What does Class mean in Java?
My question is as above. Sorry, it's probably a duplicate but I couldn't find an example with the <?>
on the end.
Why would you not just use Class
as the parameter?
java syntax
add a comment |
My question is as above. Sorry, it's probably a duplicate but I couldn't find an example with the <?>
on the end.
Why would you not just use Class
as the parameter?
java syntax
en.wikipedia.org/wiki/Wildcard_%28Java%29
– Anycorn
Mar 29 '12 at 8:27
stackoverflow.com/q/2024513/1140748
– alain.janinm
Mar 29 '12 at 8:31
add a comment |
My question is as above. Sorry, it's probably a duplicate but I couldn't find an example with the <?>
on the end.
Why would you not just use Class
as the parameter?
java syntax
My question is as above. Sorry, it's probably a duplicate but I couldn't find an example with the <?>
on the end.
Why would you not just use Class
as the parameter?
java syntax
java syntax
edited Nov 13 '18 at 4:35
LAD
1,9591720
1,9591720
asked Mar 29 '12 at 8:25
david99world
12.5k2294122
12.5k2294122
en.wikipedia.org/wiki/Wildcard_%28Java%29
– Anycorn
Mar 29 '12 at 8:27
stackoverflow.com/q/2024513/1140748
– alain.janinm
Mar 29 '12 at 8:31
add a comment |
en.wikipedia.org/wiki/Wildcard_%28Java%29
– Anycorn
Mar 29 '12 at 8:27
stackoverflow.com/q/2024513/1140748
– alain.janinm
Mar 29 '12 at 8:31
en.wikipedia.org/wiki/Wildcard_%28Java%29
– Anycorn
Mar 29 '12 at 8:27
en.wikipedia.org/wiki/Wildcard_%28Java%29
– Anycorn
Mar 29 '12 at 8:27
stackoverflow.com/q/2024513/1140748
– alain.janinm
Mar 29 '12 at 8:31
stackoverflow.com/q/2024513/1140748
– alain.janinm
Mar 29 '12 at 8:31
add a comment |
6 Answers
6
active
oldest
votes
Class
is a parametrizable class, hence you can use the syntax Class<T>
where T is a type. By writing Class<?>
, you're declaring a Class
object which can be of any type (?
is a wildcard). The Class
type is a type that contains metainformation about a class.
It's always good practice to refer to a generic type by specifying his specific type, by using Class<?>
you're respecting this practice (you're aware of Class
to be parametrizable) but you're not restricting your parameter to have a specific type.
Reference about Generics and Wildcards: http://docs.oracle.com/javase/tutorial/java/generics/wildcards.html
Reference about Class object and reflection (the feature of Java language used to introspect itself): http://java.sun.com/developer/technicalArticles/ALT/Reflection/
6
What's the benefit of doing this over just simply usingClass
without a type? They seem to represent the same thing.
– ashes999
Jun 22 '13 at 14:47
I thought the whole point of a generic is you don't know the class type upfront. Otherwise you would just define a function to use a particular class type for the parameter. This question mark still doesn't make sense.
– Brain2000
Mar 6 '15 at 17:48
3
There is no other benefit except you're telling the compiler that "I know this is a generic class, but I don't know or care about the actual type, so instead of giving a concrete type I'm giving the?
wildcard.". If you don't give the wildcard, the compiler assumes that you either forgot the type or didn't know the class was generic and will warn you about it.
– Kayaman
Feb 29 '16 at 7:51
1
What's the Kotlin equivalent ofClass<?>
– JGuo
Jun 14 '18 at 17:50
simplyClass
cannot be pass to a argument which type isClass<?>
, SoClass<?>
is more convenient for all situation.
– okwap
Oct 5 '18 at 7:08
add a comment |
This <?>
is a beast. It often leads to confusion and errors, because, when you see it first, then you start believing, <?>
is a wildcard for any java type. Which is .. not true. <?>
is the unknown type, a slight and nasty difference.
