Postgresql there is an entry for table but it cannot be referenced from this part of the query
I have a problem with my select query
select distinct l.*, tmp_addr.address from l.lic as l
left join l.hou as h on l.lic_id=h.lic_guid
left join l.org as o on o.org_id=l.org_guid
LEFT JOIN (
SELECT address
FROM dblink('sm_d','SELECT * FROM
sm.func_get(' || COALESCE(QUOTE_LITERAL(h.hguid), 'NULL') || ', TRUE, ''sm'')')
AS addr(full_address TEXT, address_guid TEXT)
) AS tmp_addr ON h.house_address_guid=tmp_addr.address_guid
where o.root_organization_ref_guid='b26961ae-f015' and l.status <> 'INACTIVE' and l.version='true' and h.registry_status_type='INCLUDED';
SQL Error [42P01]: ERROR: invalid reference to FROM-clause entry for table "h"
There is an entry for table "h", but it cannot be referenced from this part of the query.
Position: 348
sql postgresql
asked Nov 13 '18 at 5:17
Sam Kilanoff
477
add a comment |
I have a problem with my select query
select distinct l.*, tmp_addr.address from l.lic as l
left join l.hou as h on l.lic_id=h.lic_guid
left join l.org as o on o.org_id=l.org_guid
LEFT JOIN (
SELECT address
FROM dblink('sm_d','SELECT * FROM
sm.func_get(' || COALESCE(QUOTE_LITERAL(h.hguid), 'NULL') || ', TRUE, ''sm'')')
AS addr(full_address TEXT, address_guid TEXT)
) AS tmp_addr ON h.house_address_guid=tmp_addr.address_guid
where o.root_organization_ref_guid='b26961ae-f015' and l.status <> 'INACTIVE' and l.version='true' and h.registry_status_type='INCLUDED';
SQL Error [42P01]: ERROR: invalid reference to FROM-clause entry for table "h"
There is an entry for table "h", but it cannot be referenced from this part of the query.
Position: 348
sql postgresql
asked Nov 13 '18 at 5:17
Sam Kilanoff
477
distinct l.*looks strange. That usually is an indication that you don't want a join but a sub-select with an EXISTS condition.
– a_horse_with_no_name
Nov 13 '18 at 6:51
add a comment |
I have a problem with my select query
select distinct l.*, tmp_addr.address from l.lic as l
left join l.hou as h on l.lic_id=h.lic_guid
left join l.org as o on o.org_id=l.org_guid
LEFT JOIN (
SELECT address
FROM dblink('sm_d','SELECT * FROM
sm.func_get(' || COALESCE(QUOTE_LITERAL(h.hguid), 'NULL') || ', TRUE, ''sm'')')
AS addr(full_address TEXT, address_guid TEXT)
) AS tmp_addr ON h.house_address_guid=tmp_addr.address_guid
where o.root_organization_ref_guid='b26961ae-f015' and l.status <> 'INACTIVE' and l.version='true' and h.registry_status_type='INCLUDED';
SQL Error [42P01]: ERROR: invalid reference to FROM-clause entry for table "h"
There is an entry for table "h", but it cannot be referenced from this part of the query.
Position: 348
sql postgresql
asked Nov 13 '18 at 5:17
Sam Kilanoff
477
I have a problem with my select query
select distinct l.*, tmp_addr.address from l.lic as l
left join l.hou as h on l.lic_id=h.lic_guid
left join l.org as o on o.org_id=l.org_guid
LEFT JOIN (
SELECT address
FROM dblink('sm_d','SELECT * FROM
sm.func_get(' || COALESCE(QUOTE_LITERAL(h.hguid), 'NULL') || ', TRUE, ''sm'')')
AS addr(full_address TEXT, address_guid TEXT)
) AS tmp_addr ON h.house_address_guid=tmp_addr.address_guid
where o.root_organization_ref_guid='b26961ae-f015' and l.status <> 'INACTIVE' and l.version='true' and h.registry_status_type='INCLUDED';
SQL Error [42P01]: ERROR: invalid reference to FROM-clause entry for table "h"
There is an entry for table "h", but it cannot be referenced from this part of the query.
Position: 348
sql postgresql
sql postgresql
asked Nov 13 '18 at 5:17
Sam Kilanoff
477
asked Nov 13 '18 at 5:17
Sam Kilanoff
477
asked Nov 13 '18 at 5:17
Sam Kilanoff
477
asked Nov 13 '18 at 5:17
Sam Kilanoff
477
asked Nov 13 '18 at 5:17
Sam Kilanoff
477
477
distinct l.*looks strange. That usually is an indication that you don't want a join but a sub-select with an EXISTS condition.
– a_horse_with_no_name
Nov 13 '18 at 6:51
add a comment |
distinct l.*looks strange. That usually is an indication that you don't want a join but a sub-select with an EXISTS condition.
