cv2.imread always returns NoneType python 3.6

-1

cv2.imread always returning NoneType.

I have the following code:

path = cv2.imread('D:/XXX/image.jpg')

The array returned is Nonetype

But when I use

path = cv2.imread('image.jpg')

I get the correct array.
The problem only occurs when I use full path.
I have tried backslashes and double slash as well, but it makes no difference. There are many similar questions asked before, I have havent got any suitable answer.
The file path and file name are both correct.

I am using Python version 3.6 adn openCV version 3.4.3

Update
I tried to get the file path using tkinter filedialog.askopenfilename. Yet unsuccessful.

edited Nov 16 '18 at 10:59

asked Nov 16 '18 at 9:53

Gaurav Kumar

154

2

I think you should use double backslashes: '\'

– rockikz
Nov 16 '18 at 9:55

The only thing I can think of is the path is somehow incorrect. Try navigating to it via the command line to check it's validity?

– Ben Jones
Nov 16 '18 at 9:56

1

Use os.path.join("D:", "XXX", "image.jpg") (multiple arguments, one per directory) if you want to be cross-platform compatible and/or are not sure about the exact directory separator syntax.

– 9769953
Nov 16 '18 at 9:57

@rockikz: alredy tried that.

– Gaurav Kumar
Nov 16 '18 at 10:03

if the second option works you can check what is your directory with os.getcwd() also you can check if the file exists in such path with os.path.exists(file_path)

– api55
Nov 16 '18 at 10:04

|
show 4 more comments

-1

cv2.imread always returning NoneType.

I have the following code:

path = cv2.imread('D:/XXX/image.jpg')

The array returned is Nonetype

But when I use

path = cv2.imread('image.jpg')

I am using Python version 3.6 adn openCV version 3.4.3

Update
I tried to get the file path using tkinter filedialog.askopenfilename. Yet unsuccessful.

edited Nov 16 '18 at 10:59

asked Nov 16 '18 at 9:53

Gaurav Kumar

154

2

I think you should use double backslashes: '\'

– rockikz
Nov 16 '18 at 9:55

The only thing I can think of is the path is somehow incorrect. Try navigating to it via the command line to check it's validity?

– Ben Jones
Nov 16 '18 at 9:56

1

Use os.path.join("D:", "XXX", "image.jpg") (multiple arguments, one per directory) if you want to be cross-platform compatible and/or are not sure about the exact directory separator syntax.

– 9769953
Nov 16 '18 at 9:57

@rockikz: alredy tried that.

– Gaurav Kumar
Nov 16 '18 at 10:03

if the second option works you can check what is your directory with os.getcwd() also you can check if the file exists in such path with os.path.exists(file_path)

– api55
Nov 16 '18 at 10:04

|
show 4 more comments

-1

cv2.imread always returning NoneType.

I have the following code:

path = cv2.imread('D:/XXX/image.jpg')

The array returned is Nonetype

But when I use

path = cv2.imread('image.jpg')

I am using Python version 3.6 adn openCV version 3.4.3

Update
I tried to get the file path using tkinter filedialog.askopenfilename. Yet unsuccessful.

edited Nov 16 '18 at 10:59

asked Nov 16 '18 at 9:53

Gaurav Kumar

154

cv2.imread always returning NoneType.

I have the following code:

path = cv2.imread('D:/XXX/image.jpg')

The array returned is Nonetype

But when I use

path = cv2.imread('image.jpg')

I am using Python version 3.6 adn openCV version 3.4.3

Update
I tried to get the file path using tkinter filedialog.askopenfilename. Yet unsuccessful.

python python-3.x opencv

edited Nov 16 '18 at 10:59

asked Nov 16 '18 at 9:53

Gaurav Kumar

154

edited Nov 16 '18 at 10:59

asked Nov 16 '18 at 9:53

Gaurav Kumar

154

edited Nov 16 '18 at 10:59

asked Nov 16 '18 at 9:53

Gaurav Kumar

154

asked Nov 16 '18 at 9:53

Gaurav Kumar

154

asked Nov 16 '18 at 9:53

Gaurav Kumar

154

2

I think you should use double backslashes: '\'

– rockikz
Nov 16 '18 at 9:55

The only thing I can think of is the path is somehow incorrect. Try navigating to it via the command line to check it's validity?

– Ben Jones
Nov 16 '18 at 9:56

1

Use os.path.join("D:", "XXX", "image.jpg") (multiple arguments, one per directory) if you want to be cross-platform compatible and/or are not sure about the exact directory separator syntax.

