Converting varchar values that were derived from a constant field to Month and Year












0















I have a query where I am grabbing certain text out of a string. An example of the string is:



"Captured Credit Card: MasterCard, xxxx-xxxx-xxxx-xxxx, 09/19. Set as Default."



My query is pulling the expiration month and year out of that text.



SUBSTRING(ADT.MsgText, CHARINDEX('/', ADT.MsgText, 0) -2, 2) AS [Month]
,'20' + SUBSTRING(ADT.MsgText, CHARINDEX('/', ADT.MsgText, 0) + 1, 2) AS [Year]


However, I need these number values to be recognized as date values. I tried the following method, but was unsuccessful:



UPDATE CCC
SET CCC.[Month] = convert(date, convert(varchar(4), CCC.[Year]) + ' ' + convert(varchar(2), CCC.[Month]))
FROM CC_Captured CCC


The error message I get is: "Update or insert of view or function 'CCC' failed because it contains a derived or constant field."



I'm wondering how to convert these values to be date?
Any help is appreciated!



(Also I am using SQL 2016)










share|improve this question





























    0















    I have a query where I am grabbing certain text out of a string. An example of the string is:



    "Captured Credit Card: MasterCard, xxxx-xxxx-xxxx-xxxx, 09/19. Set as Default."



    My query is pulling the expiration month and year out of that text.



    SUBSTRING(ADT.MsgText, CHARINDEX('/', ADT.MsgText, 0) -2, 2) AS [Month]
    ,'20' + SUBSTRING(ADT.MsgText, CHARINDEX('/', ADT.MsgText, 0) + 1, 2) AS [Year]


    However, I need these number values to be recognized as date values. I tried the following method, but was unsuccessful:



    UPDATE CCC
    SET CCC.[Month] = convert(date, convert(varchar(4), CCC.[Year]) + ' ' + convert(varchar(2), CCC.[Month]))
    FROM CC_Captured CCC


    The error message I get is: "Update or insert of view or function 'CCC' failed because it contains a derived or constant field."



    I'm wondering how to convert these values to be date?
    Any help is appreciated!



    (Also I am using SQL 2016)










    share|improve this question



























      0












      0








      0








      I have a query where I am grabbing certain text out of a string. An example of the string is:



      "Captured Credit Card: MasterCard, xxxx-xxxx-xxxx-xxxx, 09/19. Set as Default."



      My query is pulling the expiration month and year out of that text.



      SUBSTRING(ADT.MsgText, CHARINDEX('/', ADT.MsgText, 0) -2, 2) AS [Month]
      ,'20' + SUBSTRING(ADT.MsgText, CHARINDEX('/', ADT.MsgText, 0) + 1, 2) AS [Year]


      However, I need these number values to be recognized as date values. I tried the following method, but was unsuccessful:



      UPDATE CCC
      SET CCC.[Month] = convert(date, convert(varchar(4), CCC.[Year]) + ' ' + convert(varchar(2), CCC.[Month]))
      FROM CC_Captured CCC


      The error message I get is: "Update or insert of view or function 'CCC' failed because it contains a derived or constant field."



      I'm wondering how to convert these values to be date?
      Any help is appreciated!



      (Also I am using SQL 2016)










      share|improve this question
















      I have a query where I am grabbing certain text out of a string. An example of the string is:



      "Captured Credit Card: MasterCard, xxxx-xxxx-xxxx-xxxx, 09/19. Set as Default."



      My query is pulling the expiration month and year out of that text.



      SUBSTRING(ADT.MsgText, CHARINDEX('/', ADT.MsgText, 0) -2, 2) AS [Month]
      ,'20' + SUBSTRING(ADT.MsgText, CHARINDEX('/', ADT.MsgText, 0) + 1, 2) AS [Year]


      However, I need these number values to be recognized as date values. I tried the following method, but was unsuccessful:



      UPDATE CCC
      SET CCC.[Month] = convert(date, convert(varchar(4), CCC.[Year]) + ' ' + convert(varchar(2), CCC.[Month]))
      FROM CC_Captured CCC


      The error message I get is: "Update or insert of view or function 'CCC' failed because it contains a derived or constant field."



      I'm wondering how to convert these values to be date?
      Any help is appreciated!



      (Also I am using SQL 2016)







      sql date sql-server-2016 varchar






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited Nov 15 '18 at 10:48









      Ole V.V.

