Return object with highest number from array containing multiple objects

I was able to figure out how to return the highest number from a associative array with multiple objects. But I need the whole object.

I prepared this example:

var data = [

     { nr: 235, text: "foo" }

    ,{ nr: 351, text: "bar" }

];



var highestNr = Math.max.apply(null, Object.keys(data).map(function(e) {

             return data[e]['nr'];

         }));

                

var index = "???";



console.log("Highest 'nr': " + highestNr);

console.log("Index at nr "+ highestNr + ": " + index);



//console.log(data[index]);

I need the index or the whole object. I need to show the text from the object with the highest number.

edited Nov 13 '18 at 14:08

asked Nov 13 '18 at 12:56

Black

4,439844105

5

technical point, you haven't got an associative array here. You've got an array containing two objects. JS doesn't have associative arrays, it has objects - although it is possible to use them in a similar way to you might use an associative array in, say, PHP, e.g. by looping through the properties of the object.

– ADyson
Nov 13 '18 at 12:58

Once you have the highest number can't you just filter the array on that value?

– Darren Sweeney
Nov 13 '18 at 12:59

@DarrenSweeney: you could, but see the answer from NinaScholz for a better technique.

– Scott Sauyet
Nov 13 '18 at 13:00

1

@ADyson, thanks for the hint. I changed the title of the question.

– Black
Nov 13 '18 at 14:09

add a comment |

I was able to figure out how to return the highest number from a associative array with multiple objects. But I need the whole object.

I prepared this example:

var data = [

     { nr: 235, text: "foo" }

    ,{ nr: 351, text: "bar" }

];



var highestNr = Math.max.apply(null, Object.keys(data).map(function(e) {

             return data[e]['nr'];

         }));

                

var index = "???";



console.log("Highest 'nr': " + highestNr);

console.log("Index at nr "+ highestNr + ": " + index);



//console.log(data[index]);

I need the index or the whole object. I need to show the text from the object with the highest number.

edited Nov 13 '18 at 14:08

asked Nov 13 '18 at 12:56

Black

4,439844105

5

technical point, you haven't got an associative array here. You've got an array containing two objects. JS doesn't have associative arrays, it has objects - although it is possible to use them in a similar way to you might use an associative array in, say, PHP, e.g. by looping through the properties of the object.

– ADyson
Nov 13 '18 at 12:58

Once you have the highest number can't you just filter the array on that value?

– Darren Sweeney
Nov 13 '18 at 12:59

@DarrenSweeney: you could, but see the answer from NinaScholz for a better technique.

– Scott Sauyet
Nov 13 '18 at 13:00

1

@ADyson, thanks for the hint. I changed the title of the question.

– Black
Nov 13 '18 at 14:09

add a comment |

I was able to figure out how to return the highest number from a associative array with multiple objects. But I need the whole object.

I prepared this example:

var data = [

     { nr: 235, text: "foo" }

    ,{ nr: 351, text: "bar" }

];



var highestNr = Math.max.apply(null, Object.keys(data).map(function(e) {

             return data[e]['nr'];

         }));

                

var index = "???";



console.log("Highest 'nr': " + highestNr);

console.log("Index at nr "+ highestNr + ": " + index);



//console.log(data[index]);

I need the index or the whole object. I need to show the text from the object with the highest number.

edited Nov 13 '18 at 14:08

asked Nov 13 '18 at 12:56

Black

4,439844105

I was able to figure out how to return the highest number from a associative array with multiple objects. But I need the whole object.

I prepared this example:

var data = [

     { nr: 235, text: "foo" }

    ,{ nr: 351, text: "bar" }

];



var highestNr = Math.max.apply(null, Object.keys(data).map(function(e) {

             return data[e]['nr'];

         }));

                

var index = "???";



console.log("Highest 'nr': " + highestNr);

console.log("Index at nr "+ highestNr + ": " + index);



//console.log(data[index]);

I need the index or the whole object. I need to show the text from the object with the highest number.

var data = [

     { nr: 235, text: "foo" }

    ,{ nr: 351, text: "bar" }

];



var highestNr = Math.max.apply(null, Object.keys(data).map(function(e) {

             return data[e]['nr'];

