SQL Server - Hasbytes in function gives different result then in select












1















I created a function like this:



CREATE FUNCTION dbo.HashCheeseName (@CheeseName NVARCHAR(40)) 
RETURNS VARCHAR(40)
AS BEGIN
DECLARE @Salt VARCHAR(25)
DECLARE @CheeseName NVARCHAR(40)
DECLARE @output VARCHAR(40)
SET @Salt = '123abc11aa'

SET @output = HASHBYTES('SHA2_256', CAST(@CheeseName as VARCHAR(40)) + @Salt)
RETURN @output
END
;


When I just run



SELECT HASHBYTES('SHA2_256', CAST('SwissCheese' as VARCHAR(40)) + @Salt)


I get an expected result like 0xF456D41144584064AC5456B7E3...



However, when I run the function in a query



SELECT dbo.HashCheeseName('SwissCheese')


I get a result like this: h:Mó!yýŠù’p» ªu_aøP¾æhw



Any ideas on why it would result in something like this? At first sight it looks like a conversion issue, but I don't see the problem










share|improve this question


















  • 4





    ...but you said the function returns VARCHAR(40). Of course SQL Server is going to convert it to that, then. (The actual type is VARBINARY(8000).)

    – Jeroen Mostert
    Nov 15 '18 at 12:38
















1















I created a function like this:



CREATE FUNCTION dbo.HashCheeseName (@CheeseName NVARCHAR(40)) 
RETURNS VARCHAR(40)
AS BEGIN
DECLARE @Salt VARCHAR(25)
DECLARE @CheeseName NVARCHAR(40)
DECLARE @output VARCHAR(40)
SET @Salt = '123abc11aa'

SET @output = HASHBYTES('SHA2_256', CAST(@CheeseName as VARCHAR(40)) + @Salt)
RETURN @output
END
;


When I just run



SELECT HASHBYTES('SHA2_256', CAST('SwissCheese' as VARCHAR(40)) + @Salt)


I get an expected result like 0xF456D41144584064AC5456B7E3...



However, when I run the function in a query



SELECT dbo.HashCheeseName('SwissCheese')


I get a result like this: h:Mó!yýŠù’p» ªu_aøP¾æhw



Any ideas on why it would result in something like this? At first sight it looks like a conversion issue, but I don't see the problem










share|improve this question


















  • 4





    ...but you said the function returns VARCHAR(40). Of course SQL Server is going to convert it to that, then. (The actual type is VARBINARY(8000).)

    – Jeroen Mostert
    Nov 15 '18 at 12:38














1












1








1








I created a function like this:



CREATE FUNCTION dbo.HashCheeseName (@CheeseName NVARCHAR(40)) 
RETURNS VARCHAR(40)
AS BEGIN
DECLARE @Salt VARCHAR(25)
DECLARE @CheeseName NVARCHAR(40)
DECLARE @output VARCHAR(40)
SET @Salt = '123abc11aa'

SET @output = HASHBYTES('SHA2_256', CAST(@CheeseName as VARCHAR(40)) + @Salt)
RETURN @output
END
;


When I just run



SELECT HASHBYTES('SHA2_256', CAST('SwissCheese' as VARCHAR(40)) + @Salt)


I get an expected result like 0xF456D41144584064AC5456B7E3...



However, when I run the function in a query



SELECT dbo.HashCheeseName('SwissCheese')


I get a result like this: h:Mó!yýŠù’p» ªu_aøP¾æhw



Any ideas on why it would result in something like this? At first sight it looks like a conversion issue, but I don't see the problem










share|improve this question














I created a function like this:



CREATE FUNCTION dbo.HashCheeseName (@CheeseName NVARCHAR(40)) 
RETURNS VARCHAR(40)
AS BEGIN
DECLARE @Salt VARCHAR(25)
DECLARE @CheeseName NVARCHAR(40)
DECLARE @output VARCHAR(40)
SET @Salt = '123abc11aa'

SET @output = HASHBYTES('SHA2_256', CAST(@CheeseName as VARCHAR(40)) + @Salt)
RETURN @output
END
;


When I just run



SELECT HASHBYTES('SHA2_256', CAST('SwissCheese' as VARCHAR(40)) + @Salt)


I get an expected result like 0xF456D41144584064AC5456B7E3...



However, when I run the function in a query



SELECT dbo.HashCheeseName('SwissCheese')


I get a result like this: h:Mó!yýŠù’p» ªu_aøP¾æhw



Any ideas on why it would result in something like this? At first sight it looks like a conversion issue, but I don't see the problem







sql-server tsql salt






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asked Nov 15 '18 at 12:33









DenStudentDenStudent

5691625




5691625








  • 4





    ...but you said the function returns VARCHAR(40). Of course SQL Server is going to convert it to that, then. (The actual type is VARBINARY(8000).)

    – Jeroen Mostert
    Nov 15 '18 at 12:38














  • 4





    ...but you said the function returns VARCHAR(40). Of course SQL Server is going to convert it to that, then. (The actual type is VARBINARY(8000).)

    – Jeroen Mostert
    Nov 15 '18 at 12:38








4




4





...but you said the function returns VARCHAR(40). Of course SQL Server is going to convert it to that, then. (The actual type is VARBINARY(8000).)

– Jeroen Mostert
Nov 15 '18 at 12:38





...but you said the function returns VARCHAR(40). Of course SQL Server is going to convert it to that, then. (The actual type is VARBINARY(8000).)