      28.6k63352




      28.6k63352










      asked Nov 14 '18 at 13:31









      KatelynKatelyn

      134




      134
























          1 Answer
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          0














          You can use DATEFROMPARTS to construct a date in the month (first or last day of the month).



          declare @MsgText nvarchar(1000) = N'Captured Credit Card: MasterCard, xxxx-xxxx-xxxx-xxxx, 09/19. Set as Default.'
          select SUBSTRING(@MsgText, CHARINDEX('/', @MsgText, 0) -2, 2) AS [Month]
          ,'20' + SUBSTRING(@MsgText, CHARINDEX('/', @MsgText, 0) + 1, 2) AS [Year]
          -- First day of the month
          select DATEFROMPARTS(CAST('20' + SUBSTRING(@MsgText, CHARINDEX('/', @MsgText, 0) + 1, 2) as int), CAST(SUBSTRING(@MsgText, CHARINDEX('/', @MsgText, 0) -2, 2) as int), 1) as FirstDayOfMonth
          -- Last day of the month - add 1 month to the date above and go back 1 day
          select DATEADD(day, -1, DATEADD(month, 1, DATEFROMPARTS(CAST('20' + SUBSTRING(@MsgText, CHARINDEX('/', @MsgText, 0) + 1, 2) as int), CAST(SUBSTRING(@MsgText, CHARINDEX('/', @MsgText, 0) -2, 2) as int), 1))) as EndOfMonth


          Or even better, use EOMONTH function:



          select EOMONTH(DATEFROMPARTS(CAST('20' + SUBSTRING(@MsgText, CHARINDEX('/', @MsgText, 0) + 1, 2) as int), CAST(SUBSTRING(@MsgText, CHARINDEX('/', @MsgText, 0) -2, 2) as int), 1)) as EndOfMonth





          share|improve this answer
























          • Thank you! This was very helpful!

            – Katelyn
            Nov 23 '18 at 15:06











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          1 Answer
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          1 Answer
          1






          active

          oldest

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          active

          oldest

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          active

          oldest

          votes









          0














          You can use DATEFROMPARTS to construct a date in the month (first or last day of the month).



          declare @MsgText nvarchar(1000) = N'Captured Credit Card: MasterCard, xxxx-xxxx-xxxx-xxxx, 09/19. Set as Default.'
          select SUBSTRING(@MsgText, CHARINDEX('/', @MsgText, 0) -2, 2) AS [Month]
          ,'20' + SUBSTRING(@MsgText, CHARINDEX('/', @MsgText, 0) + 1, 2) AS [Year]
          -- First day of the month
          select DATEFROMPARTS(CAST('20' + SUBSTRING(@MsgText, CHARINDEX('/', @MsgText, 0) + 1, 2) as int), CAST(SUBSTRING(@MsgText, CHARINDEX('/', @MsgText, 0) -2, 2) as int), 1) as FirstDayOfMonth
          -- Last day of the month - add 1 month to the date above and go back 1 day
          select DATEADD(day, -1, DATEADD(month, 1, DATEFROMPARTS(CAST('20' + SUBSTRING(@MsgText, CHARINDEX('/', @MsgText, 0) + 1, 2) as int), CAST(SUBSTRING(@MsgText, CHARINDEX('/', @MsgText, 0) -2, 2) as int), 1))) as EndOfMonth


          Or even better, use EOMONTH function:



          select EOMONTH(DATEFROMPARTS(CAST('20' + SUBSTRING(@MsgText, CHARINDEX('/', @MsgText, 0) + 1, 2) as int), CAST(SUBSTRING(@MsgText, CHARINDEX('/', @MsgText, 0) -2, 2) as int), 1)) as EndOfMonth





          share|improve this answer
























          • Thank you! This was very helpful!

            – Katelyn
            Nov 23 '18 at 15:06
















          0














          You can use DATEFROMPARTS to construct a date in the month (first or last day of the month).



          declare @MsgText nvarchar(1000) = N'Captured Credit Card: MasterCard, xxxx-xxxx-xxxx-xxxx, 09/19. Set as Default.'
          select SUBSTRING(@MsgText, CHARINDEX('/', @MsgText, 0) -2, 2) AS [Month]
          ,'20' + SUBSTRING(@MsgText, CHARINDEX('/', @MsgText, 0) + 1, 2) AS [Year]
          -- First day of the month
          select DATEFROMPARTS(CAST('20' + SUBSTRING(@MsgText, CHARINDEX('/', @MsgText, 0) + 1, 2) as int), CAST(SUBSTRING(@MsgText, CHARINDEX('/', @MsgText, 0) -2, 2) as int), 1) as FirstDayOfMonth
          -- Last day of the month - add 1 month to the date above and go back 1 day
          select DATEADD(day, -1, DATEADD(month, 1, DATEFROMPARTS(CAST('20' + SUBSTRING(@MsgText, CHARINDEX('/', @MsgText, 0) + 1, 2) as int), CAST(SUBSTRING(@MsgText, CHARINDEX('/', @MsgText, 0) -2, 2) as int), 1))) as EndOfMonth