– 9769953
Nov 16 '18 at 9:57

@rockikz: alredy tried that.

– Gaurav Kumar
Nov 16 '18 at 10:03

if the second option works you can check what is your directory with os.getcwd() also you can check if the file exists in such path with os.path.exists(file_path)

– api55
Nov 16 '18 at 10:04

|
show 4 more comments

2

I think you should use double backslashes: '\'

– rockikz
Nov 16 '18 at 9:55

The only thing I can think of is the path is somehow incorrect. Try navigating to it via the command line to check it's validity?

– Ben Jones
Nov 16 '18 at 9:56

1

Use os.path.join("D:", "XXX", "image.jpg") (multiple arguments, one per directory) if you want to be cross-platform compatible and/or are not sure about the exact directory separator syntax.

– 9769953
Nov 16 '18 at 9:57

@rockikz: alredy tried that.

– Gaurav Kumar
Nov 16 '18 at 10:03

if the second option works you can check what is your directory with os.getcwd() also you can check if the file exists in such path with os.path.exists(file_path)

– api55
Nov 16 '18 at 10:04

I think you should use double backslashes: '\'

– rockikz
Nov 16 '18 at 9:55

The only thing I can think of is the path is somehow incorrect. Try navigating to it via the command line to check it's validity?

– Ben Jones
Nov 16 '18 at 9:56

Use os.path.join("D:", "XXX", "image.jpg") (multiple arguments, one per directory) if you want to be cross-platform compatible and/or are not sure about the exact directory separator syntax.

– 9769953
Nov 16 '18 at 9:57

@rockikz: alredy tried that.

– Gaurav Kumar
Nov 16 '18 at 10:03

if the second option works you can check what is your directory with os.getcwd() also you can check if the file exists in such path with os.path.exists(file_path)

– api55
Nov 16 '18 at 10:04

|
show 4 more comments

1 Answer
1

active

oldest

votes

-2

You are using it correctly but missed a parameter.
calling cv2.imread(jpeg_file,0) yeild a ndtype array object

however, try this and make sure image file is not zero size.

img = cv2.imread(filename_name,0)

as the doc says

    Use the function cv2.imread() to read an image. The image should be in the working directory or a full path of image should be given.



Second argument is a flag which specifies the way image should be read.



cv2.IMREAD_COLOR : Loads a color image. Any transparency of image will be neglected. It is the default flag.

cv2.IMREAD_GRAYSCALE : Loads image in grayscale mode

cv2.IMREAD_UNCHANGED : Loads image as such including alpha channel

Note Instead of these three flags, you can simply pass integers 1, 0 or -1 respectively.

See the code below:



import numpy as np

import cv2



# Load an color image in grayscale

img = cv2.imread('messi5.jpg',0)

Cv2.imread usage

answered Nov 16 '18 at 10:13

TheExorcist

9471215

the second parameter is optional as it can be seen in the documentation. And one should use the constant (i.e. cv2.IMREAD_GRAYSCALE) rather than 0 when it is needed. The default value of the flag is cv2.IMREAD_COLOR

– api55
Nov 16 '18 at 10:18

This works when the image is in the working directory, but doest wotk when I use the full path.

– Gaurav Kumar
Nov 16 '18 at 10:20

@api55 perfect, didn't go so deep looking.

– TheExorcist
Nov 16 '18 at 10:25

Use of magic numbers is an anti-pattern -- this code would not pass even a rudimentary code review. | Changing the second parameter of imread from the default cv2.IMREAD_COLOR to cv2.IMREAD_GRAYSCALE would have no effect on the returned data type. It's always a numpy array (except when loading fails, then it returns None). The only thing it would change is what (potential) conversions are done after the image has been loaded from file -- in this case it would always return a single channel image, as opposed to always returning a 3 channel image.

– Dan Mašek
Nov 16 '18 at 13:16

I think the community should delete the answer as the answer doesn't fulfill the purpose of asking.

– TheExorcist
Nov 17 '18 at 8:12

add a comment |

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1 Answer
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1 Answer
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oldest

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-2

You are using it correctly but missed a parameter.
calling cv2.imread(jpeg_file,0) yeild a ndtype array object

however, try this and make sure image file is not zero size.

img = cv2.imread(filename_name,0)

as the doc says

    Use the function cv2.imread() to read an image. The image should be in the working directory or a full path of image should be given.



Second argument is a flag which specifies the way image should be read.



cv2.IMREAD_COLOR : Loads a color image. Any transparency of image will be neglected. It is the default flag.

cv2.IMREAD_GRAYSCALE : Loads image in grayscale mode

cv2.IMREAD_UNCHANGED : Loads image as such including alpha channel

Note Instead of these three flags, you can simply pass integers 1, 0 or -1 respectively.