         }));

                

var index = "???";



console.log("Highest 'nr': " + highestNr);

console.log("Index at nr "+ highestNr + ": " + index);



//console.log(data[index]);

var data = [

     { nr: 235, text: "foo" }

    ,{ nr: 351, text: "bar" }

];



var highestNr = Math.max.apply(null, Object.keys(data).map(function(e) {

             return data[e]['nr'];

         }));

                

var index = "???";



console.log("Highest 'nr': " + highestNr);

console.log("Index at nr "+ highestNr + ": " + index);



//console.log(data[index]);

javascript

edited Nov 13 '18 at 14:08

asked Nov 13 '18 at 12:56

Black

4,439844105

edited Nov 13 '18 at 14:08

asked Nov 13 '18 at 12:56

Black

4,439844105

edited Nov 13 '18 at 14:08

asked Nov 13 '18 at 12:56

Black

4,439844105

asked Nov 13 '18 at 12:56

Black

4,439844105

asked Nov 13 '18 at 12:56

Black

4,439844105

5

technical point, you haven't got an associative array here. You've got an array containing two objects. JS doesn't have associative arrays, it has objects - although it is possible to use them in a similar way to you might use an associative array in, say, PHP, e.g. by looping through the properties of the object.

– ADyson
Nov 13 '18 at 12:58

Once you have the highest number can't you just filter the array on that value?

– Darren Sweeney
Nov 13 '18 at 12:59

@DarrenSweeney: you could, but see the answer from NinaScholz for a better technique.

– Scott Sauyet
Nov 13 '18 at 13:00

1

@ADyson, thanks for the hint. I changed the title of the question.

– Black
Nov 13 '18 at 14:09

add a comment |

5

technical point, you haven't got an associative array here. You've got an array containing two objects. JS doesn't have associative arrays, it has objects - although it is possible to use them in a similar way to you might use an associative array in, say, PHP, e.g. by looping through the properties of the object.

– ADyson
Nov 13 '18 at 12:58

Once you have the highest number can't you just filter the array on that value?

– Darren Sweeney
Nov 13 '18 at 12:59

@DarrenSweeney: you could, but see the answer from NinaScholz for a better technique.

– Scott Sauyet
Nov 13 '18 at 13:00

1

@ADyson, thanks for the hint. I changed the title of the question.

– Black
Nov 13 '18 at 14:09

technical point, you haven't got an associative array here. You've got an array containing two objects. JS doesn't have associative arrays, it has objects - although it is possible to use them in a similar way to you might use an associative array in, say, PHP, e.g. by looping through the properties of the object.

– ADyson
Nov 13 '18 at 12:58

Once you have the highest number can't you just filter the array on that value?

– Darren Sweeney
Nov 13 '18 at 12:59

@DarrenSweeney: you could, but see the answer from NinaScholz for a better technique.

– Scott Sauyet
Nov 13 '18 at 13:00

@ADyson, thanks for the hint. I changed the title of the question.

– Black
Nov 13 '18 at 14:09

add a comment |

3 Answers
3

active

oldest

votes

You could reduce the array by selecting the one with a greater value.

var data = [{ nr: 235, text: "foo" }, { nr: 351, text: "bar" }], 

    topNr = data.reduce((a, b) => a.nr > b.nr ? a : b);



console.log(topNr);

edited Nov 13 '18 at 13:01

answered Nov 13 '18 at 12:59

Nina Scholz

178k1491158

add a comment |

You can "sort" the array by "nr" property in descending order and get first element "[0]"

var data = [

     { nr: 235, text: "foo" }

    ,{ nr: 351, text: "bar" }

];



// slice added so that original data is not mutated

var result = data.slice(0).sort((a,b) => b.nr - a.nr)[0]



console.log(result)

edited Nov 13 '18 at 13:10

answered Nov 13 '18 at 12:58

Nitish Narang

2,948815

Using sort is a good idea, especially if you also wanted the nth highest etc. But it might be worth pointing out this will mutate the array, so you might want to do .concat(data).sort( if this is not desired.