          Or even better, use EOMONTH function:



          select EOMONTH(DATEFROMPARTS(CAST('20' + SUBSTRING(@MsgText, CHARINDEX('/', @MsgText, 0) + 1, 2) as int), CAST(SUBSTRING(@MsgText, CHARINDEX('/', @MsgText, 0) -2, 2) as int), 1)) as EndOfMonth





          share|improve this answer
























          • Thank you! This was very helpful!

            – Katelyn
            Nov 23 '18 at 15:06














          0












          0








          0







          You can use DATEFROMPARTS to construct a date in the month (first or last day of the month).



          declare @MsgText nvarchar(1000) = N'Captured Credit Card: MasterCard, xxxx-xxxx-xxxx-xxxx, 09/19. Set as Default.'
          select SUBSTRING(@MsgText, CHARINDEX('/', @MsgText, 0) -2, 2) AS [Month]
          ,'20' + SUBSTRING(@MsgText, CHARINDEX('/', @MsgText, 0) + 1, 2) AS [Year]
          -- First day of the month
          select DATEFROMPARTS(CAST('20' + SUBSTRING(@MsgText, CHARINDEX('/', @MsgText, 0) + 1, 2) as int), CAST(SUBSTRING(@MsgText, CHARINDEX('/', @MsgText, 0) -2, 2) as int), 1) as FirstDayOfMonth
          -- Last day of the month - add 1 month to the date above and go back 1 day
          select DATEADD(day, -1, DATEADD(month, 1, DATEFROMPARTS(CAST('20' + SUBSTRING(@MsgText, CHARINDEX('/', @MsgText, 0) + 1, 2) as int), CAST(SUBSTRING(@MsgText, CHARINDEX('/', @MsgText, 0) -2, 2) as int), 1))) as EndOfMonth


          Or even better, use EOMONTH function:



          select EOMONTH(DATEFROMPARTS(CAST('20' + SUBSTRING(@MsgText, CHARINDEX('/', @MsgText, 0) + 1, 2) as int), CAST(SUBSTRING(@MsgText, CHARINDEX('/', @MsgText, 0) -2, 2) as int), 1)) as EndOfMonth





          share|improve this answer













          You can use DATEFROMPARTS to construct a date in the month (first or last day of the month).



          declare @MsgText nvarchar(1000) = N'Captured Credit Card: MasterCard, xxxx-xxxx-xxxx-xxxx, 09/19. Set as Default.'
          select SUBSTRING(@MsgText, CHARINDEX('/', @MsgText, 0) -2, 2) AS [Month]
          ,'20' + SUBSTRING(@MsgText, CHARINDEX('/', @MsgText, 0) + 1, 2) AS [Year]
          -- First day of the month
          select DATEFROMPARTS(CAST('20' + SUBSTRING(@MsgText, CHARINDEX('/', @MsgText, 0) + 1, 2) as int), CAST(SUBSTRING(@MsgText, CHARINDEX('/', @MsgText, 0) -2, 2) as int), 1) as FirstDayOfMonth
          -- Last day of the month - add 1 month to the date above and go back 1 day
          select DATEADD(day, -1, DATEADD(month, 1, DATEFROMPARTS(CAST('20' + SUBSTRING(@MsgText, CHARINDEX('/', @MsgText, 0) + 1, 2) as int), CAST(SUBSTRING(@MsgText, CHARINDEX('/', @MsgText, 0) -2, 2) as int), 1))) as EndOfMonth


          Or even better, use EOMONTH function:



          select EOMONTH(DATEFROMPARTS(CAST('20' + SUBSTRING(@MsgText, CHARINDEX('/', @MsgText, 0) + 1, 2) as int), CAST(SUBSTRING(@MsgText, CHARINDEX('/', @MsgText, 0) -2, 2) as int), 1)) as EndOfMonth






          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered Nov 16 '18 at 8:53









          Andrey NikolovAndrey Nikolov

          3,8883721




          3,8883721













          • Thank you! This was very helpful!

            – Katelyn
            Nov 23 '18 at 15:06



















          • Thank you! This was very helpful!

            – Katelyn
            Nov 23 '18 at 15:06

















          Thank you! This was very helpful!

          – Katelyn
          Nov 23 '18 at 15:06





          Thank you! This was very helpful!

          – Katelyn
          Nov 23 '18 at 15:06




















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