It's not a problem when you use it with Class
. Both lines work and compile:
Class anyType = String.class;
Class <?> theUnknownType = String.class;
But - if we start using it with collections, then we see strange compiletime errors:
List<?> list = new ArrayList<Object>(); // ArrayList<?> is not allowed
list.add("a String"); // doesn't compile ...
Our List<?>
is not a collection, that is suitable for just any type of object. It can only store one type: the mystic "unkown type". Which is not a real type, for sure.
add a comment |
It's a generics literal. It means that you don't know the type of class this Class
instance is representing, but you are still using the generic version.
- if you knew the class, you'd use
Class<Foo>
. That way you can create a new instance, for example, without casting:Foo foo = clazz.newInstance();
- if you don't use generics at all, you'll get a warning at least (and not using generics is generally discouraged as it may lead to hard-to-detect side effects)
add a comment |
It means your Class reference can hold a reference to any Class object.
It's basically the same as "Class" but you're showing other people who read your code that you didn't forget about generics, you just want a reference that can hold any Class object.
Bruce Eckel, Thinking in Java:
In Java SE5, Class<?> is preferred over plain Class, even though they
are equivalent and the plain Class, as you saw, doesn’t produce a
compiler warning. The benefit of Class<?> is that it
indicates that you aren’t just using a non-specific class reference by
accident, or out of ignorance. You chose the non-specific version.
1
The quote says "Class<?> is preferred over plain Class" and "The benefit of Class<?>". It seems blockquote doesn't agree with the angular brackets.
– Filip
Mar 29 '12 at 17:13
It needs to be escaped. Fixed it now :P
– Sami Kuhmonen
Feb 29 '16 at 7:08
add a comment |
In generics, an unknown type is represented by the wildcard character "?". Read here for official example.
add a comment |
That means a Class with a type of anything (unknown).
You should read java generics tutorial to get to understand it better
add a comment |
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6 Answers
6
active
oldest
votes
6 Answers
6
active
oldest
votes
active
oldest
votes
active
oldest
votes
Class
is a parametrizable class, hence you can use the syntax Class<T>
where T is a type. By writing Class<?>
, you're declaring a Class
object which can be of any type (?
is a wildcard). The Class
type is a type that contains metainformation about a class.
It's always good practice to refer to a generic type by specifying his specific type, by using Class<?>
you're respecting this practice (you're aware of Class
to be parametrizable) but you're not restricting your parameter to have a specific type.
Reference about Generics and Wildcards: http://docs.oracle.com/javase/tutorial/java/generics/wildcards.html
Reference about Class object and reflection (the feature of Java language used to introspect itself): http://java.sun.com/developer/technicalArticles/ALT/Reflection/
6
What's the benefit of doing this over just simply usingClass
without a type? They seem to represent the same thing.
– ashes999
Jun 22 '13 at 14:47
I thought the whole point of a generic is you don't know the class type upfront. Otherwise you would just define a function to use a particular class type for the parameter. This question mark still doesn't make sense.
– Brain2000
Mar 6 '15 at 17:48
3
There is no other benefit except you're telling the compiler that "I know this is a generic class, but I don't know or care about the actual type, so instead of giving a concrete type I'm giving the?
wildcard.". If you don't give the wildcard, the compiler assumes that you either forgot the type or didn't know the class was generic and will warn you about it.
– Kayaman
Feb 29 '16 at 7:51
1
What's the Kotlin equivalent ofClass<?>
– JGuo
Jun 14 '18 at 17:50
simplyClass
cannot be pass to a argument which type isClass<?>
, SoClass<?>
is more convenient for all situation.
– okwap
Oct 5 '18 at 7:08
add a comment |
Class
is a parametrizable class, hence you can use the syntax Class<T>
where T is a type. By writing Class<?>
, you're declaring a Class
object which can be of any type (?
is a wildcard). The Class
type is a type that contains metainformation about a class.
It's always good practice to refer to a generic type by specifying his specific type, by using Class<?>
you're respecting this practice (you're aware of Class
to be parametrizable) but you're not restricting your parameter to have a specific type.