– Keith
Nov 13 '18 at 13:08

1

Sorting is fine for small lists. But it's going to be O(n log n), whereas this can be done in O(n) as the reduce answers show.

– Scott Sauyet
Nov 13 '18 at 13:10

A good use case you mentioned. Updated.

– Nitish Narang
Nov 13 '18 at 13:10

@ScottSauyet Thanks for pointing complexity. Correct, it depends upon the size of array.

– Nitish Narang
Nov 13 '18 at 13:12

add a comment |

You can also use findIndex() method:

var data = [

     { nr: 235, text: "foo" }

    ,{ nr: 351, text: "bar" }

];



var highestNr = Math.max.apply(null, Object.keys(data).map(function(e) {

    return data[e]['nr'];

}));

                

var index = data.findIndex(function(ln) {

    return ln.nr === highestNr;

});



console.log("Highest 'nr': " + highestNr);

console.log("Index at nr "+ highestNr + ": " + index);



//console.log(data[index]);

answered Nov 13 '18 at 13:03

Roland Ruul

827414

add a comment |

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3 Answers
3

active

oldest

votes

3 Answers
3

active

oldest

votes

You could reduce the array by selecting the one with a greater value.

var data = [{ nr: 235, text: "foo" }, { nr: 351, text: "bar" }], 

    topNr = data.reduce((a, b) => a.nr > b.nr ? a : b);



console.log(topNr);

edited Nov 13 '18 at 13:01

answered Nov 13 '18 at 12:59

Nina Scholz

178k1491158

add a comment |

You could reduce the array by selecting the one with a greater value.

var data = [{ nr: 235, text: "foo" }, { nr: 351, text: "bar" }], 

    topNr = data.reduce((a, b) => a.nr > b.nr ? a : b);



console.log(topNr);

edited Nov 13 '18 at 13:01

answered Nov 13 '18 at 12:59

Nina Scholz

178k1491158

add a comment |

You could reduce the array by selecting the one with a greater value.

var data = [{ nr: 235, text: "foo" }, { nr: 351, text: "bar" }], 

    topNr = data.reduce((a, b) => a.nr > b.nr ? a : b);



console.log(topNr);

edited Nov 13 '18 at 13:01

answered Nov 13 '18 at 12:59

Nina Scholz

178k1491158

You could reduce the array by selecting the one with a greater value.

var data = [{ nr: 235, text: "foo" }, { nr: 351, text: "bar" }], 

    topNr = data.reduce((a, b) => a.nr > b.nr ? a : b);



console.log(topNr);

var data = [{ nr: 235, text: "foo" }, { nr: 351, text: "bar" }], 

    topNr = data.reduce((a, b) => a.nr > b.nr ? a : b);



console.log(topNr);

var data = [{ nr: 235, text: "foo" }, { nr: 351, text: "bar" }], 

    topNr = data.reduce((a, b) => a.nr > b.nr ? a : b);



console.log(topNr);

edited Nov 13 '18 at 13:01

answered Nov 13 '18 at 12:59

Nina Scholz

178k1491158

edited Nov 13 '18 at 13:01

answered Nov 13 '18 at 12:59

Nina Scholz

178k1491158

answered Nov 13 '18 at 12:59

Nina Scholz

178k1491158

answered Nov 13 '18 at 12:59

Nina Scholz

178k1491158

add a comment |

You can "sort" the array by "nr" property in descending order and get first element "[0]"

var data = [

     { nr: 235, text: "foo" }

    ,{ nr: 351, text: "bar" }

];



// slice added so that original data is not mutated

var result = data.slice(0).sort((a,b) => b.nr - a.nr)[0]



console.log(result)

edited Nov 13 '18 at 13:10

answered Nov 13 '18 at 12:58

Nitish Narang

2,948815

Using sort is a good idea, especially if you also wanted the nth highest etc. But it might be worth pointing out this will mutate the array, so you might want to do .concat(data).sort( if this is not desired.

– Keith
Nov 13 '18 at 13:08

1

Sorting is fine for small lists. But it's going to be O(n log n), whereas this can be done in O(n) as the reduce answers show.

– Scott Sauyet
Nov 13 '18 at 13:10

A good use case you mentioned. Updated.