– Jeroen Mostert
Nov 15 '18 at 12:38












1 Answer
1






active

oldest

votes


















2














What you are doing there isn't the same. HASHBYTES returns a varbinary (Hashbytes (Transact-SQL) - Return Values) where as your function is returning a varchar. Those are different datatypes. As a result, the last line of your function is effectively:



SET @output = CONVERT(varchar(40),HASHBYTES('SHA2_256', CAST(@CheeseName as VARCHAR(40)) + @Salt));


The varchar representation of a varbinary will not be the same. Either return a varbinary in your function, or your test SELECT with a CONVERT to a varchar(40).



Edit: To confirm, the solution is to simply change the return type of your function and variable:



CREATE FUNCTION dbo.HashCheeseName (@CheeseName NVARCHAR(40)) 
RETURNS varbinary(8000)
AS BEGIN
DECLARE @Salt VARCHAR(25);
DECLARE @CheeseName NVARCHAR(40);
DECLARE @output varbinary(8000) ;
SET @Salt = '123abc11aa';

SET @output = HASHBYTES('SHA2_256', CAST(@CheeseName as VARCHAR(40)) + @Salt);
RETURN @output;
END





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    1 Answer
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    1






    active

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    active

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    votes









    2














    What you are doing there isn't the same. HASHBYTES returns a varbinary (Hashbytes (Transact-SQL) - Return Values) where as your function is returning a varchar. Those are different datatypes. As a result, the last line of your function is effectively:



    SET @output = CONVERT(varchar(40),HASHBYTES('SHA2_256', CAST(@CheeseName as VARCHAR(40)) + @Salt));


    The varchar representation of a varbinary will not be the same. Either return a varbinary in your function, or your test SELECT with a CONVERT to a varchar(40).



    Edit: To confirm, the solution is to simply change the return type of your function and variable:



    CREATE FUNCTION dbo.HashCheeseName (@CheeseName NVARCHAR(40)) 
    RETURNS varbinary(8000)
    AS BEGIN
    DECLARE @Salt VARCHAR(25);
    DECLARE @CheeseName NVARCHAR(40);
    DECLARE @output varbinary(8000) ;
    SET @Salt = '123abc11aa';

    SET @output = HASHBYTES('SHA2_256', CAST(@CheeseName as VARCHAR(40)) + @Salt);
    RETURN @output;
    END





    share|improve this answer




























      2














      What you are doing there isn't the same. HASHBYTES returns a varbinary (Hashbytes (Transact-SQL) - Return Values) where as your function is returning a varchar. Those are different datatypes. As a result, the last line of your function is effectively:



      SET @output = CONVERT(varchar(40),HASHBYTES('SHA2_256', CAST(@CheeseName as VARCHAR(40)) + @Salt));


      The varchar representation of a varbinary will not be the same. Either return a varbinary in your function, or your test SELECT with a CONVERT to a varchar(40).



      Edit: To confirm, the solution is to simply change the return type of your function and variable:



      CREATE FUNCTION dbo.HashCheeseName (@CheeseName NVARCHAR(40)) 
      RETURNS varbinary(8000)
      AS BEGIN
      DECLARE @Salt VARCHAR(25);
      DECLARE @CheeseName NVARCHAR(40);
      DECLARE @output varbinary(8000) ;
      SET @Salt = '123abc11aa';

      SET @output = HASHBYTES('SHA2_256', CAST(@CheeseName as VARCHAR(40)) + @Salt);
      RETURN @output;
      END





      share|improve this answer


























        2












        2








        2







        What you are doing there isn't the same. HASHBYTES returns a varbinary (Hashbytes (Transact-SQL) - Return Values) where as your function is returning a varchar. Those are different datatypes. As a result, the last line of your function is effectively:



        SET @output = CONVERT(varchar(40),HASHBYTES('SHA2_256', CAST(@CheeseName as VARCHAR(40)) + @Salt));


        The varchar representation of a varbinary will not be the same. Either return a varbinary in your function, or your test SELECT with a CONVERT to a varchar(40).



        Edit: To confirm, the solution is to simply change the return type of your function and variable:



        CREATE FUNCTION dbo.HashCheeseName (@CheeseName NVARCHAR(40)) 
        RETURNS varbinary(8000)
        AS BEGIN
        DECLARE @Salt VARCHAR(25);
        DECLARE @CheeseName NVARCHAR(40);
        DECLARE @output varbinary(8000) ;
        SET @Salt = '123abc11aa';

        SET @output = HASHBYTES('SHA2_256', CAST(@CheeseName as VARCHAR(40)) + @Salt);
        RETURN @output;
        END





        share|improve this answer













        What you are doing there isn't the same. HASHBYTES returns a varbinary (Hashbytes (Transact-SQL) - Return Values) where as your function is returning a varchar. Those are different datatypes. As a result, the last line of your function is effectively:



        SET @output = CONVERT(varchar(40),HASHBYTES('SHA2_256', CAST(@CheeseName as VARCHAR(40)) + @Salt));


        The varchar representation of a varbinary will not be the same. Either return a varbinary in your function, or your test SELECT with a CONVERT to a varchar(40).



        Edit: To confirm, the solution is to simply change the return type of your function and variable:



        CREATE FUNCTION dbo.HashCheeseName (@CheeseName NVARCHAR(40)) 
        RETURNS varbinary(8000)
        AS BEGIN
        DECLARE @Salt VARCHAR(25);
        DECLARE @CheeseName NVARCHAR(40);
        DECLARE @output varbinary(8000) ;
        SET @Salt = '123abc11aa';

        SET @output = HASHBYTES('SHA2_256', CAST(@CheeseName as VARCHAR(40)) + @Salt);
        RETURN @output;
        END






        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Nov 15 '18 at 12:40









        LarnuLarnu

        20.4k51732




        20.4k51732
































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