Reference about Generics and Wildcards: http://docs.oracle.com/javase/tutorial/java/generics/wildcards.html
Reference about Class object and reflection (the feature of Java language used to introspect itself): http://java.sun.com/developer/technicalArticles/ALT/Reflection/
6
What's the benefit of doing this over just simply usingClass
without a type? They seem to represent the same thing.
– ashes999
Jun 22 '13 at 14:47
I thought the whole point of a generic is you don't know the class type upfront. Otherwise you would just define a function to use a particular class type for the parameter. This question mark still doesn't make sense.
– Brain2000
Mar 6 '15 at 17:48
3
There is no other benefit except you're telling the compiler that "I know this is a generic class, but I don't know or care about the actual type, so instead of giving a concrete type I'm giving the?
wildcard.". If you don't give the wildcard, the compiler assumes that you either forgot the type or didn't know the class was generic and will warn you about it.
– Kayaman
Feb 29 '16 at 7:51
1
What's the Kotlin equivalent ofClass<?>
– JGuo
Jun 14 '18 at 17:50
simplyClass
cannot be pass to a argument which type isClass<?>
, SoClass<?>
is more convenient for all situation.
– okwap
Oct 5 '18 at 7:08
add a comment |
Class
is a parametrizable class, hence you can use the syntax Class<T>
where T is a type. By writing Class<?>
, you're declaring a Class
object which can be of any type (?
is a wildcard). The Class
type is a type that contains metainformation about a class.
It's always good practice to refer to a generic type by specifying his specific type, by using Class<?>
you're respecting this practice (you're aware of Class
to be parametrizable) but you're not restricting your parameter to have a specific type.
Reference about Generics and Wildcards: http://docs.oracle.com/javase/tutorial/java/generics/wildcards.html
Reference about Class object and reflection (the feature of Java language used to introspect itself): http://java.sun.com/developer/technicalArticles/ALT/Reflection/
Class
is a parametrizable class, hence you can use the syntax Class<T>
where T is a type. By writing Class<?>
, you're declaring a Class
object which can be of any type (?
is a wildcard). The Class
type is a type that contains metainformation about a class.
It's always good practice to refer to a generic type by specifying his specific type, by using Class<?>
you're respecting this practice (you're aware of Class
to be parametrizable) but you're not restricting your parameter to have a specific type.
Reference about Generics and Wildcards: http://docs.oracle.com/javase/tutorial/java/generics/wildcards.html
Reference about Class object and reflection (the feature of Java language used to introspect itself): http://java.sun.com/developer/technicalArticles/ALT/Reflection/
answered Mar 29 '12 at 8:30
manub
2,87512030
2,87512030
6
What's the benefit of doing this over just simply usingClass
without a type? They seem to represent the same thing.
– ashes999
Jun 22 '13 at 14:47
I thought the whole point of a generic is you don't know the class type upfront. Otherwise you would just define a function to use a particular class type for the parameter. This question mark still doesn't make sense.
– Brain2000
Mar 6 '15 at 17:48
3
There is no other benefit except you're telling the compiler that "I know this is a generic class, but I don't know or care about the actual type, so instead of giving a concrete type I'm giving the?
wildcard.". If you don't give the wildcard, the compiler assumes that you either forgot the type or didn't know the class was generic and will warn you about it.
– Kayaman
Feb 29 '16 at 7:51
1
What's the Kotlin equivalent ofClass<?>
– JGuo
Jun 14 '18 at 17:50
simplyClass
cannot be pass to a argument which type isClass<?>
, SoClass<?>
is more convenient for all situation.
– okwap
Oct 5 '18 at 7:08
add a comment |
6
What's the benefit of doing this over just simply usingClass
without a type? They seem to represent the same thing.
– ashes999
Jun 22 '13 at 14:47
I thought the whole point of a generic is you don't know the class type upfront. Otherwise you would just define a function to use a particular class type for the parameter. This question mark still doesn't make sense.
– Brain2000
Mar 6 '15 at 17:48
3
There is no other benefit except you're telling the compiler that "I know this is a generic class, but I don't know or care about the actual type, so instead of giving a concrete type I'm giving the?
wildcard.". If you don't give the wildcard, the compiler assumes that you either forgot the type or didn't know the class was generic and will warn you about it.