– a_horse_with_no_name
Nov 13 '18 at 6:51
distinct l.* looks strange. That usually is an indication that you don't want a join but a sub-select with an EXISTS condition.– a_horse_with_no_name
Nov 13 '18 at 6:51
distinct l.* looks strange. That usually is an indication that you don't want a join but a sub-select with an EXISTS condition.– a_horse_with_no_name
Nov 13 '18 at 6:51
add a comment |
1 Answer
1
active
oldest
votes
This seems really weird:
select distinct l.*, tmp_addr.address
FROM l.lic as l
left join l.hou as h on l.lic_id=h.lic_guid
left join l.org as o on o.org_id=l.org_guid
l.lic as l -- You are setting an alias for LIC table as l
left join l.hou as h -- Now, when you say l.hou, it means hou is a column from table l. But you are using it as a table.
left join l.org as o -- Same problem as above.
So, if l is a schema in your database where these tables are stored, I suggest you to use another alias name than l.
If l is not a schema, just remove l from l.hou and l.org. Instead say, hou and org.
This should fix the error. Let me know if this helps.
answered Nov 13 '18 at 6:03
Mayank Porwal
4,5091624
add a comment |
Your Answer
StackExchange.ifUsing("editor", function () {
StackExchange.using("externalEditor", function () {
StackExchange.using("snippets", function () {
StackExchange.snippets.init();
});
});
}, "code-snippets");
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "1"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53274265%2fpostgresql-there-is-an-entry-for-table-but-it-cannot-be-referenced-from-this-par%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
This seems really weird:
select distinct l.*, tmp_addr.address
FROM l.lic as l
left join l.hou as h on l.lic_id=h.lic_guid
left join l.org as o on o.org_id=l.org_guid
l.lic as l -- You are setting an alias for LIC table as l
left join l.hou as h -- Now, when you say l.hou, it means hou is a column from table l. But you are using it as a table.
left join l.org as o -- Same problem as above.
So, if l is a schema in your database where these tables are stored, I suggest you to use another alias name than l.
If l is not a schema, just remove l from l.hou and l.org. Instead say, hou and org.
This should fix the error. Let me know if this helps.
answered Nov 13 '18 at 6:03
Mayank Porwal
4,5091624
add a comment |
This seems really weird:
select distinct l.*, tmp_addr.address
FROM l.lic as l
left join l.hou as h on l.lic_id=h.lic_guid
left join l.org as o on o.org_id=l.org_guid
l.lic as l -- You are setting an alias for LIC table as l
left join l.hou as h -- Now, when you say l.hou, it means hou is a column from table l. But you are using it as a table.
left join l.org as o -- Same problem as above.
So, if l is a schema in your database where these tables are stored, I suggest you to use another alias name than l.
If l is not a schema, just remove l from l.hou and l.org. Instead say, hou and org.
This should fix the error. Let me know if this helps.
answered Nov 13 '18 at 6:03
Mayank Porwal
4,5091624
add a comment |
This seems really weird:
select distinct l.*, tmp_addr.address
FROM l.lic as l
left join l.hou as h on l.lic_id=h.lic_guid
left join l.org as o on o.org_id=l.org_guid
l.lic as l -- You are setting an alias for LIC table as l
left join l.hou as h -- Now, when you say l.hou, it means hou is a column from table l. But you are using it as a table.
left join l.org as o -- Same problem as above.
So, if l is a schema in your database where these tables are stored, I suggest you to use another alias name than l.
If l is not a schema, just remove l from l.hou and l.org. Instead say, hou and org.
This should fix the error. Let me know if this helps.
answered Nov 13 '18 at 6:03
Mayank Porwal
4,5091624
This seems really weird:
select distinct l.*, tmp_addr.address
FROM l.lic as l
left join l.hou as h on l.lic_id=h.lic_guid
left join l.org as o on o.org_id=l.org_guid
l.lic as l -- You are setting an alias for LIC table as l
left join l.hou as h -- Now, when you say l.hou, it means hou is a column from table l. But you are using it as a table.
left join l.org as o -- Same problem as above.
So, if l is a schema in your database where these tables are stored, I suggest you to use another alias name than l.
If l is not a schema, just remove l from l.hou and l.org. Instead say, hou and org.
This should fix the error. Let me know if this helps.
answered Nov 13 '18 at 6:03
Mayank Porwal
4,5091624
answered Nov 13 '18 at 6:03
Mayank Porwal
4,5091624
answered Nov 13 '18 at 6:03
Mayank Porwal
4,5091624
answered Nov 13 '18 at 6:03
Mayank Porwal
4,5091624
4,5091624
add a comment |
add a comment |
Thanks for contributing an answer to Stack Overflow!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Some of your past answers have not been well-received, and you're in danger of being blocked from answering.
Please pay close attention to the following guidance:
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53274265%2fpostgresql-there-is-an-entry-for-table-but-it-cannot-be-referenced-from-this-par%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
distinct l.*looks strange. That usually is an indication that you don't want a join but a sub-select with an EXISTS condition.– a_horse_with_no_name
Nov 13 '18 at 6:51