– Nitish Narang
Nov 13 '18 at 13:10

@ScottSauyet Thanks for pointing complexity. Correct, it depends upon the size of array.

– Nitish Narang
Nov 13 '18 at 13:12

add a comment |

You can "sort" the array by "nr" property in descending order and get first element "[0]"

var data = [

     { nr: 235, text: "foo" }

    ,{ nr: 351, text: "bar" }

];



// slice added so that original data is not mutated

var result = data.slice(0).sort((a,b) => b.nr - a.nr)[0]



console.log(result)

edited Nov 13 '18 at 13:10

answered Nov 13 '18 at 12:58

Nitish Narang

2,948815

Using sort is a good idea, especially if you also wanted the nth highest etc. But it might be worth pointing out this will mutate the array, so you might want to do .concat(data).sort( if this is not desired.

– Keith
Nov 13 '18 at 13:08

1

Sorting is fine for small lists. But it's going to be O(n log n), whereas this can be done in O(n) as the reduce answers show.

– Scott Sauyet
Nov 13 '18 at 13:10

A good use case you mentioned. Updated.

– Nitish Narang
Nov 13 '18 at 13:10

@ScottSauyet Thanks for pointing complexity. Correct, it depends upon the size of array.

– Nitish Narang
Nov 13 '18 at 13:12

add a comment |

You can "sort" the array by "nr" property in descending order and get first element "[0]"

var data = [

     { nr: 235, text: "foo" }

    ,{ nr: 351, text: "bar" }

];



// slice added so that original data is not mutated

var result = data.slice(0).sort((a,b) => b.nr - a.nr)[0]



console.log(result)

edited Nov 13 '18 at 13:10

answered Nov 13 '18 at 12:58

Nitish Narang

2,948815

You can "sort" the array by "nr" property in descending order and get first element "[0]"

var data = [

     { nr: 235, text: "foo" }

    ,{ nr: 351, text: "bar" }

];



// slice added so that original data is not mutated

var result = data.slice(0).sort((a,b) => b.nr - a.nr)[0]



console.log(result)

var data = [

     { nr: 235, text: "foo" }

    ,{ nr: 351, text: "bar" }

];



// slice added so that original data is not mutated

var result = data.slice(0).sort((a,b) => b.nr - a.nr)[0]



console.log(result)

var data = [

     { nr: 235, text: "foo" }

    ,{ nr: 351, text: "bar" }

];



// slice added so that original data is not mutated

var result = data.slice(0).sort((a,b) => b.nr - a.nr)[0]



console.log(result)

edited Nov 13 '18 at 13:10

answered Nov 13 '18 at 12:58

Nitish Narang

2,948815

edited Nov 13 '18 at 13:10

answered Nov 13 '18 at 12:58

Nitish Narang

2,948815

answered Nov 13 '18 at 12:58

Nitish Narang

2,948815

answered Nov 13 '18 at 12:58

Nitish Narang

2,948815

Using sort is a good idea, especially if you also wanted the nth highest etc. But it might be worth pointing out this will mutate the array, so you might want to do .concat(data).sort( if this is not desired.

– Keith
Nov 13 '18 at 13:08

1

Sorting is fine for small lists. But it's going to be O(n log n), whereas this can be done in O(n) as the reduce answers show.

– Scott Sauyet
Nov 13 '18 at 13:10

A good use case you mentioned. Updated.

– Nitish Narang
Nov 13 '18 at 13:10

@ScottSauyet Thanks for pointing complexity. Correct, it depends upon the size of array.

– Nitish Narang
Nov 13 '18 at 13:12

add a comment |

Using sort is a good idea, especially if you also wanted the nth highest etc. But it might be worth pointing out this will mutate the array, so you might want to do .concat(data).sort( if this is not desired.

– Keith
Nov 13 '18 at 13:08

1

Sorting is fine for small lists. But it's going to be O(n log n), whereas this can be done in O(n) as the reduce answers show.

– Scott Sauyet
Nov 13 '18 at 13:10

A good use case you mentioned. Updated.

– Nitish Narang
Nov 13 '18 at 13:10

@ScottSauyet Thanks for pointing complexity. Correct, it depends upon the size of array.

