Can a task re-schedule itself with APScheduler?
I am trying to set up a delayed task task whose timing will depend on several parameters (either passed to it or obtained from a redis database).
the pseudocode would look like this:
def main():
scheduler = BackgroundScheduler()
scheduler.add_job(delayed_task,
id=task_id,
next_run_time=somedate,
args=(task_id, some_data))
scheduler.start()
do_something_else()
def delayed_task(id, passed_data):
rd = connect_to_redis()
redis_data = rd.fetch_data(id)
publish_data(passed_data, redis_data)
updated_run_time = parse(redis_data)
#obtain a scheduler object here
scheduler.modify_job(id, next_run_time=updated_run_time)
The question is the following: is there a way to access the scheduler from a task?
The scheduler cannot be passed as parameter to the task, as this will raise
TypeError: can't pickle _thread.lock objects
For the same reason, I can't put all this in a class and have it called a method since the arguments of the method include self, which is the class containing the scheduler, and will thus result in the same issue.
Is it possible to regain an instance of the scheduler from outside, like I can generate a new connexion to redis?
python-3.x scheduled-tasks apscheduler
asked Nov 15 '18 at 12:23
AdalcarAdalcar
1,101523
add a comment |
I am trying to set up a delayed task task whose timing will depend on several parameters (either passed to it or obtained from a redis database).
the pseudocode would look like this:
def main():
scheduler = BackgroundScheduler()
scheduler.add_job(delayed_task,
id=task_id,
next_run_time=somedate,
args=(task_id, some_data))
scheduler.start()
do_something_else()
def delayed_task(id, passed_data):
rd = connect_to_redis()
redis_data = rd.fetch_data(id)
publish_data(passed_data, redis_data)
updated_run_time = parse(redis_data)
#obtain a scheduler object here
scheduler.modify_job(id, next_run_time=updated_run_time)
The question is the following: is there a way to access the scheduler from a task?
The scheduler cannot be passed as parameter to the task, as this will raise
TypeError: can't pickle _thread.lock objects
For the same reason, I can't put all this in a class and have it called a method since the arguments of the method include self, which is the class containing the scheduler, and will thus result in the same issue.
Is it possible to regain an instance of the scheduler from outside, like I can generate a new connexion to redis?
python-3.x scheduled-tasks apscheduler
asked Nov 15 '18 at 12:23
AdalcarAdalcar
1,101523
add a comment |
I am trying to set up a delayed task task whose timing will depend on several parameters (either passed to it or obtained from a redis database).
the pseudocode would look like this:
def main():
scheduler = BackgroundScheduler()
scheduler.add_job(delayed_task,
id=task_id,
next_run_time=somedate,
args=(task_id, some_data))
scheduler.start()
do_something_else()
def delayed_task(id, passed_data):
rd = connect_to_redis()
redis_data = rd.fetch_data(id)
publish_data(passed_data, redis_data)
updated_run_time = parse(redis_data)
#obtain a scheduler object here
scheduler.modify_job(id, next_run_time=updated_run_time)
The question is the following: is there a way to access the scheduler from a task?
The scheduler cannot be passed as parameter to the task, as this will raise
TypeError: can't pickle _thread.lock objects
For the same reason, I can't put all this in a class and have it called a method since the arguments of the method include self, which is the class containing the scheduler, and will thus result in the same issue.
Is it possible to regain an instance of the scheduler from outside, like I can generate a new connexion to redis?
python-3.x scheduled-tasks apscheduler
asked Nov 15 '18 at 12:23
AdalcarAdalcar
1,101523
I am trying to set up a delayed task task whose timing will depend on several parameters (either passed to it or obtained from a redis database).
the pseudocode would look like this:
def main():
scheduler = BackgroundScheduler()
scheduler.add_job(delayed_task,
id=task_id,
next_run_time=somedate,
args=(task_id, some_data))
scheduler.start()
do_something_else()
def delayed_task(id, passed_data):
rd = connect_to_redis()
redis_data = rd.fetch_data(id)
publish_data(passed_data, redis_data)
updated_run_time = parse(redis_data)
#obtain a scheduler object here
scheduler.modify_job(id, next_run_time=updated_run_time)
The question is the following: is there a way to access the scheduler from a task?
The scheduler cannot be passed as parameter to the task, as this will raise
TypeError: can't pickle _thread.lock objects
For the same reason, I can't put all this in a class and have it called a method since the arguments of the method include self, which is the class containing the scheduler, and will thus result in the same issue.
Is it possible to regain an instance of the scheduler from outside, like I can generate a new connexion to redis?
python-3.x scheduled-tasks apscheduler
python-3.x scheduled-tasks apscheduler
asked Nov 15 '18 at 12:23
AdalcarAdalcar
1,101523
asked Nov 15 '18 at 12:23
AdalcarAdalcar
1,101523
asked Nov 15 '18 at 12:23
AdalcarAdalcar
1,101523
asked Nov 15 '18 at 12:23
AdalcarAdalcar
1,101523
asked Nov 15 '18 at 12:23
AdalcarAdalcar
1,101523
1,101523
add a comment |
add a comment |
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