– Kayaman
Feb 29 '16 at 7:51
1
What's the Kotlin equivalent ofClass<?>
– JGuo
Jun 14 '18 at 17:50
simplyClass
cannot be pass to a argument which type isClass<?>
, SoClass<?>
is more convenient for all situation.
– okwap
Oct 5 '18 at 7:08
6
6
What's the benefit of doing this over just simply using
Class
without a type? They seem to represent the same thing.– ashes999
Jun 22 '13 at 14:47
What's the benefit of doing this over just simply using
Class
without a type? They seem to represent the same thing.– ashes999
Jun 22 '13 at 14:47
I thought the whole point of a generic is you don't know the class type upfront. Otherwise you would just define a function to use a particular class type for the parameter. This question mark still doesn't make sense.
– Brain2000
Mar 6 '15 at 17:48
I thought the whole point of a generic is you don't know the class type upfront. Otherwise you would just define a function to use a particular class type for the parameter. This question mark still doesn't make sense.
– Brain2000
Mar 6 '15 at 17:48
3
3
There is no other benefit except you're telling the compiler that "I know this is a generic class, but I don't know or care about the actual type, so instead of giving a concrete type I'm giving the
?
wildcard.". If you don't give the wildcard, the compiler assumes that you either forgot the type or didn't know the class was generic and will warn you about it.– Kayaman
Feb 29 '16 at 7:51
There is no other benefit except you're telling the compiler that "I know this is a generic class, but I don't know or care about the actual type, so instead of giving a concrete type I'm giving the
?
wildcard.". If you don't give the wildcard, the compiler assumes that you either forgot the type or didn't know the class was generic and will warn you about it.– Kayaman
Feb 29 '16 at 7:51
1
1
What's the Kotlin equivalent of
Class<?>
– JGuo
Jun 14 '18 at 17:50
What's the Kotlin equivalent of
Class<?>
– JGuo
Jun 14 '18 at 17:50
simply
Class
cannot be pass to a argument which type is Class<?>
, So Class<?>
is more convenient for all situation.– okwap
Oct 5 '18 at 7:08
simply
Class
cannot be pass to a argument which type is Class<?>
, So Class<?>
is more convenient for all situation.– okwap
Oct 5 '18 at 7:08
add a comment |
This <?>
is a beast. It often leads to confusion and errors, because, when you see it first, then you start believing, <?>
is a wildcard for any java type. Which is .. not true. <?>
is the unknown type, a slight and nasty difference.
It's not a problem when you use it with Class
. Both lines work and compile:
Class anyType = String.class;
Class <?> theUnknownType = String.class;
But - if we start using it with collections, then we see strange compiletime errors:
List<?> list = new ArrayList<Object>(); // ArrayList<?> is not allowed
list.add("a String"); // doesn't compile ...
Our List<?>
is not a collection, that is suitable for just any type of object. It can only store one type: the mystic "unkown type". Which is not a real type, for sure.
add a comment |
This <?>
is a beast. It often leads to confusion and errors, because, when you see it first, then you start believing, <?>
is a wildcard for any java type. Which is .. not true. <?>
is the unknown type, a slight and nasty difference.
It's not a problem when you use it with Class
. Both lines work and compile:
Class anyType = String.class;
Class <?> theUnknownType = String.class;
But - if we start using it with collections, then we see strange compiletime errors:
List<?> list = new ArrayList<Object>(); // ArrayList<?> is not allowed
list.add("a String"); // doesn't compile ...
Our List<?>
is not a collection, that is suitable for just any type of object. It can only store one type: the mystic "unkown type". Which is not a real type, for sure.
add a comment |
This <?>
is a beast. It often leads to confusion and errors, because, when you see it first, then you start believing, <?>
is a wildcard for any java type. Which is .. not true. <?>
is the unknown type, a slight and nasty difference.
