesAndNewLines: Bool = true) -> Float {
var firstString = self
var secondString = string
if ignoreCase {
firstString = firstString.lowercased()
secondString = secondString.lowercased()
}
if trimWhiteSpacesAndNewLines {
firstString = firstString.trimmingCharacters(in: .whitespacesAndNewlines)
secondString = secondString.trimmingCharacters(in: .whitespacesAndNewlines)
}
let empty = [Int](repeating:0, count: secondString.count)
var last = [Int](0...secondString.count)
for (i, tLett) in firstString.enumerated() {
var cur = [i + 1] + empty
for (j, sLett) in secondString.enumerated() {
cur[j + 1] = tLett == sLett ? last[j] : Swift.min(last[j], last[j + 1], cur[j])+1
}
last = cur
}
// maximum string length between the two
let lowestScore = max(firstString.count, secondString.count)
if let validDistance = last.last {
return 1 - (Float(validDistance) / Float(lowestScore))
}
return 0.0
}
}
infix operator =~
func =~(string: String, otherString: String) -> Bool {
return string.levenshteinDistanceScore(to: otherString) >= 0.85
}
What does this actually calculate? As far as I know the Levenshtein Distance is an Int, not a float.
– hashier
Dec 2 '18 at 8:20
add a comment |
Updated and improved answer to Swift 4, based on @Spads answer.
extension String {
func levenshteinDistanceScore(to string: String, ignoreCase: Bool = true, trimWhiteSpacesAndNewLines: Bool = true) -> Float {
var firstString = self
var secondString = string
if ignoreCase {
firstString = firstString.lowercased()
secondString = secondString.lowercased()
}
if trimWhiteSpacesAndNewLines {
firstString = firstString.trimmingCharacters(in: .whitespacesAndNewlines)
secondString = secondString.trimmingCharacters(in: .whitespacesAndNewlines)
}
let empty = [Int](repeating:0, count: secondString.count)
var last = [Int](0...secondString.count)
for (i, tLett) in firstString.enumerated() {
var cur = [i + 1] + empty
for (j, sLett) in secondString.enumerated() {
cur[j + 1] = tLett == sLett ? last[j] : Swift.min(last[j], last[j + 1], cur[j])+1
}
last = cur
}
// maximum string length between the two
let lowestScore = max(firstString.count, secondString.count)
if let validDistance = last.last {
return 1 - (Float(validDistance) / Float(lowestScore))
}
return 0.0
}
}
infix operator =~
func =~(string: String, otherString: String) -> Bool {
return string.levenshteinDistanceScore(to: otherString) >= 0.85
}
Updated and improved answer to Swift 4, based on @Spads answer.
extension String {
func levenshteinDistanceScore(to string: String, ignoreCase: Bool = true, trimWhiteSpacesAndNewLines: Bool = true) -> Float {
var firstString = self
var secondString = string
if ignoreCase {
firstString = firstString.lowercased()
secondString = secondString.lowercased()
}
if trimWhiteSpacesAndNewLines {
firstString = firstString.trimmingCharacters(in: .whitespacesAndNewlines)
secondString = secondString.trimmingCharacters(in: .whitespacesAndNewlines)
}
let empty = [Int](repeating:0, count: secondString.count)
var last = [Int](0...secondString.count)
for (i, tLett) in firstString.enumerated() {
var cur = [i + 1] + empty
for (j, sLett) in secondString.enumerated() {
cur[j + 1] = tLett == sLett ? last[j] : Swift.min(last[j], last[j + 1], cur[j])+1
}
last = cur
}
// maximum string length between the two
let lowestScore = max(firstString.count, secondString.count)
if let validDistance = last.last {
return 1 - (Float(validDistance) / Float(lowestScore))
}
return 0.0
}
}
infix operator =~
func =~(string: String, otherString: String) -> Bool {
return string.levenshteinDistanceScore(to: otherString) >= 0.85
}
edited Jul 27 '18 at 10:58
answered Feb 25 '18 at 17:54
Daniel IllescasDaniel Illescas
1,999920
1,999920
What does this actually calculate? As far as I know the Levenshtein Distance is an Int, not a float.
– hashier
Dec 2 '18 at 8:20
add a comment |
What does this actually calculate? As far as I know the Levenshtein Distance is an Int, not a float.
– hashier
Dec 2 '18 at 8:20
What does this actually calculate? As far as I know the Levenshtein Distance is an Int, not a float.
– hashier
Dec 2 '18 at 8:20
What does this actually calculate? As far as I know the Levenshtein Distance is an Int, not a float.
– hashier
Dec 2 '18 at 8:20
add a comment |
func ~=(string: String, otherString: String) -> Bool {
return string.levenshteinDistanceScore(to: otherString) >= 0.85
}
This is the correct operator Overloading for levenshteinDistanceScore String Extension. stackoverflow.com/a/48976605/9991497
– akash soni
Nov 16 '18 at 8:13
add a comment |
func ~=(string: String, otherString: String) -> Bool {
return string.levenshteinDistanceScore(to: otherString) >= 0.85
}
This is the correct operator Overloading for levenshteinDistanceScore String Extension. stackoverflow.com/a/48976605/9991497
– akash soni
Nov 16 '18 at 8:13
add a comment |
func ~=(string: String, otherString: String) -> Bool {
return string.levenshteinDistanceScore(to: otherString) >= 0.85
}
func ~=(string: String, otherString: String) -> Bool {
return string.levenshteinDistanceScore(to: otherString) >= 0.85
}
edited Nov 16 '18 at 21:35
Tiago Martins Peres
2,23162036
2,23162036
answered Nov 16 '18 at 8:12
akash soniakash soni
13
13
This is the correct operator Overloading for levenshteinDistanceScore String Extension. stackoverflow.com/a/48976605/9991497
– akash soni
Nov 16 '18 at 8:13
add a comment |
This is the correct operator Overloading for levenshteinDistanceScore String Extension. stackoverflow.com/a/48976605/9991497
– akash soni
Nov 16 '18 at 8:13
This is the correct operator Overloading for levenshteinDistanceScore String Extension. stackoverflow.com/a/48976605/9991497
– akash soni
Nov 16 '18 at 8:13
This is the correct operator Overloading for levenshteinDistanceScore String Extension. stackoverflow.com/a/48976605/9991497
– akash soni
Nov 16 '18 at 8:13
add a comment |
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1
Not a direct answer to your question, but here stackoverflow.com/questions/26990394/… is an implementation which should require only minor modifications for Swift 3.
– Martin R
May 21 '17 at 22:06
Thanks, worked but would still love to use their(Rosetta) method since it seems shorter.
– styl3r
May 21 '17 at 22:25