See the code below:



import numpy as np

import cv2



# Load an color image in grayscale

img = cv2.imread('messi5.jpg',0)

Cv2.imread usage

answered Nov 16 '18 at 10:13

TheExorcist

9471215

the second parameter is optional as it can be seen in the documentation. And one should use the constant (i.e. cv2.IMREAD_GRAYSCALE) rather than 0 when it is needed. The default value of the flag is cv2.IMREAD_COLOR

– api55
Nov 16 '18 at 10:18

This works when the image is in the working directory, but doest wotk when I use the full path.

– Gaurav Kumar
Nov 16 '18 at 10:20

@api55 perfect, didn't go so deep looking.

– TheExorcist
Nov 16 '18 at 10:25

Use of magic numbers is an anti-pattern -- this code would not pass even a rudimentary code review. | Changing the second parameter of imread from the default cv2.IMREAD_COLOR to cv2.IMREAD_GRAYSCALE would have no effect on the returned data type. It's always a numpy array (except when loading fails, then it returns None). The only thing it would change is what (potential) conversions are done after the image has been loaded from file -- in this case it would always return a single channel image, as opposed to always returning a 3 channel image.

– Dan Mašek
Nov 16 '18 at 13:16

I think the community should delete the answer as the answer doesn't fulfill the purpose of asking.

– TheExorcist
Nov 17 '18 at 8:12

add a comment |

-2

You are using it correctly but missed a parameter.
calling cv2.imread(jpeg_file,0) yeild a ndtype array object

however, try this and make sure image file is not zero size.

img = cv2.imread(filename_name,0)

as the doc says

    Use the function cv2.imread() to read an image. The image should be in the working directory or a full path of image should be given.



Second argument is a flag which specifies the way image should be read.



cv2.IMREAD_COLOR : Loads a color image. Any transparency of image will be neglected. It is the default flag.

cv2.IMREAD_GRAYSCALE : Loads image in grayscale mode

cv2.IMREAD_UNCHANGED : Loads image as such including alpha channel

Note Instead of these three flags, you can simply pass integers 1, 0 or -1 respectively.

See the code below:



import numpy as np

import cv2



# Load an color image in grayscale

img = cv2.imread('messi5.jpg',0)

Cv2.imread usage

answered Nov 16 '18 at 10:13

TheExorcist

9471215

the second parameter is optional as it can be seen in the documentation. And one should use the constant (i.e. cv2.IMREAD_GRAYSCALE) rather than 0 when it is needed. The default value of the flag is cv2.IMREAD_COLOR

– api55
Nov 16 '18 at 10:18

This works when the image is in the working directory, but doest wotk when I use the full path.

– Gaurav Kumar
Nov 16 '18 at 10:20

@api55 perfect, didn't go so deep looking.

– TheExorcist
Nov 16 '18 at 10:25

Use of magic numbers is an anti-pattern -- this code would not pass even a rudimentary code review. | Changing the second parameter of imread from the default cv2.IMREAD_COLOR to cv2.IMREAD_GRAYSCALE would have no effect on the returned data type. It's always a numpy array (except when loading fails, then it returns None). The only thing it would change is what (potential) conversions are done after the image has been loaded from file -- in this case it would always return a single channel image, as opposed to always returning a 3 channel image.

– Dan Mašek
Nov 16 '18 at 13:16

I think the community should delete the answer as the answer doesn't fulfill the purpose of asking.

– TheExorcist
Nov 17 '18 at 8:12

add a comment |

-2

You are using it correctly but missed a parameter.
calling cv2.imread(jpeg_file,0) yeild a ndtype array object

however, try this and make sure image file is not zero size.

img = cv2.imread(filename_name,0)

as the doc says

    Use the function cv2.imread() to read an image. The image should be in the working directory or a full path of image should be given.



Second argument is a flag which specifies the way image should be read.



cv2.IMREAD_COLOR : Loads a color image. Any transparency of image will be neglected. It is the default flag.

cv2.IMREAD_GRAYSCALE : Loads image in grayscale mode

cv2.IMREAD_UNCHANGED : Loads image as such including alpha channel

Note Instead of these three flags, you can simply pass integers 1, 0 or -1 respectively.