It's not a problem when you use it with Class
. Both lines work and compile:
Class anyType = String.class;
Class <?> theUnknownType = String.class;
But - if we start using it with collections, then we see strange compiletime errors:
List<?> list = new ArrayList<Object>(); // ArrayList<?> is not allowed
list.add("a String"); // doesn't compile ...
Our List<?>
is not a collection, that is suitable for just any type of object. It can only store one type: the mystic "unkown type". Which is not a real type, for sure.
This <?>
is a beast. It often leads to confusion and errors, because, when you see it first, then you start believing, <?>
is a wildcard for any java type. Which is .. not true. <?>
is the unknown type, a slight and nasty difference.
It's not a problem when you use it with Class
. Both lines work and compile:
Class anyType = String.class;
Class <?> theUnknownType = String.class;
But - if we start using it with collections, then we see strange compiletime errors:
List<?> list = new ArrayList<Object>(); // ArrayList<?> is not allowed
list.add("a String"); // doesn't compile ...
Our List<?>
is not a collection, that is suitable for just any type of object. It can only store one type: the mystic "unkown type". Which is not a real type, for sure.
answered Mar 29 '12 at 8:55
Andreas_D
95.1k11144231
95.1k11144231
add a comment |
add a comment |
It's a generics literal. It means that you don't know the type of class this Class
instance is representing, but you are still using the generic version.
- if you knew the class, you'd use
Class<Foo>
. That way you can create a new instance, for example, without casting:Foo foo = clazz.newInstance();
- if you don't use generics at all, you'll get a warning at least (and not using generics is generally discouraged as it may lead to hard-to-detect side effects)
add a comment |
It's a generics literal. It means that you don't know the type of class this Class
instance is representing, but you are still using the generic version.
- if you knew the class, you'd use
Class<Foo>
. That way you can create a new instance, for example, without casting:Foo foo = clazz.newInstance();
- if you don't use generics at all, you'll get a warning at least (and not using generics is generally discouraged as it may lead to hard-to-detect side effects)
add a comment |
It's a generics literal. It means that you don't know the type of class this Class
instance is representing, but you are still using the generic version.
- if you knew the class, you'd use
Class<Foo>
. That way you can create a new instance, for example, without casting:Foo foo = clazz.newInstance();
- if you don't use generics at all, you'll get a warning at least (and not using generics is generally discouraged as it may lead to hard-to-detect side effects)
It's a generics literal. It means that you don't know the type of class this Class
instance is representing, but you are still using the generic version.
- if you knew the class, you'd use
Class<Foo>
. That way you can create a new instance, for example, without casting:Foo foo = clazz.newInstance();
- if you don't use generics at all, you'll get a warning at least (and not using generics is generally discouraged as it may lead to hard-to-detect side effects)
answered Mar 29 '12 at 8:27
Bozho
482k1079421059
482k1079421059
add a comment |
add a comment |
It means your Class reference can hold a reference to any Class object.
It's basically the same as "Class" but you're showing other people who read your code that you didn't forget about generics, you just want a reference that can hold any Class object.
Bruce Eckel, Thinking in Java:
In Java SE5, Class<?> is preferred over plain Class, even though they
are equivalent and the plain Class, as you saw, doesn’t produce a
compiler warning. The benefit of Class<?> is that it
indicates that you aren’t just using a non-specific class reference by
accident, or out of ignorance. You chose the non-specific version.
1
The quote says "Class<?> is preferred over plain Class" and "The benefit of Class<?>". It seems blockquote doesn't agree with the angular brackets.
– Filip
Mar 29 '12 at 17:13
It needs to be escaped. Fixed it now :P
– Sami Kuhmonen
Feb 29 '16 at 7:08
add a comment |
It means your Class reference can hold a reference to any Class object.
It's basically the same as "Class" but you're showing other people who read your code that you didn't forget about generics, you just want a reference that can hold any Class object.
Bruce Eckel, Thinking in Java:
In Java SE5, Class<?> is preferred over plain Class, even though they
are equivalent and the plain Class, as you saw, doesn’t produce a
compiler warning. The benefit of Class<?> is that it
indicates that you aren’t just using a non-specific class reference by
accident, or out of ignorance. You chose the non-specific version.
