Reactstrap modals
I want to take advantage of reactstarp modal. I also use it in the project eslintrc. I am showing such a mistake
Line 17: Unused state field: 'modal' react/no-unused-state
Line 26: Unused state field: 'modal' react/no-unused-state
this is my code
class AccountModal extends Component {
constructor(props) {
super(props);
this.state = {
modal: false,
};
this.toggle = this.toggle.bind(this);
}
toggle() {
const { state } = this.state;
this.setState({
modal: !state.modal,
});
}
render() {
const { state } = this.state;
return (
<div>
<Button color="danger" onClick={this.toggle}>Delete account</Button>
<Modal isOpen={state.modal} toggle={this.toggle}>
<ModalHeader toggle={this.toggle}>Modal title</ModalHeader>
<ModalBody>
Deleting your account will remove all of
your information from our database.
This cannot be undone.
</ModalBody>
<ModalFooter>
<Button color="primary" onClick={this.toggle}>Delete Account</Button>
{' '}
<Button color="secondary" onClick={this.toggle}>Cancel</Button>
</ModalFooter>
</Modal>
</div>
);
}
}
I do not know why the state is unused. I have copied the above code from the reactstarp documentation.
reactjs reactstrap
asked Nov 14 '18 at 14:30
ElderElder
728
add a comment |
I want to take advantage of reactstarp modal. I also use it in the project eslintrc. I am showing such a mistake
Line 17: Unused state field: 'modal' react/no-unused-state
Line 26: Unused state field: 'modal' react/no-unused-state
this is my code
class AccountModal extends Component {
constructor(props) {
super(props);
this.state = {
modal: false,
};
this.toggle = this.toggle.bind(this);
}
toggle() {
const { state } = this.state;
this.setState({
modal: !state.modal,
});
}
render() {
const { state } = this.state;
return (
<div>
<Button color="danger" onClick={this.toggle}>Delete account</Button>
<Modal isOpen={state.modal} toggle={this.toggle}>
<ModalHeader toggle={this.toggle}>Modal title</ModalHeader>
<ModalBody>
Deleting your account will remove all of
your information from our database.
This cannot be undone.
</ModalBody>
<ModalFooter>
<Button color="primary" onClick={this.toggle}>Delete Account</Button>
{' '}
<Button color="secondary" onClick={this.toggle}>Cancel</Button>
</ModalFooter>
</Modal>
</div>
);
}
}
I do not know why the state is unused. I have copied the above code from the reactstarp documentation.
reactjs reactstrap
asked Nov 14 '18 at 14:30
ElderElder
728
add a comment |
I want to take advantage of reactstarp modal. I also use it in the project eslintrc. I am showing such a mistake
Line 17: Unused state field: 'modal' react/no-unused-state
Line 26: Unused state field: 'modal' react/no-unused-state
this is my code
class AccountModal extends Component {
constructor(props) {
super(props);
this.state = {
modal: false,
};
this.toggle = this.toggle.bind(this);
}
toggle() {
const { state } = this.state;
this.setState({
modal: !state.modal,
});
}
render() {
const { state } = this.state;
return (
<div>
<Button color="danger" onClick={this.toggle}>Delete account</Button>
<Modal isOpen={state.modal} toggle={this.toggle}>
<ModalHeader toggle={this.toggle}>Modal title</ModalHeader>
<ModalBody>
Deleting your account will remove all of
your information from our database.
This cannot be undone.
</ModalBody>
<ModalFooter>
<Button color="primary" onClick={this.toggle}>Delete Account</Button>
{' '}
<Button color="secondary" onClick={this.toggle}>Cancel</Button>
</ModalFooter>
</Modal>
</div>
);
}
}
I do not know why the state is unused. I have copied the above code from the reactstarp documentation.
reactjs reactstrap
asked Nov 14 '18 at 14:30
ElderElder
728
I want to take advantage of reactstarp modal. I also use it in the project eslintrc. I am showing such a mistake
Line 17: Unused state field: 'modal' react/no-unused-state
Line 26: Unused state field: 'modal' react/no-unused-state
this is my code
class AccountModal extends Component {
constructor(props) {
super(props);
this.state = {
modal: false,
};
this.toggle = this.toggle.bind(this);
}
toggle() {
const { state } = this.state;
this.setState({
modal: !state.modal,
});
}
render() {
const { state } = this.state;
return (
<div>
<Button color="danger" onClick={this.toggle}>Delete account</Button>
<Modal isOpen={state.modal} toggle={this.toggle}>
<ModalHeader toggle={this.toggle}>Modal title</ModalHeader>
<ModalBody>
Deleting your account will remove all of
your information from our database.
This cannot be undone.
</ModalBody>
<ModalFooter>
<Button color="primary" onClick={this.toggle}>Delete Account</Button>
{' '}
<Button color="secondary" onClick={this.toggle}>Cancel</Button>
</ModalFooter>
</Modal>
</div>
);
}
}
I do not know why the state is unused. I have copied the above code from the reactstarp documentation.
reactjs reactstrap
reactjs reactstrap
asked Nov 14 '18 at 14:30
ElderElder
728
asked Nov 14 '18 at 14:30
ElderElder
728
asked Nov 14 '18 at 14:30
ElderElder
728
asked Nov 14 '18 at 14:30
ElderElder
728
asked Nov 14 '18 at 14:30
ElderElder
728
728
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
You are not accessing the state correctly. Try;
toggle() {
const { modal } = this.state;
this.setState({
modal: !modal,
});
}
You should be able to access the modal property like in the render method as well.