– Nitish Narang
Nov 13 '18 at 13:12

Using sort is a good idea, especially if you also wanted the nth highest etc. But it might be worth pointing out this will mutate the array, so you might want to do .concat(data).sort( if this is not desired.

– Keith
Nov 13 '18 at 13:08

Sorting is fine for small lists. But it's going to be O(n log n), whereas this can be done in O(n) as the reduce answers show.

– Scott Sauyet
Nov 13 '18 at 13:10

A good use case you mentioned. Updated.

– Nitish Narang
Nov 13 '18 at 13:10

@ScottSauyet Thanks for pointing complexity. Correct, it depends upon the size of array.

– Nitish Narang
Nov 13 '18 at 13:12

add a comment |

You can also use findIndex() method:

var data = [

     { nr: 235, text: "foo" }

    ,{ nr: 351, text: "bar" }

];



var highestNr = Math.max.apply(null, Object.keys(data).map(function(e) {

    return data[e]['nr'];

}));

                

var index = data.findIndex(function(ln) {

    return ln.nr === highestNr;

});



console.log("Highest 'nr': " + highestNr);

console.log("Index at nr "+ highestNr + ": " + index);



//console.log(data[index]);

answered Nov 13 '18 at 13:03

Roland Ruul

827414

add a comment |

You can also use findIndex() method:

var data = [

     { nr: 235, text: "foo" }

    ,{ nr: 351, text: "bar" }

];



var highestNr = Math.max.apply(null, Object.keys(data).map(function(e) {

    return data[e]['nr'];

}));

                

var index = data.findIndex(function(ln) {

    return ln.nr === highestNr;

});



console.log("Highest 'nr': " + highestNr);

console.log("Index at nr "+ highestNr + ": " + index);



//console.log(data[index]);

answered Nov 13 '18 at 13:03

Roland Ruul

827414

add a comment |

You can also use findIndex() method:

var data = [

     { nr: 235, text: "foo" }

    ,{ nr: 351, text: "bar" }

];



var highestNr = Math.max.apply(null, Object.keys(data).map(function(e) {

    return data[e]['nr'];

}));

                

var index = data.findIndex(function(ln) {

    return ln.nr === highestNr;

});



console.log("Highest 'nr': " + highestNr);

console.log("Index at nr "+ highestNr + ": " + index);



//console.log(data[index]);

answered Nov 13 '18 at 13:03

Roland Ruul

827414

You can also use findIndex() method:

var data = [

     { nr: 235, text: "foo" }

    ,{ nr: 351, text: "bar" }

];



var highestNr = Math.max.apply(null, Object.keys(data).map(function(e) {

    return data[e]['nr'];

}));

                

var index = data.findIndex(function(ln) {

    return ln.nr === highestNr;

});



console.log("Highest 'nr': " + highestNr);

console.log("Index at nr "+ highestNr + ": " + index);



//console.log(data[index]);

var data = [

     { nr: 235, text: "foo" }

    ,{ nr: 351, text: "bar" }

];



var highestNr = Math.max.apply(null, Object.keys(data).map(function(e) {

    return data[e]['nr'];

}));

                

var index = data.findIndex(function(ln) {

    return ln.nr === highestNr;

});



console.log("Highest 'nr': " + highestNr);

console.log("Index at nr "+ highestNr + ": " + index);



//console.log(data[index]);

var data = [

     { nr: 235, text: "foo" }

    ,{ nr: 351, text: "bar" }

];



var highestNr = Math.max.apply(null, Object.keys(data).map(function(e) {

    return data[e]['nr'];

}));

                

var index = data.findIndex(function(ln) {

    return ln.nr === highestNr;

});



console.log("Highest 'nr': " + highestNr);

console.log("Index at nr "+ highestNr + ": " + index);



//console.log(data[index]);

answered Nov 13 '18 at 13:03

Roland Ruul

827414

answered Nov 13 '18 at 13:03

Roland Ruul

827414

answered Nov 13 '18 at 13:03

Roland Ruul

827414

answered Nov 13 '18 at 13:03

Roland Ruul

827414

add a comment |

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