See the code below:



import numpy as np

import cv2



# Load an color image in grayscale

img = cv2.imread('messi5.jpg',0)

Cv2.imread usage

answered Nov 16 '18 at 10:13

TheExorcist

9471215

You are using it correctly but missed a parameter.
calling cv2.imread(jpeg_file,0) yeild a ndtype array object

however, try this and make sure image file is not zero size.

img = cv2.imread(filename_name,0)

as the doc says

    Use the function cv2.imread() to read an image. The image should be in the working directory or a full path of image should be given.



Second argument is a flag which specifies the way image should be read.



cv2.IMREAD_COLOR : Loads a color image. Any transparency of image will be neglected. It is the default flag.

cv2.IMREAD_GRAYSCALE : Loads image in grayscale mode

cv2.IMREAD_UNCHANGED : Loads image as such including alpha channel

Note Instead of these three flags, you can simply pass integers 1, 0 or -1 respectively.

See the code below:



import numpy as np

import cv2



# Load an color image in grayscale

img = cv2.imread('messi5.jpg',0)

Cv2.imread usage

answered Nov 16 '18 at 10:13

TheExorcist

9471215

answered Nov 16 '18 at 10:13

TheExorcist

9471215

answered Nov 16 '18 at 10:13

TheExorcist

9471215

answered Nov 16 '18 at 10:13

TheExorcist

9471215

the second parameter is optional as it can be seen in the documentation. And one should use the constant (i.e. cv2.IMREAD_GRAYSCALE) rather than 0 when it is needed. The default value of the flag is cv2.IMREAD_COLOR

– api55
Nov 16 '18 at 10:18

This works when the image is in the working directory, but doest wotk when I use the full path.

– Gaurav Kumar
Nov 16 '18 at 10:20

@api55 perfect, didn't go so deep looking.

– TheExorcist
Nov 16 '18 at 10:25

Use of magic numbers is an anti-pattern -- this code would not pass even a rudimentary code review. | Changing the second parameter of imread from the default cv2.IMREAD_COLOR to cv2.IMREAD_GRAYSCALE would have no effect on the returned data type. It's always a numpy array (except when loading fails, then it returns None). The only thing it would change is what (potential) conversions are done after the image has been loaded from file -- in this case it would always return a single channel image, as opposed to always returning a 3 channel image.

– Dan Mašek
Nov 16 '18 at 13:16

I think the community should delete the answer as the answer doesn't fulfill the purpose of asking.

– TheExorcist
Nov 17 '18 at 8:12

add a comment |

the second parameter is optional as it can be seen in the documentation. And one should use the constant (i.e. cv2.IMREAD_GRAYSCALE) rather than 0 when it is needed. The default value of the flag is cv2.IMREAD_COLOR

– api55
Nov 16 '18 at 10:18

This works when the image is in the working directory, but doest wotk when I use the full path.

– Gaurav Kumar
Nov 16 '18 at 10:20

@api55 perfect, didn't go so deep looking.

– TheExorcist
Nov 16 '18 at 10:25

Use of magic numbers is an anti-pattern -- this code would not pass even a rudimentary code review. | Changing the second parameter of imread from the default cv2.IMREAD_COLOR to cv2.IMREAD_GRAYSCALE would have no effect on the returned data type. It's always a numpy array (except when loading fails, then it returns None). The only thing it would change is what (potential) conversions are done after the image has been loaded from file -- in this case it would always return a single channel image, as opposed to always returning a 3 channel image.

– Dan Mašek
Nov 16 '18 at 13:16

I think the community should delete the answer as the answer doesn't fulfill the purpose of asking.

– TheExorcist
Nov 17 '18 at 8:12

the second parameter is optional as it can be seen in the documentation. And one should use the constant (i.e. cv2.IMREAD_GRAYSCALE) rather than 0 when it is needed. The default value of the flag is cv2.IMREAD_COLOR

– api55
Nov 16 '18 at 10:18

This works when the image is in the working directory, but doest wotk when I use the full path.

– Gaurav Kumar
Nov 16 '18 at 10:20

@api55 perfect, didn't go so deep looking.

– TheExorcist
Nov 16 '18 at 10:25

Use of magic numbers is an anti-pattern -- this code would not pass even a rudimentary code review. | Changing the second parameter of imread from the default cv2.IMREAD_COLOR to cv2.IMREAD_GRAYSCALE would have no effect on the returned data type. It's always a numpy array (except when loading fails, then it returns None). The only thing it would change is what (potential) conversions are done after the image has been loaded from file -- in this case it would always return a single channel image, as opposed to always returning a 3 channel image.

– Dan Mašek
Nov 16 '18 at 13:16

I think the community should delete the answer as the answer doesn't fulfill the purpose of asking.

– TheExorcist
Nov 17 '18 at 8:12

add a comment |

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