Explanation
const { state } = this.state;
this means that you are looking for an attribute with the name "state" inside "this.state",
this.state = {
modal: false,
};
whereas there is only one attribute named "modal" inside "this.state".
answered Nov 14 '18 at 15:12
Haseeb BurkiHaseeb Burki
11710
thanks. or maybe you send some article about what has been done before, because it works but I do not understand it :<
– Elder
Nov 14 '18 at 15:23
1
I have added a little explanation.
– Haseeb Burki
Nov 14 '18 at 15:28
1
Also look at destructuring in JS
– Haseeb Burki
Nov 14 '18 at 15:29
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
You are not accessing the state correctly. Try;
toggle() {
const { modal } = this.state;
this.setState({
modal: !modal,
});
}
You should be able to access the modal property like in the render method as well.
Explanation
const { state } = this.state;
this means that you are looking for an attribute with the name "state" inside "this.state",
this.state = {
modal: false,
};
whereas there is only one attribute named "modal" inside "this.state".
answered Nov 14 '18 at 15:12
Haseeb BurkiHaseeb Burki
11710
thanks. or maybe you send some article about what has been done before, because it works but I do not understand it :<
– Elder
Nov 14 '18 at 15:23
1
I have added a little explanation.
– Haseeb Burki
Nov 14 '18 at 15:28
1
Also look at destructuring in JS
– Haseeb Burki
Nov 14 '18 at 15:29
add a comment |
You are not accessing the state correctly. Try;
toggle() {
const { modal } = this.state;
this.setState({
modal: !modal,
});
}
You should be able to access the modal property like in the render method as well.
Explanation
const { state } = this.state;
this means that you are looking for an attribute with the name "state" inside "this.state",
this.state = {
modal: false,
};
whereas there is only one attribute named "modal" inside "this.state".
answered Nov 14 '18 at 15:12
Haseeb BurkiHaseeb Burki
11710
thanks. or maybe you send some article about what has been done before, because it works but I do not understand it :<
– Elder
Nov 14 '18 at 15:23
1
I have added a little explanation.
– Haseeb Burki
Nov 14 '18 at 15:28
1
Also look at destructuring in JS
– Haseeb Burki
Nov 14 '18 at 15:29
add a comment |
You are not accessing the state correctly. Try;
toggle() {
const { modal } = this.state;
this.setState({
modal: !modal,
});
}
You should be able to access the modal property like in the render method as well.
Explanation
const { state } = this.state;
this means that you are looking for an attribute with the name "state" inside "this.state",
this.state = {
modal: false,
};
whereas there is only one attribute named "modal" inside "this.state".
answered Nov 14 '18 at 15:12
Haseeb BurkiHaseeb Burki
11710
You are not accessing the state correctly. Try;
toggle() {
const { modal } = this.state;
this.setState({
modal: !modal,
});
}
You should be able to access the modal property like in the render method as well.
Explanation
const { state } = this.state;
this means that you are looking for an attribute with the name "state" inside "this.state",
this.state = {
modal: false,
};
whereas there is only one attribute named "modal" inside "this.state".
answered Nov 14 '18 at 15:12
Haseeb BurkiHaseeb Burki
11710
edited Nov 14 '18 at 15:28
answered Nov 14 '18 at 15:12
Haseeb BurkiHaseeb Burki
11710
answered Nov 14 '18 at 15:12
Haseeb BurkiHaseeb Burki
11710
answered Nov 14 '18 at 15:12
Haseeb BurkiHaseeb Burki
11710
11710
thanks. or maybe you send some article about what has been done before, because it works but I do not understand it :<
– Elder
Nov 14 '18 at 15:23
1
I have added a little explanation.
– Haseeb Burki
Nov 14 '18 at 15:28
1
Also look at destructuring in JS
– Haseeb Burki
Nov 14 '18 at 15:29
add a comment |
thanks. or maybe you send some article about what has been done before, because it works but I do not understand it :<
– Elder
Nov 14 '18 at 15:23
1
I have added a little explanation.
– Haseeb Burki
Nov 14 '18 at 15:28
1
Also look at destructuring in JS
– Haseeb Burki
Nov 14 '18 at 15:29
thanks. or maybe you send some article about what has been done before, because it works but I do not understand it :<
– Elder
Nov 14 '18 at 15:23
thanks. or maybe you send some article about what has been done before, because it works but I do not understand it :<
– Elder
Nov 14 '18 at 15:23
1
1
I have added a little explanation.
– Haseeb Burki
Nov 14 '18 at 15:28
I have added a little explanation.
– Haseeb Burki
Nov 14 '18 at 15:28
1
1
Also look at destructuring in JS
– Haseeb Burki
Nov 14 '18 at 15:29
Also look at destructuring in JS
– Haseeb Burki
Nov 14 '18 at 15:29
add a comment |
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