1
The quote says "Class<?> is preferred over plain Class" and "The benefit of Class<?>". It seems blockquote doesn't agree with the angular brackets.
– Filip
Mar 29 '12 at 17:13
It needs to be escaped. Fixed it now :P
– Sami Kuhmonen
Feb 29 '16 at 7:08
add a comment |
It means your Class reference can hold a reference to any Class object.
It's basically the same as "Class" but you're showing other people who read your code that you didn't forget about generics, you just want a reference that can hold any Class object.
Bruce Eckel, Thinking in Java:
In Java SE5, Class<?> is preferred over plain Class, even though they
are equivalent and the plain Class, as you saw, doesn’t produce a
compiler warning. The benefit of Class<?> is that it
indicates that you aren’t just using a non-specific class reference by
accident, or out of ignorance. You chose the non-specific version.
It means your Class reference can hold a reference to any Class object.
It's basically the same as "Class" but you're showing other people who read your code that you didn't forget about generics, you just want a reference that can hold any Class object.
Bruce Eckel, Thinking in Java:
In Java SE5, Class<?> is preferred over plain Class, even though they
are equivalent and the plain Class, as you saw, doesn’t produce a
compiler warning. The benefit of Class<?> is that it
indicates that you aren’t just using a non-specific class reference by
accident, or out of ignorance. You chose the non-specific version.
edited Feb 29 '16 at 7:08
Sami Kuhmonen
20.8k73148
20.8k73148
answered Mar 29 '12 at 8:28
Filip
998515
998515
1
The quote says "Class<?> is preferred over plain Class" and "The benefit of Class<?>". It seems blockquote doesn't agree with the angular brackets.
– Filip
Mar 29 '12 at 17:13
It needs to be escaped. Fixed it now :P
– Sami Kuhmonen
Feb 29 '16 at 7:08
add a comment |
1
The quote says "Class<?> is preferred over plain Class" and "The benefit of Class<?>". It seems blockquote doesn't agree with the angular brackets.
– Filip
Mar 29 '12 at 17:13
It needs to be escaped. Fixed it now :P
– Sami Kuhmonen
Feb 29 '16 at 7:08
1
1
The quote says "Class<?> is preferred over plain Class" and "The benefit of Class<?>". It seems blockquote doesn't agree with the angular brackets.
– Filip
Mar 29 '12 at 17:13
The quote says "Class<?> is preferred over plain Class" and "The benefit of Class<?>". It seems blockquote doesn't agree with the angular brackets.
– Filip
Mar 29 '12 at 17:13
It needs to be escaped. Fixed it now :P
– Sami Kuhmonen
Feb 29 '16 at 7:08
It needs to be escaped. Fixed it now :P
– Sami Kuhmonen
Feb 29 '16 at 7:08
add a comment |
In generics, an unknown type is represented by the wildcard character "?". Read here for official example.
add a comment |
In generics, an unknown type is represented by the wildcard character "?". Read here for official example.
add a comment |
In generics, an unknown type is represented by the wildcard character "?". Read here for official example.
In generics, an unknown type is represented by the wildcard character "?". Read here for official example.
answered Mar 29 '12 at 8:30
Jasonw
4,77173141
4,77173141
add a comment |
add a comment |
That means a Class with a type of anything (unknown).
You should read java generics tutorial to get to understand it better
add a comment |
That means a Class with a type of anything (unknown).
You should read java generics tutorial to get to understand it better
add a comment |
That means a Class with a type of anything (unknown).
You should read java generics tutorial to get to understand it better
That means a Class with a type of anything (unknown).
You should read java generics tutorial to get to understand it better
edited Sep 21 '16 at 17:56
Matt
62k18118159
62k18118159
answered Mar 29 '12 at 8:28
fmucar
12.1k13948
12.1k13948
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en.wikipedia.org/wiki/Wildcard_%28Java%29
– Anycorn
Mar 29 '12 at 8:27
stackoverflow.com/q/2024513/1140748
– alain.janinm
Mar 29 '12 at 8:31